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必修-數學課程綱要 43 普通高級中學必修科目「數學」課程綱要 壹、課程目標 普通高級中學必修科目「數學」課程欲達成的目標如下: 一、培養學生具備以數學思考問題、分析問題和解決問題的能力。 二、培養學生具備實際生活應用和學習相關學科所需的數學知能。 三、培養學生欣賞數學內涵中以簡馭繁的精神和結構嚴謹完美的特質。 貳、核心能力 一、演算能力:能熟練多項式、分式、根式、指對數、三角的運算及估算。 二、抽象化能力:能將具體世界中的概念以數學形式表徵。 三、推理能力:能認識證明,並進行推論。 四、連結能力:能整合數學內部知識並與具體世界連結。 五、解題能力:能解決數學形式與生活情境中的數學問題。 六、溝通能力:能正確、流暢地利用口語或文字表達解題想法。 七、使用計算工具的能力:能使用計算器來處理繁瑣的計算與解決較複雜的問題。 參、時間分配 第一、二學年每學期四學分,每週授課四節。 肆、教材綱要 普通高級中學必修科目「數學」課程分為數學 IIIIIIIV,各四學分。 一、各學年課程的定位如下: 高一數學(數學 III)的定位為學習與生活關聯或其他學科需要用到的數 學,以建立學生在各學科進行量化分析時所需要的基礎。高一上處理有關連續量 的課題,包括由度量連續量所產生的實數,以及描述量與量關係的基本函數,如 多項式函數與指數、對數函數。高一下處理有關離散量的課題,包括數列與級數、 排列組合、生活中常見的古典機率,以及其他學科常用到的數據分析等。 高二數學(數學 IIIIV)的定位為社會組與自然組學生在學習上所應具備 的數學知識,其主題為坐標、向量幾何與線性代數。 二、教材綱要包括主題、子題、內容、備註。備註欄表列學習規範及全國性評量 不應測試的內容。有關綱要內容的說明與範例則置於附錄。 三、課程分版:高二數學分為 AB 兩版,B 版的內容包含 A 版,所增加的題材 以加註◎號區隔。

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    43

    IIIIIIIV

    III

    IIIIV

    AB B A

  • 44

    I4

    1.1

    1.

    1.2

    1.3

    1.2

    2. 2.1

    2.2

    1.1 1.2

    1.

    1.3

    1.3 4

    2.

    2.1

    2.1

    3. 3.1 3.2 n a

    3.3

    3.1

    4.

    4.1

    4.1

    1. 1.1

    2. 2.1

    3. 3.1 3.2

    3.2

    4. 4.1

  • -

    45

    5.

    5.1

    5.2 5.3 5.4

    5.1

    2

  • 46

    II4

    1. 1.1 1.2

    1.1

    1.2 / I

    2. 2.1 1.

    1.1

    1.2

    1.3

    1.4

    2. 2.1 2.2

    2.1

    3. 3.1

    3.1

    1.

    1.1

    2.

    2.1 2.1

    3.

    3.1

    1.

    1.1 1.1

    2. 2.1

    2.1

    1.

    2.

  • -

    47

    III4

    1.

    1.1

    2.

    2.1

    2.2

    2.1 cot, sec, csc II

    3.

    3.1

    4. 4.1

    4.1

    5. 5.1 5.2

    5.1

    1.

    1.1 1.2

    2. 2.1 2.2

    3.

    3.1 3.2

    3.2

    1.

    1.1

    1.2

    2.

    2.1

    2.2

    3.

    3.1

    3.2

  • 48

    IV4

    1. 1.1

    1.1

    2.

    2.1

    2.2

    3.

    3.1

    4.

    4.1

    4.2

    4.3

    4.3

    1. 1.1

    2.

    2.1

    2.2

    3.

    3.1 3.2

    1.

    1.1

    1.1

    2. 2.1

    3. 3.1

    4.

    4.1 4.2

    4.2

    1. 1.1 2. 2.1

    3. 3.1

  • -

    49

    1.

    2. 3. 4.

    5.

    1 2 3 6.

    7.

    8.

