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7/29/2019 k1 jawapan
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Jadikan UjianJadikan soalan-soalan di kertas ini sebagai ujian bagi murid-murid
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Markah: 0% | Progres: 0/40 |Masa: 00:00:01/01:00:00 |
Ended
1 Round off 586 341 to the nearest hundred thousand. Give your answer in million.(ID:1224766548211 /KLON/UPSR/2008/1)
A 0.6 million
B 0.59 million
C 0.586 million
D 0.58 million
Jaw ab
Huraian:
To find answer
1. Determine the hundred thousands place value and mark
586 341
2. Round off to the nearest hundred thousand
+1
586 341
= 600 000
3. Convert to unit of million ( 1 000 000)
600 000 1 000 000
= 0.6 million
[Atas]
2 Diagram 1 shows a number card.
9.467
Diagram 1
What is the value of the digit 4 on that card?(ID:1225990311659 /KLON/UPSR/2008/2)
A
B
C
D
Jaw ab
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85862&_remote=#q1228419277170http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1225991283241http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1224798866937http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1225567716331http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1224798301297http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1226257575890http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1227994805355http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1226257430601http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1225990071553http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1223712791733http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1225990516235http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1230057958072http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1225990981879http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1234986402137http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1226960548076http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1227553802518http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1225991371627http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1226257289724http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1228419168912http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1225990157020http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1229006344702http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1228419957023http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q1230816975891http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#qtophttp://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#q12247665482117/29/2019 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Huraian:
1. The value of the digit 4 is
2. The correct answer is
[Atas]
3 Diagram 2 shows two cards of equal size. Each card is divided into severalequal parts.
Diagram 2
Calculate the total percentage of the coloured regions in both of the cards.(ID:1228419869881 /KLON/UPSR/2008/3)
A 20
B 30
C 50
D 80
Jaw ab
Huraian:
To find the percentage of the coloured regions
Add the percentage of the coloured regions of the two cards
30% + 50% = 80%
[Atas]
4 2 days =(ID:1224798562355 /KLON/UPSR/2008/4)
http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#qtophttp://ad%28%271228419869881%27%29/http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#qtophttp://ad%28%271224798562355%27%29/http://ad%28%271224798562355%27%29/http://ad%28%271228419869881%27%29/http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#qtophttp://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#qtop7/29/2019 k1 jawapan
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A 18 hours
B 30 hours
C 48 hours
D 66 hours
Jaw ab
Huraian:
Convert days to hours
1. 2 days = 2 days + day
2. 2 days = 2 x 24 hours
= 48 hours
3. day = x 24 hours
= 18 hours
4. 48 hours + 18 hours = 66 hours
[Atas]
5 Diagram 3 shows the mass of a bag of rice and a bag of flour.
Diagram 3
Which of the following shows the total mass of both bags?(ID:1228419763089 /KLON/UPSR/2008/5)
A Jaw ab
http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#qtophttp://ad%28%271228419763089%27%29/http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#qtop7/29/2019 k1 jawapan
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B
C
D
Huraian:
To find the total mass, mass of a bag of rice + mass of a bag of flour
Look at the reading on the weighing scale
1. Mass of a bag of rice
1.8 kg
2. Mass of a bag of flour
800 g = 0.8 kg
3. Solve
1.8 kg + 0.8 kg
= 2.6 kg
[Atas]
