18
Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks about what is the purpose of the “junk” DNA.) Today Review quiz

Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

Embed Size (px)

Citation preview

Page 1: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

HomeworkWritten HW #1 due Thursday

Reading #2, Scientific American by Mattick,assigned today, due next Tuesday(a few question quiz next Tuesday)

(Talks about what is the purpose of the “junk” DNA.)

TodayReview quiz

Page 2: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

Quiz

Eukaryotes, Prokaryotes, Archea

Central Dogma Biol: DNA RNA Proteins, or Nucleic Acids Proteins

G=Hsystem (enthalpy) –TSsystem (entropy)

H < 0 ; S > 0

Stotal must increase = Ssystem +Ssurrounding

Htotal = constant = Hsystem +Hsurrounding

(Either one can go up or down) Water will H-bond with itself but also w amino acids. Therefore where H-bonding occurs within protein is often regions that water is excluded

from.

Page 3: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

Basic Biology & some calculations

[Read Chpt 1 of Berg et al.: lots of important things about Molecular

Binding, Central Dogma, Entropy, G]

1.Size of Cells and King Kong2.Entropy Matters, G, ATP.

Page 4: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

The Cell is the Fundamental Unit of Life

A bacteria and archea, (w/o nucleus): 1 x 2 mA eukaryotic cell, (w nucleus): 10-100 m.

from Latin cella, meaning "small room"

Three types:

What determines how small a cell can be?.

What determines how large a cell can be?

Minimum size to have enough room for ~1000 reactions necessary for life.

Maximum size to make sure molecules find each other rapidly enough so metabolism can take place

--will study more, but partly based on diffusion. Bacteria small enough that don’t need anything else beside diffusion. Eukaryotes

also have molecular motors to cause molecules to get close together and react.

(Bacteria has about 10x faster metabolism than eukaryotic cells.)

Page 5: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

Mass?

Strength?

King Kong is proportionally speaking is 10x weaker than regular gorilla!

Regular gorilla with 10 gorilla’s on him—couldn’t walk.

10 x 10 x 10 = 103

Strength/Mass ratio?

10 x 10 = 102.

1/10… 1/dimension

(density is the same):

Cross-sectional area (rope):

Page 6: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

Bones break; also overheat (because warm-blooded and water is going at conducting away heat, whereas air is not.)

If whale stranded on the beach?

In water– held up by buoyant force.Bones do not need to support weightIf have to, have super big bones– would sink.

Whales

Page 7: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

Thermal energy matters a lot!

Everything (which goes like x2 or v2 in PE or KE) has ½ kT of energy.

If a barrier has on this order, you can jump over it and you will be a mixture of two states.

Boltzman distribution = Z-1 exp (-E/kBT)

E

kf

kb

Keq = kf/kb

Page 8: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

Entropy also matters(if lots of states can go into due to

thermal motion)Probability of going into each state increases

as # of states increases

E1 E1E1

Add up the # of (micro-)states, and take logarithm: ln i= Si = Entropy

E2E2

E3

Page 9: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

In general, there can be a number of different states, Wi, that are degenerate—have the same energy, but can put a molecule into, with P(Ei)

2

1

0

3W=1

W=1

W= 1

W=1

2

1

0

3W=3

W=2

W=3

W=2

Usual Boltzmann Faxtor:

P(Ei) = (1/Z) e-Ei/kT

P(Ei, Wi) = (Wi/Z) e-Ei/kT

P(Ei, Wi) = (2/Z) e-0/kT + (3/Z) e-/kT + (2/Z) e-2/kT +…

Boltzmann factor & Degeneracy

With degeneracy

Page 10: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

• Generalize the definition of the free energy to include degeneracy. Like flipping a deck of cards twice.

