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Linear Thinking: Solving First Degree Equations. Laura Farnam. First Degree Equations. Techniques developed wherever math was studied Rhind Papyrus A quantity; its half and its third are added to it. It becomes 10. x + (1/2)x + (1/3)x = 10 False Position Double False Position. - PowerPoint PPT Presentation
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Laura Farnam
Linear Thinking:Solving First Degree
Equations
First Degree EquationsTechniques developed
wherever math was studied
Rhind PapyrusA quantity; its half and
its third are added to it. It becomes 10.
x + (1/2)x + (1/3)x = 10
False PositionDouble False Position
False PositionGuessing methodExpect wrong
answerMake computations
easy
Example 1: A quantity; its fourth is added to it. It becomes 15.
False Position
Example 1: A quantity; its fourth is added to it. It becomes 15.x + (1/4)x = 154 + (1/4)(4) = 4+1 = 515/5 = 34 x 3 = 12
False Position
Example 2: A quantity; its third and its fifth are added to it. It becomes 46.
False Position
Example 2: A quantity; its third and its fifth are added to it. It becomes 46.x + (1/3)x + (1/5)x = 4615 + 5 + 3 = 2346/23 = 215 x 2 = 30
False Position
False Position
Why Does it Work?Ax = BMultiply x by a factorA(kx) = k(Ax) = kB
Double False PositionUsed in textbooks
until 19th centuryDaboll’s
Schoolmaster’s Assistant (early 1800s)
Guessing method
Example 3:A purse of 100 dollars is to be divided among four men A, B, C, and D, so that B may have four dollars more than A, and C eight dollars more than B, and D twice as many as C; what is each one’s share of the money?
Double False Position
StepsGuessFind errorRepeatCross-multiply guesses and errorsTake the difference (if similar) or the sum (if
different)Divide by the difference/sum of the errors
Double False Position
Double False Position
y = mx +bPlot the line using
two points“Rise over Run”
100 – 70 = 100 – 80 x – 6 x - 8
False Position (Ax = B)Double False Position (Ax + C = B)Linear
A constant ratio“the change in the output is proportional to the
change in the input”
Conclusion