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BIOCHEMISTRY EXPERIMENT ARTICLE THE DETERMINATION OF ENZYME REACTION KINETIC (Vmax and KM) OF TRYPSIN IN CATELIZE CASEIN REACTION By Ni Kadek Wahyuni Antari 1213031002 A CHEMISTRY EDUCATION DEPARTMENT FACULTY OF MATHEMATICS AND NATURAL SCIENCES UNIVERSITAS PENDIDIKAN GANESHA 2015

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  • BIOCHEMISTRY EXPERIMENT

    ARTICLE

    THE DETERMINATION OF ENZYME REACTION KINETIC

    (Vmax and KM) OF TRYPSIN IN CATELIZE CASEIN REACTION

    By

    Ni Kadek Wahyuni Antari

    1213031002

    A

    CHEMISTRY EDUCATION DEPARTMENT

    FACULTY OF MATHEMATICS AND NATURAL SCIENCES

    UNIVERSITAS PENDIDIKAN GANESHA

    2015

  • Rubrik Penilaian Artikel Praktikum

    Biokimia S1

    Nama mahasiswa : Ni Kadek Wahyuni Antari

    NIM : 1213031002

    Tanggal : 13 April 2015

    Mata Acara praktikum : Kinetika Reaksi Enzim

    No. Aspek yang dinilai Bobot

    (%)

    Skor

    (0-100)

    Bobot x skor

    1 Format 5

    2 Abstract 10

    3. Introduction 20

    4. Materials and Methods 10

    5. Result and discussion 30

    6. Conclusion 10

    7. Acknowledgment 5

    8. References 5

    9. Clear 5

    Total score 100

    Singaraja, 13 April 2015

    Penilai,

    Dr. I Nyoman Tika, M.Si

  • THE DETERMINATION OF ENZYME REACTION KINETIC (Vmax and KM) OF

    TRYPSIN IN CATELIZE CASEIN REACTION

    Ni Kadek Wahyuni Antari

    Chemistry Education Department, FMIPA, UNDIKSHA

    Udayana Street Singaraja, Bali

    Email: [email protected]

    Abstract

    Enzyme is a protein that has a specific three-dimensional structure that is able to catalyze biological reactions

    (biocatalytic activation). In the kinetics of enzyme reaction, the value of Vmax and KM are determined by using the

    graphical relationship between the rates of enzymatic reaction with substrate concentration. The objective of this

    experiment was to determine the Kinetics of trypsin enzyme in catalyze casein reactions by calculating the value of Km and Vmax. for incubation time 20 minutes and 0 minute using Lineweaver-Burk plot. The method used in this

    experiment was qualitative and quantitative analysis. Then, the instrument used is spectronic 20+. The result of

    this experiment revealed that the value of Km for the enzymatic reaction with the enzyme trypsin and casein

    substrate with t = 0 min and t = 20 min was 0.428 mg/mL and Vmax rates of 0.519 mole/minutes respectively.

    Keywords: Enzyme, enzyme activities, concentration and reaction rate

    INTRODUCTION

    Enzyme is biocatalyst that able

    increase reaction rate in biology system and

    enzymes do not change during reaction. An

    enzyme is a protein that has a particular three-dimensional structure that is able to catalyze

    biological reactions (biocatalytic activity).

    Enzymes can increase the reaction rate due to the presence of the enzyme reaction that occurs

    will have a lower activation energy than the

    usual reaction. Enzymes assist in providing a

    reaction to the reaction pathway has a lower activation energy for the transition of substrate

    into products as compared to the process

    without a catalyst, so that the enzyme is often referred to as a catalyst (Tika, 2010).

    Trypsin is one kind of enzyme, which

    is a protein that speeds up a certain biochemical reaction. It has different names, such as

    proteinase, proteolytic, and tripsina enzymes.

    Trypsin is found in the small intestine. It can

    also be made from fungus, plants, and bacteria. But it is usually made for commercial purposes

    from the pancreas of livestock. Trypsin is given

    to people who lack enzymes needed for digestion. It is also given in combination with

    bromelain and routine for treatment of

    osteoarthritis. Some people apply trypsin directly to wounds and ulcers to remove dead

    tissue and improve healing (WebMD, 2014).

    Enzymes have specific shapes and

    structures that determine their functions. The enzymes active site is very selective, allowing only certain substances to bind. If the shape of

    an enzyme is changed in any way, or the protein

    denatured, then the binding site also changes,

    thus disrupting enzymatic functions (Murray,

    1995). Measurement of enzyme levels can be done in two ways, namely: (1) as compared

    with pure enzyme, (2) measuring the reaction

    rate its catalyzed. At the lab is done by determining the levels of the enzyme reaction

    rate catalyzed (Tika, 2010).

