Msteam = Q / hfg = 1,000,000 Btu/hr / 881 Btu/lb = 1,135 lb/hr If the temperature of hot water dropped by 100 F as t passed through a heat e!"ha# ger, the mass $ow rate of water to tra#sfer the same amou#t of heat would be about ##e tmes as mu"h as steam% Mwater = Q / &"p ! dt' = 1,000,000 Btu/hr / &1 Btu/lb(F ! 100 F' = 10,000 lb/hr If the temperature of hot ar dropped by 100 F as t passed through a heat e!"ha# ger, the mass $ow rate of ar to tra#sfer the same amou#t of heat wth the same temperature d)er e#"e would be about 3* tmes as mu"h as steam% +-ourse .M001 1or sho p 2af ety Measur #g 4 Mar #g ut 36a#d 7 oo ls *+orta ble + ower 7 ool s 5ra w# gs a#d a gr ams 9:er:ew of ;tlt es <Bear#gs 8-o mpressors rl l#g , 7 hre ad# g 4 F tt# g 10y#am" 2eals 11>asets 1>la#d +a"#g 13+pewor1*+re"so# Measureme#t 15+umps 19?al:es 1<2team turb#es 18>as 7urb#es 1@e"pro "at#g e#g#es 7hs s a l st for the tr a##gA
