Hey! Hey!Hey!

Hey! Hey!

Hey!

Hey!

Hey!Hey!

Hey!Hey!

Hey! Hey!

Hey! Hey!

Hay

Today TodayToday

Today!!!!!!!!!

We will be working on

solving system of equations by elimination !

BUT FIRST !!!!

RANDOM DANCE PARTY

!!!!!!

Okay now we’re ready to work

:D haha

But first.

We’re going to need to know a few things

aren’t we?

(this is where you say yes and nod your head so

Mrs. Austin thinks your smart and are

Paying attention)

How do you solve a system of equations

using elimination??

It’s actually a whole lot easier than you think.

So let’s get started!!!! HEY STOP

DANCING!!! >:(

Okay. Here’s our problem

2x + y = 93x – y = 16

Note that, if I add down, the y's will cancel out. So I'll draw an "equals"

bar under the system,

and add down

Then I get this.2x + y = 93x – y = 165x      = 25

Now I can divide through to solve for

x = 5, and then back-

solve, using either of the original

equations, to find the value of y. The first equation

has smaller numbers,

so I'll back-solve in that one:2(5) + y = 9

  10 + y = 9          y = –1

Then the solution is…..

RAVE DANCE TIME!!!

Haha!! Just Kidding!!!

(x, y) = (5, –1).

(x, y)

= (5, –

1).

(x, y) = (5, –

1).(x, y) = (5, –

1).

(x, y) = (5, –1).

(x, y)

= (

5,

–1

).

(x, y) = (5, –

1).

(x, y

) = (5

, –

1).

Some of you may bewondering what would

happen if I use the other equation.It doesn't matter which equation you use for the backsolving;

you'll get the same answer either way. If I'd used the second equation, I'd have gotten:

3(5) – y = 16  15 – y = 16        –y = 1

          y = –1

...which is the same result as before.

Now…How is this all usedIn the real world?

Of course silly!When you become a

Algebra One teacher likeMrs. Austin.

Thank you for listening toMy presentation

But of course we can’t go Without one last thing….

DANCE PARTY!!!!!!

AND JUST TO GIVE YOU NIGHTMARES!!!!

End.