Introduction to the Practice Test - Mrs. Warner's Learning …mrswarnerarlington.weebly.com/uploads/6/9/0/0/6900648/in... · 2019. 11. 18. · Here are some hints to help you when

Practice Test 37

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Introduction to the Practice Test The Practice Test for the ISTEP+ gives students an opportunity to apply the mathematics and test-taking skills covered in this book. It gives students an opportunity to practice answering multiple-choice questions as well as constructed response questions.

Every Grade 4 mathematics standard in Indiana’s Academic Standards—Mathematics is tested in this Practice Test and is identified in your teacher notes. When scoring the Practice Test, refer to the standard and indicator given in the teacher notes. The Sample and Practice Problems section contains ideas for review, practice, and reteaching for Indiana’s Academic Standards—Mathematics for Grade 4.

The Practice Test contains 42 items—which is as long as the Grade 4 ISTEP+.

Preparation

1. Allow enough time A good estimate for the time most students will need is 80 minutes for the test. Students who are engaged and working should be granted extra time to finish if at all possible.

2. A “Testing—Do Not Disturb” sign on the door will help eliminate unnecessary interruptions.

3. Clear desks, comfortably spaced apart, are important in any testing situation.

4. Two sharpened pencils equipped with erasers should be provided for each student.

5. Distribute the tests.

AdministrationHave students open their books to page 27. Discuss the bulleted items.

Say: Make sure that you clearly circle each choice or fill in the blanks. Work until you come to the word STOP at the bottom of page 48. Do you have any questions?

Start the test now. You will have about 80 minutes to answer all the questions.

Student Book, p. 27

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Grad

e 4

Prac

tice

Test

Grade 4Practice Test

Here are some hints to help you when you take the ISTEP+. Use these hints as you try to answer the questions on the Practice Test.

Take your time and read each problem carefully. Think about how you might solve the problem before you try to choose an answer.

If you are not sure how to answer a question, skip it. Answer the questions that are easier for you first. Then go back and work on the harder questions you skipped.

Circle each letter choice clearly.

Watch for questions that do not have letters. Make sure you read carefully to see what response is required.

Don’t worry if there are some questions that are too hard for you. Take your time and think about them carefully.

After you have answered a question, go back and reread the problem. Make sure the answer you chose makes sense.

Almost everyone gets a little nervous when taking a test. Do not worry. The most important thing is to do your best.

This test contains 42 questions. It should take you about 80 minutes to answer all the questions.

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EM3_G4_TP_SE_27-48_IN.indd 27 6/5/09 1:05:04 PM

EM3_G4_TP_TE_37-58_IN.indd 37EM3_G4_TP_TE_37-58_IN.indd 37 6/17/09 1:05:28 PM6/17/09 1:05:28 PM

38 Solutions

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Practice Test SolutionsIndicator 4.2.4

1 The correct answer is (a) 4 × (16 + 14) = n; (b) 4 × (16 + 14) = (4 × 16) + (4 × 14) = 64 + 56 = $120.

n represents the total earned: n = $120.

Scoring RubricScoring Rubric

2

The student writes an equation to show the amount earned in 2 days, 4 × (16 + 14) = n, AND solves the equation using the Distributive Property.

1The student writes an equation to show the amount earned in 2 days OR solves the equation using the Distributive Property, but not both.

0

The student does not write an equation to show the total amount earned AND does not correctly solve the equation to get the answer OR the student does not attempt the problem.

Indicator 4.1.6

2 The correct answer is D.

To solve this problem, students need to identify the operation to be performed. Because there are 7 classes of fourth graders, with 84 pictures collected by each class, the correct operation is multiplication: 7 × 84 = 588.

Common Errors

A. Divides 84 ÷ 7

B. Adds 84 + 7

C. Multiplies 7 × 84 but does not “carry” the 2

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Student Book, p. 28

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1. A bookstore is selling posters for $4 each. Sixteen posters were sold on Monday, and 14 were sold on Tuesday.

a. Using an equation, represent the amount of money the bookstore took in from the sale of the posters for these 2 days.

b. Solve the equation using the Distributive Property.

2. Each of 7 classes of fourth graders collected 84 pictures for their end-of-the-year collage. How many pictures will they have altogether?

A. 12

B. 91

C. 568

D. 588



Practice Test 39

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3 The correct answer is (a) 8; and (b) red striped, red plain, green striped, green plain, blue striped, blue plain, yellow striped, yellow plain.

