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Oakland Math Test Select Questions and Answers NOT Multiple Choice

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Oakland Math Test. Select Questions and Answers NOT Multiple Choice. What number added to the sum of equal the number 1?. solve for w. - PowerPoint PPT Presentation

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Page 1: Oakland Math Test

Oakland Math TestSelect Questions and Answers

NOT Multiple Choice

Page 2: Oakland Math Test

What number added to the sum of equal the number 1?

๐‘ฅ+ 13 +14=1

12๐‘ฅ+4+3=12

12๐‘ฅ=5

๐‘ฅ= 512

Page 3: Oakland Math Test

(43 )2

16=?

(43 )2

16=4

6

42=44=254

Page 4: Oakland Math Test

solve for w.

10๐‘ค=35๐‘ค=3.5

Page 5: Oakland Math Test

Jan is making clay coasters for an art fair. Each coaster costs $2.25 to make. If she sells the coasters for $4.00 each, how many will she have to sell to make a profit of exactly $70.00?

๐ฟ๐‘’๐‘ก ๐‘ฅ๐‘๐‘’ h๐‘ก ๐‘’๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘œ๐‘Ž๐‘ ๐‘ก๐‘’๐‘Ÿ๐‘  h๐‘  ๐‘’๐‘š๐‘Ž๐‘˜๐‘’ .๐‘๐‘Ÿ๐‘œ๐‘“๐‘–๐‘ก ๐‘œ๐‘“ h๐‘’๐‘Ž๐‘ ร— h๐‘ก ๐‘’๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘œ๐‘Ž๐‘ ๐‘ก๐‘’๐‘Ÿ๐‘ =๐‘๐‘Ÿ๐‘œ๐‘“๐‘–๐‘ก

(4.00โˆ’2.25 ) ๐‘ฅ=70.00

1.75 ๐‘ฅ=70๐‘ฅ=40

Page 6: Oakland Math Test

Four pieces of ribbon are cut from a length of ribbon that is 80 ft long. One of the pieces is 15 feet long. Two of the pieces are 7ยฝ feet long. One of the pieces is 3ยพ feet long. How many feet of ribbon are left from the original length?

๐ฟ๐‘’๐‘ก ๐‘ฅ ๐‘“๐‘ก ๐‘๐‘’ h๐‘ก ๐‘’ h๐‘™๐‘’๐‘›๐‘”๐‘ก ๐‘œ๐‘“ h๐‘ก ๐‘’ ๐‘™๐‘’๐‘“๐‘ก๐‘œ๐‘ฃ๐‘’๐‘Ÿ ๐‘๐‘–๐‘’๐‘๐‘’ .15+2(7 12 )+3 34 +๐‘ฅ=80

15+15+ 154 +๐‘ฅ=80154 +๐‘ฅ=50

15+4 ๐‘ฅ=2004 ๐‘ฅ=185๐‘ฅ=46 14 ๐‘“๐‘ก

Page 7: Oakland Math Test

A taxi cab charges $0.80 for the first of a mile and $0.10 for each additional of a mile. What is the cost of 3 mile trip?

๐ฟ๐‘’๐‘ก $ ๐‘ฅ๐‘๐‘’ h๐‘ก ๐‘’๐‘๐‘œ๐‘ ๐‘ก

๐‘ฅ=0.80+0.10 [ (3โˆ’ 15 )110

]๐‘ฅ=๐‘๐‘œ๐‘ ๐‘ก ๐‘œ๐‘“ 1 ๐‘ ๐‘ก 15๐‘š๐‘–๐‘™๐‘’+๐‘๐‘œ๐‘ ๐‘ก ๐‘œ๐‘“ h๐‘ก ๐‘’๐‘Ÿ๐‘’๐‘ ๐‘ก๐‘œ๐‘“ h๐‘ก ๐‘’๐‘ก๐‘Ÿ๐‘–๐‘

๐‘ฅ=0.80+0.10 [ 145110

]๐‘ฅ=0.80+0.10 (28)๐‘ฅ=0.80+2.80๐‘ฅ=3.60

Page 8: Oakland Math Test

Another Method: since taxi cab charges by tenths of a mile. For a 3 mile trip, there are 30 tenths of a mile. The first or 2 tenths of a mile costs 80ยข, the rest, 28 tenths of a mile costs 10ยข.