  • 50

    IIIIII IV

    I

    2

    1. 1.1

  • -

    51

    1.2

    2 12

    121 +=

    2a a=

    2a bab +

    1.3 ( )3a b+ ( ) ( )2 2a b a ab b+ + ( ) ( )2 2a b a ab b + + ( )2a b c+ +

    ( ) ( )21 1x x x + + ( ) ( )1 2x y x y+ + 3 3 3 2 2 23 ( )( )x y z xyz x y z x y z xy yz zx+ + = + + + +

    1 21 1 12

    aba b

    a b

    = + +

    2 2 2 2

    1 c

    a ba bc c

    = + +

    5 2 6 3 2+ = +

    2 2 12x x x x + + = + 2. 2.1

    ,a b ,a b 2:3 x 2.2 a b a b+ + 3 2x < 1 1x < 1 2x< < 1 2 3x x <

    ncxy = n=1234

  • 52

    ( )ax ( )ax ( )bx 2 1x + 2 1x x+ + ( )xf ( )ax ( )f a ( )ax ( )xf ( )ax ( )xf a ( )xf ( )ax ( )bx ( ),a ( ),b ( )xf ( )ax ( )bx

    I n

    1. 1.1 ( )y f x= ( )0y mx b m x x= + = 0, ,m x b m y x 1.2 22,32)( 2 ++= xxxxf 2 4x x +

  • -

    53

    ( ) ( )y c x a x b= 2y ax bx c= + + ( )2y a x h k= +

    1.3 ny x= 1, 2,3, 4n = [ ]1.5,1.5

    n ny cx= c ny cx= ( )ny c x h k= +

    2. 2.1 ( ) ( )1 2 1n n n n nx a x x a a x a + + + = L n = 2,3,4 3322 ))(( axaaxxax +=++

    ( ) ( ) ( ) ( )2 33 22 5 6 3 1 1 1f x x x x a b x c x d x= + + = + + + , , ,a b c d ( )1.01f

    ( ) ( ) ( )( ) ( ) ( ) ( )3 22 5 6 3 1 1 2 1 2 3f x x x x a b x c x x d x x x= + + = + + +

    , , ,a b c d ( )xf ( )ax ( )bx ( )( ) ( )( ), , ,a f a b f b f a,b f ( ) ( )( )( )f x q x x a x b= ( ) ( ) ( )1,1 , 2, 3 , 3, 7 ( ) ( ) ( ) ( )1 1 2f x a b x c x x= + +

    , ,a b c 12

    f

  • 54

    )8,13(),5,12(),3,11(

    )1213)(1113()12)(11(8

    )1312)(1112()13)(11(5

    )1311)(1211()13)(12(3)(

    ++

    = xxxxxxxf

    ( )11.5f ( ) ( ) ( )1,1 , 2, 3 , 3, 7

    ( ) 2f x a bx cx= + + , ,a b c IV

    3. 3.1

    2 0ax bx c+ + =

    2 5 3 0x x+ + = 2 2 + 3 3 + 1 1 3

    1 2 2x x+ =

    3.2 n a

    nx a= a>0 ( ) 3 22 3 4f x x x x= + + + n 3.3

    ( ) ( ) ( ) ( ) ( )11 2 21 1 1 mk s sr rk m mf x k x a x a x b x c x b x c= + + + +L L

    ( ) 4 3 25 21 30 9 7f x x x x x= + + 2x i= + 4. 4.1

    ( ) ( ) ( )21 2 4 0x x x + > ( ) ( ) ( )3 21 2 1 0x x x x + + > 3 1 0x > 4 22 3 0x x > 1 0

    x< 1 1

    1x

  • -

    55

    10 , 0.1,0.2, ,0.9x x = L

    0, 1a a> 2x 10x

    logax b= xa b= 10 ( ) yxxy logloglog +=

    ( )log / log logx y x y= ( ) xx loglog =

    10 1log log

    logax x

    a=

    logy x= logy x=

    1. 1.1

    n 1 513 6210 10 10 =

    1 1 13 3 32 3 6 =

    1 13 210 10<

    1 1 1( ) ( ) ( )a b ca b c a b c a b c a b cx x x 2 2 3xa = +

    3 3

    6

    x x

    x x

    a aa a

    +

    + +

  • 56

    2. 2.1 2x

    10x 3. 3.1 ( ) yxxy logloglog += ( )log / log logx y x y= ( ) xx loglog =

    ( )( ) log loglog log , log log log , x xm b an a a b aa nb b b c c a bm= = = 3.2 1log log

    logax x

    a=

    10 4. 4.1 xy a= logax y= 1log loga x x= log a =

    2

    a bab + log log log2 2

    a b a b+ + a b= 5. 5.1

    5.2 1002 ( )101.18

    5.3 5.4

  • -

    57

    II

    / 1. 1.1 1n na a d+ = + 1n na ra+ = 1n na a n+ = + 21n na a n+ = + ( )1 1n na n a+ = + 1.2 / II 2. 2.1