To solve this problem, students should list the 8 outcomes. Then students should look for duplicates when the list is complete. To earn full credit, students must give the correct number of outcomes and a list or picture of the outcomes.


2The student states the number of outcomes AND gives an organized list or picture of all the possible outcomes.

1The student states the number of outcomes OR gives an organized list or picture of all the possible outcomes.

0

The student does not state the number of outcomes or does not give an organized list or picture of all the possible outcomes OR the student does not attempt the problem.

Indicator PS-23

4 The correct answer is A.

To solve this problem, students should compare the lengths of the photos’ sides with those of the frame to make sure the picture is not too long or too wide. They could also find the area of the frame (15 in2) and compare it to the area of the photos.

Common Errors

B. 3 in. by 6 in. is equal to 18 in2, which is greater than the area of the frame.

C. 4 in. by 6 in. is equal to 24 in2, which is greater than the area of the frame.

D. 6 in. by 2 in. is equal to 12 in2, which is less than the area of the frame, but 6 in. is greater than the length of the frame.

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Student Book, p. 29

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PracticeTest

4. Daryl has a picture frame that is 3 in. by 5 in.

5 in.

3 in.

Which of the following size photos will fit inside the frame?

A. 3 in. by 4 in.

B. 3 in. by 6 in.

C. 4 in. by 6 in.

D. 6 in. by 2 in.

3. School notebooks are made in 4 colors: red, green, blue, and yellow. Each color comes in 2 styles: striped and plain.

a. How many different varieties of notebooks are available?

b. Draw a picture or an organized list to represent all the possible outcomes.



40 Solutions

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Practice Test SolutionsIndicator PS-8


Quadrilaterals are polygons with 4 sides. Squares have 4 sides. All squares are rectangles because they have 4 sides with 4 right angles, which rectangles must have.

Common Errors

B. Only those rectangles that have all 4 sides equal are squares

C. Squares have 2 pairs of parallel sides

D. Squares are convex

Indicator PS-12

6 The correct answer 1 8

2 9

3 5 7

4 0 4

5 6

6 1

7 3

8 2

is (a)

and (b) the difference between the greatest and least dog weights is 82 - 18 = 64.

The weights of the dogs in the stem-and-leaf plot would be shown with the tens digit on the left side of the vertical line and the ones digits on the right side of the vertical line.

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2The student correctly creates a stem-and-leaf plot for the data AND calculates the difference between the greatest and least dog weights (82 - 18 = 64).

1The student correctly creates a stem-and-leaf plot for the data OR calculates the difference between the greatest and least dog weights, but not both.

0The student does not create a stem-and-leaf plot for the data AND does not calculate the difference between the greatest and least dog weights OR the student does not attempt the problem.


2The student correctly creates a stem-and-leaf plot for the data AND calculates the difference between the greatest and least dog weights (82 - 18 = 64).

1The student correctly creates a stem-and-leaf plot for the data OR calculates the difference between the greatest and least dog weights, but not both.

0The student does not create a stem-and-leaf plot for the data AND does not calculate the difference between the greatest and least dog weights OR the student does not attempt the problem.

Student Book, p. 30

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6. The data represent the weights of various dogs.

37, 82, 56, 44, 18, 29, 35, 61, 73, 40

a. Create a stem-and-leaf plot for the data.

b. What is the difference between the greatest and least dog weights?

5. Squares are quadrilaterals. What is true about all squares?

A. All squares are rectangles.

B. All rectangles are squares.

C. All squares have exactly 1 pair of parallel sides.

D. All squares are nonconvex.



Practice Test 41

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7 The correct answer is C.

Students would solve the equation by adding 12 to both sides. Because the low temperature is 12° and the high temperature is 18 degrees warmer than that, addition is the correct operation for the answer of 30°.

Common Errors

A. “Carries” too many tens

B. Adds 18 + 12 incorrectly

D. Subtracts 18 – 12 = 6

Indicator PS-2

8 The correct answer is B.

To solve this problem, students calculate the distance around the polygon by adding all the sides, 5 + 7 + 4 + 3 + 2 + 3 = 24 ft. Students need to identify that the figure has 6 sides, and the measurements for each side are not all equal in length.