6 Diagram 4 shows a cuboid.
http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#qtophttp://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#qtop7/29/2019 k1 jawapan
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Diagram 4
Which of the following is the correct net of the cuboid?(ID:1230410570209 /KLON/UPSR/2008/6)
A
B
C
Jaw ab
http://ad%28%271230410570209%27%29/7/29/2019 k1 jawapan
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D
Huraian:
- To find the correct net
- Determine the length of every side
- The correct net is A
[Atas]
7- 20 096 - 900 = 33 654
What number must be written in the ?(ID:1225568108423 /KLON/UPSR/2008/7)
A 12 658
B 14 458
C 54 640
D 54 650
Jaw ab
Huraian:
To find the value in the box
Add in vertical form. The ones place value be the guide
1. Solve
[Atas]
8 4 - 2 =(ID:1225990782475 /KLON/UPSR/2008/8)
A 2
B 2
C 1
Jaw ab
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D 1
Huraian:
To determine the result
1. Subtract the whole number
4 - 2
= 2
2. Subtract the fraction
2 -
3. Solve
2 -
= 2 -
= 1 + -
= 1 -
= 1
[Atas]
9 156.7 8 =
Round off the answer to three decimal places.(ID:1225991181972 /KLON/UPSR/2008/9)
A 19.580
B 19.588
C 19.590
D 19.597
Jaw ab
Huraian:
To determine the correct answer
Calculate the quotient and round off to the nearest thousandth
1. The quotient
= 19.5875
2. The place value to be rounded off
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Thousandths
3. Solve
19.5875 = 19.588
[Atas]
10 Which of the following is the largest value?(ID:1225989909421 /KLON/UPSR/2008/10)
A 25% x RM28
B 30% x RM21.50
C 60% x RM25.50
D 90% x RM32
Jaw abHuraian:
To find the largest value
Calculate all the given options and compare
1. The largest value is
90% x RM32
= RM28.80
[Atas]
11 (718 x 5) - (62 x 30) =(ID:1225990429865 /KLON/UPSR/2008/11)
A 5 450
B 3 230
C 1 730
D 1 520
Jaw ab
Huraian:
To solve a mixed operation
1. Solve the operation in the bracket first718 x 5 = 3 590
62 x 30 = 1 860
2. Solve subtraction
= 3 590 - 1 860
= 1 730
[Atas]
12 8 - 2 + 1 =(ID:1229005770269 /KLON/UPSR/2008/12)
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A 5
B 4
C 6
D 7
Jaw ab
Huraian:
1. Solve the front operation first
8 - 2
= 7 - 2
= 5
2. Solve the second operation (addition operation)
5 + 1
= 5 + 1
= 6
[Atas]
13 9.3 - (7.8 + 1.26) =(ID:1223709052169 /KLON/UPSR/2008/13)
A 0.04
B 0.24
C 0.36
D 9.06
Jaw ab
Huraian:
Untuk menyelesaikan operasi bergabung yang melibatkan kurungan
Selesaikan operasi didalam kurungan dahulu
9.3 - (7.8 + 1.26) =
1. Solve the operation in the bracket first
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7.8 + 1.26 = 9.06
2. Solve the other operation
9.3 - 9.06 = 0.24
3. Solve
9.3 - (7.8 + 1.26) = 0.24
[Atas]
14 Calculate 6 440 000 - 2.07 millions.
Round off the answer to the nearest hundred thousand.(ID:1225990888517 /KLON/UPSR/2008/14)
A 4 000 000
B 4 300 000C 4 400 000
D 4 700 000
Jaw ab
Huraian:
To determine the answer
1. Convert the given number in millions to the whole number
2.07 millions = 2 070 000
2. Subtract
3. Round off the answer to the nearest hundred thousand
4 370 000 = 4 400 000
[Atas]
15 Diagram 5 shows a time on a clock.
Diagram 5
2 hours 50 minutes before the time shown is.(ID:1225567910508 /KLON/UPSR/2008/15)
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A 10.15 p.m.
B 6.35 p.m.
C 5.35 p.m.
D 4.35 p.m.
Jaw ab
Huraian:
To find the answer
The time shown - duration of the time stated
1. The time shown
= 1925 hours
2. Duration of the time stated
= 2 hours 50 minutes
3. 'Before' means subtract
4. Solve the operation in vertical form
[Atas]
16x 8 m = 2 m 40 cm. What number must be written in the ?