    Enzyme activity is defined as the

    amount of enzyme that will convert a certain amount of S to P in a specified period of time

    under conditions of constant temperature and

    pH (Wirahadikusuma, 2001). Circumstances where the maximum initial reaction rate (Vmax)

    was achieved on saturated substrate conditions.

    This can be explained by the postulate of reaction as follows.

    E + Sk1

    k2

    ESk3

    k4

    E + P

    Where E, S, and P are each enzyme, substrate,

    and reaction products respectively. The effect of substrate concentration

    when substrate concentration is increased two

    times, then the initial reaction velocity (Vo) has

    doubled. Michaelis and Menten stated that the enzymatic reaction at various concentrations of

    substrates having two phases: 1) when [S] is

    low, not all of the active enzyme bound to the enzyme, 2) on [S] is high, the active side was

    entirely bound to the substrate. At this time the

  • enzyme has been working at full capacity

    (Poedjadi,1994).

    Figure 1. Relationship between substrate concentration and Vo plot directly

    Figure 2. Relationship between 1/Vo and 1/[S]

    plot of Lineweaver Burk

    Figure 1 filled the equation of Michaelis-

    Menten as follows.

    [S]K

    [S]VoV

    M

    max

    Where: Vo is reaction rate enzyme and

    substrate [S] and KM is constant of Michaelis Menten (mol/L) and Vmax is maximum rate of enzyme

    KM is a measure of the ES complex

    stability, the speed of decomposition of the complex ES with ES Kompeks formation rates.

    The specificity of a substrate that is catalyzed

    by first looking at the formation of complex

    enzyme substrate (ES), which then decomposes into enzyme and products (E and P). In this case

    k1, k2, k3,k4 is the reaction rate constant. Initially

    is achieved disintegration of the state of the enzyme rate equal to the speed of formation of

    ES.

    k1[S][E] + k4 [E][P] = k2 [ES] + k3 [ES]

    3k

    2k

    [P]4

    k

    3k

    2k

    [S]1

    k

    [E]

    [ES]

    In these conditions the concentration of P (product) is very little that is ignored. Constants

    k1, k2, k3 and k4 is written as a constant KM. KM

    =

    1

    32

    k

    kk . The equation becomes:

    [S]

    MK

    [ES]

    [E]

    If the total amount or concentration of

    enzyme [E]t is considered as the sum of the free

    enzyme, [E] and joined the substrate [ES] is the

    concentration [E] = [E]t - [ES],

    [S]

    MK

    1[ES]

    t[E]

    [ES]

    [ES]t[E]

    [ES]

    [E]

    1[S]

    MK

    [ES]

    t[E]

    So the maximum rate (Vmax) when the

    enzymes are all in the form of complexes with

    substrates. While Vo is proportional to [ES]. It can be written as follows.

    1[S]

    MK

    V

    Vso

    [ES]

    t[E]

    V

    V maxmax

    In Figure 1 it can see that KM is

    expressed as moles per liter. And KM is very

    large then the equation is written as follows (Redhana, 2003):

    M

    max

    K

    [S]VV

    Because KM is 1

    32

    k

    kk so that Ks =

    1

    32

    k

    kk

    So KM will always be equal to or greater than Ks. Judging from the equation:

    maxmax

    M

    M

    max

    V

    1

    [S]

    1

    V

    K

    V

    1so

    [S]K

    [S]VV

    Above equation is identical to the straight line equation y = ax + b

    Where y =maxmax

    M

    V

    1band

    V

    Ka;

    [S]

    1x;

    V

    1

    oV

    1is

    maxV

    1, the crossing point on the axis

    [S]

    1

    isMK

    1 . Equal to the slope of the line

    maks

    M

    V

    K

    Lineweaver-Burk plot is also very useful for

    Vmax

    Vo

    Vmax

    2

    0

    0

    KM 2KM 3KM 4KM 5KM

    [S]

    KM/Vmax

    -1/KM

    1/V

    1/Vmax

    01/[S]

  • determining the type inhibition enzymatic

    reactions that occur in (Tika, 2010).

    MATERIALS AND METHOD This experiment was conducted at

    Organic Chemistry Laboratory of Chemistry Education Department, Faculty of Mathematics

    and Natural Sciences, Ganesha Education

    University on 30th March 2015.