Common Errors

A. 5 + 4 + 3 + 2 + 3: does not add the side from the bottom of the figure

C. 5 + 4 + 2 + 3 + 3 + 4 + 2 + 3: adds the bottom side as 9 instead of 7 ft

D. 7 × 5: counts 7 sides with 5 ft on each

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Student Book, p. 31

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PracticeTest

8. Nadine’s room is planned as shown.

7 ft

4 ft

3 ft

3 ft

2 ft

5 ft

What is the perimeter of her room?

A. 17 ft

B. 24 ft

C. 28 ft

D. 35 ft

7. During January, the average low temperature in Rensselaer, Indiana, is 12°F. The average high temperature is 18° warmer than that. In the equation, h represents the average high temperature.

h - 12 = 18

What is the average high temperature?

A. 40°F

B. 36°F

C. 30°F

D. 6°F



42 Solutions

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To solve this problem, students need to know that parallel lines do not intersect. There are several sets of parallel lines in the diagram, but only one set is identified by the pairing of the problem statement and an answer choice. Smithfield Drive and Ditch Road are parallel streets. Greenfield Drive, Valdosta Place, and Pawtucket Drive intersect with Smithfield Drive.

Common Errors

A. Greenville Drive intersects with Smithfield Drive

B. Valdosta Place intersects with Smithfield Drive

D. Pawtucket Drive intersects with Smithfield Drive

Indicator PS-24

10 The correct answer is (a) 600 pencils; either multiply 6 by 100 or use 100 as an addend six times; and (b) Sample answer: Because 1,000 is 10 times as great as 100, she will order 10 × 600, or 6,000 pencils.

A mental strategy for multiplying by 10, 100, or 1,000, is to first ignore the final 0s and multiply without them. Then annex the same number of 0s to the product. So for 6 × 1,000, you would think 6 × 1 = 6 and then annex the 0s to obtain 6,000.

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Student Book, p. 32

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PracticeTest

10. Mrs. Ling orders 100 pencils each month for 6 months.

a. Find the number of pencils she orders in all for 6 months. Explain your strategy.

b. Suppose Ms. Ling orders 1,000 pencils per month for 6 months. Find the number of pencils she orders in 6 months. Explain your strategy.

9. Some streets in Carmel, Indiana, are shown.

Pawtucket Drive

Middlebury Drive

Sm

ithfie

ld D

rive

Bow

ie D

rive

Ditc

h R

oad

Po

rtlan

d D

rive

Lo

ckp

ort D

rive

Greenville Drive

W 156th Street

Ashville Drive

Lewiston Drive

Liberty Drive

Valdosta Place

Which street is parallel to Smithfield Drive?

A. Greenville Drive

B. Valdosta Place

C. Ditch Road

D. Pawtucket Drive



2The student describes a mental strategy for solving each problem. The student also states answers for 100 pencils and 1,000 pencils over 6 months.

1The student gives an adequate explanation for solving the problem using a mental strategy OR states correct answers for 100 pencils and 1,000 pencils over 6 months, but not both.

0The student does not give an adequate explanation for either part of the problem OR the student does not attempt the problem.


Practice Test 43

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To solve this problem, students look at the number line and identify that each mark represents one tenth. W represents 1.1, X represents 1.2, and Y represents 1.3.

Common Errors

A. Gives the interval between labeled marks on the number line.

B. Skips the tick mark after the one for 0.9

D. Counts too far on the number line

Indicator 4.1.8

12 The correct answer is (a)

10 11 12 13 14 15 16 17 18

x

x

x

x

x

x

x

x x x

and (b) The second tallest is 17 in.

To solve this problem, examine the numbers along the line plot that have at least one X placed above them. The second value from the right that has an X is the second tallest plant.

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2 The student correctly displays the data in a line plot AND identifies the second tallest plant.

1 The student correctly displays the data in a line plot OR identifies the second tallest plant, but not both.

0 The student does not display the data using a line plot OR does not attempt the problem.


2 The student correctly displays the data in a line plot AND identifies the second tallest plant.

1 The student correctly displays the data in a line plot OR identifies the second tallest plant, but not both.

0 The student does not display the data using a line plot OR does not attempt the problem.

Student Book, p. 33

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PracticeTest

12. The following measurements are heights in inches of flowers planted in pots at school.

18, 15, 10, 12, 15, 13, 12, 17, 13, 12

a. Display the heights of the flowers using a line plot.

b. Explain which height is the second tallest.

11. A number line is shown.

0.5 0.7 0.9 W X Y 1.4

What decimal is represented by W?

