Chuyn java

Lp trnh Java

BI TP TUN 3: Lung nhp xut v bit l

Bi tp c nhn Bi tp nhm

Bi tp t luyn Bi tp cn np

1. Qui nh v vic np bi:

1.1 Thi hn np bi: bui thc hnh tip theo

1.2 Cch np: np qua din n.

1.3 Bi lm c nn li thnh mt tp tin ( .zip hoc .rar )

1.4 Nu lm theo nhm th t tn: MSSV1-MSSV2-MSSV3-MSSV4.zip (hoc .rar). Lu MSSV theo th t tng dn.

1.5 Nu lm mt mnh th MSSV.zip ( hoc .rar )

2. Tham kho

3. Yu cu:

1. c t tp tin 2 mng s nguyn A(kch thc n) (a.txt) To mng s nguyn B (kch thc m) vi cc gi tr ngu nhin (Math.random) Xut ton b cc phn t ca B ra tp tin (b.txt) To mng C t mng A (hay copy A qua C) Thay th phn t th 13 ca mng C bng 3 phn t cui ca mng B Sp xp mng C tng dn v xut ra tp tin (c.txt)

p dng cho c 2 loi tp tin vn bn v nh phn2. Nhp vo s x t bn phm, kim tra x c nm trong mng C (tp tin c.txt) hay khng?

Tp tin vn bn: c vo b nh ri kim tra Tp tin nh phn: truy xut trc tip t tp tin

3. To mng 2 chiu nh sau v xut ra tp tin (loi tp tin vn bn)

UIT - HCM Trang 1

Chuyn java

11 11 2 11 3 3 11 4 6 4 11 5 10 10 5 11 6 15 20 15 6 1

4. c vo ma trn s nguyn t tp tin, kch thc mxn. Xut ra tp tin cc yu cu sau: Tm gi tr nh nht ca ma trn Tm gi tr ln nht ca ma trn Tm tt c cc s nguyn t ca ma trn Tnh tng tt c cc gi tr ca ma trn

p dng cho c 2 loi tp tin vn bn v nh phn5. Vit chng trnh cho php

c t file input.txt 2 dy phn s. Thc hin tnh tng v tch theo th t index ca tng phn s tng ng 2 dy

Sp xp dy phn s theo th t tng dn v ghi xung tp tin output.txt

nh dng tp tin

Tp tin input.txt:

Tp tin output.txt

6. Vit chng trnh copy tp tin

UIT - HCM Trang 2

1. Qui nh v vic np bi:1.1 Thi hn np bi: bui thc hnh tip theo1.2 Cch np: np qua din n.1.3 Bi lm c nn li thnh mt tp tin ( .zip hoc .rar )1.4 Nu lm theo nhm th t tn: MSSV1-MSSV2-MSSV3-MSSV4.zip (hoc .rar). Lu MSSV theo th t tng dn.1.5 Nu lm mt mnh th MSSV.zip ( hoc .rar )

2. Tham kho3. Yu cu:Tp tin input.txt:Tp tin output.txt