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MATHEMATICAL METHODS (CAS) Written examination 1 Wednesday 4 November 2015 Reading time: 9.00 am to 9.15 am (15 minutes) Writing time: 9.15 am to 10.15 am (1 hour) QUESTION AND ANSWER BOOK Structure of book Number of questions Number of questions to be answered Number of marks 10 10 40 Students are permitted to bring into the examination room: pens, pencils, highlighters, erasers, sharpeners, rulers. Students are NOT permitted to bring into the examination room: notes of any kind, blank sheets of paper, correction fluid/tape or a calculator of any type. Materials supplied Question and answer book of 16 pages, with a detachable sheet of miscellaneous formulas in the centrefold. Working space is provided throughout the book. Instructions Detach the formula sheet from the centre of this book during reading time. Write your student number in the space provided above on this page. All written responses must be in English. Students are NOT permitted to bring mobile phones and/or any other unauthorised electronic devices into the examination room. © VICTORIAN CURRICULUM AND ASSESSMENT AUTHORITY 2015 SUPERVISOR TO ATTACH PROCESSING LABEL HERE Victorian Certificate of Education 2015 STUDENT NUMBER Letter

MATHEMATICAL METHODS (CAS)2015 MATHMETH (CAS) EXAM 1 12 Question 9 – continued Question 9 (4 marks) An egg marketing company buys its eggs from farm A and farm B. Let p be the proportion

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MATHEMATICAL METHODS (CAS)Written examination 1

Wednesday 4 November 2015 Reading time: 9.00 am to 9.15 am (15 minutes) Writing time: 9.15 am to 10.15 am (1 hour)

QUESTION AND ANSWER BOOK

Structure of bookNumber of questions

Number of questions to be answered

Number of marks

10 10 40

• Studentsarepermittedtobringintotheexaminationroom:pens,pencils,highlighters,erasers,sharpeners,rulers.

• StudentsareNOTpermittedtobringintotheexaminationroom:notesofanykind,blanksheetsofpaper,correctionfluid/tapeoracalculatorofanytype.

Materials supplied• Questionandanswerbookof16pages,withadetachablesheetofmiscellaneousformulasinthe

centrefold.• Workingspaceisprovidedthroughoutthebook.

Instructions• Detachtheformulasheetfromthecentreofthisbookduringreadingtime.• Writeyourstudent numberinthespaceprovidedaboveonthispage.

• AllwrittenresponsesmustbeinEnglish.

Students are NOT permitted to bring mobile phones and/or any other unauthorised electronic devices into the examination room.

©VICTORIANCURRICULUMANDASSESSMENTAUTHORITY2015

SUPERVISOR TO ATTACH PROCESSING LABEL HEREVictorian Certificate of Education 2015

STUDENT NUMBER

Letter

2015MATHMETH(CAS)EXAM1 2

THIS PAGE IS BLANK

3 2015MATHMETH(CAS)EXAM1

TURN OVER

Question 1 (4marks)a. Lety=(5x+1)7.

Find dydx. 1mark

b. Let f x xxe( ) log ( ) .= 2

i. Findf ′ (x). 2marks

ii. Evaluatef ′ (1). 1mark

InstructionsAnswerallquestionsinthespacesprovided.Inallquestionswhereanumericalanswerisrequired,anexactvaluemustbegivenunlessotherwisespecified.Inquestionswheremorethanonemarkisavailable,appropriateworkingmustbeshown.Unlessotherwiseindicated,thediagramsinthisbookarenotdrawntoscale.

2015MATHMETH(CAS)EXAM1 4

Question 2 (3marks)

Let ′ = −f xx

( ) ,1 3 wherex≠0.

Giventhatf (e)=–2,find f (x).

5 2015MATHMETH(CAS)EXAM1

TURN OVER

Question 3 (2marks)

Evaluate 11

4

xdx

∫ .

2015MATHMETH(CAS)EXAM1 6

Question 4–continued

Question 4 (6marks)Considerthefunction f R f x x x: , , ( ) .−[ ]→ = + −( )3 2 1

23 43 2

a. Findthecoordinatesofthestationarypointsofthefunction. 2marks

7 2015MATHMETH(CAS)EXAM1

TURN OVER

Theruleforfcanalsobeexpressedas f x x x( ) .= −( ) +( )12

1 2 2

b. Ontheaxesbelow,sketchthegraphoff, clearlyindicatingaxisinterceptsandturningpoints. Labeltheendpointswiththeircoordinates. 2marks

y

x–8 –7 –6 –5 –4 –3 –2 –1 1 2 3 4 5 6 7 8

–8–7–6–5–4–3–2–1

1

O

2345678

c. Findtheaveragevalueoffovertheinterval0≤x≤2. 2marks

2015 MATHMETH (CAS) EXAM 1 8

Question 5 (3 marks)On any given day, the depth of water in a river is modelled by the function

h t t t( ) sin ,= +

≤ ≤14 8

120 24π

where h is the depth of water, in metres, and t is the time, in hours, after 6 am.

a. Find the minimum depth of the water in the river. 1 mark

b. Find the values of t for which h(t) = 10. 2 marks

9 2015MATHMETH(CAS)EXAM1

TURN OVER

Question 6 (3marks)LettherandomvariableXbenormallydistributedwithmean2.5andstandarddeviation0.3LetZbethestandardnormalrandomvariable,suchthatZ~N(0,1).

a. FindbsuchthatPr(X>3.1)=Pr(Z<b). 1mark

b. Usingthefactthat,correcttotwodecimalplaces,Pr(Z<–1)=0.16,findPr(X<2.8|X>2.5). Writetheanswercorrecttotwodecimalplaces. 2marks