    ( )1 1 1

    n n n

    k k k kk k k

    a b a b= = =

    + = + 1 1

    n n

    k kk k

    ca c a= =

    =

    1

    11 2

    n n

    k kk k

    a a+

    = =

    =

    1

    n

    kk

    = 2

    1

    n

    kk

    = ( )1

    11

    n

    k k k= +

    1. 1.1

  • 58

    1.2

    1.3 |S| S

    10 8 3 5 7 21 4 1 3 6

    10+8+3+5+7+21+4+1+3+6 = 68

    51 51 50 1.4 A B |A B| = |A| + |B| A, B A B |A B| = |A||B| A, B, C

    1 |A B| = |A| + |B| |A B| 2 |A B C| = |A| + |B| + |C| |A B| |B C| |C A| + |A B C| Principle of Inclusion and Exclusion PIE

    Inclusion and Exclusion PIE 2. 2.1 n n!

    1 n 1 n n!

    n k

  • -

    59

    )!(!kn

    nPnk = 1 k 1 n nkP

    50 1

    n k nk

    1 k 1 n nk

    10 310 1 0 A={0,1} n

    An = A A . . . A n 2n 2.2

    !!( )!

    nk

    nCk n k

    = n k

    !!( )!

    nk

    nCk n k

    = k 1 n

    nkC

    n k

    1n kkC+

    k 1 n

    1n kkC + n k x1 + x2 + + xn = k

    1n kkC + 3.

    3.1 (x + yn

    5

    2 1 1xx

    + + x

  • 60

    1. 1.1

    3 2. 2.1

    50 3. 3.1 ABC A 40%B

    30%C 30% A 5%B 10%C 8% A

    90% 90% 90% 2%

    1. 1.1

    1

    1 nk

    kx

    n

    =

    = ( )1

    1 2n

    nx x xL

    ( )21

    1 nk

    kx

    n

    =

    = ( )2

    1

    1 nk

    kx x

    n = 2 x=

    ix ix

  • -

    61

    2. 2.1 0

    ( ) , , 1,2, ,k kx y k n= L , ( )21

    ( )n

    k kk

    e r y rx=

    = r 2 2 2 2

    1 1

    ( ) ( 2 ) = 2( ) 1n n

    i i i i i ii i

    e r y x y r x r r x y r= =

    = + +

    1

    n

    i ii

    r x y=

    = y rx= ( )e r

    II

    1. 2.

    III

  • 62

    360 r 0 360

    X

    1. 1.1

  • -

    63

    O

    ( )2 2cos ,sinB ( )1 1cos ,sinA

    1,0

    2. 2.1

    X 150 , 30 ; 225 , 45 ; 300 , 60 = = = = = =

    cos , sin

    2.2 r, 0 , 0 360r < < 3.

    ABC B ( ), 0c C ( )cos , sinb A b A ABC 1 sin

    2c b A

    ABC 1 sin2

    a c B

    ABC 1 sin2

    a b C ABC A B ( ), 0c C

    ( )cos , sinb A b A ( ) ( )2 22 2 2cos sin 2 cosa b A c b A b c bc A= + = +

    4. ( )2 1 1 2 1 2cos cos cos sin sin = + 4.1

    A,B ( ) ( )1 1 2 2cos ,sin , cos ,sin OAB ( )2 1 1 2 1 2cos cos cos sin sin = +

    A B D

    C

    ( )2 2 2 22 22 2

    sin cos

    2 cos

    BC CD BD b A c b A

    b c bc A

    = + = + = +

  • 64

    ( )1 2cos + ( )1 2sin + ( )1 2tan + cos2 sin 2 cos

    2 sin

    2

    cos15o 5.

