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MATHPOWER TM 10, WESTERN EDITION hapter 6 Coordinate Geometry 6.7 6.7.1

MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

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Page 1: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

MATHPOWERTM 10, WESTERN EDITION

Chapter 6 Coordinate Geometry6.7

6.7.1

Page 2: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

Parallel Lines

A(-3, 0)

B(0, 5)

C(0, -5)

D(3, 0)

mAB =5−00−−3

mCD =0−−53−0

mCD =53

mAB =53

If the slopes of two lines areequal, the lines are parallel.

If two lines are parallel, their slopes are equal.

AB is parallel to CD.6.7.2

Page 3: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

Show that the line segment AB with endpoints A(2, 3) and B(6, 5) is parallel to the line segment CD with endpoints C(-1, 4) and D(3, 6).

m=y2 −y1

x2 −x1

mAB =5−36−2

mAB =12

mCD =6−43−−1

mCD =12

Since the slopes are equal, the line segments are parallel.6.7.3

Verifying Parallel Lines

Page 4: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

The following are slopes of parallel lines. Find the value of k.

a) 23,

4k

b) -15

, 2k

c) -k5

, 32 d)

-k3

, -27

23

=4k

2k = 12 k = 6

−15

=2k

-1k = 10 k = -10

−k5

=32

-2k = 15 −k3

=−27

-7k = -6

6.7.4

Using Parallel Slopes to Find k

−152

k = 67

k =

Page 5: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

Perpendicular Lines

A(-2, -2)

B(4, 2)

C(3, -2)

D(-1, 4)mAB =

2−−24−−2

mCD =4−− 2−1−3

mCD =−32

mAB =23

If the slopes of two linesare negative reciprocals, the lines are perpendicular.

If two lines are perpendicular, their slopes are negative reciprocals.

AB is perpendicular to CD.

6.7.5

Page 6: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

Show that the line segment AB with endpoints A(0, 2) and B(-3, -4) is perpendicular to the line segment CDwith endpoints C(2, -4) and D(-8, 1).

m=y2 −y1

x2 −x1

mAB =−4−2−3−0

mAB =2

mCD =1−−4−8−2

mCD =−12

The slopes are equal so line segments are perpendicular.6.7.6

Perpendicular Line Segments

Page 7: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

The following are slopes of perpendicular lines. Find the value of k.

a) 23

, 4k

b) -15

, 2k

c) -k5

, 32

d) -k3

, -27

23

=−k4

-3k = 8 −15

=−k2

-5k = -2

−k5

=−23

-3k = -10 −k3

=72

-2k = 21

6.7.7

Using Perpendicular Slopes to Find k

k = −83

k =25

k =103

k =−212

Page 8: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

Given the following equations of lines, determine which are parallel and which are perpendicular.

A) 3x + 4y - 24 = 0 B) 3x - 4y + 10 = 0

C) 4x + 3y - 16 = 0 D) 6x + 8y + 15 = 0

4y = -3x + 24

y = x + 6

-4y = -3x - 10

y = x + 5/2

3y = -4x + 16 8y = -6x - 15

Lines A and D have the same slope, so they are parallel.Lines B and C have negative reciprocal slopes, so they areperpendicular. 6.7.8

−34

34

y=−43x+

163

y=−34x−

158

Slope = −34

Slope =34

Slope = −43 Slope = −

34

Parallel and Perpendicular Lines

Page 9: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

Find the equation of the line through the point A(-1, 5) and parallel to 3x - 4y + 16 = 0.

Find the slope.

3x - 4y + 16 = 0 -4y = - 3x - 16

4y - 20 = 3(x + 1)4y - 20 = 3x + 30 = 3x - 4y + 23

3x - 4y + 23 = 0

6.7.9

Writing the Equation of a Line

y = x + 434

Slope =34

y - y1 = m(x - x1)

y - 5 = (x - -1)34

Page 10: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

Find the equation of the line through the point A(-1, 5) and perpendicular to 3x - 4y + 16 = 0.

Find the slope.3x - 4y + 16 = 0 -4y = -3x - 16

3y - 15 = -4(x + 1)3y - 15 = -4x - 44x + 3y - 11 = 0

4x + 3y - 11 = 0Therefore, use the slope

6.7.10

Writing the Equation of a Line

Slope =34

y = x + 434

y - y1 = m(x - x1)

y - 5 = (x - -1)−43

−43

.

Page 11: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

Determine the equation of the line parallel to 3x + 6y - 9 = 0and with the same y-intercept as 4x + 4y - 16 = 0.

3x + 6y - 9 = 06y = -3x + 9

4x + 4y - 16 = 0For the y-intercept, x = 0:4(0) + 4y - 16 = 0 4y = 16 y = 4

A point is (0, 4).

2y - 8 = -1xx + 2y - 8 = 0

6.7.11

Writing the Equation of a Line

y=−12x+

32

.The slope is−12

y - y1 = m(x - x1)

y - 4 = (x - 0)−12

.

Page 12: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

Determine the equation of the line that is perpendicular to 3x + 6y - 9 = 0 and has the same x-intercept as 4x + 4y - 16 = 0.

3x + 6y - 9 = 06y = -3x + 9

The slope is 2.

4x + 4y - 16 = 0

For the x-intercept, y = 0:4x + 4(0)- 16 = 0 4x = 16 x = 4

A point is (4, 0).y - y1 = m(x - x1) y - 0 = 2(x - 4) y = 2x - 8 0 = 2x - y - 8 The equation of the

line is 2x - y - 8 = 0.6.7.12

y=−12x+

32

Writing the Equation of a Line

Page 13: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

Determine the equation of each of the following lines.

A) perpendicular to 5x - y - 1 = 0 and passing through (4, -2)

B) perpendicular to 2x - y - 3 = 0 and intersects the y-axis at -2

C) parallel to 2x + 5y + 10 = 0 and same x-intercept as 4x + 8 = 0

D) passing through the point (3, 6) and parallel to the x-axis

x + 2y + 4 = 0

2x + 5y + 4 = 0

x + 5y + 6 = 0

y = 6 or y - 6 = 0 E) passing through the y-intercept of 6x + 5y + 25 = 0 and parallel to 4x - 3y + 9 = 0

4x - 3y - 15 = 0F) passing through the x-intercept of 6x + 5y + 30 = 0 and perpendicular to 4x - 3y + 9 = 0

3x + 4y + 15 = 0 6.7.13

Writing the Equation of a Line

Page 14: MATHPOWER TM 10, WESTERN EDITION Chapter 6 Coordinate Geometry 6.7 6.7.1

Pages 294 and 2951 - 25 odd,27ace, 28 - 42 even,44 - 50 6.7.14

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