A. 0.2

B. 1.0

C. 1.1

D. 1.2



44 Solutions

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To solve this problem, students would use the basic facts to solve 6 × 8 = 48. Then students use basic facts and discover that 4 × 12 = 48. Students need to recognize that 6 and 8 are being multiplied.

Common Errors

B. Thinks that 6 × 8 = 24

C. Thinks that 6 × 8 = 8 + 6

D. Thinks of a related division fact

Indicator 4.3.2


To solve this problem, students look at the figure and determine the number of angles that are acute, obtuse, right, and straight. There are 10 acute angles, which is the most of any type in this picture. Students could start by looking at the angles at the corners of the rectangle and then identify more in the center of the figure.

Common Errors

B. There are 2 obtuse angles

C. There are 4 right angles

D. There are 2 straight angles

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Student Book, p. 34

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PracticeTest

14. Leonardo has created a design for a window pane.

What type of angle is represented most often?

A. acute

B. obtuse

C. right

D. straight

13. Leticia wrote 6 × 8 = on her paper. Which expression can her friend write on the line to make a true number sentence?

A. 4 × 12

B. 4 × 6

C. 6 + 8

D. 48 ÷ 8



Practice Test 45

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To solve this problem, students need to identify that 1 acre produces 167 bushels of corn. So, if a farmer has 5 acres of corn fields, students can multiply 167 and 5 or use repeated addition.

Common Errors

A. Adds 167 + 5

B. Does not "carry" the 3 tens to the tens place when multiplying

D. Multiplies 167 × 6

Indicator PS-5


To solve this problem, students need to know that a rhombus has 4 equal sides, while a kite has 2 pairs of equal sides. A kite has acute and obtuse angles. A rhombus may have both acute and obtuse angles, or it may have all right angles (when it is a square). The only correct statement is C.

Common Errors

A. Not all sides are equal on a kite.

B. A kite does not have 4 congruent angles.

D. A rhombus may or may not have all right angles.

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Student Book, p. 35

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16. Trish drew a kite and a rhombus.

Explain how Trish knows the difference between a kite and a rhombus.

A. A kite and a rhombus each have all sides equal.

B. A kite and a rhombus each have 4 congruent angles.

C. A kite has 2 pairs of equal sides, and a rhombus has all 4 sides equal.

D. A kite has acute and obtuse angles, and a rhombus has all right angles.

15. In 2006, Indiana farmers produced 167 bushels of corn per acre. If a farmer has 5 acres of corn fields, how many bushels of corn did that farmer produce?

A. 172

B. 505

C. 835

D. 1002



46 Solutions

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To solve this problem, students first need to determine how many team members attended the picnic. The bar graph shows that 20 people attended the picnic because each team member was to bring a food item and 3 brought fruit, 4 brought drinks, 6 brought salad, 2 brought hot dogs, and 5 brought pizza (3 + 4 + 6 + 2 + 5 = 20). With 20 team members at the picnic, then 3 __

20 brought fruit and

6 __ 20

brought salad, for a total of 9 __ 20

.

Common Errors

A., C. Miscounts how many attended and does not add to find the total of fruit and salad

D. Reads the graph incorrectly so that the total of fruit and salad is incorrect

Indicator 4.2.3

18 The correct answer is (a) check that students have drawn 2 rows of 8; (b) check that students have drawn 8 rows of 2; and (c) 8 rows of 2 is equal to 2 × 8 because both have a total of 16 crayons even though the arrangements are different.

To solve this problem, students should show a total of 16 in the first array and a total of 16 in the second array. Each array of crayons is equal to 16, but the arrangement is different. To earn full credit, students need to show a correct representation of 2 × 8 and 8 × 2.

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2The student represents 2 × 8 and 8 × 2 in arrays AND gives an explanation that the two arrays are equal to 16.

1The student represents the arrays correctly OR gives an explanation that the two arrays are equal to 16, but not both.

0The student does not represent either array and does not state an accurate explanation OR the student does not attempt the problem.


2The student represents 2 × 8 and 8 × 2 in arrays AND gives an explanation that the two arrays are equal to 16.

1The student represents the arrays correctly OR gives an explanation that the two arrays are equal to 16, but not both.

0The student does not represent either array and does not state an accurate explanation OR the student does not attempt the problem.