(ID:1223710375265 /KLON/UPSR/2008/16)
A 0.03
B 0.3
C 3
D 30
Jaw ab
Huraian:
To find the value in the
1. Divide 2 m 40 cm by 8 m, then x by 100
240 cm 800 = 0.3
2. Multiply by 100
0.3 x 100 = 30
3. The number in the is 30
[Atas]
17 RM371 14 =
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(ID:1226257060480 /KLON/UPSR/2008/17)
A 1 piece of RM10 + 1 piece of RM5 + 1 piece of 50 sen
B 1 piece of RM10 + 3 pieces of RM1 + 7 pieces of 50 sen
C 2 pieces of RM10 + 5 pieces of RM1 + 1 piece of 50 senD 2 pieces of RM10 + 5 pieces of RM1 + 3 pieces of 50 sen
Jaw ab
Huraian:
To determine the correct answer:
Determine the total value of money given is equivalence to the quotient
1. Quotient
RM371 14
= RM26.50
2. Total value given
A = RM15.50
B = RM16.50
C = RM25.50
D = RM26.50
3.
4. Solve
D = RM26.50[Atas]
18 3.6 l 8 =
Match the answer with the volume of water in the container.(ID:1228419277170 /KLON/UPSR/2008/18)
A Jaw ab
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B
C
D
Huraian:
To match the answer with the volume
1. Solve the division operation
= Determine the required unit (ml)
2. Match the answer with the volume in each container
3. Solve
3.6 l 8 = 0.45 l0.45 l = 450
ml
4.
5. Container B contains 450 mlof water
[Atas]
19 Calculate the average of km, 2 km, 0.35 km and 3 km, in m.(ID:1225991283241 /KLON/UPSR/2008/19)
A 1 525
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B 1 425
C 1 400
D 1 40
Jaw ab
Huraian:
To find the average of distance in m
Total distance number of quantities
1. Total up
km = 250 m
2 km = 2 500 m
0.35 km = 350 m
3 km = 3 000 m= 6 100 m
2.
3. Number of quantities
4
4. Solve
= 1 525 m
[Atas]
20 Table 1 shows the sales of exercise books in three months.
Table 1
How many exercise books in total were not sold in the three months?(ID:1224798866937 /KLON/UPSR/2008/20)
A 49
B 51
C 61
D 71
Jaw ab
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Huraian:
To find the number of exercise books not sold
Number of exercise books not sold in March +
number of exercise books not sold in April +
number of exercise books not sold in May
1. Number of exercise books not sold in March
250 - 238 = 12
2. Number of exercise books not sold in April
x 200 = 16
0
200 - 160 = 40
3.
4. Number of exercise books not sold in May
250 - 241 = 9
5. Solve
12 + 40 + 9
= 61 exercise books
[Atas]
21 Table 2 shows the number of eggs produced by three farms.
Table 2
Calculate the number of eggs produced by the three farms.(ID:1225567716331 /KLON/UPSR/2008/21)
A 190 680 eggs
B 279 455 eggs
C 289 455 eggs
D 289 465 eggs
Jaw ab
Huraian:
To find the number of eggs produced by the farms
Number of eggs in farm X + number of eggs in farm Y + number of eggs infarm Z
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1. Number of eggs in farm X
98 775 eggs
2. Number of eggs in farm Y
89 660 eggs
3. Number of eggs in farm Z
2 245 + 98 775 = 101 020 eggs
4. Solve
98 775 + 89 660 + 101 020 = 289 455 eggs
5. Total number of eggs produced by the three farms
289 455 eggs
[Atas]
22 4 x 240 g =(ID:1224798301297 /KLON/UPSR/2008/22)
A 0.104 kg
B 1.04 kg
C 10.4 kg
D 104.0 kg
Jaw ab
Huraian:
To solve the multiplication operation of the mixed number and the whole
number (g)
Convert the mixed number to an improper fraction
Then multiply by the whole number (g)
1. Convert the mixed number to an improper fraction
4 =
2. Solve
x 240 g
= 1040 g
= 1.04 kg
[Atas]
23 Table 3 shows the members in four sports houses.
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Table 3
What is the fraction of the Hang Tuah's members to the total members of the four sports
houses?(ID:1226257575890 /KLON/UPSR/2008/23)
A
B
C
D
Jaw ab
Huraian:
To find the fraction of the Hang Tuah's members from the whole members
and simplify
1. Hang Tuah's members
= 70 members
2. Total of all the members
Hang Tuah + Hang Jebat + Hang Lekir + Hang Kasturi
70 + 79 + 63 + 68
= 280
3. Solve
=
=
[Atas]
24 Puan Shuriana's salary is RM3 600 a month. She
spends of her salary. She gives of the remaining
money to her mother and saves the remainder. Howmuch is her savings?
