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A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. - PowerPoint PPT Presentation
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A compound contains 18.8% sodium, A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 molar mass of the compound is 122.44 g/mol, determine the empirical and g/mol, determine the empirical and molecular formulas.molecular formulas.
A compound contains 18.8% sodium, A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 molar mass of the compound is 122.44 g/mol, determine the empirical and g/mol, determine the empirical and molecular formulas.molecular formulas.
Grams of Na = Molar Mass =Grams of Na = Molar Mass =
Grams of Cl = Empirical Formula= Grams of Cl = Empirical Formula=
Grams of O = Molecular Formula =Grams of O = Molecular Formula =
A compound contains 18.8% sodium, A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 molar mass of the compound is 122.44 g/mol, determine the empirical and g/mol, determine the empirical and molecular formulas.molecular formulas.
Grams of Na = 18.8 Molar Mass =Grams of Na = 18.8 Molar Mass =
Grams of Cl = Empirical Formula= Grams of Cl = Empirical Formula=
Grams of O = Molecular Formula =Grams of O = Molecular Formula =
A compound contains 18.8% sodium, A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 molar mass of the compound is 122.44 g/mol, determine the empirical and g/mol, determine the empirical and molecular formulas.molecular formulas.
Grams of Na = 18.8 Molar Mass =Grams of Na = 18.8 Molar Mass =
Grams of Cl = 29.0 Empirical Formula= Grams of Cl = 29.0 Empirical Formula=
Grams of O = Molecular Formula =Grams of O = Molecular Formula =
A compound contains 18.8% sodium, A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 molar mass of the compound is 122.44 g/mol, determine the empirical and g/mol, determine the empirical and molecular formulas.molecular formulas.
Grams of Na = 18.8 Molar Mass =Grams of Na = 18.8 Molar Mass =
Grams of Cl = 29.0 Empirical Formula= Grams of Cl = 29.0 Empirical Formula=
Grams of O = 52.2 Molecular Formula =Grams of O = 52.2 Molecular Formula =
A compound contains 18.8% sodium, 29.0% A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the of the compound is 122.44 g/mol, determine the empirical and molecular formulas.empirical and molecular formulas.
Grams of Na = 18.8 Molar Mass = 122.44Grams of Na = 18.8 Molar Mass = 122.44
Grams of Cl = 29.0 Empirical Formula=Grams of Cl = 29.0 Empirical Formula=
Grams of O = 52.2 Molecular Formula =Grams of O = 52.2 Molecular Formula =
Moles of Na = Moles of Na =
Moles of Cl =Moles of Cl =
Moles of O =Moles of O =
Moles of SodiumMoles of Sodium
Moles of SodiumMoles of Sodium
Moles of SodiumMoles of Sodium
A compound contains 18.8% sodium, 29.0% A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the of the compound is 122.44 g/mol, determine the empirical and molecular formulas.empirical and molecular formulas.
Grams of Na = 18.8 Molar Mass = 122.44Grams of Na = 18.8 Molar Mass = 122.44
Grams of Cl = 29.0 Empirical Formula=Grams of Cl = 29.0 Empirical Formula=
Grams of O = 52.2 Molecular Formula =Grams of O = 52.2 Molecular Formula =
Moles of Na = .8177 Moles of Na = .8177
Moles of Cl =Moles of Cl =
Moles of O =Moles of O =
A compound contains 18.8% sodium, 29.0% A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the of the compound is 122.44 g/mol, determine the empirical and molecular formulas.empirical and molecular formulas.
Grams of Na = 18.8 Molar Mass = 122.44Grams of Na = 18.8 Molar Mass = 122.44
Grams of Cl = 29.0 Empirical Formula=Grams of Cl = 29.0 Empirical Formula=
Grams of O = 52.2 Molecular Formula =Grams of O = 52.2 Molecular Formula =
Moles of Na = .8177 Moles of Na = .8177
Moles of Cl = .8181Moles of Cl = .8181
Moles of O =Moles of O =
A compound contains 18.8% sodium, 29.0% A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the of the compound is 122.44 g/mol, determine the empirical and molecular formulas.empirical and molecular formulas.
Grams of Na = 18.8 Molar Mass = 122.44Grams of Na = 18.8 Molar Mass = 122.44
Grams of Cl = 29.0 Empirical Formula= NaClOGrams of Cl = 29.0 Empirical Formula= NaClO44
Grams of O = 52.2 Molecular Formula = NaClOGrams of O = 52.2 Molecular Formula = NaClO44
Moles of Na = .8177 Moles of Na = .8177
Moles of Cl = .8181Moles of Cl = .8181
Moles of O = 3.263Moles of O = 3.263
A compound contains 18.8% sodium, 29.0% A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the of the compound is 122.44 g/mol, determine the empirical and molecular formulas.empirical and molecular formulas.