Student Book, p. 36

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PracticeTest

18. Wayne has 2 sets of crayons with 8 different colors in each set.

a. Draw an array that represents 2 × 8.

b. Draw an array that represents 8 × 2.

c. Explain how an array that represents 8 × 2 is the same as one that represents 2 × 8.

17. The softball team at Colgate Elementary celebrated their championship season with a picnic. Each team member was asked to bring a food item to the picnic. The following food items were brought:

Food

2

0

4

6

8

Num

ber

of

Team

Mem

bers

Fruit

Drin

ks

Salad

Hot

Dog

s

Pizza

Colgate Elementary Picnic

What fraction of the team members brought fruit and salad?

A. 3 __ 10

B. 9 __ 20

C. 6 __ 10

D. 8 __ 20



Practice Test 47

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To solve this problem, students need to identify that a reflection is when the figure is shown on its opposite side. B shows a flip, which is a mirror reflection of the letter. The other answer choices show rotation or translation.

Common Errors

A. Shows a rotation of 90°

C. Shows a rotation of 180°

D. Shows a translation

Indicator PS-10


To solve this problem, students use the order of operations to evaluate an expression. The expression does not have any exponents, so students should begin by finding the value of the expression in parentheses: 6 - 2 = 4. From there, they should multiply to find 4 × 4 = 16. The final step is to add: 8 + 16 = 24.

Common Errors

B. Disregards the parentheses

C. Adds and subtracts first, then multiplies

D. Performs the operations in sequence without regard to the order of operations

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Student Book, p. 37

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20. Mariko challenged a classmate to find the value of this expression.

8 + 4 × (6 - 2)

What is the correct value for this expression?

A. 24

B. 30

C. 48

D. 70

19. Look at the figure.

Which shows a reflection of the letter?

A.

B.

C.

D.



48 Solutions

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21 The correct answer is (a) Indiana house: 1,184 ft2; Wisconsin house: 1,248 ft2; (b) Sample answer: I separated each diagram into two rectangles, found the area of each rectangle, and then added the two areas to find the total area; (c) Wisconsin house.

To solve this problem, students need to know the formula for the area of a rectangle, which is A = b × h.

Indiana house: (40 × 20) + (24 × 16) = 1,184 ft2; or (24 × 36) + (16 × 20) = 1,184 ft2; or (40 × 36) - (16 × 16) = 1,184 ft2

Wisconsin house: (40 × 24) + (18 × 16) = 1,248 ft2; or (42 × 16) + (24 × 24) = 1,248 ft2; or (40 × 42) - (18 × 24) = 1,248 ft2


2The student correctly finds the area, explains how the area was found, and identifies the greater area.

1The student incorrectly calculates the area but explains the proper process.

0The student’s response shows no understanding of area OR the student does not attempt the problem.

Indicator 4.1.4


To solve this problem, students need to know the place values of each digit. Students can begin by writing each part of the number as a numeral with a word following it to describe the place value. Each phrase would be separated by a plus sign. So 7.15 would be 7 ones + 1 tenth + 5 hundredths.

Common Errors

A. Ignores the decimal point and treats 7.15 as if it were 715

B. Thinks 1 tenth and 5 tenths is 15 hundredths

D. Thinks 1 hundredth and 5 tenths is 15 hundredths

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Student Book, p. 38

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PracticeTest

22. The Indianapolis marathon has a relay event. The fourth leg of the relay is 7.15 mi. What is the expanded form for that distance?

A. 7 + 10 + 5

B. 7 + 0.1 + 0.5

C. 7 + 0.1 + 0.05

D. 7 + 0.01 + 0.5

21. The floor plans for the first floors of two houses are shown below.

Indiana House

16 ft

WisconsinHouse

40 ft

40 ft

20 ft

36 ft

42 ft

24 ft

24 ft

24 ft

16 ft

16 ft

18 ft

a. Find the area of each first floor.

b. Explain how you found each area.

c. Which first floor has the greater area?



Practice Test 49

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To solve this problem, students need to identify the digit to the right of the hundreds place value and round up to the next ten because 7 ones is larger than 5 ones.

Common Errors

A. Incorrectly rounds to the nearest hundred

C. Incorrectly rounds down instead of up to the nearest ten

D. Rounds to the nearest hundred

Indicator PS-25


To solve this problem, students need to know that they are estimating the amount of precipitation per month. Students could divide the total by 12, which is equal to more than 3 in. and less than 4 in. because 3 × 12 = 36 and 4 × 12 = 48. So, 4 in. is the closest answer choice given. Another strategy is to round 41 to 40 and 12 to 10. Because 40 ÷ 10 = 4, a good estimate is 4 in.

