ME 304 FLUID MECHANICS II

Prof. Dr. Haşmet Türkoğlu

Çankaya University Faculty of Engineering

Mechanical Engineering Department

Spring, 2017

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The Fundamental LawsExperience have shown that all fluid motion analysis must be consistent with the following fundamental laws of nature.

The law of conservation of mass: Mass can be neither created nor destroyed. It canonly be transported or stored.

Newton’s three laws of motion:- A mass remains in a state of equilibrium, that is, at rest or moving at constantvelocity, unless acted on by an unbalanced force.

- The rate of change of linear momentum of mass is equal to the net force acting onthe mass.

- Any force action has a force reaction equal in magnitude and opposite in direction.

The first law of thermodynamics (law of conservation of energy) Energy, like mass, canbe neither created nor destroyed. Energy can be transported, changed in form, orstored.

The second law of thermodynamics: The entropy of the universe must increase or, inthe ideal case, remain constant in all natural processes.

The state of postulate (law of property relations): The various properties of a fluid arerelated. If a certain minimum number (usually two) of fluid’s properties are specified,the remainder of the properties can be determined.

Differential versus Integral FormulationWe must now consider the level of detail of the resulting flow analysis. We must choose between a detailed point by point description and a global or lumped description.

When a point by point (local) description is desired, fundamental laws are applied toan infinitesimal control volume. The result will be a set of differential equations withthe fluid velocity and pressure as dependent variables and the location (x, y, z) andtime as independent variables. Solution of these differential equations, together withboundary conditions, will be two functions V(x, y, z, t), and P(x, y, z, t) that can tell usthe velocity and pressure at every point.

When global information such as flow rate, force and temperature change betweeninlet and outlet is desired, the fundamental laws are applied to a finite control volume.The result will be a set of integral equations.

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FLUID STATICS

Basic Equation of fluid statics

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HYDROSTATIC FORCE ACTING ON A PLANE SUBMERGED SURFACE

Integral Method

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Algebraic method

Pressure Prism Method

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BASIC EQUATIONS FOR A FINITE CONTROL VOLUME (Equations In Integral Form)

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Equation of Conservation of Mass (Continuity Equation):

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Linear Momentum Equation:

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Bernoulli Equation:

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Moment of Momentum Equation:

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Bernoulli equation subject to restrictions:1. Steady flow2. No friction3. Incompressible flow4. Flow along a streamline

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Energy Equation:

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Extended Bernouilli Equation:

Reynolds Transport Equation:

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HEAD LOSS (PRESSURE DROP)

The head loss (pressure loss) in closed conduits can be dived into two part:

1) Major (friction) loss: Losses due to viscous effects on the duct wall.

2) Minor (local) losses): Losses due to the flow through valves, tees, elbows and other non-constant cross-sectional area portions of the system.

Major Head Loss (Pressure Drop)

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For laminar flow, friction factor, Re

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For turbulent flow, friction factor, dff s /Re,

Friction factors for turbulent flows are given in charts (Mood Diagram) or as correlations.

Minor (Local) Head Loss

The minor head losses in variable area parts are proportional to the velocity head of the fluid, i.e.

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Minor head losses for valves, fittings and bends can be calculated using the equivalent length technique, which may be given by the following equation:

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Total loss = (Major loss) + (Minor loss)

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INTRODUCTION TO DIFFERENTIAL ANALYSIS OF FLUID MOTION (Chapter 5)

In course Fluid Mechanics I, we developed the basic equations in integral form for afinite control volume. The integral equations are particularly useful when we areinterested in the gross behavior of a flow and its effect on various devices. However,the integral approach does not enable us to obtain detailed point by point data ofthe flow field.

To obtain this detailed knowledge, we must apply the equations of fluid motion indifferential form.

In this chapter, we will derive fundamental equations in differential form andapply this equations to simple flow problems.

EQUATION OF CONSERVATION OF MASS (CONTINUITY EQUATION)

The application of the principle of conservation of mass to fluid flow yields anequation which is referred as the continuity equation. We shall derive thedifferential equation for conservation of mass in rectangular and in cylindricalcoordinates.