๐‘๐‘œ๐‘ ๐‘ก=80ยข+10ยข(28)

Continue

ยฟ80+280=360=$3.60

Page 9: Oakland Math Test

John works a variety of different jobs. On Monday he earned $50. Tuesday he earned $40. On Wednesday and Thursday he earned $30 each day, and ion Friday he earned $100. What was johnโ€™s average daily pay for the 5 days?

๐ด๐‘ฃ๐‘’๐‘Ÿ๐‘Ž๐‘”๐‘’=50+40+30+30+100

5

ยฟ2505 =$50

Page 10: Oakland Math Test

Evaluate:

3 (โˆ’2 )2โˆ’2 (โˆ’2 ) (3 )+32

ยฟ3 (4 )+12+9

ยฟ12+12+9

ยฟ33

Page 11: Oakland Math Test

Simplify:

(๐‘ฅ+ ๐‘ฆ )2โˆ’ (9๐‘ฅ๐‘ฆโˆ’6 ๐‘ฅ2 )ยฟ ๐‘ฅ2+2๐‘ฅ๐‘ฆ+ ๐‘ฆ2โˆ’9 ๐‘ฅ๐‘ฆ+6 ๐‘ฅ2

ยฟ7 ๐‘ฅ2โˆ’7๐‘ฅ๐‘ฆ+ ๐‘ฆ2

Page 12: Oakland Math Test

Multiply:

(2 ๐‘ฅโˆ’5 ) (6 ๐‘ฅ+4 )

ยฟ12 ๐‘ฅ2+8๐‘ฅโˆ’30 ๐‘ฅโˆ’20

ยฟ12 ๐‘ฅ2โˆ’22 ๐‘ฅโˆ’20

Page 13: Oakland Math Test

Divide:

12๐‘ฅ5โˆ’6 ๐‘ฅ3+4 ๐‘ฅ2

4 ๐‘ฅ2

ยฟ12๐‘ฅ5

4 ๐‘ฅ2โˆ’ 6 ๐‘ฅ

3

4 ๐‘ฅ2+4 ๐‘ฅ2

4 ๐‘ฅ2

ยฟ3 ๐‘ฅ3โˆ’ 32 ๐‘ฅ+1

Page 14: Oakland Math Test

Factor:

6 ๐‘ฅ3+27 ๐‘ฅ2โˆ’105 ๐‘ฅยฟ3 ๐‘ฅ (2๐‘ฅ2+9 ๐‘ฅโˆ’35)

ยฟ3 ๐‘ฅ (2 ๐‘ฅโˆ’5 ) (๐‘ฅ+7 )

Page 15: Oakland Math Test

Simplify:

๐‘ฅ2โˆ’5 ๐‘ฅ+4๐‘ฅโˆ’1

ยฟ(๐‘ฅโˆ’4 ) (๐‘ฅโˆ’1 )

๐‘ฅโˆ’1

ยฟ ๐‘ฅโˆ’4

Page 16: Oakland Math Test

Simplify:

ยฟ3+4=7

Page 17: Oakland Math Test

Evaluate: , find A

๐ด=๐‘ƒ (1+๐‘Ÿ )

๐ด=450 (1+0.12 )

๐ด=450(1.12)

๐ด=504

Page 18: Oakland Math Test

Simplify:

โˆš18 ๐‘ฅโˆ’4โˆš๐‘ฅ3ยฟ3 โˆš2 ๐‘ฅโˆ’4 ๐‘ฅ โˆš๐‘ฅ

Page 19: Oakland Math Test

Rationalize:

