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EE5712 Power System Reliability :: Reliability Theory Panida Jirutitijaroen 8/30/2010 1 EE5712 Power System Reliability

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  • EE5712 Power System Reliability:: Reliability Theory

    Panida Jirutitijaroen

    8/30/2010 1EE5712 Power System Reliability

  • Announcement#1

    Should we start the class at 6PM?

    Do not follow lecture notes in 2009!!

    Download reading materials from the given references.

    Homework 2 uploaded & Homework 1 due today!

    Ask your questions about homework earlier, dont wait until the last minute!

    8/30/2010 EE5712 Power System Reliability 2

  • Announcement#2

    ECE NUS and IEEE PES Invited seminar next week.

    Solar system integration by Dr. Thomas Reindl, SERIS on Tuesday August 31st, 4-5pm at E5-03-50.

    Optimal Hydrothermal Generation Scheduling using Self-Organizing Hierarchical PSO by Dr. WeerakornOngsakul, AIT on Friday September 3rd,3-4pm at E5-03-21.

    How reliabile electricity system in Singapore is?

    http://www.channelnewsasia.com/stories/singaporelocalnews/view/1077279/1/.html

    8/30/2010 EE5712 Power System Reliability 3

  • Outline

    Reliability Theory

    Reliability Measure

    Simple reliability evaluation methods

    Example Quick introduction to MATLAB

    8/30/2010 EE5712 Power System Reliability 4

  • X: Time to Failure

    Outcome: time to failure

    Random Variable, X

    GA generator start working at time x = 0

    It can fail at any time, x 0

    x 0

    8/30/2010 5EE5712 Power System Reliability

  • Failure Probability Density Function

    Probability that a component fails at time x.

    1 2 3 4 5

    Exponential distribution function

    3

    2

    5.05.032Pr dxeX x

    0,5.0 5.0 xexf x0.5

    x

    xxXxxf

    x

    Prlim

    0

    8/30/2010 6EE5712 Power System Reliability

  • Failure Probability Distribution Function

    A probability that a component fails before or at time x.

    Exponential distribution function

    dttfxXxFx

    Pr

    1 2 3 4 5

    8/30/2010 7EE5712 Power System Reliability

  • Survival Function

    Time to failure of a component is a random variable, X.

    Commonly used in reliability theory

    A function that gives probability of a component survival beyond time x.

    1 2 3 4 5

    xFxXxXxR 1Pr1Pr

    4

    5.05.04Pr4 dxeXR x0.5

    8/30/2010 8EE5712 Power System Reliability

  • Hazard Rate Function

    Denoted by (x),

    A function that gives a rate at time x, at which a component fails ( i.e. failure rate), given that it has survived for time x.

    x

    xXxxXxx

    x

    |Prlim

    0

    Probability of a component fails between time x and x+x given that it has survived for time x

    8/30/2010 9EE5712 Power System Reliability

  • Triangle Relationship

    xf

    xR x

    x

    dttf

    xf

    x

    dttf

    dx

    xdR

    dx

    xdR

    xR

    1

    x

    dtt

    ex 0

    x

    dtt

    e 0

    Probability density function

    Survival function Hazard function

    8/30/2010 10EE5712 Power System Reliability

  • Important Note

    Although , for simplicity, survival function and hazard rate function have been described with respect to a component failure, they apply to any random variable.

    For example if the random variable is time to repair, then (x) represents the repair rate

    8/30/2010 11EE5712 Power System Reliability

  • RELIABILITY THEORY

    Reliability evaluation

    Failure distribution

    Survival function

    Hazard rate function

    8/30/2010 12EE5712 Power System Reliability

  • Reliability Evaluation

    Concern with time of a component/system to fail.

    At time = 0, probability of failure = 0.

    As time , probability of failure 1.

    t = 0

    This looks like cumulative distribution function!

    8/30/2010 13EE5712 Power System Reliability

  • Cumulative Failure Distribution

    Cumulative failure distribution

    Measure of probability of failure as a function of time

    Denote as Q(t).

    t = 0

    8/30/2010 14EE5712 Power System Reliability

  • Survival Function

    More interested to know what is the survival probability.

    Denoted by R(t), or equivalently, S(t)

    Probability of a component/system surviving

    Complement of probability of failure

    R(t) = 1 Q(t)

    8/30/2010 15EE5712 Power System Reliability

  • Failure Probability Density Function

    Denoted by f(t).

