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Houston, We Have a Problem! By Leena Bakshi and my group members

Houston, We Have a Problem! By Leena Bakshi and my group members

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Page 1: Houston, We Have a Problem! By Leena Bakshi and my group members

Houston, We Have a Problem!

Houston, We Have a Problem!

By Leena Bakshi and my group members

By Leena Bakshi and my group members

Page 2: Houston, We Have a Problem! By Leena Bakshi and my group members

Task 1: Varying Variables!Task 1: Varying Variables!

Initial Velocity: v, the initial velocity of each rocket. These values are given. Rocket #1: has an initial velocity of 250 m/s, but must be launched at ground zero. Rocket #2 has an initial velocity of 90 m/s, but can be launched at an initial height on 300 meters.

Acceleration: a, -9.8 m/s2: the force of gravity acting on the rocket.

Time: t, the time it takes to reach the final height. Initial Height: h0, These values are given. Rocket #1 = 0, Rocket

#2 = 300 meters Final Height: h, the final height of each rocket. This value is

given, since the two rockets need to reach a final height of 63,198 meters.

Initial Velocity: v, the initial velocity of each rocket. These values are given. Rocket #1: has an initial velocity of 250 m/s, but must be launched at ground zero. Rocket #2 has an initial velocity of 90 m/s, but can be launched at an initial height on 300 meters.

Acceleration: a, -9.8 m/s2: the force of gravity acting on the rocket.

Time: t, the time it takes to reach the final height. Initial Height: h0, These values are given. Rocket #1 = 0, Rocket

#2 = 300 meters Final Height: h, the final height of each rocket. This value is

given, since the two rockets need to reach a final height of 63,198 meters.

Page 3: Houston, We Have a Problem! By Leena Bakshi and my group members

Task 2: Algebraic Evidence Task 2: Algebraic Evidence

Rocket #1:

0.5at2 + vt + h0 0.5(-9.8)( t2) + (250)(t) + (0) = 63,198 meters(simplified): 63,198 = 250t-4.9 t2

This is false: The maximum for this equation is 25.51

seconds and can only reach a maximum height of

3188.78 meters.

Rocket #1:

0.5at2 + vt + h0 0.5(-9.8)( t2) + (250)(t) + (0) = 63,198 meters(simplified): 63,198 = 250t-4.9 t2

This is false: The maximum for this equation is 25.51

seconds and can only reach a maximum height of

3188.78 meters.

Page 4: Houston, We Have a Problem! By Leena Bakshi and my group members

Rocket #2:

0.5at2 + vt + h0 0.5(-9.8)( t2) + (90)(t) + (300) = 63,198

metersThis rocket only reaches a maximum of

713.265 meters. Again, this will reach a false result and will not reach the moon.

Rocket #2:

0.5at2 + vt + h0 0.5(-9.8)( t2) + (90)(t) + (300) = 63,198

metersThis rocket only reaches a maximum of

713.265 meters. Again, this will reach a false result and will not reach the moon.

Task 2: Algebraic Evidence Task 2: Algebraic Evidence

Page 5: Houston, We Have a Problem! By Leena Bakshi and my group members

Task 3: After 5 seconds…Task 3: After 5 seconds…

Rocket #1:0.5at2 + vt + h0

0.5(-9.8)( 52) + (250)(5) + (0) = final height

1127.5 meters

Rocket #1:0.5at2 + vt + h0

0.5(-9.8)( 52) + (250)(5) + (0) = final height

1127.5 meters

Page 6: Houston, We Have a Problem! By Leena Bakshi and my group members

Rocket #2:0.5at2 + vt + h0

0.5(-9.8)( 52) + (90)(5) + (300) = final height

627.5 meters

Rocket #2:0.5at2 + vt + h0

0.5(-9.8)( 52) + (90)(5) + (300) = final height

627.5 meters

Task 3: After 5 seconds…Task 3: After 5 seconds…

Page 7: Houston, We Have a Problem! By Leena Bakshi and my group members

ConclusionsConclusions

These amateur rockets will not make it to the moon.

If the initial velocity on rocket one is modified, it can be a viable rocket.

Initial velocity affects the final height more than the initial height.

These amateur rockets will not make it to the moon.

If the initial velocity on rocket one is modified, it can be a viable rocket.

Initial velocity affects the final height more than the initial height.

Page 8: Houston, We Have a Problem! By Leena Bakshi and my group members

Video: Rocket Launch to MarsVideo: Rocket Launch to Mars

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