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The simplest derivation of the non Abelian field tensor and Lagrangian density. J.R.G. (Hans) de Vries (Dated: December 8, 2008) First the Abelian electromagnetic field is handled after which the same steps are repeated for the non Abelian case. The Field tensors are derived from the operator that determines the phase change rates when acting on the fields. The starting point of the Lagrangian density is simply the scalar Lagrangian which is extended to the more complex groups by taking symmetries in account which lead to the addition of terms which produce indistinguishable phase change rates in U(1) and SU(2) respectively. I. THE ABELIAN FIELD TENSOR In the Abelian case we have a scalar field ψ with an U(1) symmetry. Such a field with inertial momentum p μ in- cluding the momentum from electromagnetic interaction A μ is given by: ψ = ψ p ψ A = exp - i x μ p μ + eA μ (1) If the inertial momentum p μ , and the electromagnetic momentum eA μ are not constant then we need to take the the integrals along the coordinate axis. ψ = ψ p ψ A = exp - i dx μ p μ + eA μ (2) This is an over specified expression. The phase is a scalar while p μ and A μ are four vectors. This restricts the pos- sible values of p μ and A μ . More specifically, the four-curl of the total momentum p μ + eA μ must be zero. The inte- gral is the inverse of the (four)gradient operator and the curl of a gradient is zero per definition. Changes in A μ require a cancelation by opposite changes in p μ to keep the integral a simply connected scalar field. These changes of p μ of course represent the Lorentz force. The operator which gives the changes of the four momen- tum when acting on ψ is given by. μ p ν ψ p = i μ ν ψ p (3) Which can be seen by applying this operator on (2). The order of the μ ν derivatives should make no difference in the case of the complete field ψ and therefor. i μ ν - ν μ ψ = 0 (4) This states that the curl of p μ + eA μ is zero. However, if we separate ψ into p μ and A μ factors then we have the individual fields ψ p and ψ A which are not simply connected anymore on their own. F μν ψ A = i e μ ν - ν μ ψ A (5) If we let the differential operators act on the on the ”A μ only” part of (2) then we obtain. F μν ψ A = μ A ν - ν A μ ψ A (6) We have derived the Abelian field tensor corresponding to the electro magnetic field. II. THE ABELIAN LAGRANGIAN Although the Lagrangian density of the electromagnetic field looks rather different compared to the scalar La- grangian density. It’s actually just a few steps away from the Klein Gordon Lagrangian density which is given by. L = 1 2 (μ φ)(μ φ) - 1 2 m 2 φ 2 (7) We discard the mass term and we replace the scalar field ψ with the four components of the vector field A μ coos- ing the indices so that the resulting Lagrangian density transforms like a Lorentz scalar. The result is, up to a unit system dependent constant: L = 1 2 (μ A ν )(μ A ν ) (8) However, we have to replace all terms like μ A ν with (μ A ν - ν A μ ). The phase which the two terms between brackets induce in a scalar field is indistinguishable. We therefor get. L = 1 2 (μ A ν - ν A μ )(μ A ν - ν A μ ) (9) So only the curl of the potential A μ contributes to the Lagrangian density of the electro magnetic field. Conse- quently it can be expressed in terms of the field tensor. L = - 1 4μ o F μν F μν = 1 2 B · H - D · E (10) Normalized in SI units.

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Non-Abelian Lagrangian

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Page 1: Non Abelian Lagrangian

The simplest derivation of the non Abelian field tensor and Lagrangian density.

J.R.G. (Hans) de Vries(Dated: December 8, 2008)

First the Abelian electromagnetic field is handled after which the same steps are repeated for thenon Abelian case. The Field tensors are derived from the operator that determines the phase changerates when acting on the fields. The starting point of the Lagrangian density is simply the scalarLagrangian which is extended to the more complex groups by taking symmetries in account whichlead to the addition of terms which produce indistinguishable phase change rates in U(1) and SU(2)respectively.

I. THE ABELIAN FIELD TENSOR

In the Abelian case we have a scalar field ψ with an U(1)symmetry. Such a field with inertial momentum pµ in-cluding the momentum from electromagnetic interactionAµ is given by:

ψ = ψpψA = exp{− i

~xµ

(pµ + eAµ

)}(1)

If the inertial momentum pµ, and the electromagneticmomentum eAµ are not constant then we need to takethe the integrals along the coordinate axis.

ψ = ψpψA = exp{− i

~

∫dxµ

(pµ + eAµ

)}(2)

This is an over specified expression. The phase is a scalarwhile pµ and Aµ are four vectors. This restricts the pos-sible values of pµ and Aµ. More specifically, the four-curlof the total momentum pµ +eAµ must be zero. The inte-gral is the inverse of the (four)gradient operator and thecurl of a gradient is zero per definition.