    Materials Materials used in this experiment were

    TCA solution 20% (30 mL), casein solution 2% (20 mL), phosphate buffer 0.1 M (pH 8.0) (42

    mL), trypsin solution (10 mL), NaOH solution

    0.5 M (40 mL), follin-ciocalteu reagnet (10

    mL), and distilled water.

    Equipment

    Equipment used in this experiment

    were test tubes (10 units), test tube rack (1 unit), volumetric pipette 5 mL (2 units), volumetric

    pipette 10 mL (2 units), graduated cylinder 5

    mL (2 units), graduated cylinder 10 mL (2 units), stirrer rod (2 units), drop pipette (3

    units), beaker glass 500 mL (2 units), centrifuge

    (1 unit), spectrophotometer (1 unit), volumetric

    flask 100 mL (2 units), and stopwatch.

    Procedures

    This experiment was carried out

    accordance with the procedures adopted from Penuntun Praktikum Biokima book developed by I Wayan Redhana and Siti

    Maryam (2003: 26-28). There are several

    procedures was conducted in this experiment, as follow:

    Making TCA Solution 20%

    As much as 20 mL of pure TCA was taken and diluted until rich the scale of 100 mL.

    Making Casein Solution 2%

    Casein powder was weighed as much as 2.0008 grams and mixed with water until reach the

    scale of 100 mL.

    Makin Trypsin solution

    Trypsin solution was made by dissolved enzymefort as much as 0.5001 grams into 50

    mL of water.

    Making Folin-Ciocalteu Reagent As much as 1 mL of pure folin-ciocalteu was

    taken and diluted until reach the scale volume

    of 10 mL. Making Phosphate Buffer 0.1 M (pH 8.0)

    As much as 94 mL of K2HPO4 solution 1 M was

    mixed with 6 mL of KH2PO4 solution 1 M and the pH was checked by pH meter.

    Making NaOH solution 0.5 M

    As much as 0.2002 grams of solid NaOH was

    weighed and dissolved with water until reach the scale volume of 100 mL.

    Incubation t = 20 minutes

    Five test tubes were prepared and give label 1, 2, 3, 4, 5. A total of 5 mL of casein solution 2

    % were added into all test tubes and incubated

    in water bath for 5 minutes at 35oC. Then it was added a solution of phosphate buffer and

    trypsin solution while stirring slowly. After

    that, it was incubated in water bath for 20

    minute at 35oC calculated from the enzyme is added. The reaction was stopped by addition of

    3 mL 20% TCA solution is accompanied with

    strong stirring. Furthermore, it was settling for 30 minutes in ice water so that the deposition of

    protein and trypsin could perfectly happen.

    After that, the solution was centrifuged for 10 minutes and then filtered. The filtrate obtained

    then done according to Anson's method, in

    which as many as 2 mL of filtrate was taken and

    then added 4 mL of NaOH solution 0.5 M and 1 mL of folin-cioceltau reagent. It was allowed

    to stand for 10 minutes. Finally, the absorbance

    of each solution in test tube was measured by using a spectrophotometer.

    Incubation t = 0 minute

    Buffer phosphate solution was entered into test

    tube and then it was added by trypsin solution. After that, it was added by 3 mL 20% TCA

    solution and incubate in water bath for 30

    minutes at 35oC. Last one was added 1% casein solution as much as 5 mL and stirred strong. It

    was incubated for 30 minutes in ice water

    calculated from the casein solution is added. After that, the solution was centrifuged for 10

    minutes and then filtered. The filtrate obtained

    then done according to Anson's method, in

    which as many as 2 mL of filtrate was taken and then added 4 mL of NaOH solution 0.5 M and

    1 mL of folin-cioceltau reagent. It was allowed

    to stand for 10 minutes. Finally, the absorbance of each solution in test tube was measured by

    using a spectrophotometer.

    The composition of solution in each test tube was followed the following table.

