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Student name: Ahmed Hassan Ibrahim
Page 1 of 10
Ain Shams University
MANF 487: Computer Applications in Industry Faculty Of Engineering Fall 2012
Manufacturing Engineering Credit Hours Engineering Programs
Time allowed : 90 Minutes
Answer all the following questions:
1- Choose the correct answer(s): (21 Marks)
Each correct answer is worth 1 point. Each omitted answer or wrong answer
reduces the score by 1 point, and each additional answer beyond the correct
number of answers reduces the score by 1 point.
Question Answer symbol(s)
Which of the following industries are classified as secondary
industries (three correct answers):
(a) beverages (b) financial services, (c) fishing, (d) mining,
(e) power utilities, (f) publishing, and, (g) transportation?
a
e
f
Mining is classified in which one of the following industry
categories:
(a) agricultural industry, (b) manufacturing industry,
(c) primary industry,(d) secondary industry, (e) service industry,
or, (f) tertiary industry?
C
A production planning and control department accomplishes
which of the following functions in its role of providing
manufacturing support (two best answers):
(a) Designs and orders machine tools, (b) develops corporate
strategic plans, (c) orders materials and purchased parts,
(d) performs quality inspections, and, (e) schedules the order of
products on a machine?
c
e
Which of the following rapid prototyping processes starts with
a photosensitive liquid polymer to fabricate a component (two
correct answers):
(a) Ballistic particle manufacturing, (b) fused deposition
modeling, (c) selective laser sintering, (d) solid ground curing,
and (e) stereolithography?
d
e
Which one of the following RP technologies uses solid sheet
stock as the starting material:
(a) Ballistic particle manufacturing, (b) fused-deposition
modeling, (c) laminated-object manufacturing, (d) solid ground
curing, or (e) stereolithography?
c
Student name: Ahmed Hassan Ibrahim
Page 2 of 10
Which of the following are problems with the current material
addition rapid prototyping technologies (three best answers):
(a) inability of the designer to design the part, (b) inability to
convert a solid part into layers, (c) limited material variety,
(d) part accuracy, (e) part shrinkage, and (f) poor machinability
of the starting material?
c
d
e
Fixed routing is associated with which of the following types
of manufacturing systems (two best answers):
(a) Automated production lines, (b) automated storage systems,
(c) cellular manufacturing systems, (d) flexible manufacturing
systems, (e) job shops, and (f) manual assembly lines?
a
f
Which of the following types of material handling equipment
are typically used in a process type layout (two best answers):
(a) Conveyors, (b) cranes and hoists, (c) fork lift trucks, and
(d) rail-guided vehicles?
c
d
Most parts classification and coding systems are based on
which of the following types of part attributes (two best
answers):
(a) Annual production rate, (b) date of design, (c) design,
(d) manufacturing, and (e) weight?
c
d
What is the dividing line between a manufacturing cell and a
flexible manufacturing system:
(a) Two machines, (b) four machines, or (c) six machines?
b
In a control chart, the upper control limit is set equal to which
one of the following:
(a) Process mean, (b) process mean plus three standard
deviations, (c) upper design tolerance limit, or (d) upper value of
the maximum range R?
b
The R chart is used for which one of the following product or
part characteristics:
(a) Number of rejects in the sample, (b) number of reworked
parts in a sample, (c) radius of a cylindrical part, or (d) range of
sample values?
d
Student name: Ahmed Hassan Ibrahim
Page 3 of 10
2- Why is the normal statistical table used in a Six Sigma program different from
the standard normal tables found in textbooks on probability and statistics? Use
a neat sketch in your answer. (4 Marks)
There are two reasons for this:
First, the values in table refer to only
one tail of the distribution, so that an appropriate
comparison with the standard normal tables would
only use one tail of the distribution (1350 DPM).
Second, and much more significant, is that when Motorola devised
the Six Sigma program, they considered
the operation of processes over long periods of
time, and processes over long periods tend to experience
shifts from their original process means. To
compensate for these shifts, Motorola decided
to adjust the standard normal values by 1.5σ. These effects
can be seen in the following figure.