Common Errors

B. Gives the number of months in a year

C. Divides the total in half

D. Thinks annual and monthly are the same

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Student Book, p. 39

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PracticeTest

24. The annual average precipitation in Indiana is about 41 in. About how much precipitation does Indiana receive per month?

A. 4 in.

B. 12 in.

C. 20.5 in.

D. 41 in.

23. The attendance at an amusement park was 5,617 people. What is that attendance rounded to the nearest ten?

A. 5,700

B. 5,620

C. 5,610

D. 5,600



50 Solutions

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To solve this problem, students need to first identify the place value of the given digit. Then students will need to identify that there are 7 ten-thousands, which is 70,000. Some students might need to sketch a place-value chart and fill in the appropriate values. Other students will be able to identify the ten-thousands place. Looking at the written number from left to right, the leftmost digit 7 in 6,376,792 represents the ten-thousands place.

Common Errors

A. Identifies 7 tens and misses the values of the final 3 digits

B. Identifies 7 thousands

D. Identifies hundred-thousands instead of ten-thousands

Indicator 4.3.4


To solve this problem, students need to know how to measure to the nearest 1 _ 8 of an inch using a ruler. When the ruler is lined up on the end of the key, its length is measured as 2 1 _ 8 in.

Common Errors

A. Does not line up the ruler correctly

C. Does not look at the correct mark on the ruler

D. Does not line up the ruler and measure correctly

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Student Book, p. 40

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PracticeTest

26. Measure the length of the key to the nearest 1 __

8 of an inch.

A. 2 in.

B. 2 1 __ 8 in.

C. 2 1 __ 4 in.

D. 2 1 __ 2 in.

25. The population of the state of Indiana was 6,376,792 in 2008. What is the value of the leftmost digit 7?

A. 70

B. 7,000

C. 70,000

D. 700,000



Practice Test 51

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To solve this problem, students need to know that the total number of water bottles divided by 6 will result in the number of players in the camp. Students can also multiply numbers by 6 until the total is reached.

Common Errors

A. Does not divide correctly

C. Subtracts 6 rather than divides by 6

D. Multiplies by 6 rather than divides by 6

Indicator PS-13


To solve this problem, students need to know their basic facts and how fact families are related to them. Because 6 × 8 and 8 × 6 both equal 48, then 48 ÷ 8 is related to it. A is addition with related numbers, but this fact family is multiplication and division.

Common Errors

A. Thinks that fact families only apply to the digits, not to the operations

B. Thinks 7 × 8 = 56 is related to this fact family

C. Thinks that 6 × 8 = 42

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Student Book, p. 41

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PracticeTest

28. 6 × 8 = 8 × 6. Which of the following is related to this fact family?

A. 6 + 8

B. 7 × 8

C. 42 ÷ 6

D. 48 ÷ 8

27. The players in the Soccer Camp drank 444 bottles of water. If each player received 6 bottles of water, how many players were in the camp?

A. 70

B. 74

C. 338

D. 2,664



52 Solutions

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To solve this problem, students may use rounding to get the most reasonable answer and then add. Round 13.75 to 14 and 21.45 to 21 and then add 14 + 21 = 35. The other answer choices are not reasonable because they are either too low or too high.

Common Errors

A. Rounds the numbers to 21 and 14 and then subtracts

B. Rounds $21.45 to 21 and stops

D. Rounds both numbers to 20 and then adds to get 40

Indicator PS-15


To solve this problem, students need to measure to the nearest centimeter using a ruler. Students need to use the correct mark on the ruler and measure the length of the eraser, which is 3 cm. The other answer choices are not measured correctly.

Common Errors

A. Measures incorrectly

C. Measures 1 cm too many

D. Does not line up the ruler correctly

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Student Book, p. 42

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30. Measure the length of the eraser to the nearest centimeter.

A. 2 cm

B. 3 cm

C. 4 cm

D. 5 cm

29. Aaron earned $13.75 for delivering newspapers and $21.45 for mowing lawns in his neighborhood. Which amount is the most reasonable for the total Aaron earned?