Grams of Na = 18.8 Molar Mass = 122.44Grams of Na = 18.8 Molar Mass = 122.44
Grams of Cl = 29.0 Empirical Formula= NaClOGrams of Cl = 29.0 Empirical Formula= NaClO44
Grams of O = 52.2 Molecular Formula = NaClOGrams of O = 52.2 Molecular Formula = NaClO44
Moles of Na = .8177 Moles of Na = .8177
Moles of Cl = .8181Moles of Cl = .8181
Moles of O = 3.263Moles of O = 3.263
Molar massMolar mass
PP22OO33
P: 30.97(2) = 61.94P: 30.97(2) = 61.94
O: 15.999(3) = 47.997O: 15.999(3) = 47.997
------------------------------------------------------------------------
109.937 g 109.937 g
Percent CompositionPercent Composition
SOSO33
S: 32.06 = 32.06S: 32.06 = 32.06
O: 15.999 (3) = 47.997O: 15.999 (3) = 47.997
--------------------------------------------------------------------
80.057 80.057 47.997 47.997 * 100= 59.95% * 100= 59.95%
80.057 80.057
A compound contains 18.8% sodium, A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 molar mass of the compound is 122.44 g/mol, determine the empirical and g/mol, determine the empirical and molecular formulas.molecular formulas.
Grams of Na = 18.8 Molar Mass = 122.44Grams of Na = 18.8 Molar Mass = 122.44
Grams of Cl = 29.0 Empirical Formula=Grams of Cl = 29.0 Empirical Formula=
Grams of O = 52.2 Molecular Formula =Grams of O = 52.2 Molecular Formula =
A compound contains 18.8% sodium, A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 molar mass of the compound is 122.44 g/mol, determine the empirical and g/mol, determine the empirical and molecular formulas.molecular formulas.
Grams of Na = 18.8 Molar Mass = 122.44Grams of Na = 18.8 Molar Mass = 122.44
Grams of Cl = 29.0 Empirical Formula= NaClOGrams of Cl = 29.0 Empirical Formula= NaClO44
Grams of O = 52.2 Molecular Formula = NaClOGrams of O = 52.2 Molecular Formula = NaClO44
A compound contains 18.8% sodium, A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 molar mass of the compound is 122.44 g/mol, determine the empirical and g/mol, determine the empirical and molecular formulas.molecular formulas.
Grams of Na = 18.8 Molar Mass = 122.44Grams of Na = 18.8 Molar Mass = 122.44
Grams of Cl = 29.0 Empirical Formula= Grams of Cl = 29.0 Empirical Formula=
Grams of O = 52.2 Molecular Formula =Grams of O = 52.2 Molecular Formula =
A compound contains 18.8% sodium, A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 molar mass of the compound is 122.44 g/mol, determine the empirical and g/mol, determine the empirical and molecular formulas.molecular formulas.
Grams of Na = 18.8 Molar Mass = 122.44Grams of Na = 18.8 Molar Mass = 122.44
Grams of Cl = 29.0 Empirical Formula= Grams of Cl = 29.0 Empirical Formula=
Grams of O = 52.2 Molecular Formula =Grams of O = 52.2 Molecular Formula =
Ascorbic acid is another name for Vitamin Ascorbic acid is another name for Vitamin C. It is composed of 40.92% carbon, C. It is composed of 40.92% carbon, 4.58% hydrogen, and 54.50% oxygen, by 4.58% hydrogen, and 54.50% oxygen, by mass. Determine the empirical formula for mass. Determine the empirical formula for ascorbic acid.ascorbic acid.
Ascorbic acid is another name for Vitamin C. It Ascorbic acid is another name for Vitamin C. It is composed of 40.92% carbon, 4.58% is composed of 40.92% carbon, 4.58% hydrogen, and 54.50% oxygen, by mass. hydrogen, and 54.50% oxygen, by mass. Determine the empirical formula for ascorbic Determine the empirical formula for ascorbic acid.acid.
Grams of C = Moles of Carbon =Grams of C = Moles of Carbon = Grams of H = Moles of Hydrogen =Grams of H = Moles of Hydrogen = Grams of O = Moles of Oxygen =Grams of O = Moles of Oxygen = Molar Mass = Molecular Formula =Molar Mass = Molecular Formula = Empirical Formula =Empirical Formula =
