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Dr. Williamson’s Molecular Geometry Notes
1
Molecular Geometry
Dr. V.M. WilliamsonTexas A & M UniversityStudent Version
Valence Shell Electron Pair Repulsion-VSEPR
1. Valence e- ___________to some extent 2. Electron pairs move as far away as possible
to ________________ repulsive forces3. Shape determined by repulsive position of
electron pairs to give base or electron geo. MUST consider both lone pairs and bonds.
4. Molecular geo from base or electron geo! If no lone pairs (only bonds), then electron geo _____
molecular geo5. Molecular geometry describes the position
of the bonded atoms around the central atom.
2 Principal originator: R. J. Gillespie in the 1950’s
VSEPR: Definition of Terms" Central atom: bonded to more than
one other atom" Regions of high electron density:
bonding electron pair = ___ region (multiple bonds count = ___ region)lone pair of electrons = ___ region
" Electronic geometry: geometry of regions of high electron density around central atom
" Molecular geometry: geometry of atoms around central atom
Determining Geometry1. Count the regions of electron density
from Lewis structure. (lone pairs and single, double or triple bonds are just 1 region.)
2. Determine the "base" or electron geometry.
3. Determine the number of electron regions that are bonded to another atom.
4. Determine the actual molecular geometry from the "base" or electron geometry
4
" To minimize repulsions, situate electron pairs as far apart as possible
VSEPR: Electronic Geometries
109.5°
109.5°
O
VSEPR
6
Dr. Williamson’s Molecular Geometry Notes
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7 4 regions 5 regions 6 regions
Electronic Geometries in 3-D
Copyright © 1995 by Saunders College Publishing
" Lone pairs occupy ______ space than bonding pairs
VSEPR: Space Considerations
>109.5°
<109.5°
O H H
10
" Multiple bonds treated as single bonds but they occupy ______ space
VSEPR: Multiple Bonds
Predict 120° actually 117°
Multiple Bonds
12
Dr. Williamson’s Molecular Geometry Notes
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13
Electronic vs Molecular Geometry" When nonbonding or lone electron pairs are
present, electronic and molecular geometries are not identical
Copyright © 1995 by Saunders College Publishing
CH4SF4
SF4 CH4
Electronic and Molecular Geometries 4 regions of Electron Density
15 16
5 regions of electron density
17
5 Regions of Electron Density
6 Regions of Electron Density
18
Dr. Williamson’s Molecular Geometry Notes
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19
VSEPR: When There is More Than One Central Atom" Determine molecular geometry about
each central atom to obtain complete structure of the molecule
C C H
H H
H H
H
Tetrahedral Carbons Copyright © 1995 by Saunders College Publishing
VSEPR: Another Example109° 120°
lone pair bonding electrons
caffeine
VSEPR: A Look at Caffeine
Copyright © 1995 by Saunders College Publishing
Predict the shape and the approximate bond angles for the atom numbered 1 and 2.
23
(A) linear, _____ and tetrahedral, ____ (B) ____________, 109.5 and ____________, 109.5 (C) angular, ____ and square planar, ____ (D) __________, 109.5 and ___________, 109.5
Bond Polarity and Molecular Polarity
" Bond polarity can be determined by examining the difference in EN for the 2 atoms in the bond
" Molecular Polarity is the sum of the bonds in the molecule. This sum depends on the ________________________!!
24
Dr. Williamson’s Molecular Geometry Notes
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25
Measurement of Molecular Polarity
27
Molecular Polarity from Bond Polarity and Geo
28
Molecular Polarity:Symmetrical Molecular Geometries
µ total = 0
Symmetry and Polarity
30 CH4 CClH3
Dr. Williamson’s Molecular Geometry Notes
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31
Dipole Moment" A measure of the polarity of a molecule" Defined as the product of the magnitude of the
partial charges δ + and δ – and the distance d separating these charges
" Represented by symbol µ in unit of debye (D)
H Cl δ+ δ-
dipoles
µ = 1.07 D ∴ polar molecule
dipole moment
Dipole Moment: An Application" The dipole moment of a molecule can be
used to provide, indirectly, information on molecular geometry
Y X Y Linear
Y X Y
Net dipole = 0 ∴ Nonpolar
Y X Y Bent
Y X Y
Net dipole > 0 ∴ Polar
Polarity of Water
Copyright © 1995 by Saunders College Publishing
See demo
Why is water attracted to this comb? (Try it at home J)
35 36
Dr. Williamson’s Molecular Geometry Notes
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Why polarity??
" Solubility!!" See demo" Likes dissolve _____" Ionic and polar covalent substances
dissolve in polar solvents! Think of ionic as polar extreme!!