2+โˆš32โˆ’โˆš3

โˆ™(2+โˆš3 )(2+โˆš3 )

ยฟ 4+4โˆš3+34โˆ’3

ยฟ7+4 โˆš3

Page 20: Oakland Math Test

Solve:

3 ๐‘ฅ+7=2(๐‘ฅโˆ’1)

3 ๐‘ฅ+7=2๐‘ฅโˆ’2

๐‘ฅ+7=โˆ’2๐‘ฅ=โˆ’9

Page 21: Oakland Math Test

Find the sum of the roots:

๐‘ฅ2โˆ’6 ๐‘ฅ=7๐‘ฅ2โˆ’6 ๐‘ฅโˆ’7=0

(๐‘ฅ+1 ) (๐‘ฅโˆ’7 )=0

๐‘ฅ+1=0 ๐‘œ๐‘Ÿ ๐‘ฅโˆ’7=0

๐‘ฅ=โˆ’1๐‘œ๐‘Ÿ ๐‘ฅ=7

๐‘ ๐‘ข๐‘š๐‘œ๐‘“ ๐‘Ÿ๐‘œ๐‘œ๐‘ก๐‘ =โˆ’1+7=6

Page 22: Oakland Math Test

Solve for x:

1๐‘ฅ +

2๐‘ฅ=10

1+2=10 ๐‘ฅ

10 ๐‘ฅ=3

๐‘ฅ= 310

Page 23: Oakland Math Test

Solve the Inequality:

โˆ’2 ๐‘ฅ+3<5โˆ’2 ๐‘ฅ<2๐‘ฅ>โˆ’1

Page 24: Oakland Math Test

System of Equations:

(1 )2๐‘ฅ+3 ๐‘ฆ=โˆ’11(2 )6 ๐‘ฅ+๐‘ฆ=7

๐น๐‘Ÿ๐‘œ๐‘š (2): ๐‘ฆ=7โˆ’6 ๐‘ฅ๐‘†๐‘ข๐‘ ๐‘ก๐‘œ (1 ) :2 ๐‘ฅ+3 (7โˆ’6 ๐‘ฅ )=โˆ’11

2 ๐‘ฅ+21โˆ’18 ๐‘ฅ=โˆ’11โˆ’16 ๐‘ฅ=โˆ’32๐‘ฅ=2

๐‘ฆ=7โˆ’6 (2 )=7โˆ’14=โˆ’7

Solution:

Page 25: Oakland Math Test

Simplify the Expression:

2๐‘Žโˆ’ 2

(2๐‘Ž)โˆ’ 3

ยฟ2 (2๐‘Ž)3

๐‘Ž2

ยฟ2 (8๐‘Ž3 )๐‘Ž2

ยฟ16๐‘Ž3

๐‘Ž2

ยฟ16 ๐‘Ž

Page 26: Oakland Math Test

Scientific Notation:

(2.1ร—105 )2

ยฟ (2.1ร—105 ) (2.1ร—105 )

ยฟ 4.41ร—1010

Page 27: Oakland Math Test

Radicals:

3โˆš๐‘Ž โˆ™ 4โˆš๐‘Žยฟ๐‘Ž1 /3 โˆ™๐‘Ž1 /4

ยฟ๐‘Ž13 +14

ยฟ๐‘Ž412+ 312

ยฟ๐‘Ž712

ยฟ 12โˆš๐‘Ž7

Page 28: Oakland Math Test

Altogether Mark, John, and Alan earned $104. John earned twice as much as Mark and Alan earned $4 more than John. How much did Alan earn?

