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6/17/2015 1 ET 332a Dc Motors, Generators and Energy Conversion Devices 1 Lesson 17 332a.pptx Learning Objectives Identify common connections of dc motors Explain how to connected various dc motors to reverse their rotation. Identify the circuit model of a series dc motor and use model equations to solve problems 2 Lesson 17 332a.pptx

Lesson 17 332a · 2015-06-17 · Lesson 17 332a.pptx 10 Example 17-1: A 440 V series motor draws a current of 100 A at a speed of 1000 rpm The total armature circuit resistance is

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Page 1: Lesson 17 332a · 2015-06-17 · Lesson 17 332a.pptx 10 Example 17-1: A 440 V series motor draws a current of 100 A at a speed of 1000 rpm The total armature circuit resistance is

6/17/2015

1

ET 332a

Dc Motors, Generators and Energy Conversion Devices

1Lesson 17 332a.pptx

Learning Objectives

� Identify common connections of dc motors� Explain how to connected various dc motors to reverse

their rotation.� Identify the circuit model of a series dc motor and use

model equations to solve problems

2Lesson 17 332a.pptx

Page 2: Lesson 17 332a · 2015-06-17 · Lesson 17 332a.pptx 10 Example 17-1: A 440 V series motor draws a current of 100 A at a speed of 1000 rpm The total armature circuit resistance is

6/17/2015

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Other Dc Motor Connections

Lesson 17 332a.pptx 3

Series dc motor- field excitation comes from armature current.

VT

RfRa

Eaload

+

Series field

Field current equalsarmature current

Armature

Field winding constructed of few turns of large diameter wire

Lesson 17 332a.pptx 4

Other Dc Motor Connections

Compound motor - series and shunt windings in the same machine combine to make the field flux.

load

VTRfRa

Ea

+Rs

Series field

Armature

Shuntfield

Type of compound motors

Commulatively compounded motors - series and shuntmmfs add to the flux produced in the field

Differentially compounded motors - series and shuntmmfs subtract - unstable connection.

Page 3: Lesson 17 332a · 2015-06-17 · Lesson 17 332a.pptx 10 Example 17-1: A 440 V series motor draws a current of 100 A at a speed of 1000 rpm The total armature circuit resistance is

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Reversing Dc Motors

Lesson 17 332a.pptx 5

Reverse the polarity of either the armature or the field connections. Changes the direction of armature/field flux which reverses the direction of the developed torque.

Reversing direction of Series or Compound motor

General theory - shunt and separately excited motors

Same as other types- take care to avoid creating differentially compounded motor. series and shunt fields must change polarity together.

In series motor must only change the polarity of the field or armature. Reversing terminal voltage will reverse both field and armature polarity

Reversing Connections for Series and

Compound Dc Motors

Lesson 17 332a.pptx 6

Series Motors

Reverse connection

VT

Series field++

Forward connection

+

VT

+Ia flowsinto negativeterminal

Page 4: Lesson 17 332a · 2015-06-17 · Lesson 17 332a.pptx 10 Example 17-1: A 440 V series motor draws a current of 100 A at a speed of 1000 rpm The total armature circuit resistance is

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Lesson 17 332a.pptx 7

Reversing Connections for Series and Compound Dc Motors

Compound Motors

Reverse connection

Series field

Shuntfield

+

+

Forward connection

Shuntfield

+

+

Series Dc Motor Model and Equations

Lesson 17 332a.pptx 8

Racir

Rs

VT

Ia

Circuit Model Linear operation equations –assumes nomagnetic saturation.

General Equations

afTD

pGa

IIkT

nkE

⋅⋅=

Φ⋅⋅=

aciraTa

pG

aciraT

RIVE

k

RIVn

⋅−=

Φ⋅

⋅−=

In series motor, Ia = If so above equations become

2

aTD

pGa

IkT

nkE

⋅=

Φ⋅⋅=

)RR(IVE

k

)RR(IVn

saciraTa

pG

saciraT

+⋅−=

Φ⋅

+⋅−=Torque

proportional to Ia squared

Include series field R

Page 5: Lesson 17 332a · 2015-06-17 · Lesson 17 332a.pptx 10 Example 17-1: A 440 V series motor draws a current of 100 A at a speed of 1000 rpm The total armature circuit resistance is

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Lesson 17 332a.pptx 9

Series Dc Motor Model and Equations

Torque and speed characteristics of series motor

2

aTD IkT ⋅=

pG

saciraT

k

)RR(IVn

Φ⋅

+⋅−=

For linear operation, Φp proportional to Ia

As load torque decreases developed torque decreases causing Ia to decrease This decreases field flux. Motor speed, n, increases with decreasing field flux.

TD ΦpIa

n

Series motors must operate with direct coupled mechanical loads to prevent centrifugal damage due to high speeds.

Series Dc Motor Example-Speed and Torque

Calculations

Lesson 17 332a.pptx 10

Example 17-1: A 440 V series motor draws a current of 100 A at a speed of 1000 rpm The total armature circuit resistance is 0.11 ohms and the field resistance is 0.09 ohms. Assuming a linear magnetizing, curve calculate the speed and the torque when the current drops to 50 A.

Page 6: Lesson 17 332a · 2015-06-17 · Lesson 17 332a.pptx 10 Example 17-1: A 440 V series motor draws a current of 100 A at a speed of 1000 rpm The total armature circuit resistance is

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Example 17-1 Solution (1)

Lesson 17 332a.pptx 11

Information from problem statement

Racir = 0.11 ohms

Rs = 0.09 ohms

VT= 440 V

Ia = 100 A

n1 =1000 rpm

Lesson 17 332a.pptx 12

Example 17-1 Solution (2)

Find the motor speed at reduced armature current

Answer

Page 7: Lesson 17 332a · 2015-06-17 · Lesson 17 332a.pptx 10 Example 17-1: A 440 V series motor draws a current of 100 A at a speed of 1000 rpm The total armature circuit resistance is

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Lesson 17 332a.pptx 13

Example 17-1 Solution (3)

Torque is proportional to Ia2

Find TD1, initial developed torque

Answer

As load torque decreases developed torque decreases causing speed increase

ET 332a

Dc Motors, Generators and Energy Conversion Devices

Lesson 17 332a.pptx 14