• Each energy level may be populated with several molecules, i.e. have many accessible states. We define the multiplicity Wi as the number of accessible states with energy Ei. For example:

Boltzmann factor & Degeneracy

2

1

0

3W=3

W=2

W=3

W=2

  (1/Z) [exp(lnWi)] exp(-Ei/kT)

 Assume that a more general formula for the probability

P(Ei, Wi) = (Wi/Z) e-Ei/kT

of finding a molecule with energy Ei, with the multiplicity factor Wi.  Using Wi = exp[ln Wi]

P(Ei, Wi) = (Wi/Z) exp(-Ei/kT) =

= (1/Z) exp -(Ei – kTlnWi)/kT

Define S= kln[Wi] P(Ei, Wi) = (1/Z) exp -(Ei – TS)/kT = = (1/Z) exp –[Fi /kT]

where F = Helmholtz free energy which is same as Gibb’s Free Energy for liquids (non-gasses).Note: ∆G because always energy w.r.t. some zero (like E, ∆E); define E and S. Typically, 1M concentration.

Page 11: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

G vs FUp till now we said change in energy

= kinetic + potential energy.In some cases, there is a change in volume

(e.g. explosives work)

H (enthalpy) = E (energy) + pV.

Takes into account changes in pressure and volume.

In biochemical reactions, p and V are ~ 0, so you can use either F or G.

F = E – TSG = H – TS

(F ~ G)Can use either.

Bottom line: Whenever you usually use E, use G,

and entropy is taken care of!

Page 12: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

Equilibrium How stable is one state over

another?

A B

Probability of being in B = Z-1exp(-GB/kT)

Probability of being in A = Z-1(exp-GA/kT)

Keq = B/A = exp (-GB/kT+ GA/kT)

= exp –([GA- GA]/kT)= exp –(∆G/kT)

What about A B + CKeq = [B][C]/[A]. But how to figure out in terms of ∆G?

Keq = exp –(∆G/kT)

∆G = -kTlnKeq

Page 13: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

This tells about equilibrium.

Tells nothing about why two are stable

Page 14: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

Stability and thermal activationBoth systems are stable because they

have activation energy to convert!All chemical reactions involve changes in energy. Some reactions release energy (exothermic) and others absorb it (endothermic).

Enzymes (Catalyst)

If Activation Energy < kT, then rxn goes forward. If not, need to couple it to external energy source (ATP).

Keq= [B]/[A][Says nothing about ∆G+

rev/forward]∆G+forward

∆G+rev

∆G

∆G+forward

∆G+rev

∆G

Keq = exp(-∆G/kT)

Keq = f(∆G)?

∆G = -kT ln (Keq)

Page 15: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

ATP, Energy, Entropy

You must add up not only the energy (two vs. three negative charges forced together), but the free energy arising from loss or gain in Entropy.

Take energy from a couple of photons, and convert ADP + Pi into ATP

ATP ADP + Pi

Page 16: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

Energetics of ATP

1 ATP= 80-100 pN-nm of energy at 37 ºC

= 20-25 kT of energy

(much more than kT = 4 pN-nm)

A lot of energy

Why do I say 80 to 100 pN-nm? Why not an exact amount?

Let’s say that you let reaction in a (small) box.Start out with no ADP and no Pi. Then there are a ton of places for each to go and so you have tons of places to go where negative charges are far from each other.

Now if there is a lot of ADP and Pi around, not much energy from splitting ATP.

ATP sometimes gives 20 kT, sometimes 25 kT

You will have to calculate this. (Easiest to do in moles/liter,

rather than by single molecules.)

Page 17: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

How can use 90 lbs?

Net weight = WATP-WADP

Page 18: Homework Written HW #1 due Thursday Reading #2, Scientific American by Mattick, assigned today, due next Tuesday (a few question quiz next Tuesday) (Talks

Class evaluation

1. What was the most interesting thing you learned in class today?

2. What are you confused about?

3. Related to today’s subject, what would you like to know more about?

4. Any helpful comments.

Answer, and turn in at the end of class.