    Recall: pdf= derivative (cumulative function)

    dt

    tdQtf

    dt

    tdR

    dt

    tRdtf

    1

    dttftQt

    0

    dttfdttftRt

    t

    0

    1 t

    f(t)

    Q(t) R(t) = Survival Function

    0 time

    8/30/2010 16EE5712 Power System Reliability

  • Hazard Rate Function

    Equivalently

    transition rate function, failure rate function, repair rate function, force of mortality

    Definition:

    Compute as per unit to the number of components

    Measure of the rate at which failure occur

    8/30/2010 17EE5712 Power System Reliability

  • Hazard Rate Calculation

    Denote by (t).

    Depends on

    number of failure in given time

    number of components exposed to failure

    (t) = Number of failures per unit time

    Number of components exposed to failure

    8/30/2010 18EE5712 Power System Reliability

    This implies that we only consider those components that are survived up to this time t!

  • Example

    N0 = number of component tested

    Ns(t) = number of component survived at t

    Nf(t) = number of failure at t

    R(t) = Ns(t)

    N0

    Q(t) = Nf(t)

    N0

    (t) = Number of failures per unit time

    Number of components exposed to failure

    (t) = dNf(t)/dt

    Ns(t)8/30/2010 19EE5712 Power System Reliability

  • (t) VS. R(t)

    From f(t) = dQ(t)/dt,

    Hazard rate function is a conditional function of failure density function.

    f(t) = dNf(t)/dt

    N0

    (t) = dNf(t)/dt

    Ns(t)= dNf(t)/dt

    Ns(t) N0N0 =

    R(t)f(t)

    8/30/2010 20EE5712 Power System Reliability

  • (t) VS. f(t)

    Failure density function Probability of failure in any period of time

    Hazard rate function Probability of failure in next period of time, given

    that it has survived up to time t

    (t) equivalent to f(t) but covers only time up to point of interest.

    Need to normalize back to unity for times up to t.

    8/30/2010 21EE5712 Power System Reliability

  • Example: Hazard Rate Calculation

    An equipment initially contain 1000 identical components has the following history data in 20 hours.

    Taken from Reliability Evaluation of Engineering Systems: concepts and techniques by Roy billinton and Ron Allan8/30/2010 22EE5712 Power System Reliability

  • Hazard Rate Function

    8/30/2010 23EE5712 Power System Reliability

  • A Bath Tub Curve

    Typical hazard function of a component.

    It is fairly common to assume constant transition rates in reliability modeling.

    Burn-in period Wear-out periodUseful life

    t

    8/30/2010 24EE5712 Power System Reliability

  • A Two-State Component

    Consider a two-state component

    (t) is a hazard function of the up time, called failure rate.

    (t) is a hazard function of the down time, called repair rate.

    Generally, hazard function is called transition rate in reliability work.

    UP DOWN

    (t)

    (t)

    8/30/2010 25EE5712 Power System Reliability

  • RELIABILITY MEASURE

    Mean time to failure

    Mean time to repair

    Mean time between failure

    System availability

    Frequency of failure

    8/30/2010 26EE5712 Power System Reliability

  • Mean Time to Failure (MTTF)

    If system spend Tsuccess hours in success states, the mean up time is given by

    MTTF = Tsuccess / nsuccess-to-failurensuccess-to-failure = number of transitions from success states to failure states during T hours.

    Average time that the system is in good working condition, also called mean up time.

    8/30/2010 27EE5712 Power System Reliability

  • A Two-State Example

    Mean time to failure (MTTF) =

    nUD

    Tup

    Tdown

    UP

    DOWN

    Tup

    nUD nUD nUD

    8/30/2010 28EE5712 Power System Reliability

  • Mean Time to Repair (MTTR)

    If system spend Tfailure hours in failure states, the mean down time is given by

    MTTR = Tfailure / nfailure-to-successnfailure-to-success = number of transitions from failure states to success states during T hours.

    Average time that the system is in repair condition, also called mean down time.

    8/30/2010 29EE5712 Power System Reliability

  • A Two-State Example

    Mean time to repair (MTTR) =

    nUD

    Tdown

    Tdown

    UP

    DOWN

    Tup

    nUD nUD nUD

    8/30/2010 30EE5712 Power System Reliability

  • Mean Cycle Time

    If system has mean up time of MTTF, and mean down time of MTTR, the mean cycle time is

    MTBF = MTTF + MTTR

    Average time between failures, also called Mean time Between Failure (MTBF)

    8/30/2010 31EE5712 Power System Reliability

  • A Two-State Example

    Tdown

    UP

    DOWN

    Tup

    nUD nUD nUD

    Mean cycle time (MTBF) =

    nUD

    Tup + Tdown

    8/30/2010 32EE5712 Power System Reliability

  • System Availability

    If system has mean up time of MTTF, and mean down time of MTTR, the mean cycle time is MTTF + MTTR, system availability is found from

    A = MTTF/ (MTTF + MTTR)

    Probability of being found in the success states.

