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Logics for Data and Knowledge Representation. Exercises: Description Logics. Fausto Giunchiglia, Rui Zhang and Vincenzo Maltese. Normalization of a TBox. Normalize the TBox below: MonkeyLow ⊑ GetBanana GetBanana ≡ Survive Possible solution: MonkeyLow ≡ GetBanana ⊓ ClimbBox - PowerPoint PPT Presentation
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Logics for Data and KnowledgeRepresentation
Exercises: Description Logics
Fausto Giunchiglia, Rui Zhang and Vincenzo Maltese
Normalization of a TBox Normalize the TBox below:
MonkeyLow ⊑ GetBananaGetBanana ≡ Survive
Possible solution:MonkeyLow ≡ GetBanana ⊓ ClimbBoxGetBanana ≡ Survive
Note that, with this theory, the monkey necessarily needs to get the banana to survive.
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
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Expansion of a TBox Expand the TBox below:
MonkeyLow ≡ GetBanana ⊓ ClimbBoxGetBanana ≡ Survive
T’, expansion of T (The Venn diagram gives a possible model):MonkeyLow ≡ Survive ⊓ ClimbBoxGetBanana ≡ Survive
SurviveGetBanana MonkeyLow
ClimbBoxNotice that the fact that a monkey climbs the box does not necessarily mean that it survives.
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TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Satisfiability with respect to a TBox T (I)
RECALL:
A concept P is satisfiable w.r.t. a terminology T, if there exists an interpretation I with I ⊨ θ for all θ ∈ T, and such that I ⊨ P, namely I(P) is not empty
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TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Satisfiability with respect to a TBox T (II) Suppose we model the Monkey-Banana problem as follows:
“If the monkey is low in position then it cannot get the banana. If the monkey gets the banana it survives”.
TBox TMonkeyLow ⊑ GetBananaGetBanana ⊑ Survive
Is T satisfiable?
Survive
GetBanana MonkeyLow
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YES! Look at the Venn diagram
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Satisfiability with respect to a TBox T (III) Suppose we model the Monkey-Banana problem as follows:
TBox TMonkeyLow ⊑ GetBananaGetBanana ⊑ Survive
Is it possible for a monkey to survive even if it does not get the banana?
We can restate the problem as follow: does T ⊨ GetBanana Survive⊓ ?
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Survive
GetBanana MonkeyLow
YES! Look at the Venn diagram
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Translate the following statements in DL (I) All users can download files
User ⊑ ∃Download.File
A read access user can read files only ReadAccesUser ⊑ ∀Read.File
Those who can write can also read Write ⊑ Read
A limited user can download no more than 3 files LimitedUser ⊑ ≤3 Download.File
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Translate the following statements in DL (I) Programmers write programs
Programmer ⊑ ∃Write.Programs
Producers can produce music and song files onlyMusic ⊑ FileSong ⊑ File
Producer ⊑ ∀Produce.(Music ⊔ Song)
A program can be downloaded by developers only Program ⊑ ∀Download-1.Developer
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Define a TBox and ABox for the following problem Diana wants to give read access to her friends to the files on
her PC, and write access to her best friend Gloria only. Bill is just a friend.
Friend ⊑ ∃Read.FileBestFriend ⊑ ∃Write.File ⊓ Friend
BestFriend(Gloria)Friend(Bill)
Can Gloria read Diana’s files? YesBestFriend(Gloria) Friend(Gloria) ∃Read.File(Gloria)
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Define a TBox and ABox for the following problem In a library, employees have access to books. However, a
loaned book is a non precious book and can be read by clients. Mary is a client and reads a book titled “Top stories”.
Employee ⊑ ∃Access.BookLoanedBook ⊑ Book ⊓ Precious ⊓ ∀Read-1.Client
Client(Mary) Book(TopStories)
Read(Mary,TopStories)
Is it possible for the book to be precious? YesWe can verify that Precious(TopStories) is consistent with the ABox and TBox above.
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Defining the TBox and ABox: the LDKR Class
Name Nationality HairFausto Italian White
Enzo Italian Black
Rui Chinese Black
Bisu Indian Black
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ABox ={Italian(Fausto), Italian(Enzo), Chinese(Rui), Indian(Bisu), BlackHair(Enzo), BlackHair(Rui), BlackHair(Bisu),WhiteHair(Fausto)}
TBox ={Italian ⊑ LDKR, Indian ⊑ LDKR,Chinese ⊑ LDKR, BlackHair ⊑ LDKR,WhiteHair ⊑ LDKR}
Define a TBox and ABox for the following database:
LDKR
NOTE: ClassL is not expressive enough to represent database constrains such as keys involving two fields.
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Formalization of a semantic network
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instance-of
instance-of
Person Drives.Car⊑ ∃Person HasHobby.SportCar⊑ ∃Person HasHobby.Opera⊑ ∃Student Person⊑SportCar ⊑ CarStudent(Ralf)Opera(DonCarlos)
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Venn diagrams Provide the Venn diagram for: A ⊑ B ⊓ ¬C
as a way to prove the satisfiability
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B
A
C
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
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TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
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TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
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TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
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TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Using DPLL for reasoning tasks DPLL solves the CNFSAT-problem by searching a truth-assignment that
satisfies all clauses θi in the input proposition P = θ1 … θn DL sentences must to be translated in PL (via TBox and ABox
elimination)
Model checking Does ν satisfy P? (ν P?⊨ )Check if ν(P) = true
Satisfiability Is there any ν such that ν P?⊨Check that DPLL(P) succeeds and returns a ν
Unsatisfiability Is it true that there are no ν satisfying P?Check that DPLL(P) fails
Validity Is P a tautology? (true for all ν)Check that DPLL(P) fails
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TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Reduce to PL reasoning Consider the TBox T = {A B ⊑ ⊔ C, C D ⊑ ⊓ E}.
