METODE FOSM PROBLEM : Hitung β index, SF, dengan Performance Function sebagai berikut: G fs d , Q , tw , ( ) fs tw ⋅ d ⋅ Q 2 - := μ tw 5.5 := μ fs 95 := Ω fs 0.105263 := μ d 423 := Ω d 0.01182033 := μ Q 200000 := Ω Q 0.2666666666666 := SOLUTION : tw μ tw := fs μ fs := σ fs Ω fs μ fs ⋅ 10 = := d μ d := σ d Ω d μ d ⋅ 5 = := Q μ Q := σ Q Ω Q μ Q ⋅ 5.333 10 4 × = := A fs G fs d , Q , tw , ( ) d d 2326.5 → := B Q G fs d , Q , tw , ( ) d d 1 2 - → := σ G A 2 σ fs ( ) 2 ⋅ B 2 σ Q ( ) 2 ⋅ + 3.539 10 4 × = := μ G μ fs μ tw ⋅ μ d ⋅ μ Q 2 - 1.21 10 5 × = := β μ G σ G 3.42 = := SF fs tw ⋅ d ⋅ Q 2 2.21 = := Probability of Safe (pS) & Probability of Failure (pF) fx () e 0.5 - x 2 ⋅ ( ) 2 π ⋅ := p S 10 - β x fx () ⌠ ⌡ d := p F 1 p S - := p S 99.9686 % ⋅ = p F 0.0314 % ⋅ =