2015MATHMETH(CAS)EXAM1 10

Question 7 (5marks)a. Solvelog2(6–x)–log2(4–x)=2forx,wherex<4. 2marks

b. Solve3et=5+8e–tfort. 3marks

11 2015MATHMETH(CAS)EXAM1

TURN OVER

Question 8 (3marks)

ForeventsA and B fromasamplespace,Pr( )A B =34 andPr( ) .B =

13

a. CalculatePr(A ∩B). 1mark

b. CalculatePr(A′ ∩B),whereA′denotesthecomplementofA. 1mark

c. IfeventsAandB areindependent,calculatePr(A∪B). 1mark

2015MATHMETH(CAS)EXAM1 12

Question 9–continued

Question 9 (4marks)AneggmarketingcompanybuysitseggsfromfarmAandfarmB.Letpbetheproportionofeggsthatthecompanybuysfromfarm A.Therestofthecompany’seggscomefromfarmB.Eachday,theeggsfrombothfarmsaretakentothecompany’swarehouse.

Assumethat35 ofalleggsfromfarmAhavewhiteeggshellsand

15 ofalleggsfromfarmBhave

whiteeggshells.

a. Aneggisselectedatrandomfromthesetofalleggsatthewarehouse.

Find,intermsofp,theprobabilitythattheegghasawhiteeggshell. 1mark

13 2015MATHMETH(CAS)EXAM1

TURN OVER

b. Anothereggisselectedatrandomfromthesetofalleggsatthewarehouse.

i. Giventhattheegghasawhiteeggshell,find,intermsofp,theprobabilitythatitcamefromfarmB. 2marks

ii. IftheprobabilitythatthiseggcamefromfarmB is0.3,findthevalueofp. 1mark

2015MATHMETH(CAS)EXAM1 14

Question 10–continued

Question 10(7marks)Thediagrambelowshowsapoint,T,onacircle.Thecirclehasradius2andcentreatthepointC

withcoordinates(2,0).TheangleECTisθ,where 02

< ≤θπ .

x

Y

B (2, b)

T

D (4, d)

y

E (4, 0)C (2, 0)O Xθ

ThediagramalsoshowsthetangenttothecircleatT.ThistangentisperpendiculartoCTandintersectsthex-axisatpointXandthey-axisatpointY.

a. FindthecoordinatesofTintermsofθ. 1mark

b. FindthegradientofthetangenttothecircleatTintermsofθ. 1mark

15 2015MATHMETH(CAS)EXAM1

Question 10–continuedTURN OVER

c. TheequationofthetangenttothecircleatTcanbeexpressedas

cos(θ)x+sin(θ)y=2+2cos(θ)

i. PointB,withcoordinates(2,b),isonthelinesegmentXY.

Findbintermsofθ. 1mark

ii. Point D,withcoordinates(4,d),isonthelinesegmentXY.

Finddintermsofθ. 1mark

2015MATHMETH(CAS)EXAM1 16

END OF QUESTION AND ANSWER BOOK

d. ConsiderthetrapeziumCEDBwithparallelsidesoflengthbandd.

FindthevalueofθforwhichtheareaofthetrapeziumCEDB isaminimum.Alsofindtheminimumvalueofthearea. 3marks

MATHEMATICAL METHODS (CAS)

Written examinations 1 and 2

FORMULA SHEET

Instructions

Detach this formula sheet during reading time.

This formula sheet is provided for your reference.

© VICTORIAN CURRICULUM AND ASSESSMENT AUTHORITY 2015

MATHMETH (CAS) 2

THIS PAGE IS BLANK

3 MATHMETH (CAS)

END OF FORMULA SHEET

Mathematical Methods (CAS)Formulas

Mensuration

area of a trapezium: 12a b h+( ) volume of a pyramid:

13Ah

curved surface area of a cylinder: 2π  rh volume of a sphere: 43

3π r

volume of a cylinder: πr 2h area of a triangle: 12bc Asin

volume of a cone: 13

2π r h

Calculusddx

x nxn n( ) = −1

x dx

nx c nn n=

++ ≠ −+∫ 1

111 ,

ddxe aeax ax( ) =

e dx a e cax ax= +∫ 1

ddx

x xelog ( )( ) = 1 1x dx x ce= +∫ log

ddx

ax a axsin( ) cos( )( ) = sin( ) cos( )ax dx a ax c= − +∫ 1

ddx

ax a axcos( )( ) −= sin( ) cos( ) sin( )ax dx a ax c= +∫ 1

ddx

ax aax

a axtan( )( )

( ) ==cos

sec ( )22

product rule: ddxuv u dv

dxv dudx

( ) = + quotient rule: ddx

uv

v dudx

u dvdx

v

=

2

chain rule: dydx

dydududx

= approximation: f x h f x h f x+( ) ≈ ( ) + ′( )

ProbabilityPr(A) = 1 – Pr(A′) Pr(A ∪ B) = Pr(A) + Pr(B) – Pr(A ∩ B)

Pr(A|B) = Pr

PrA BB∩( )( ) transition matrices: Sn = Tn×S0

mean: µ = E(X) variance: var(X) = σ 2 = E((X – µ)2) = E(X 2) – µ2

Probability distribution Mean Variance

discrete Pr(X = x) = p(x) µ = ∑ x p(x) σ 2 = ∑ (x – µ)2 p(x)

continuous Pr( ) ( )a X b f x dxa

b< < = ∫ µ =

−∞

∫ x f x dx( ) σ µ2 2= −−∞

∫ ( ) ( )x f x dx