Determine if A E by elimination of T. ⊑
T’ = {A ≡ (B ⊔ C) ⊓ X, C ≡ D ⊓ E ⊓ Y}
A’ = (B ⊔ (D ⊓ E ⊓ Y)) ⊓ XE’ = E
A’ = (B (D E Y)) XE’ = E
Call DPLL((B (D E Y)) X → E)(Note that the formula has to be converted in CNF first)
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The steps:T’ = Normalize(T); C’ = Expand(C, T’);D’ = Expand(D, T’);C’ =
RewriteInPL(C’);D’ =
RewriteInPL(D’);return DPLL(C’ →
D’);
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Satisfiability of a TBox (a set of formulas) Say if the following TBox is satisfiable and provide a class
valuation in the case: FederalAgent Access.TopSecretDocument⊑ ∃ XFile TopSecretDocument ⊑ ⊓ Restricted Read⊓ ∀ -1.Policeman
I(FederalAgent) = {A} We have that I ⊨ TI(TopSecretDocument) = {D1, D2}I(Access) = {(A, D1), (A, D2)}I(XFile) = {D1}I(Restricted) = {D2}I(Read) = {(B, D1)}I(Policeman) = {B}
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TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Satisfiability w.r.t. a TBox Consider the TBox T:
FederalAgent Access.TopSecretDocument⊑ ∃ XFile TopSecretDocument ⊑ ⊓ Restricted Read⊓ ∀ -1.Policeman and the formula P: TopSecretDocument Restricted⊓ does T P ?⊨ Yes, if fact these is an interpretation I (e.g. the one of the previous
exercise) such that I T and I P. ⊨ ⊨I(TopSecretDocument) = {D1, D2}I(Restricted) = {D1} Notice that T does not affect P at all (i.e. we cannot further
expand P w.r.t. T)
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TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Subsumption Consider the TBox T:
FederalAgent Access.TopSecretDocument⊑ ∃ XFile TopSecretDocument ⊑ ⊓ Restricted Read⊓ ∀ -1.Policeman does T ⊨ TopSecretDocument Restricted⊑ ?
By definition, it must be I(TopSecretDocument ) I(Restricted ) for every model I of T. Even if this is true for the I of the previous exercise, this is not true in general. It is enough to provide a counterexample:
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I(FederalAgent) = {A}I(TopSecretDocument) = {D2}I(Access) = {(A, D1), (A, D2)}
I(XFile) = {D2}I(Restricted) = {D1}I(Read) = {(B, D2)}I(Policeman) = {B}
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Satisfiability of a TBox using tableaux Say if the following TBox is satisfiable using the tableaux: FederalAgent Access.TopSecretDocument⊑ ∃ XFile TopSecretDocument ⊑ ⊓ Restricted Read⊓ ∀ -1.Policeman
Translate into a formula:( FederalAgent ⊔ Access.TopSecretDocument) ∃ ⊓( XFile ⊔ (TopSecretDocument ⊓ Restricted Read⊓ ∀ -1.Policeman))
Apply the tableaux rules:(1) FederalAgent(x) or Access.TopSecretDocument(x)∃and(2) Xfile(x) or {TopSecretDocument(x), Restricted(x), Read∀ 1.Policeman(x)}
…
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TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
Expansion of an ABox Provide the expansion of A w.r.t. T (without normalization),
where:
TBox T = {Student Faculty, Professor Faculty Teach} ⊑ ⊑ ⊓ ABox A = {Professor(Bob), Faculty(Rui)}
Professor(Bob), Faculty(Bob), Teach(Bob)Faculty(Rui)
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TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
ABox Consistency An ABox A is consistent with respect to a TBox T if there is an
interpretation I which is a model of both A and T.
T = {Parent⊑≤1hasChild}A = {hasChild(mary, bob), hasChild(mary, cate), Parent(mary)}
A is consistent ALONE but is not consistent with respect T.In fact, from A mary has two children while T imposes maximum one
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TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
ABox: Instance checking (I)Given the TBox and ABox below T:
Female⊑Human Male⊑Human Mother⊑Female Father⊑Male Child≡∃has.Mother⊓ ∃has.Father Male⊓Female⊑⊥
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Prove:1. Human(Anna)2. ¬Female(Bob)3. Child(Cate)
A: Mother(Anna) Father(Bob) has(Cate,Anna) has(Cate,Bob)
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
ABox: Instance checking (II)
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Expand A w.r.t. T:
A: Mother(Anna) Female(Anna) Human(Anna) Father(Bob) Male(Bob) Human(Bob) , ¬Female(Bob) has(Cate,Anna) , has(Cate,Bob) Child(Cate)
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING
ABox: Instance checking (III)
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Given the ABox A = {R(a,b), R(a, c), A(b)} is a an instance of ∃R.A?
Take R.A(a). Given its semantics, there should be {R(a, x), A(x)} ∃ A for some x.
If we take x = b we see that this actually holds.
TBOX :: MODELING IN DL :: PROOFS :: TBOX REASONING :: ABOX REASONING