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Keys and Coupling
• Many Types of Keys and couplings, however understand how Torque is transferred in between each, and forms shearing stresses
Shaft Coupling• Sometimes, join 2 shafts together• Flanged couplings• Torque in Shaft Torque in Couplings Shear in
bolts • Similarly keys
Bolt
Flanged Couplings
Shaft
Bolt circle
Design of Shaft Torque applied, TA = ∏ τ d3 / 16
» Where, τ = shear stress in shaft d = shaft dia.
Design of bolts Torque resisted,
TR = Shear Stress Area x Radius of bolt circle
TR = n . (∏/4) . db2 . τ b . (D/2)
Where, τ b = shear stress in bolt db = bolt dia.
D = Diameter of bolt circlen = number of bolts
TA < TR
Design of Shaft Torque applied, TA = ∏ τ d3 / 16
» Where, τ = shear stress in shaft d = shaft dia.
Design of keysTorque resisted,
Tk = Shear Stress Area x Radius of shaft
Tk = l b τ k (D/2) Where, τ k = shear stress in key db = bolt dia.
D = Diameter of bolt circlen = number of bolts
TA < Tk
.
Springs and Stiffness
Stiffness of springLoad required to produce a unit deflection in spring. K = F/xx=unit deflectionUnder gravity,W = F
SpringsTypes of spring1. Bending / leaf / laminated spring
2. Torsion / helical spring
1. Close Coil helical spring
2. Open Coil helical spring
SpringsUses of Springs1. Storing energy, used in watch2. Shock absorbers3. Seismic isolation4. Spring balance5. Cycle seats
Closed Coiled helical springs subjected to axial loads
R = radius of the coild = Spring wire diameterW= axial load on springN = number of coils/turnsδ = deflection τ, θ, G,
Torque produced by axial load
T = W R
Also T = ∏ τ d3/16
Thus, ∏ τ d3/16 = W R
Length of wire = no. of coils x length of one coilOr, l = n 2∏R
T = G θJ l θ = 64 WR2 n Gd4
δ = R. θ = 64 WR3 n Gd4
Stiffness, s = W = Gd4
δ 64 R3 nEnergy Stored in a spring, U = (1/2) W δ
Combined Bending and Torsion
Find how Tanθ = 2 τ / f = T /M
Where • T = Torsion, • M = Bending Moment• τ = Shear Stress• M = Bending Stress
Tutorial- 2
1. Sketch 5 examples of use of springs2. List differences between closed and open coil
springs. Provide one sketch minimum3. Answer Q.1. from Rethalia’s exercise on
Helical Springs. pp. 724. Answer Q.1. to Q.7 from Rethalia’s example
exercise