  • Table 1. Addition of solution to each tube

    No Tubes Casein

    (mL)

    Phosphate

    Buffer (mL)

    Trypsin

    (mL)

    I t = 0 minute 0.1 5.9 1

    t = 20 minutes 0.1 5.9 1

    II t = 0 minute 0.5 5.5 1

    t = 20 minutes 0.5 5.5 1

    III t = 0 minute 1.0 5.0 1

    t = 20 minutes 1.0 5.0 1

    IV t = 0 minute 3.0 3.0 1 t = 20 minutes 3.0 3.0 1

    V t = 0 minute 5.0 1.0 1

    t = 20 minutes 5.0 1.0 1

    RESULT AND DISCUSSION

    Result

    After measuring the absorbance of each solutions at = 650 nm by using

    spectrophotometer is obtained data as follow:

    Table 2. The Absorbance of each solutions at = 650 nm

    Test

    Tubes

    Absorbance

    t = 0 minute t = 20 minutes

    I 0.050 0.260 II 0.056 0.420

    III 0.066 0.510

    IV 0.090 0.590 V 0.116 0.680

    Discussion

    In this experiment was analyzed the influence of substrate concentration on enzyme

    activity. In this analysis done two variations,

    namely the time spent at 0 minutes and 20 minutes, which given the time variation of this

    enzyme shows a length of binding to the

    substrate until finally precipitated by TCA. This enzyme reaction kinetics are determined by the

    value of Vmax and Km. Vmax and Km is the value

    determined in a way to graph the relationship

    between the reaction rate against substrate concentration.

    In this experiment which was used as

    the substrate namely casein and an enzyme trypsin. Trypsin is a proteolytic enzyme, this

    enzyme catalyzes the hydrolysis of the bond

    peptide, where in the peptide bonds were

    broken in the substrate casein is located on the carboxyl side of lysine or arginine residues are

    charged.

    Before starting the experiment, it was prepared ten test tubes filled with a solution of

    casein, trypsin and acetate buffer with different

    concentrations then given two different treatments. Five of the ten test tubes given

    incubation time 0 minutes and five others were

    treated test tube incubation for 20 minutes. For incubation 20 minutes, firstly carried out the

    initial incubation for 5 min at 35oC. The

    purpose of this incubation process is to create condition the substrate at the optimal

    temperature (35oC). After it was added with

    phosphate buffer solution (pH = 8.0) and trypsin solution. The addition of trypsin

    solution aims to catalyze the hydrolysis of

    peptide bonds that exist in casein. The next

    solution was incubated for 20 minutes, in which the incubation of trypsin allows the enzyme

    bound to the substrate. After the incubation

    process is completed, then the solution was added a solution of 20% TCA and was

    accompanied by stirring. The purpose of the

    addition of TCA solution is to stop the enzyme

    activity that can be analyzed the influence of substrate concentration on the rate of enzymatic

    reactions. In addition, all of test tubes were

    incubate in ice water to accelerate the reaction stop. The ability of TCA to stop the enzyme

    activity is due to the acidic solution of TCA so

    as to lower the pH of the solution so as to denaturate either protein or casein on trypsin.

  • Regarding the solution to the long

    incubation time 0 min, there was little difference in work procedures. Where in the

    fifth test tube were added first phosphate buffer

    and trypsin solutions, then continue added

    solution of TCA. Having experienced the process of incubation and then added to the

    casein solution with different volume.

    After TCA solution stop the enzyme activity, the solution was centrifuged for 10

    minutes and then filtered. The filtrate obtained

    was then done by the method of Anson where as many as 2 mL of filtrate was taken and then

    added with 4 mL of 0.5 M NaOH solution and

    Folin cioceltau reagent. These reagents can be

    reduced by the phenolic group on the amino acid tyrosine in the filtrate are produce

    tungstate and molybdate that has blue color.

    The blue color produce in each test tube from

    test tube 1 until 5 after the filtrate was done by Ansons method is darker, in which the first test tube contained light blue solution, second test

    tube contained turkish solution, third test tube contained bluish solution, forth test tube

    contained dark blue solution, and the last test

    tube contained blackish blue solution as shown as following figure.

    (a) (b)

    Figure 3. The color of solution after trating by Ansons method for (a) t = 0 minutes (b) t = 20 minutes. The color from test tube 1 until 5 is more darker (bluish until blackish blue solution)

    Then the absorbance of each colored solution

    was measured by using spectronic 20+. Absorbance measurement results for each

    colored solutions are presented in following

    table.