    8/30/2010 33EE5712 Power System Reliability

  • System Unavailability

    If system has mean up time of MTTF, and mean down time of MTTR, the mean cycle time is MTTF + MTTR, system unavailability is found from

    U = MTTR/ (MTTF + MTTR)

    Probability of being found in the failure states.

    8/30/2010 34EE5712 Power System Reliability

  • Example

    A two-state system has the following history over 10 years, 20 transitions from up to down state

    9 years spent in up state

    Find the followings Mean up time in days

    Mean down time in days

    Mean cycle time in days

    System availability

    System unavailability

    8/30/2010 35EE5712 Power System Reliability

  • Other Measures

    Frequency of failure

    Equivalent failure rate

    8/30/2010 36EE5712 Power System Reliability

  • SIMPLE RELIABILITY EVALUATION METHODS

    Assumptions

    Probability convolution

    Failure mode and effects analysis

    8/30/2010 37EE5712 Power System Reliability

  • Assumptions

    Use only probability rules

    Known failure probability of each component

    independent failure

    Simple system configurations, series/parallel

    Solution: Failure probability (equivalently, system unavailability)

    8/30/2010 38EE5712 Power System Reliability

  • Probability Convolution Method

    Two independent random variables, X and Y with probability density function

    Interest to find the distribution of a new random variable Z = X + Y

    Continuous case:

    Discrete case:

    dtyxtyxtz

    m

    mnymxnyxnz

    8/30/2010 39EE5712 Power System Reliability

  • Excess Generation at Load Point

    X: generating capacity distribution

    Y: load distribution

    Interest to find Z: Excess generation

    Z = X Y

    System loss is when Z < 0

    System unavailability is Pr{Z < 0}

    Need to find the distribution of Z

    8/30/2010 40EE5712 Power System Reliability

  • Probability Convolution for Z

    Z = X Y = X + Y, where Y = -Y

    Continuous case:

    Discrete case:

    dtyxdtyxtyxtz

    m

    nmymxnyxnz

    8/30/2010 41EE5712 Power System Reliability

  • Excess Generation Distribution Example

    Capacity (MW) Probability

    0 0.000001

    50 0.000297

    100 0.029403

    150 0.970299

    Interest to find excess capacity (E), given that the generation capacity (G) and load (L) has the following distribution

    Load (MW) Probability

    0 0.00

    50 0.20

    100 0.75

    150 0.05

    8/30/2010 42EE5712 Power System Reliability

  • Convolution Example

    From z*n+ = (all m) x[m]y[m-n] E[-150] = G[0]L[150] E[-100] = G[0]L[100] + G[50]L[150] E[-50] = G[0]L[50] + G[50]L[100] + G[100]L[150] E[0] = G[0]L[0] + G[50]L[50] + G[100]L[100] + G[150]L[150] E[50] = G[50]L[0] + G[100]L[150] + G[150]L[100] E[100] = G[100]L[0] + G[150]L[50] E[150] = G[150]L[0]

    n G: Capacity (MW) Probability L: Load (MW) Probability

    0 0 0.000001 0 0.00

    1 50 0.000297 50 0.20

    2 100 0.029403 100 0.75

    3 150 0.970299 150 0.05

    8/30/2010 43EE5712 Power System Reliability

  • Failure Mode and Effects Analysis

    Model the system

    Categorized into subsystems

    Define function of each system and its requirement

    Block diagram

    Examine all failure modes of a component

    For example, A circuit breaker ground faults

    failure to open

    undesired tripping

    Study the effects according to the failure

    8/30/2010 44EE5712 Power System Reliability

  • You are the weakest link!!

    "A chain is only as strong as its weakest link

    Does this mean that system reliability is determined by the least reliable component in the system?

    8/30/2010 45EE5712 Power System Reliability

  • SYSTEM RELIABILITY-NETWORK METHODS

    Reliability block diagram

    System structure

    Series-Parallel network

    Conditional Probability Approach

    Cut-set or tie-set method

    8/30/2010 EE5712 Power System Reliability 46

  • Structure

    System is called structure by definition when the followings apply.

    Only 2-state components: Up or Down.

    System has only 2 states: Up or Down.

    8/30/2010 EE5712 Power System Reliability 47

    UP DOWN

    (t)

    (t)

  • Monotonic Structures

    A system is called monotonic structure when the system is structured and the followings apply. System operates if all components are up.