A. $7

B. $21

C. $35

D. $40



Practice Test 53

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31 The correct answer is (a) 1 _ 2 + 2 _ 6 + 1 _ 6 = 1; and (b) Sample answer: Each part of the hexagon is represented by a fraction, and the sum of the parts of a whole is equal to 1.


2The student writes the number sentence 1

_ 2 +

2

_ 6 +

1

_ 6 = 1 AND explains how the sum is equal

to 1.

1The student writes a number sentence to show the sum of 1 OR explains how the sum is equal to 1, but not both.

0

The student does not write a number sentence to show the sum of 1 AND does not explain how the sum is equal to 1 OR the student does not attempt the problem.

Indicator 4.2.2


To solve this problem, students need to know how many tickets are sold in 1 hr, which is 1,000. Over 4 hr, there would be 4,000 tickets sold. So, 6,000 - 4,000 = 2,000.

Common Errors

A., C. Calculates incorrectly

D. Assumes there would be no tickets left after 4 hr

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Student Book, p. 43

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PracticeTest

32. West Elementary had a Family Fun Day. They started with 6,000 tickets. Each hour the number of tickets decreased by 1,000. How many tickets were left after 4 hr?

A. 3,000

B. 2,000

C. 1,000

D. 0

31. The hexagon represents one whole.

a. Write a number sentence with fractions to show that the sum of all the parts is equal to 1.

b. Explain how you know that the sum is equal to 1.



54 Solutions

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To solve this problem, students need to know that a trapezoid is one half of a hexagon. So, 6 small triangles will represents sixths, and one triangle is 1 _ 6 of the hexagon. The other answer choices are different fractional parts that are greater than 1 _ 6 .

Common Errors

A. Chooses the picture that looks like the trapezoid

B. Chooses the picture of the whole hexagon

C. Mistakes 1 _ 3 for 1 _ 6

Indicator PS-9

34 The correct answer is (a) 66,000; and

(b)

66,000

66,378

68,000 70,000

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Student Book, p. 44

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PracticeTest

34. The average attendance at an Indianapolis Colts game in 2008 was 66,378.

a. Round the attendance to the nearest thousand.

b. Draw a number line to show the exact number between the rounded number and 70,000.

33. The trapezoid below covers one-half of a hexagon.

Which of the following covers 1 __ 6 of

the same hexagon?

A.

B.

C.

D.



2The student correctly rounds the attendance to the nearest thousand (66,000) AND draws a number line to show the exact number between the rounded number and 70,000.

1The student correctly rounds the attendance to the nearest thousand OR draws a number line to show the exact number between the rounded number and 70,000, but not both.

0The student does not correctly round the attendance to the nearest thousand AND does not draw a number line to show the exact number between the rounded number and 70,000 OR the student does not attempt the problem.


Practice Test 55

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Students solve this problem by converting fractions to decimals. Another method would be to draw circles for each fraction, divide them according to the denominator, and then compare the pictures. A third method to order the fractions is to find a common denominator for them and then compare.

Common Errors

A. Orders by the numerators and ignores the denominators

C. Orders the first two fractions correctly but lists 3 _ 4 as the greatest

D. Orders the fractions from greatest to least

Indicator PS-19


To solve this problem, students first need to find the number of minutes Josie read the first week. Students may mentally compute 7 × 25 = 175, and then subtract 100, which was rounded from 95 min the next week: 175 - 100 = 75.

Common Errors

B. Rounds 95 min to 100 min and does nothing more

C. Multiplies 7 × 25 and does nothing more

D. Adds instead of subtracts the numbers after rounding

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Student Book, p. 45

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PracticeTest

36. Josie spent about 24 min reading each day for 7 days. The next week she read 95 min over the entire week. About how much more did she read for one week than the next week?

A. 75 min

B. 100 min

C. 175 min

D. 275 min

35. Remy rode his bicycle 3 __ 4 mi on

Sunday, 2 __ 5 mi on Monday, 1 __

2 mi on

Tuesday, and 4 __ 5 mi on Wednesday.

Order the distances Remy rode from least to greatest.

A. 1 __ 2 , 2 __

5 , 3 __

4 , 4 __

5

B. 2 __ 5 , 1 __

2 , 3 __

4 , 4 __

5

C. 2 __ 5 , 1 __

2 , 4 __

5 , 3 __

4

D. 4 __ 5 , 3 __

4 , 1 __

2 , 2 __

5



56 Solutions

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37 The correct answer is 6 hr per day for 5 days is 6 × 5 = 30, then 30 hr per week times 9 weeks is 270 hr: 6 × 5 × 9 = 270 hr.


