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Linear Wire Antennas – Continued EE-4382/5306 - Antenna Engineering

Linear Wire Antennas Continued - EMPossible

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Page 1: Linear Wire Antennas Continued - EMPossible

Linear Wire Antennas –Continued

EE-4382/5306 - Antenna Engineering

Page 2: Linear Wire Antennas Continued - EMPossible

Perfect Ground Effects

2

Page 3: Linear Wire Antennas Continued - EMPossible

Boundary Conditions

Linear Wire Antennas

Page 4: Linear Wire Antennas Continued - EMPossible

Boundary Conditions on PEC

Linear Wire Antennas

Page 5: Linear Wire Antennas Continued - EMPossible

Image Theory

Slide 5

Virtual sources (images) are introduced to account for reflections. They also need to satisfy boundary conditions. We will assume infinitesimal dipoles for infinite ground plane.

Linear Wire Antennas

Page 6: Linear Wire Antennas Continued - EMPossible

Image Theory – Vertical Dipole

Introduction to Antennas Slide 6

Page 7: Linear Wire Antennas Continued - EMPossible

Slide 7Linear Wire Antennas

Image Theory – Vertical DipoleFor electric field direct component (radiated),

𝐸𝜃𝑑 = 𝑗𝜂

𝑘𝐼0𝑙𝑒−𝑗𝑘𝑟1

4𝜋𝑟1sin 𝜃1

For electric field reflected component,

𝐸𝜃𝑟 = 𝑗𝑅𝑣𝜂

𝑘𝐼0𝑙𝑒−𝑗𝑘𝑟2

4𝜋𝑟2sin(𝜃2)

𝑅𝑣 is reflection coefficient. For PEC, 𝑅𝑣 = 1

𝐸𝜃𝑟 = 𝑗𝜂

𝑘𝐼0𝑙𝑒−𝑗𝑘𝑟2

4𝜋𝑟2sin 𝜃2

𝐸𝜃𝑡 = 𝐸𝜃

𝑑 + 𝐸𝜃𝑟

Page 8: Linear Wire Antennas Continued - EMPossible

Image Theory – Vertical Dipole

Introduction to Antennas Slide 8

Page 9: Linear Wire Antennas Continued - EMPossible

Image Theory – Vertical Dipole

Introduction to Antennas Slide 9

In general, assuming the antenna lies at the origin, we can write that

𝑟1 = 𝑟2 + ℎ2 − 2𝑟ℎ cos 𝜃12

𝑟2 = 𝑟2 + ℎ2 − 2𝑟ℎ cos 𝜋 − 𝜃12

For components in the far-field (𝑟 ≫ ℎ)𝑟1 ≅ 𝑟 − ℎ𝑐𝑜𝑠 𝜃𝑟2 ≅ 𝑟 + ℎ𝑐𝑜𝑠 𝜃

𝑟1 ≅ 𝑟2 ≅ 𝑟Thus we obtain

𝐸𝜃 = 𝑗𝜂𝑘𝐼0𝑙𝑒

−𝑗𝑘𝑟

4𝜋𝑟sin 𝜃 [2 cos 𝑘ℎ cos 𝜃 ]

And the scalloping (number of total lobes) is

number of lobes ≅2ℎ

𝜆+ 1 (for ℎ ≫ 𝜆)

Element Factor Array Factor

Page 10: Linear Wire Antennas Continued - EMPossible

Image Theory – Vertical Dipole

Introduction to Antennas Slide 10

The normalized power pattern is equal to

𝑈 = 𝑟21

2𝜂𝐸𝜃

2 =𝜂

2

𝐼0𝑙

𝜆

2

sin2 𝜃 cos2(𝑘ℎ cos 𝜃)

Page 11: Linear Wire Antennas Continued - EMPossible

Introduction to Antennas Slide 11

Vertical Dipole Above Ground

Page 12: Linear Wire Antennas Continued - EMPossible

Introduction to Antennas Slide 12

Vertical Dipole Above Ground

Page 13: Linear Wire Antennas Continued - EMPossible

Introduction to Antennas Slide 13

Vertical Dipole Above Ground

Page 14: Linear Wire Antennas Continued - EMPossible

Ground Effects - Example

Introduction to Antennas Slide 14

An infinitesimal dipole of length 𝑙 is placed a distance 𝑠 from an air-conductor interface and at an angle of 𝜃 = 60° from the vertical axis, as shown in the figure. Sketch the location and direction of the image source which can be used to account for reflections. Be very clear when indicating the location and direction of the image.

𝜎 = ∞𝜖0, 𝜇0

𝑠

60°

+∞

Page 15: Linear Wire Antennas Continued - EMPossible

Ground Effects - Example

Introduction to Antennas Slide 15

An infinitesimal vertical dipole of length 𝑙 is mounted on a pole at a height ℎabove the ground, which is assumed to be flat, perfectly conducting, and of infinite extent. The dipole transmits in the VHF band (𝑓 = 50 MHz) for ground-to-air communications. In order for the transmitting antenna to not interfere with a nearby radio station, it is necessary to place a null in the dipole pattern at an angle 80° from the vertical. What should the shortest height in meters be of the pole to achieve the desired null?