    System fails if all components fail.

    Failure of a component in an already-failed system cannot restore system to work, and the repair of a component in operation will not cause system failures.

    Sometimes called Coherent.

    8/30/2010 EE5712 Power System Reliability 48

  • Reliability Block Diagram

    Can only be used for monotonic structure system.

    Also called Logic diagram.

    Logical relationship between failure of the network and failure of the components.

    A block represents working components.

    Removal of a block represents failure of a component.

    Usually consistent with system structure

    Not necessarily refer to physical connections

    8/30/2010 EE5712 Power System Reliability 49

  • Series System

    The success of all components causes the system to success.

    Let PsA and PsB be the success probability of component A and B

    System availability is

    A = PsA PsB

    A B

    8/30/2010 50EE5712 Power System Reliability

  • Parallel System

    The failure of all components causes the system to fail.

    Let PfA and PfB be the failure probability of component A and B

    System unavailability is

    U = PfA PfB

    A

    B

    8/30/2010 51EE5712 Power System Reliability

  • Series/Parallel Example

    If all component has failure probability of 0.01, evaluate system reliability in terms of availability and unavailability

    1

    6

    3

    45

    7

    8

    2

    8/30/2010 52EE5712 Power System Reliability

  • Applications

    Probability Convolution

    Develop excess generating capacity distribution

    Single area analysis

    Modeling injected power at each bus

    Series/Parallel Network

    Distribution systems

    Simple substation configuration

    Components Circuit breakers

    Transformers

    Transmission lines

    8/30/2010 53EE5712 Power System Reliability

  • Limitations

    1

    2

    5

    3

    4

    Series or Parallel??

    2

    8

    5

    3

    9

    1

    7

    4

    10

    6

    8/30/2010 54EE5712 Power System Reliability

  • Conditional Probability Approach

    Decompose a complex system into simpler subsystems

    Each subsystem is disjoint event

    Use conditional probability rule to calculate system failure probability

    Denote key component, X, the probability of system failure is calculated from.

    Pf = Pr{system fails | X fails} Pr {X fails} +

    Pr{system fails | X works} Pr {X works}

    8/30/2010 55EE5712 Power System Reliability

  • Conditional Probability Example

    Assume that each component has failure probability of 0.01 and component 5 is key component, calculate system failure probability

    1

    2

    5

    3

    4

    1

    2

    3

    4

    1

    2

    3

    4

    5 fails5 is working

    subsystem A subsystem B8/30/2010 56EE5712 Power System Reliability

  • Failure Probability Calculation

    Pf = Pr{system fails | 5 works} Pr {5 works} +

    Pr{system fails | 5 fails} Pr {5 fails}

    Pf = Pr{A fails} 0.99 + Pr{B fails} 0.01

    8/30/2010 57EE5712 Power System Reliability

  • Limitations

    1

    2

    5

    3

    4

    Series or Parallel??

    2

    8

    5

    3

    9

    1

    7

    4

    10

    6

    8/30/2010 58EE5712 Power System Reliability

  • Cut-Set and Tie-Set Method

    Evaluate reliability of a block diagram network

    Assume independent failure

    Definition Cut set

    Minimal cut set

    Tie set

    Minimal tie set

    Use probability rules to calculate system availability

    8/30/2010 59EE5712 Power System Reliability

  • Cut-Set

    A set of components whose failure causes system failure

    1

    2

    5

    3

    4

    Example (1,2), (1,2,3), (1,2,4), (1,2,5), (1,4,5) , (1,2,3,4) , (1,2,3,4,5) ,

    8/30/2010 60EE5712 Power System Reliability

  • Minimal Cut-Set

    A smallest set of components whose failure causes system failure

    1

    2

    5

    3

    4

    Minimal cut-set = { (1,2), (3,4), (1,4,5) , (2,3,5) }

    8/30/2010 61EE5712 Power System Reliability

  • Cut-Set Method

    Enumerate all minimal cut-set in the system. Failure of all components in a minimal cut-set

    causes system failure. This implies parallel connections among these

    components. Each minimal cut set causes system failure. This implies series connections among the

    minimal cut sets. Draw equivalent system and use series/parallel

    method to compute for system availability.