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(ID:1227994805355 /KLON/UPSR/2008/24)
A RM400
B RM1 000
C RM1 200
D RM2 400
Jaw ab
Huraian:
To find the amount of the savings
Total salary - money spent - money given to her mother
1. Total salary
= RM3 600
2. Money spent
x RM3 600 = RM2 400
3. Money given to her mother
x remainder of the money
Remainder of the money
RM3 600 - RM2 400
= RM1 200
x RM1 200 = RM200
4. Solve
RM3 600 - RM2 400 - RM200
= RM1 000 (savings)
[Atas]
25 Diagram 6 shows the number of beads in two boxes, Y and Z.
Diagram 6
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Shawn takes some beads from box Y and 20% of the
beads from box Z. The total number of beads that he
takes is 361. Calculate the percentage of the beads
taken from box Y?
(ID:1226257430601 /KLON/UPSR/2008/25)
A 70
B 60
C 40
D 30
Jaw ab
Huraian:
To find the percentage of the beads taken from box Y
x 100
1. Number of beads taken
= 361 beads
2. Number taken from box Z
x 370 = 74 beads
3. Number of beads taken from box Y361 - 74 = 287 beads
4. Number of beads in box Z
= 410 beads
5. Solve
x 100 = 70%
[Atas]
26 Azwan buys 5 baskets of guavas. Each basket
contains 80 guavas. 3% of the total guavas are not
ripe. How many guavas are ripe?
(ID:1225990071553 /KLON/UPSR/2008/26)
A 392
B 388
C 364
D 325
Jaw ab
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Huraian:
To find the number of the ripe guavas
Percentage of the ripe guavas x number of guavas
1. Percentage left100% - 3% = 97%
2. Number of guavas
5 x 80 = 400
3. Solve
x 400
= 97 x 4
= 388 guavas
[Atas]
27 Ah Hing saved RM340 in October. In November, he saved RM100 more than he saved
in October. In December, he saved RM35 less than he saved in November. What is Ah
Hing's total savings for the three months?(ID:1223712791733 /KLON/UPSR/2008/27)
A RM1 185
B RM1 085
C RM475
D RM405
Jaw ab
Huraian:
To find the total of Ah Hing's savings
Savings in October + savings in November + savings in December
1. Savings in October
RM340
2. Savings in November
RM340 + RM100 = RM440
3. Savings in December
RM440 - RM35 = RM405
4. Solve
RM340 + RM440 + RM405 = RM1 185
5. The total of Ah Hing's savings for three months isRM1 185
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[Atas]
28 Diagram 7 shows the time Encik Zubir left his house for Kuala Terengganuone morning.
Diagram 7
Encik Zubir took 3 hours 35 minutes to reach Kuala
Terengganu. He was there for 5 hours. At what
time did he start back from Kuala Terengganu?
(ID:1225990516235 /KLON/UPSR/2008/28)
A 1355 hours
B 1730 hours
C 2030 hours
D 2220 hours
Jaw ab
Huraian:
To find the time Encik Zubir left from Kuala Trengganu
Departure from home + Duration of the journey + Time spent in KualaTerengganu
Give your answer in the 24 hour system
1. Departure from home
8.25 a.m. = 08 hours 25 minutes
2. Duration of the journey
= 03 hours 35 minutes
3. Time spent in Kuala Terengganu
5 hours = 05 hours 30 minutes
4. Solve
08 hours 25 minutes + 03 hours 35 minutes + 05 hours 30 minutes
= 17 hours 30 minutes
= 1730 hours
[Atas]
29 Table 4 shows the distance from the house to the recreational garden forthree students.
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Table 4
Which of the following diagrams represents the information in Table 4 correctly?(ID:1230057958072 /KLON/UPSR/2008/29)
A
B
C
D
Jaw ab
Huraian:
To determine the correct distance:
Determine the correct distance from each student's house
1. Hamzah
= 2.3 km (2 300 m)
2. Ismail
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= 2 (2 125 m)
3. Adibah
(2 300 m + 2 125 m) - 700 m
= 4 425 m - 700 m
= 3 725 m (3.725 km)
4.