2The student correctly calculates the number of hours of school in 9 weeks (6 × 5 × 9 = 270 hr) AND explains how the problem was solved.

1The student correctly solves the problem OR explains how the problem was solved, but not both.

0The student does not correctly solve the problem AND does not explain how the problem was solved OR the student does not attempt the problem.

Indicator 4.3.5


To solve this problem, students need to find the area of the rectangle, which is the length of the base times its width. The rectangle is 12 ft by 6 ft, so the area is 6 × 12, or 72 ft2.

Common Errors

A. Adds the dimensions

B. Calculates the perimeter

C. Gives the answer in feet rather than in square feet

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Student Book, p. 46

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PracticeTest

37. Kelly attends 6 hr of school 5 days a week. How many hours of school does Kelly attend in 9 weeks? Solve the problem and explain how you solve it.

38. Mr. Kendall’s garden is shown.

12 ft

6 ft

What is the area of the garden?

A. 18 ft2

B. 36 ft2

C. 72 ft

D. 72 ft2



Practice Test 57

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To solve this problem, students need to know that 25 squares out of 100 are shaded, which represents 0.25. Therefore, 1.25 is represented with 1 whole shaded and 25 out of 100 squares shaded on a second grid. The other answer choices are more or less than 1.25.

Common Errors

B. Counts incorrectly; 1 whole and 35 out of 100 are shaded

C. Ignores 0.25; only 1 whole is shaded

D. Misunderstands question; only 12 1 __ 2 out of

100 are shaded

Indicator PS-7


To solve this problem, students need to know that a right angle measures 90° and an angle with a measure greater than that is an obtuse angle. An acute angle measures less than 90°. The rays are closer together in an acute angle than in an obtuse angle.

Common Errors

A. Confuses obtuse and acute angles

C. Confuses obtuse and right angles

D. Selects this angle because it opens in a different direction than the others

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Student Book, p. 47

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PracticeTest

39. 0.25 is represented as shown.

How is 1.25 represented?

A.

B.

C.

D.

40. Which angle is an obtuse angle?

A.

B.

C.

D.



58 Solutions

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41 The correct answer is Yes, the figures are congruent. Sample answer: if you slide Figure A 8 units to the right, then Figure A would set directly on top of Figure B, so Figure B is a translation of Figure A. Fitting directly on top of Figure B means the figures A and B are exactly the same size and shape.

To solve this problem, students need to know what it means for two figures to be congruent and the kind of transformation required to compare Figure A and Figure B.


2The student identifies Figures A and B as congruent and demonstrates an understanding of congruency and translations (slides).

1The student identifies Figures A and B as congruent but does not explain his or her reasoning.

0

The student does not identify Figures A and B as congruent and gives no reasoning for his or her answer OR the student does not attempt the problem.

Indicator PS-16

42 The correct answer is (a) 12 families; and (b) The number of families that have visited 4 or more states is 4 greater than the number of families that have visited fewer than 4 states.

Student Book, p. 48

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PracticeTest

42. The line plot represents the number of states outside of Indiana that each family living on one block has visited.

0 1 2 3 4 5 6 7 8

xx

x

x

x

x

x

x

x

x

x

x

x

x

x

x

x

x

x

x

Number of States VisitedOutside of Indiana

a. How many families have visited 4 or more states outside of Indiana?

b. Explain how the number of families that have visited 4 or more states compares to those visiting less than 4 states.

41. Look at Figure A and Figure B.

A B

Are the figures congruent? Use what you know about transformations to prove whether the figures are congruent.



2The student determines the number of families that have visited 4 states or more (12) AND explains how the number of families that have visited 4 or more states compares to those visiting less than 4 states (12 is greater than 8).

1The student determines the number of families that have visited 4 states or more (12) OR explains how the number of families that have visited 4 or more states compares to those visiting less than 4 states (12 is greater than 8), but not both.

0The student does not determine the number of families that have visited 4 states or more AND does not explain how the number of families that have visited 4 or more states compares to those visiting less than 4 states OR the student does not attempt the problem.


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Introduction to the Practice Test - Mrs. Warner's Learning …mrswarnerarlington.weebly.com/uploads/6/9/0/0/6900648/in... · 2019. 11. 18. · Here are some hints to help you when