" Nonpolar substances dissolve in nonpolar solvents
" What will dissolve in water? In CCl4?37
Valence Bond (VB) Theory(orbital overlap model)" A bond is formed by the overlap of an
orbital from 1 atom with an orbital from another atom. This theory allows for mixing of orbitals (hybridization) to fit the shape and energies observed in the molecule.
Principal originator: L. Pauling in the 1930’s & 40’s
Hybrid Orbital Formation
Copyright © 1995 by Saunders College Publishing
• Explains why Carbon will form 4 bonds • Carbon = 2s2 2p2
• ↑↓ ↑ ↑
40
41 42
Dr. Williamson’s Molecular Geometry Notes
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Hybrid Orbitals:Linear Geometry
Why does BeCl2 form?Be is 2s2:↑↓ 2s 2p
In order to make 2 bonds, need 2 places so:
44
180 degrees
Hybrid Orbitals: Trigonal Planar Geometry
Why does BF3 form? B is 2s22p1 : ↑↓ ↑ 2s 2p
In order to make 3 bonds, need 3 places so:
46
120 degrees
47
90 & 120 degrees
P is 3s23p3 : ↑↓ ↑ ↑ ↑ 3s 3p
To make PF5
Note: ___ empty, unhybridized d orbitals
48
90 degrees
To make SF6 Note: __ empty, unhybridized d orbitals
S is 3s23p4 : ↑↓ ↑↓ ↑ ↑ 3s 3p
Dr. Williamson’s Molecular Geometry Notes
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Electronic Geometries andHybridizations of Central Atom
High Electron Density Regions
Electronic Geometry
Hybridized Atomic Orbitals
Hybridi- zation
2 linear 1 s, 1 p sp
3 trigonal 1 s, 2 p’s sp2 planar
4 tetrahedral 1 s, 3 p’s sp3
5 trigonal 1 s, 3 p’s, 1 d sp3d bipyramidal
6 octahedral 1 s, 3 p’s, 2 d’s sp3d2 50
Predict the hybridization at the numbered atoms in the following molecule.
51
(A) sp, ____ (B) ___, sp3 (C) ___ , sp2 (D) sp3, __
52
Predict the hybridization for # ___: (A) ____ (B) ____ (C) ____ (D) _____
Sigma (σ) Bond FormationSigma (σ) Bond Formation
Dr. Williamson’s Molecular Geometry Notes
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Pi (π) Bond Formation
σ and π bonding
57 58
OR
C2H4
Hybrid Orbitals:Compounds with Double Bonds
60
Dr. Williamson’s Molecular Geometry Notes
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Triple Bonding
61
How many sigma and pi bonds are in:
62
Molecule (b)?? (A) ____, 1 (B) ___, 1 (C) ____, ___ (D) ____, 1
Molecule (c)?? (A) ___, 2 (B) ___, 3 (C) ___, 2 (D) ___, 3
63
Benzene C6H6
64
Benzene C6H6
65
Benzene C6H6
66
Dr. Williamson’s Molecular Geometry Notes
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67
" VSEPR = Repulsion between e- pairs such that distance was maximized and effect of repulsion minimized determines _______.
" Valence Bond = atomic orbitals overlap to form bonds. Atomic __________ orbitals can form.
" Both FAILED to explain:! why O2 was attracted to a magnet (was
paramagnetic) ! Or why SO2 had 2 equivalent bond that are an
intermediate between a double and single bond.
68
Liquid N2 and O2 with a Magnet
69 70
Molecular Orbital Theory" MO theory = molecular orbital theory.
Assumes that new MOLECULAR orbitals are formed from the atomic orbitals of the bonding atoms. These molecular orbitals can reflect the geom. of the molecule, but are hard to visualize.
71 72
Bonding molecular orbitals (MO’s) = e- spend most of time between the two nuclei.
Antibonding MO’s = e- spend most of time on the outside of nuclei.
Consider H2
Dr. Williamson’s Molecular Geometry Notes
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MO Energy Level Diagrams H2 through N2 NEW filling order
Ener
gy Molecularorbitals
2p 2p
π2p
σ*2p
π*2p
1s 1s σ1s
σ*1s
2s σ2s
σ*2s
Atomic orbitals
2s
σ2p
MO Energy Level Diagrams O2 through Ne2 NEW filling order
Ener
gy Molecular orbitals
2p 2p
1s 1s σ1s
σ*1s
σ*2p
σ2p
π*2p
2s 2s σ2s
σ*2s
Atomic orbitals
π2p
How Is O2 Paramagnetic?
1s 1s σ1s
σ*1s
2s 2s σ2s
σ*2s
2p 2p
σ2p
π2p
σ*2p
π*2p
Ener
gy
O2 MO’s
Oxygen AO’s