Changes in Aµ require a cancelation by opposite changesin pµ to keep the integral a simply connected scalar field.These changes of pµ of course represent the Lorentz force.The operator which gives the changes of the four momen-tum when acting on ψ is given by.

∂µ pνψp = i~ ∂µ∂νψ

p (3)

Which can be seen by applying this operator on (2). Theorder of the ∂µ∂ν derivatives should make no differencein the case of the complete field ψ and therefor.

i~(∂µ∂ν − ∂ν∂µ

)ψ = 0 (4)

This states that the curl of pµ + eAµ is zero. However,if we separate ψ into pµ and Aµ factors then we havethe individual fields ψp and ψA which are not simplyconnected anymore on their own.

Fµν ψA =i~e

(∂µ∂ν − ∂ν∂µ

)ψA (5)

If we let the differential operators act on the on the ”Aµ

only” part of (2) then we obtain.

Fµν ψA =(∂µAν − ∂νAµ

)ψA (6)

We have derived the Abelian field tensor correspondingto the electro magnetic field.

II. THE ABELIAN LAGRANGIAN

Although the Lagrangian density of the electromagneticfield looks rather different compared to the scalar La-grangian density. It’s actually just a few steps away fromthe Klein Gordon Lagrangian density which is given by.

L =12(∂µφ)(∂µφ)− 1

2m2φ2 (7)

We discard the mass term and we replace the scalar fieldψ with the four components of the vector field Aµ coos-ing the indices so that the resulting Lagrangian densitytransforms like a Lorentz scalar. The result is, up to aunit system dependent constant:

L =12(∂µAν)(∂µAν) (8)

However, we have to replace all terms like ∂µAν with(∂µAν −∂νAµ). The phase which the two terms betweenbrackets induce in a scalar field is indistinguishable. Wetherefor get.

L =12(∂µAν − ∂νAµ)(∂µAν − ∂νAµ) (9)

So only the curl of the potential Aµ contributes to theLagrangian density of the electro magnetic field. Conse-quently it can be expressed in terms of the field tensor.

L = − 14µo

FµνFµν =12

(B ·H −D · E

)(10)

Normalized in SI units.

Page 2: Non Abelian Lagrangian

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III. THE NON-ABELIAN FIELD TENSOR

We can derive the non-Abelian field tensor in exactly thesame way. The non-Abelian interaction is given by.

ψG = exp{− ig

~T i

∫dxµG

µi

}(11)

Where the T i are the generators of the group. In case ofthe SU(2) group these are the Pauli-matrices divided bytwo. We can now derive the non-Abelian field tensor inexactly the same way as in (5)

Fµν ψG = − i~g

(∂µ∂ν − ∂ν∂µ

)ψG 6= 0 (12)

Showing the i-indices explicitly with the definitionsFµν = T iFµν

i and Gµ = T iGµi in mind, we derive.

T i Fµνi = T i

(∂µGν

i − ∂νGµi

)−

i g~

(T jGν

j TkGµ

k − T kGνk T

jGµj

) (13)

The last two terms, which cancel in the U(1) case, canbe written as a commutation over the i-indices.

Fµν = ∂µGν − ∂νGµ − ig[Gµ , Gν

](14)

This is the usual presentation. We have set ~ to 1 here.We can also group the terms of the non Abelian fieldtensor depending on from which term of (∂µ∂ν−∂ν∂µ)ψG

they originate.

T i Fµνi =

(∂µ − igT jGµ

j

)T kGν

k −(∂ν − igT kGν

k

)T jGµ

j

(15)Making the i-indices implicit and defining a gauge co-variant derivative Dµ = ∂µ − igGµ we can simplify thisto.

Fµν = DµGν −DνGµ (16)

This shows that the non Abelian field interacts with it-self.

IV. THE NON-ABELIAN LAGRANGIAN

Going back to the scalar Lagrangian density.

L =12(∂µφ)(∂µφ)− 1

2m2φ2 (17)

Applying this to the non Abelian field Gµ we use the ”co-variant derivative” Dµ since this is the expression whichdetermines the phase change rates in this case: The ro-tation rates in SU(2). Ignoring the mass term we get

L = tr12(DµGν)(DµGν) (18)

The trace sums over the i-indices. We must however re-place terms like DµGν with ones like (DµGν − DνGµ)since the two terms between brackets contribute equallyto the rotation rates in SU(2) and are there for indistin-guishable. Hence the Lagrangian becomes.

L = tr12(DµGν −DνGµ)(DµGν −DνGµ) (19)

Which we express in the field tensor as follows.

L = − tr14FµνFµν (20)

Where the factor 1/4 stems from the structure coeffi-cients.