    5.1 5.2

    1. 1.1 1.2 2. 2.1 2.2 ax by k+ = 3. 3.1 3.2

    2

  • -

    65

    a

    vb

    v

    1 1 2 2cosa b a b a b = +v v

    1 2 2 1sina b a b a b =

    v v

    1 1 12 2 2

    a x b y ca x b y c

    + = + =

    c xa yb= +v v v av bv 0 a

    vb

    v

    1. 1.1

    1.2

    1 2 0 1 ,0 12 1

    x y x y +

    45

    12

    21

    2. 2.1

  • 66

    ar

    br

    ( )1 2,b b

    ( )1 2,a a

    ( ) ( )1 2 1 2, , ,a a a b b b= =r r ( ) ( ) 2 22 21 1 2 2 2 cosa b a b a b a b + = + r r r r 1 1 2 2 cosa b a b a b + =

    r r

    ,a b

    r r a br r

    a b b a = r r r r ( )a b c a c b c+ = + r r r r r r r 2a a a =r r r ( ) ( )2 2 2 2 2ax by a b x y+ + + a b a b+ +r rr r 4, 51, 2

    2.2 3. 3.1

    1. O ABO0,0 ( )1 2,A a a ( )1 2,B b b 2. ,a b

    r r

    ( )( ) ( ) ( )

    2 2 2

    22 2 2 21 2 1 2 1 1 2 2 1 2 2 1

    1 1 1sin 1 cos2 2 2

    1 12 2

    OAB a b a b a b a b

    a a b b a b a b a b a b

    2 = = =

    = + + + =

    v v v v v v v v

    1 1 1 2 1 12 2 1 2 2 2

    a b a a b aa b b b b a

    = = 1 1 1 1 1 1 12 2 2 2 2 2 2

    a c b a b c ba c b a b c b

    + = ++

    1 1 1 1

    2 2 2 2

    ca b a bc

    ca b a b=

    D C

    ( )1 2,A a a ( )1 2,B b b

    O x

    y

    ( )1 2 2 2 1 1 1 2

    1 2 2 1

    1 1 1( )( )2 2 2

    12

    OAB b b a b a b a a

    a b a b

    = + +

    =

  • -

    67

    3.2

    1 1 12 2 2

    a x b y ca x b y c

    + = + =

    cv

    av

    bv

    av

    bv

    0

    IV

    0 0 1. 1.1 2. 2.1 2.2

    ( ) ( ){ }1,2,3 0,1, 1 | 0 1t t+ ( ) ( ){ }1,2,3 0,1, 1 | 0 1,0 2s t s t+ 3. 3.1 ( )1 2 3, ,a a a ( )1 2 3, ,b b b

    1 1 2 2 3 3 cosa b a b a b a b + + =v v

    av

    bv

    1 1 2 2 3 3a b a b a b+ + 4. 4.1

  • 68

    ( ) 2 2 22 2 3 3 1 1 22 2 22 3 3 1 1 2

    | | | |a a a a a a

    A a b a bb b b b b b

    = = + +v v v v 4.2 , ,a b c

    vv v )( cba vvv

    4.3

    2

    2

    2

    1 1 1

    a ba caab b cbac bc c

    ++

    +

    baccbcabaacb

    ++

    +

    1. 1.1 2. 2.1 1: 1

    2 3x zL y = + = : 2 3E x y z+ =

    2.2 3. 3.1 3.2

    1 1 1 1

    2 2 2 2

    3 3 3 3

    a x b y c z da x b y c z da x b y c z d

    + + = + + = + + =

    d

    uv a

    vb

    v c

    v a

    vb

    v c

    v

    0

  • -

    69

    1.

    2. 2.1 Caley-Hamilton 3. 3.1 4. 4.1 4.2

    1 22 1

    A = A 1

    0

    01

    12

    21

    12

    34

    12

    21

  • 70

    1. 1.1

    ( )22x y c y c+ - = + 2. 2.1

    ( ) ( )2 22 2 2x c y x c y a + + + + =

    x x hy y k= =

    ( ) ( )2 22 2 1

    x h y ka b + =

    2 2

    2 2 1x ya b

    + =

    2 2

    2 2x y ka b

    + =

    ,x yx yt t

    = = 2 2

    22 2

    x y ta b

    + = 2 2

    2 2 1x ya b

    + =

    2 2 0ax cy dx ey f+ + + + = ( ) ( )2 2 2 2a x h c y k ah ck f + = +

    3. 3.1

    ( ) ( )2 22 2 2x c y x c y a + + + =