Lecture 2A Macro Mechanics Stress Strain Relations for Material Types

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    Macro Mechanical Analysis of a Composite Lamina

    Chapter Objectives

    Develop stressstrain relationships for different types of materials.

    Develop stressstrain relationships for a unidirectional/bidirectional

    lamina.

    Find the engineering constants of a unidirectional/bidirectional

    lamina in terms of the stiffness and compliance parameters of the

    lamina.

    Develop stressstrain relationships, elastic moduli, strengths, andthermal and moisture expansion coefficients of an angle ply based

    on those of a unidirectional/bidirectional lamina and the angle of

    the ply.

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    and the angle between the axes of the 123 system and the 123

    system:

    Inverting Equation (2.25), the general strainstress relationship for a

    three dimensional body in a 123 Orthogonal Cartesian coordinate

    system would be:

    2.25

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    2.3.1 Anisotropic Material.

    The material that has 21 independent elastic constants at a point is

    called an anisotropic material. Once these constants are found at a

    particular point, the stress-strain relationship can be developed at that

    point. Note that these constants can vary from point to point if the

    material is

    non-homogeneous. Even if the material is homogeneous (orassumed to be one), one needs to find these 21 elastic constants

    analytically or experimentally. However, many natural and synthetic

    materials do possess material symmetry that is, elastic properties

    are identical in directions of symmetry about the symmetric planes

    because symmetry exists in the internal material structure.

    Consequently, this material symmetry reduces the number of

    independent elastic constants by zeroing out or relating some of the

    constants in the 6 6 material stiffness and compliance matrices. This

    i lifi th l tt t i l t i l ti hi f i t f

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    C14 = 0, C15 = 0, C24 = 0, C25 = 0, C 34 = 0, C35 = 0 , C46 = 0,

    and C56 = 0 (i.e. any elastic constant involving the indices 4 or 5 relatingthe shearing strain components would be zero).This is so because, the

    corresponding shearing strains which reverse the sign at the symmetric

    points on either side of the symmetric plane (0, 0, +z and 0, 0,-z) would violate the symmetric condition. The direction perpendicular to the

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    2.3.3 Orthotropic Material

    If a material has three mutually perpendicular planes of material

    symmetry, then the material is referred to as Three-Dimensional

    Orthotropic Material. Then the stiffness matrix would be given by:

    The preceding stiffness matrix can be derived by starting from the

    stiffness matrix [C] for the monoclinic material (Equation 2.35) where two

    more planes of symmetry would lead to: C16 = 0, C26 = 0, C36 = 0 and

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    The compliance matrix for 3-D Orthotropic Material reduces to:

    2.3.4 Transversely Isotropic Material

    Consider a plane of material isotropy in one of the planes of an

    orthotropic body. If direction-1 is normal to that plane (23) of isotropy,

    then the stiffness matrix is given by:

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    The Transverse isotropy results in the following relations:

    Note the five independent elastic constants. An example of this is a thin

    idi ti l l i i hi h th fib d i

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    2.3.5 Isotropic Material

    If all planes in an orthotropic body are identical, it is an isotropic

    material; then, the stiffness matrix is given by:

    Isotropy results in the following additional relationships:

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    The compliance matrix reduces to:

    The number of independent elastic constants for various types of

    materials is listed below:

    1. Anisotropic Material : 21Elastic constants

    2. Monoclinic Material: 13 Elastic constants

    3. Orthotropic Material: 9 Elastic constants

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