๐ฟ๐‘’๐‘ก $ ๐‘ฅ๐‘๐‘’ h๐‘ก ๐‘’๐‘Ž๐‘š๐‘œ๐‘ข๐‘›๐‘ก ๐‘€๐‘Ž๐‘Ÿ๐‘˜๐‘’๐‘Ž๐‘Ÿ๐‘›๐‘’๐‘‘h๐ฝ๐‘œ ๐‘›=2 ๐‘ฅ

๐ด๐‘™๐‘Ž๐‘›= h๐ฝ๐‘œ ๐‘›+4=2๐‘ฅ+4

๐‘€๐‘Ž๐‘Ÿ๐‘˜+ h๐ฝ๐‘œ ๐‘›+ ๐ด๐‘™๐‘Ž๐‘›=104๐‘ฅ+2๐‘ฅ+2๐‘ฅ+4=104

5 ๐‘ฅ+4=1045 ๐‘ฅ=100๐‘ฅ=20

๐‘€๐‘Ž๐‘Ÿ๐‘˜=$20

h๐ฝ๐‘œ ๐‘›=2 (20 )=$ 40

๐ด๐‘™๐‘Ž๐‘›=2 (20 )+4=$ 44

Page 29: Oakland Math Test

A train travels 4 hrs at 60 miles per hour and 2 hours at 75 miles per hour. What is the trainโ€™s average rate for 6 hours?

๐ด๐‘ฃ๐‘’๐‘Ÿ๐‘Ž๐‘”๐‘’=๐ท๐‘–๐‘ ๐‘ก๐‘Ž๐‘›๐‘๐‘’๐‘œ๐‘“ 1 ๐‘ ๐‘ก๐‘๐‘Ž๐‘Ÿ๐‘ก+๐ท๐‘–๐‘ ๐‘ก๐‘Ž๐‘›๐‘๐‘’๐‘œ๐‘“ 2๐‘›๐‘‘๐‘๐‘Ž๐‘Ÿ๐‘ก

๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™๐‘ก๐‘–๐‘š๐‘’

๐ด๐‘ฃ๐‘’๐‘Ÿ๐‘Ž๐‘”๐‘’=4 (60 )+2 (75 )

6

ยฟ3906 =65 h๐‘š๐‘

Page 30: Oakland Math Test

Graph:

2 ๐‘ฅ+๐‘ฆ=5๐‘ฆ=โˆ’2๐‘ฅ+5

๐‘š=โˆ’21 ๐‘œ๐‘Ÿ

2โˆ’1 ๐‘Ž๐‘›๐‘‘๐‘=5

Start with point A, where b = 5 or (0, 5).For point B, start from point A, go down 2 and go to the right 1, For point C, start from point A,go up 2 and go to the left 1.

๐ด

๐ต

๐ถ

Page 31: Oakland Math Test

Slope: Are these two lines parallel?

๐ฟ13 ๐‘ฆ=โˆ’2๐‘ฅ+6

๐‘ฆ=โˆ’ 23 ๐‘ฅ+2 ;๐‘š1=โˆ’23

๐ฟ2๐‘š2=7โˆ’105โˆ’3 =

โˆ’32

๐ฟ1๐‘Ž๐‘›๐‘‘๐ฟ2๐‘Ž๐‘Ÿ๐‘’๐‘๐‘‚๐‘‡ ๐‘๐‘Ž๐‘Ÿ๐‘Ž๐‘™๐‘™๐‘’๐‘™ ,๐‘ ๐‘™๐‘œ๐‘๐‘’๐‘ ๐‘Ž๐‘Ÿ๐‘’ ๐‘๐‘‚๐‘‡ ๐‘’๐‘ž๐‘ข๐‘Ž๐‘™ .

Page 32: Oakland Math Test

Write the equation of the line through (2, -1) and has slope m = 3. Write the equation in general form (standard form).

(2 ,โˆ’1 )๐‘ฅ1 , ๐‘ฆ1

๐‘ฆโˆ’ ๐‘ฆ1=๐‘š (๐‘ฅโˆ’๐‘ฅ1 )

๐‘ฆโˆ’ (โˆ’1 )=3(๐‘ฅโˆ’2)

๐‘š=3

๐‘ฆ+1=3 ๐‘ฅโˆ’6โˆ’3 ๐‘ฅ+๐‘ฆ=โˆ’7

Standard form

Page 33: Oakland Math Test

What is the distance between A(2, -5) and B(6, 3)? (Round to the nearest tenth).