Rectangular Coordinate System

The differential form of the continuity equation may be obtained by applying theprinciple of conservation of mass to an infinitesimal control volume. The sizes of thecontrol volume are dx, dy, and dz. We consider that, at the center, O, of the controlvolume, the density is and the velocity is

For the control voule, equation of consevation of mass in integral form is

To evaluate the first term in this equation, we must evaluate the massflow rate over each face of the control volume.

To be completed in class

The values of the mass fluxes at each of six faces of the control volume may beobtained by using a Taylor series expansion of the density and velocity componentsabout point O. For example, at the right face,

Neglecting higher order terms, we can write

and similarly,

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Corresponding terms at the left face are

To be completed in class

Table. Mass flux through the control surface of a rectangular differential control volume

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The net rate of mass flux out through control surface is

The rate of change of mass inside the control volume is given by

Therefore, the continuity equation in rectangular coordinate is

Since the vector operator, , in rectangular coordinates, is given by

The continuity equation may be simplified for two special cases.

1. For an incompressible flow, the density is constant, the continuity equation becomes,

2. For a steady flow, the partial derivatives with respect to time are zero, that is _________. Then, ……………………………….

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Example: For a 2-D flow in the xy plane, the velocity component in the y direction is given by

a) Determine a possible velocity component in the x direction for steady flow of an incompressible fluid. How many possible x components are there?

b) Is the determined velocity component in the x-direction also valid for unsteady flow of an incompressible fluid?

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To be completed in class

12

Example: A compressible flow field is described by

Determine the rate of change of the density at point x=3 m, y=2 m and z=2 m for t=0.

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Derivation of Continuity Equation Cylindrical Coordinate System

In cylindrical coordinates, a suitable differential control volume is shownin the figure. The density at center, O, is and the velocity there is

Figure. Differential control volume in cylindrical coordinates.

To evaluate , we must consider the mass flux through each of

the six faces of the control surface. The properties at each of the six

faces of the control surface are obtained from Taylor series expansion

about point O.

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Table. Mass flux through the control surface of a cylindrical differential control volume

The net rate of mass flux out through the control surface is given by

The rate of change of mass inside the control volume is given by

In cylindrical coordinates the continuity equation becomes

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Dividing by r gives

or

In cylindrical coordinates the vector operator is given by

Then the continuity equation can be written in vector notation as

The continuity equation may be simplified for two special cases:

1. For an incompressible flow, the density is constant, i.e.,

2. For a steady flow,

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Derivation of Continuity Equation in Cylindrical Coordinate sytem Using Vector Form of the Equation

To be completed in class

Example: Consider one-dimensional radial flow in the r plane, characterized by vr =f(r) and v = 0. Determine the conditions on f(r) required for incompressible flow.

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STREAM FUNCTION FOR TWO-DIMENSIONAL INCOMPRESSIBLE FLOW

For a two-dimensional flow in the xy plane of the Cartesian coordinate systems,the continuity equation for an incompressible fluid reduces to

If a continuous function , called stream function, is defined such that

Then continuity equation is satisfied exactly, since

Streamlines are tangent to the direction of flow at every point in the flow field.Thus, if dr is an element of length along a streamline, the equation of streamline isgiven by

Substituting for the velocity components of u and v, in terms of the streamfunction

(A)

At a certain instant of time, t0, the stream function may be expressed as. At this instant, the streamfunction

(B)

Comparing equations (A) and (B), we see that along instantaneous streamline = constant. In the flow field, 2-1, depends only on the end points ofintegration, since the differential equation of is exact.

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For a unit depth, the flow rate across AB is

Along AB, x = constant and . Therefore,

For a unit depth, the flow rate across BC is

Along BC, y = constant and . Therefore,

Thus, the volumetric flow rate per unit depth between any two streamlines, can beexpressed as the difference between constant values of defining the twostreamlines.

Now, consider the two-dimensional flowof an incompressible fluid between twoinstantaneous streamlines, as shown inthe Figure. The volumetric flow rateacross areas AB, BC, DE, and DF must beequal, since there can be no flow acrossa streamline.

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In r plane of the cylindrical coordinate system, the incompressible continuityequation reduces to

The streamfunction (r, ,t) then is defined such that

Example: Consider the stream function given by = xy. Find the correspondingvelocity components and show that they satisfy the differential continuity equation.Then sketch a few streamlines and suggest any practical applications of the resultingflow field.

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