%% calculates the response of a two-mass, two-spring system % obtains trajectory using ode45 on DE's in 'de2'%% global m1 m2 k1 k2 % define system parameters m1= 1.; m2= 1.; k1= 10.; k2 = 10.; % system1%m1 = 0.29292; m2 = 0.59376; k1 = 50.445; k2 = 34.026 % system2% define system matrix (Minvk)M = [m1 0; 0 m2];K = [(k1+k2) -k2 ; -k2 k2];MinvK = inv(M)*K;[V,D] = eig(MinvK);Dw1 = sqrt(D(1,1))Tp1=2.*pi/w1w2 = sqrt(D(2,2))Tp2=2.*pi/w2Vtspan1 = [0.:.05:20]; pauseSys = 0.01; % system1%tspan2 = [0.:.01:10]; pauseSys = 0.01; % system2% calculate trajectory % 4 INITIAL CONDITIONS: [x1(0) xldot(0) x2(0) x2dot(0)][ts,ys] = ode45(@de2,tspan1, [0.618 0 1. 0]); %system%[ts,ys] = ode45(@de2,tspan1, [1.618 0 -1. 0]); %system%[ts,ys] = ode45(@de2,tspan1, [1 0 .5 0]); %system%[ts,ys] = ode45(@de2,tspan2, [0.4119 0 0.9112 0]); %system%[ts,ys] = ode45(@de2,tspan2, [0.9760 0 -.2177 0]); %system%[ts,ys] = ode45(@de2,tspan2, [1 0 1. 0]); %systemplot(ts, ys(:,1), ts, ys(:,3), 'LineWidth', 2);reply = input('PRESS ENTER TO PROCEED');% SIMULATION