Student name: Ahmed Hassan Ibrahim
Page 4 of 10
3- What is the common approach used in all of the material addition technologies
to prepare the control instructions for the RP system? Describe using a neat
sketch the RP technology called laminated object manufacturing. (13 Marks)
Steps to Prepare Control Instructions ≡ Part program
1. Geometric modeling - model the component on
CAD system to define its enclosed
volume. Solid modeling provide a complete
mathematical representation of the geometry.
2. Tessellation of the geometric model - the CAD model is
converted into a computerized format that
approximates its surfaces by triangles or
polygons.
3. Slicing of the model into spaced parallel
horizontal layers. As shown in figure (1).
Student name: Ahmed Hassan Ibrahim
Page 5 of 10
Solid physical model made by stacking layers
of sheet stock, each an outline of the cross-sectional
shape of a CAD model that is sliced into layers.
Starting sheet stock includes paper, plastic,
cellulose, metals, or fiber-reinforced materials.
The sheet is usually supplied with adhesive
backing.
After cutting, excess material in the layer remains in place to
support the part during building.
Used for large parts.
Student name: Ahmed Hassan Ibrahim
Page 6 of 10
4- Six samples of size n = 4 have been collected from a process in statistical
control, and the dimension of interest has been measured for each part. The
calculated values of �̅� for each sample are (mm) 9.15, 9.20, 9.19, 9.12, 9.24,
and 9.23. The values of R are (mm) 0.24, 0.26, 0.19, 0.21, 0.21, and 0.23,
respectively. (a) Determine the values of the center, LCL, and UCL for the �̅�
and R charts. (b) Construct the control charts and plot the sample data on the
charts. (20 Marks)
Constants for the �̅� and R charts Sample �̅�chart R chart Size n 𝐴2 𝐷3 𝐷4
4 0.729 0 2.282
For �̅� charts:
𝐿𝐶𝐿 = �̿� − 𝐴2�̅� and 𝑈𝐶𝐿 = �̿� + 𝐴2�̅�
For 𝑅 charts:
𝐿𝐶𝐿 = 𝐷3�̅� and 𝑈𝐶𝐿 = 𝐷4�̅�
𝑥 ̿ =∑ �̅�
𝑛𝑜.=
9.15 + 9.20 + 9.19 + 9.12 + 9.24 + 9.23
6= 9.188𝑚𝑚
�̅� =∑ 𝑅
𝑛𝑜.=
0.24 + 0.26 + 0.19 + 0.21 + 0.21 + 0.23
6= 0.2233𝑚𝑚
For �̅� charts:
𝐿𝐶𝐿 = �̿� − 𝐴2�̅� and 𝑈𝐶𝐿 = �̿� + 𝐴2�̅�
𝐿𝐶𝐿 = �̿� − 𝐴2�̅� = 9.188 − 0.729 × 0.2233 = 9.0252𝑚𝑚
𝑈𝐶𝐿 = �̿� + 𝐴2�̅� = 9.188 + 0.729 × 0.2233 = 9.3507𝑚𝑚
𝐶𝑒𝑛𝑡𝑒𝑟 (�̿�) = 9.188𝑚𝑚 For 𝑅 charts:
Student name: Ahmed Hassan Ibrahim
Page 7 of 10
𝐿𝐶𝐿 = 𝐷3�̅� and 𝑈𝐶𝐿 = 𝐷4�̅�
𝐿𝐶𝐿 = 𝐷3�̅� = 0 × 0.2233 = 0𝑚𝑚
𝑈𝐶𝐿 = 𝐷4�̅� = 2.282 × 0.2233 = 0.50957𝑚𝑚
𝑐𝑒𝑛𝑡𝑒𝑟 (�̅�) = 0.2233𝑚𝑚
8.8
8.9
9
9.1
9.2
9.3
9.4
1 2 3 4 5 6
Sample size, s
𝑥 ̅ charts
0
0.1
0.2
0.3
0.4
0.5
0.6
1 2 3 4 5 6
Sample size, s
R chart
Student name: Ahmed Hassan Ibrahim
Page 8 of 10
5- A foundry that casts turbine blades inspects for eight features that are
