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Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard

Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

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Page 1: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

Module 1 Lesson 19Use the distributive property to

decompose units(Or, how to use easy math to solve hard problems)

Page 2: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

Skip Count By 4s To 40 … (whisper) 4 8 12 16 20 24 28 32 36 40

Skip Count by 6s to 60 … (Russian) 6 12 18 24 30 36 42 48 54 60

Skip Count by 3s to 30 … (Operator) 3 6 9 12 15 18 21 24 27 30

Skip Count By 5s To 50 … (Robot)

5 10 15 20 25 30 35 40 45 50

Skip Count

Page 3: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

COMMUTATIVE MultiplyingI will give you multiplication sentences. Use the commutative property to “Move It, Move It!” and give me an equivalent equation:

3 x 2 = 6 5 x 2 = 102 x 3 = 6 2 x 5 = 10

3 x 4 = 12 2 x 8 = 164 x 3 = 12 8 x 2 = 16

3 x 7 = 21 5 x 3 = 157 x 3 = 21 3 x 5 = 15

Page 4: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

Decompose & Multiply

In your math journal write the multiplication sentence for 7 fours:

7 x 4Now write:

(5 fours) + ( _____ fours ) = 7 foursWhat goes in the blank?

2

Page 5: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

Decompose & Multiply

(5 fours) + ( 2 fours ) = 7 fours=

20 + 8 = 28

Page 6: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

Let’s try it again!

In your math journal write the multiplication sentence for 8 twos:

8 x 2Now write:

(5 twos) + ( _____ twos ) = 8 twosWhat goes in the blank?

3

Page 7: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

(5 twos) + ( 3 twos ) = 8 twos=

10 + 6 = 16

Page 8: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

Problem of the Day ...

Henrietta works in a shoe store. She uses 2 shoelaces to lace each pair of shoes. Henrietta has a total of 24 shoelaces. How many pairs of shoes can Henrietta lace?

Page 9: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

Problem of the Day ... 2 laces

24 laces? pairs of shoes

Henrietta can lace 12 pairs of shoes.

2 4 6 8 10 12 14 16 18 20 22 24

Page 10: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

Divide by Breaking Apart❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂

24 ÷ 2 = ______

Let’s use the array to solve. Here is one way to break apart the array.

20 ÷ 2 = 10 and 4 ÷ 2 = 2

10 + 2 = 12

Page 11: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

Divide by Breaking ApartThe twins are having a birthday party! They invite 27 people.

ALL THE PEOPLE ARE TRIPLETS!! One twin invited 15 people.How many sets of triplets attended the birthday party?

How many triplets did each twin invite?

Page 12: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

Concept Development❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂❂

Let’s use an array to solve.

27 ÷ 3 = ?

15 ÷ 3 = 5 and 12 ÷ 3 = 4

5 + 4 = 9

9 SETS OF TRIPLETS ATTENDED THE PARTY.One twin invited 5 sets; the other twin invited 4 sets.

27 ÷ 3 = 9

Page 13: Module 1 Lesson 19 Use the distributive property to decompose units (Or, how to use easy math to solve hard problems)

Problem Set: Show What You Know!