    Table 3. The result of absorbance measurement in each solution at = 650 nm

    Test

    Tubes

    Absorbance Absorbance

    t = 0 minute t = 20 minutes

    I 0.050 0.260 0.210

    II 0.056 0.420 0.364

    III 0.066 0.510 0.444

    IV 0.090 0.590 0.500 V 0.116 0.680 0.564

    Based on the result above, the value of 1/Vo can be calculated by using the value of absorbance

    because 1/A = 1/Vo. The result calculation of

    1/Vo in each test tube is represent in following table:

    Table 4. The value of 1/Vo in each test tube

    Test Tube A 1/A = 1/Vo

    (mole/minutes)

    I 0.210 4.762

    II 0.364 2.747

    III 0.444 2.252 IV 0.500 2.000

    V 0.564 1.773

    Then, to make the graph of enzymatic reaction

    kinetic is need to calculate the concentration of

    substrate or in this case is the concentration of

    casein solution in each test tube after diluting process. The mass of casein is added is equal to

    2.0008 grams in 100 mL of distilled water, so

    the concentration of casein as substrate as

    follow:

  • [Casein] = mL100

    gram2.0008

    = 0.02 gr/mL = 20 mg/mL After dilution process until reach the volume of

    7 mL, so the concentration of casein as

    substrate in each test tube can be known by

    using the equation V1 x M1 = V2 x M2. The result of calculation toward the concentration of

    casein in each test tube represent as following

    table:

    Table 5. The concentration of casein solution as substrate in each test tube after diluting process

    Test Tube [S] 1/[S] (mg/mL)

    I 0.286 3.496

    II 1.429 0.700

    III 2.857 0.350 IV 8.571 0.117

    V 14.286 0.070

    After the value of 1/Vo and 1/[S] is obtained, it can be made the curve of relationship between

    1/Vo and 1/[S] as the following figure.

    Figure 4. The graph of relationship between 1/Vo and 1/[S]

    The resulting graph between 1/Vo and 1/[S] is

    produce a straight line. The linear equation of

    the graph is y = 0.8248x + 1.926 with R = 0.9814. Then, by combining this linear

    equation with equation from Lineweaver-Burk,

    so the value of 1/Vmaks, 1/[S], and -1/Km could be obtained. The equation of Lineweaver-Burk

    is as follow.

    maxmax

    M

    V

    1

    [S]

    1

    V

    K

    oV

    1

    So, based on the linear equation the value of

    maxV

    1is the value at x = 0, so

    y = 0.8248x + 1.926

    y = 0.8248 (0) + 1.926

    y = 1.926

    maxV

    1= 1.926

    Vmax = 0.5191.926

    1 mole/minutes

    While the intersection of [S]

    1 axis

    is -MK

    1, this

    value is equal with value when y = 0, so y = 0.8248x + 1.926

    0 = 0.8248x + 1.926

    -1.926 = 0.8248x x = -2.335

    Therefore -MK

    1= -2.335 and KM =

    2.335

    1

    =0.428 mg/mL

    y = 0.8248x + 1.926R = 0.9814

    0

    1

    2

    3

    4

    5

    6

    0 1 2 3 4

    1/V

    o(m

    ole

    /min

    ute

    s)

    1/[S] (mg/mL)

    The Curve of Relationship between 1/Vo and 1/[S]

    Series1

    Linear (Series1)

  • CONCLUSION

    Based on the discussion above, it can be conclude that: (1) Kinetics of enzyme

    reactions can be studied and determined by

    determining the value of Km and Vmax. (2) The

    Value of Km for the enzymatic reaction with the enzyme trypsin and casein substrate with t = 0

    min and t = 20 min was 0.428 mg/mL and

    0.519 mole/minutes.

    ACKNOWLEDGEMENT In writing this article, the author has of

    a lot of support, guidance and encouragement from many quarters. For this reason, the author

    respectfully thanks for Dr. I Nyoman Tika,

    M.Si as lecturer on the practicum, Ms. Dewi as lecturer assistant, Mr. Dewa Subamia as the

    laboratory assistant and also all member of

    RKBI12 of chemistry class for always as good partners.

    REFERENCES Murray, Robert K, dkk. 1995. Biokimia Harper.

    Terjemahan. Andri Hartono. Jakarta:

    Buku Kedokteran EGC.

    Poedjadi, Anna dan Titin Supriyanti. 1994.

    Dasar-Dasar Biokimia. Jakarta: Universitas Indonesia

    Redhana, I Wayan dan Siti Maryam. 2003.

    Penuntun Praktikum Biokimia. Singaraja : IKIP Negeri Singaraja

    Tika, I Nyoman. 2010. Penuntun Praktikum

    Biokimia. Singaraja: Universitas Pendidikan Ganesha

    WebMD. (2014). WebMD. Retrieved April 22,

    2014, from http://www.webmd.com/

    Wirahadikusuma, Muhamad. 2001. Biokimia :Protein, Enzim, dan Asam Nukleat.

    Bandung : Penerbit ITB