    8/30/2010 62EE5712 Power System Reliability

  • Example

    1

    2

    5

    3

    4

    1

    2

    Minimal cut-set = { (1,2), (3,4), (1,4,5) , (2,3,5) }

    3

    4

    1

    5

    4

    2

    5

    3

    8/30/2010 63EE5712 Power System Reliability

  • System Unavailability Calculation

    If the system has C1, , Cn minimal cut sets, system failure probability is found from

    Pf = Pr,1 U 2 U U n},

    is an event that the cut-set fails

    These minimal cut sets are not disjoint,

    Pf = Pr,1 U 2 U U n}

    = i Pr{i} - ij Pr{i j- + ijk Pr{i j k}

    - + (-1) Pr,1 n} 1

    8/30/2010 64EE5712 Power System Reliability

  • Probability Approximation

    Total number of terms in previous equation is 2-1.

    Use Booles inequality,

    Pf = Pr,1 U 2 U U n- i Pr{i}

    Upper bound on failure probability

    Lower bound on success probability

    8/30/2010 65EE5712 Power System Reliability

  • Tie-Set

    A set of components whose function causes system success

    1

    2

    5

    3

    4

    Example (1,3), (1,3,4), (1,3,5), (1,4,5), (2,4) , (2,3,4) , (1,2,3,4,5) ,

    8/30/2010 66EE5712 Power System Reliability

  • Minimal Tie-Set

    A smallest set of components whose function causes system success

    1

    2

    5

    3

    4

    Minimal tie-set = { (1,3), (2,4), (1,4,5) , (2,3,5) }

    8/30/2010 67EE5712 Power System Reliability

  • Tie-Set Method

    Enumerate all minimal tie-set in the system. Success of all components in a minimal tie-set

    causes system success. This implies series connections among these

    components. Each minimal tie set causes system success. This implies parallel connections among the

    minimal tie sets. Draw equivalent system and use series/parallel

    method to compute for system availability.

    8/30/2010 68EE5712 Power System Reliability

  • Example

    1

    2

    5

    3

    4

    Minimal tie-set = { (1,3), (2,4), (1,4,5) , (2,3,5) }

    1

    2

    3

    4

    1 54

    2 538/30/2010 69EE5712 Power System Reliability

  • System Availability Calculation

    If the system has T1, , Tn minimal tie-sets, system success probability is found from

    Ps = Pr{T1 U T2 U U Tn},

    T is an event that the tie-set is success

    These minimal tie sets are not disjoint,

    Ps = Pr{T1 U T2 U U Tn}

    = i Pr{Ti} - ij Pr{Ti Tj- + ijk Pr{Ti Tj Tk}

    - + (-1) Pr,T1 Tn} 1

    8/30/2010 70EE5712 Power System Reliability

  • Probability Approximation

    Total number of terms in previous equation is 2-1.

    Use Booles inequality,

    Ps = Pr{T1 U T2 U U Tn- i Pr{Ti}

    Upper bound on success probability

    Lower bound on failure probability

    8/30/2010 71EE5712 Power System Reliability

  • Bounds on Probability Approximation

    Cut-set Method

    Compute for failure probability

    Upper bound on failure probability

    Lower bound on success probability

    Tie-set Method

    Compute for success probability

    Upper bound on success probability

    Lower bound on failure probability

    8/30/2010 72EE5712 Power System Reliability

  • Limitations

    1

    2

    5

    3

    4

    Series or Parallel??

    2

    8

    5

    3

    9

    1

    7

    4

    10

    6

    8/30/2010 73EE5712 Power System Reliability

  • INTRODUCTION TO MATLABExample of hazard function construction

    8/30/2010 EE5712 Power System Reliability 74

  • Goal

    To review logical concepts of programming

    To familiarize yourself with MATLAB environment

    Feel free to work with program language of your choice!-same logic still applies

    8/30/2010 EE5712 Power System Reliability 75

  • Simple MATLAB Command

    Initialize a vector, matrix

    Manipulate a vector, matrix

    Program control statement

    Resources

    http://www.mathworks.com/access/helpdesk/help/techdoc/learn_matlab/bqr_2pl.html

    8/30/2010 EE5712 Power System Reliability 76

  • Summary

    Reliability theory Failure distribution Survival function Hazard rate function

    Reliability Measure Simple reliability analysis

    Probability convolution method Series/parallel system Conditional probability approach Cut-set/Tie-set method

    Input: failure probability of each component Output: failure probability of a system

    8/30/2010 77EE5712 Power System Reliability

  • About Next Lecture

    Interest to know how often the system fails

    Frequency of failure is another reliability measure.

    Need to study stochastic process

    Model stochastic behavior of a system

    Transition rate from one state to others

    From success to failure state called Failure rate

    From failure to success state called Repair rate

    8/30/2010 78EE5712 Power System Reliability