considered critical-to-quality. During the previous month, 1236 castings were
produced. During inspection, 47 defects among the eight features were found,
and 29 castings had one or more defects. Determine DPMO, DPM, and DUPM
in a Six Sigma program for these data and convert each to its corresponding
sigma level. (12 Marks)
Nd = total number of defects found = 47
Nu = number of units in the population of interest = 1236
No = number of opportunities for a defect per unit = 47
Ndu= number of defective units in the population = 29
𝐷𝑃𝑀𝑂 = 1,000,000𝑁𝑑
𝑁𝑢𝑁𝑜
𝐷𝑃𝑀𝑂 = 1,000,000 ×47
1236 × 8= 4754 (4.1 𝑠𝑖𝑔𝑚𝑎)
𝐷𝑃𝑀𝑂 = 1,000,000𝑁𝑑
𝑁𝑢
𝐷𝑃𝑀𝑂 = 1,000,000 ×47
1236= 38026 (3.3 𝑠𝑖𝑔𝑚𝑎)
𝐷𝑃𝑀𝑂 = 1,000,000𝑁𝑑𝑢
𝑁𝑢
𝐷𝑃𝑀𝑂 = 1,000,000 ×29
1236= 23463 (3.5 𝑠𝑖𝑔𝑚𝑎)
Student name: Ahmed Hassan Ibrahim
Page 9 of 10
6- A prototype of a part is to be fabricated using Stereolithography. The part is
shaped like a right triangle whose base = 15 mm, height = 6 mm, and thickness
= 10 mm. In application, the part will stand on its base, which is 15 mm by 10
mm. In the Stereolithography process, the layer thickness = 0.5 mm. The
diameter of the laser beam = 0.15 mm, and the beam is moved across the
surface of the photopolymer at a velocity of 400 mm/s. Compute the minimum
possible time required to build the part, if 8 seconds are lost each layer to lower
the height of the platform that holds the part. Neglect the time for post curing.
(30 Marks)
𝑻𝒊 =𝑨𝒊
𝒗 × 𝑫+ 𝑻𝒓
i w b area Ti
0 10 15 150 10.5
1 10 13.75 137.5 10.29167
2 10 12.5 125 10.08333
3 10 11.25 112.5 9.875
4 10 10 100 9.666667
5 10 8.75 87.5 9.458333
6 10 7.5 75 9.25
7 10 6.25 62.5 9.041667
8 10 5 50 8.833333
9 10 3.75 37.5 8.625
10 10 2.5 25 8.416667
11 10 1.25 12.5 0.208333
Total time 104.25
Student name: Ahmed Hassan Ibrahim
Page 10 of 10
Some useful relations:
𝐓𝐢 = 𝐀𝐢
𝐯 ∗ 𝐃+ 𝐓𝐫 𝐃𝐏𝐌 = 𝟏𝟎𝟔 ∗
𝐍𝐝
𝐍𝐮
𝐃𝐏𝐌𝐎 = 𝟏𝟎𝟔 ∗ 𝐍𝐝
𝐍𝐮 ∗ 𝐍𝐨 𝐃𝐔𝐏𝐌 = 𝟏𝟎𝟔 ∗
𝐍𝐝𝐮
𝐍𝐮
For �̅� chart LCL = �̿� - A2 �̅� 𝐚𝐧𝐝 𝐔𝐂𝐋 = �̿� + 𝐀𝟐 �̅�
For R chart LCL = D3 �̅� 𝐚𝐧𝐝 𝐔𝐂𝐋 = 𝐃𝟒 �̅�
********************************************************************
Constants for the �̅� and R charts
Sample Size �̅� Chart R chart
n A2 D3 D4
3 1.023 0 2.574
4 0.729 0 2.282
5 0.577 0 2.114
6 0.483 0 2.004
7 0.419 0.076 1.924
8 0.373 0.136 1.864
9 0.337 0.184 1.816
10 0.308 0.223 1.777
********************************************************************
Sigma Levels And Corresponding Defects Per Million In A Six Sigma Program
Sigma level Defects per
Million Sigma level
Defects per
Million Sigma level
Defects per
Million
6.0 σ 3.4 4.6 σ 968 3.2 σ 44565
5.8 σ 8.5 4.4 σ 1866 3.0 σ 66807
5.6 σ 21 4.2 σ 3467 2.8 σ 96801
5.4 σ 48 4.0 σ 6210 2.6 σ 135666
5.2 σ 108 3.8 σ 10724 2.4 σ 184060
5.0 σ 233 3.6 σ 17864 2.2 σ 241964
4.8 σ 483 3.4 σ 28716 2.0 σ 308538