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MICE Collaboration meeting at Columbia University, New York 12 – 14 June 2003 How Liquid Hydrogen behaves thermally in a Convective Absorber. by Wing Lau, Stephanie Yang -- Oxford University. Cooling performance of the Convective absorber design - PowerPoint PPT Presentation
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MICE Collaboration meeting at Columbia University, New York
12 – 14 June 2003
How Liquid Hydrogen behaves thermally in a Convective Absorber
by
Wing Lau, Stephanie Yang -- Oxford University
Cooling performance of the Convective absorber design
The MICE absorber adopts a convective cooling design.
The heating power of the beam is being cooled by the stagnant pool of liquid hydrogen which contacts directly. The liquid hydrogen is in turn being cooled by the gas helium.
The analysis are being carried out in two phases. In the first phase, we examine the cooling effect of the absorber without any heat exchange from the gas helium. In this model, the initial temperature of the liquid hydrogen was set at 17K and the containment walls of the absorber is kept at 17 K. Adiabatic boundary conditions were applied, i.e. no heat is exchanged between the outside and the inside of the containment wall. This is a reasonable assumption as there is a layer of vacuum outside the absorber that prevents heat transfer by convection;
This work is now completed. We looked at how the liquid hydrogen behaves under a beam power of 60W, 150W and 300W respectively.
In our second phase of the analysis, we have included the helium gas a medium of heat exchange. The temperature of the containment wall is no longer specified, but determined by flow and heat carrying capacity of the gas helium. This work is still on going.
Absorber diameter: 300mm
Beam diameter: 10mm, Power: 150W
GHe pipe diameter: 15mm, length of pipe is 15mm, inlet velocity: 2m/s
Multicomponent: fluid domain: GHe, LH2, fluid sub-domain: beam, solid sub-domain: wall
Turbulent Model: K-Epsilon
Initial temperature: GHe:17K, LH2: 17K
Global Temperature result see next page
beam
GHe inlets
GHe outlets
Meshed model
LH2 region
Solid dividing wall
Simple hand calculation:
Given: Specific heat of LH2: 9680 J/kg K
LH2 density: 70.79kg/m^3
Volume of absorber window: 0.0196672m^3
Density * volume = 70.79*0.0196672 = 1.392241088kg
Cp*1.392241088kg = 13476.8937318 J/K
300W = 300 J/s
300 (J/s) / 13476.8937318 (J/K) = 0.02226K/s
For 300W, 2.5K needs 44 secs
60W, 1K needs 2246 secs