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Exercise 11.1 1) Draw a line segment of length 7.6 cm and divide it in 5: 8 ration. In addition, find the measure of two parts. Solution: B X Procedure for construction: 1. Draw any ray AX, making an acute angle with AB. 2. Locate 13(= 5 + 8) points A 1 , A 2 , A 3 ......... A13 on AX so that AA 1 = A 1 A 2 A 12 A 13- 3. Join BA 13- 4. Through the po int AS(m = 5), draw a line parallel to BA13 (by making an angle equal to LAA13 B at AS intersecting AB at C. Then AC: CB = 5 : 8) 2) Construct a triangle with sides 4 cm, 5 cm and 6 cm and then a similar triangle to it whose sides are 2/3 of the corresponding sides of the first one. Solution: B S cm C X Procedure for construction: 1. Draw a line segment BC with length 5 cm. 2. With B as centre and radi us of 4 cm draw an arc. 3. With C as centre and radius of 6 cm draw an arc. 4. Join AB and AC. Then, MSC is the required triangle. 5. Below BC, make an acute angle LCBX 6. Along BX, mark up three po ints 81, 82, 83 such that 881 = 8 1 8 2 = 8 2 8 3 7. Join 8 3 C 0 L O ,., 0 'llO - ,,; , 0 , r,, NCERT SOLUTIONS CLASS 10 MATHS CHAPTER 11 - CONSTRUCTIONS myncertsolutions.com

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Exercise 11.1

1) Draw a line segment of length 7.6 cm and divide it in 5: 8 ration. In addition, find the measure of two parts.

Solution:

B

X

Procedure for construction:

1. Draw any ray AX, making an acute angle with AB.

2. Locate 13(= 5 + 8) points A1, A2, A3 ......... A 13 on AX so that AA1 = A1A2 A12 A13-

3. Join BA13-

4. Through the point AS(m = 5), draw a line parallel to BA 13 (by making an angle equal to LAA 13 B at AS intersecting AB at C. Then

AC: CB = 5 : 8)

2) Construct a triangle with sides 4 cm, 5 cm and 6 cm and then a similar triangle to it whose sides are 2/3 of the

corresponding sides of the first one.

Solution:

B S cm

C

X

Procedure for construction:

1. Draw a line segment BC with length 5 cm.

2. With B as centre and radius of 4 cm draw an arc.

3. With C as centre and radius of 6 cm draw an arc.

4. Join AB and AC. Then, MSC is the required triangle.

5. Below BC, make an acute angle LCBX

6. Along BX, mark up three points 81, 82, 83 such that 881 = 81 82 = 8283

7. Join 83C

0 L ...... ...,.. O""I .J ..... ,., 0 f"''llO - ...,..,..,..,1.; ..,. ,.. 01"' ,...a. r,,

NCERT SOLUTIONS CLASS 10 MATHS

CHAPTER 11 - CONSTRUCTIONSmyn

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