5. Solve
[Atas]
30 Yuslan is 23 years old. In 7 years time, Yusri will be half the age of Yuslan. How old is
Yusri now?(ID:1225990981879 /KLON/UPSR/2008/30)
A 5 years
B 8 yearsC 12 years
D 15 years
Jaw ab
Huraian:
To find how old Yusri is now
Yuslan age in 7 years x - 7 years
1. Yuslan's age in 7 years
23 years + 7 = 30 years
2. Yusri's age in 7 years
30 x = 15
3. Yusri's age now
15 years - 7 years = 8
years
[Atas]
31 Table 5 shows the masses of three boxes U, V and W.
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Table 5
Calculate the total mass, in kg, of the three boxes.(ID:1234986402137 /KLON/UPSR/2008/31)
A 4.6
B 5.3
C 6.7
D 6.9
Jaw ab
Huraian:
To find the total mass of the three boxes
Mass of box V + Mass of box U + Mass of box W
1. Mass of box V
= 2.1 kg
2. Mass of box U
700 g = 0.7 kg less than the mass of box V
2.1 kg - 0.7
kg
= 1.4 kg
3.
4. Mass of box W
1.8 kg more than the mass of box U
1.8 kg + 1.4 kg = 3.2 kg
5. Solve
2.1 kg + 1.4 kg + 3.2 kg= 6.7 kg
[Atas]
32 The base area of a cuboid shape container is 910
cm2. The height of the container is 36 cm. of the
container is filled with water. Calculate the volume,
in cm3, of the water in the container.
(ID:1226960548076 /KLON/UPSR/2008/32)
A 32 760
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B 24 570
C 8 190
D 5 570
Jaw ab
Huraian:
To find the volume of the water in the container
x volume of the container
1. Volume of the container
910 cm2 x 36 cm = 32 760 cm3
2. Solve
= x 32 760 cm3
= 3 x 8 190 cm3
= 24 570 cm3
[Atas]
33 Table 6 shows the score given to a Malaysiansilat exponent by judges from five countries.
Table 6
The highest and the lowest score are not included as
the total score. What is the average score of the
Malaysian silat exponent?
(ID:1227553802518 /KLON/UPSR/2008/33)
A 4.38
B 4.58
C 7.09D 7.30
Jaw ab
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Huraian:
To find the average score
Total score Number of scores
1. Total scores7.73 + 6.95 + 7.22 =
21.90
2. Number of scores
3
3. Solve
21.90 3 = 7.30
[Atas]
34 Diagram 8 is a pictograph showing thenumber of televisions sold by a companyover four months.
Diagram 8
The number of televisions sold in July is 7% more
than in April. What is the total number of televisions
sold from March until July?
(ID:1225991371627 /KLON/UPSR/2008/34)
A 1 314
B 1 300
C 1 114
D 1 100
Jaw ab
Huraian:
To find the total sales of the televisions from March until July
Add the total number of televisions from March until June + number of
televisions in July
1. Determine the value representing a symbol
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1 symbol represents 50 televisions
2. Number of televisions from March until June
22 symbols x 50 televisions = 1 100 televisions
3. Number of televisions in July
7% more than the number of televisions sold in April
Number of televisions in April
4 symbols x 50 televisions = 200 televisions
x 200 = 14 televisions
200 + 14 = 214 televisions
4.
5. Solve1 100 + 214 = 1 314 televisions
[Atas]
35 Diagram 9 is a bar chart showing the number of floodvictims at four relief centres V, W, X and Y. The number ofvictims at centre Z is not shown.
Diagram 9
The average number of victims at the five centres is 480. Calculate
the number of victims at Z.
(ID:1226257289724 /KLON/UPSR/2008/35)
A 230
B 480
C 1 050
Jaw ab
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D 1 350
Huraian:
To find the number of victims at Z.Total all - Number of victims given.
1. Total number of victims
Average x Number of centre
480 x 5 = 2 400
2. Number of victims given
150 + 350 + 200 + 650
= 1 350
3. Solve2 400 - 1 350
= 1 050
[Atas]
36 Diagram 10 shows triangles PQR and PST.
Diagram 10
The length of PT is of QR. The length of PS = SR. Calculate the perimeter, in cm, of
the whole diagram.(ID:1228419168912 /KLON/UPSR/2008/36)
A 50
B 46
C 43
D 40
Jaw ab
Huraian:
To find the perimeter of the whole diagram
Add all the outside measurements of the whole diagram
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1. Side of PQ
14 cm
2. Side of PT
x QR = 7 cm
3. Side of SR
8 cm (equal to PS)
4. Side of TS
7 cm
5. Side of QR
14 cm
6. Solve
14 cm + 7 cm + 8 cm + 14 cm + 7 cm = 50 cm
7. The perimeter of the whole diagram is 50 cm
[Atas]
37 Diagram 11 shows a rectangle WXYZ.
Diagram 11
The area of the coloured region is 18 cm2
. This areais of the area of the rectangle. Calculate the length,
in cm, of ZY.
(ID:1225990157020 /KLON/UPSR/2008/37)
A 3
B 9
C 15
D 18
Jaw ab
Huraian:
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To find the length of ZY
The area of WXYZ the side length of WZ
1. The area of WXYZ
x area of WXYZ = 18 cm2
Area of WXYZ = 18 cm2 x 6 1
= 108 cm2
2.
3. The side length of WZ
= 12 cm
4. The length of ZY
108 cm2 12 cm= 9 cm
[Atas]
38 Diagram 12 shows 3 cuboids P, Q and R.
Diagram 12
The lengths of each cuboid is 4 cm. Calculate the total volume, in cm 3, of the three
cuboids.(ID:1229006344702 /KLON/UPSR/2008/38)
A 28
B 180
C 320
D 360
Jaw ab
Huraian:
To find the total volume of the three cuboids
Volume of cuboid P + Volume of cuboid Q + Volume of cuboid R
1. Volume of cuboid P
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5 cm x 4 cm x 9 cm = 180 cm3
2. Volume of cuboid Q
5 cm x 4 cm x 6 cm = 120 cm3
3. Volume of cuboid R
5 cm x 3 cm x 4 cm = 60 cm3
4. Solve
180 cm3 + 120 cm3 + 60 cm3 = 360 cm3
5. The total volume of the three cuboids is 360 cm3.
[Atas]
39 Diagram 13 shows triangles E, F, G, H and J drawn
on squares of the same size.
Diagram 13
Which of the following has the same area as triangle E(ID:1228419957023 /KLON/UPSR/2008/39)
A F
B G
C H
D J
Jaw ab
Huraian:
To find the area that is the same as E
Find the area of E and the area of each of the options given.
Area E =
=
= 6
Area F =
=
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= 6
Area G =
=
= 9
Area H =
=
= 10
Area J =
=
= 10
The triangle with the same area as E is F.
[Atas]
40 Diagram 14 shows rectangle WXYZ.
Diagram 14
Which of the following diagrams have the same perimeter as rectangle WXYZ?
http://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#qtophttp://202.157.188.87/cgi-bin/m/zoom-a-com-skpkjp-kathy-MJSZN4Y6gQNGidhehE/paper/qtest?_setid=1247751385862&_remote=#qtop7/29/2019 k1 jawapan
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(ID:1230816975891 /KLON/UPSR/2008/40)
A III and IV
B II and IV
C II and III
D I and III
Jaw ab
Huraian:
To determine diagrams with the same perimeter:
Determine perimeter of the diagram that equals to the perimeter of rectangle
WXYZ.
1. Perimeter of rectangle WXYZ(6 cm + 4 cm) x 2
= 20 cm
2. Diagrams that have the same perimeter
Diagram II and III
3. Solve
II and III
[Atas]
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