๐ด (2 ,โˆ’5 )๐ต (6 ,3)๐‘ฅ1 ๐‘ฆ1๐‘ฅ2 ๐‘ฆ2

๐ท=โˆš๐‘Ÿ๐‘–๐‘ ๐‘’2+๐‘Ÿ๐‘ข๐‘›2

๐ท=โˆš ( ๐‘ฆ2โˆ’ ๐‘ฆ1 )2+ (๐‘ฅ2โˆ’๐‘ฅ1)2

๐ท=โˆš (3+5 )2+(6โˆ’2 )2

๐ท=โˆš (8 )2+ (4 )2

๐ท=โˆš64+16๐ท=โˆš80๐ท=4โˆš5

Page 34: Oakland Math Test

Graph:

๐‘ฆ=โˆ’๐‘ฅ2+4๐‘ฆ=โˆ’(๐‘ฅ2โˆ’4)๐‘ฆ=โˆ’ (๐‘ฅ+2 ) (๐‘ฅโˆ’2 )๐‘Ÿ๐‘œ๐‘œ๐‘ก๐‘  : ๐ด (โˆ’2 ,0 ) ,๐ต (2 ,0 )

๐‘Ž๐‘ฅ๐‘–๐‘ ๐‘œ๐‘“ ๐‘ ๐‘ฆ๐‘š๐‘š๐‘’๐‘ก๐‘Ÿ๐‘ฆ :๐‘ฅ=โˆ’ ๐‘2๐‘Ž

๐‘ฅ=โˆ’ 02 (โˆ’1 )

=0

๐‘Ž=โˆ’1 ;๐‘=0 ;๐‘=4

๐‘ฆ=โˆ’02+4=4๐‘€๐‘Ž๐‘ฅ=๐ถ(0 ,4 )

๐ด๐ต

๐ถ

Page 35: Oakland Math Test

.

ยฟ๐‘Ž2+2๐‘Ž+1+2๐‘Ž+2+3

ยฟ๐‘Ž2+4๐‘Ž+6

Page 36: Oakland Math Test

What is the domain of ?

2 ๐‘ฅ+6=02 ๐‘ฅ=โˆ’6๐‘ฅ=โˆ’3

The domain of f(x) is ALL real numbers except -3

๐ท๐‘œ๐‘š๐‘Ž๐‘–๐‘›=(โˆ’โˆž ,โˆ’3 )โˆช (โˆ’3 ,โˆž )

h๐‘Š ๐‘’๐‘›๐‘–๐‘  ๐‘“ (๐‘ฅ )๐‘ข๐‘›๐‘‘๐‘’๐‘“๐‘–๐‘›๐‘’๐‘‘?

Page 37: Oakland Math Test

What is the domain of

๐‘ฅโˆ’7 โ‰ฅ0๐‘ฅโ‰ฅ7h๐‘‡ ๐‘’๐‘‘๐‘œ๐‘š๐‘Ž๐‘–๐‘›๐‘œ๐‘“ ๐‘“ (๐‘ฅ ) ๐ด๐‘™๐‘™๐‘Ÿ๐‘’๐‘Ž๐‘™ ๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ๐‘ โ‰ฅ7

๐‘‘๐‘œ๐‘š๐‘Ž๐‘–๐‘›=ยฟ

Page 38: Oakland Math Test

Composition of functions: Find

( ๐‘“ โˆ™๐‘”) (3 )= ๐‘“ (3) โˆ™๐‘”(3)ยฟ [3 (3 )โˆ’2 ] โˆ™[32+1]

ยฟ7 โˆ™10( ๐‘“ โˆ™๐‘” ) (3 )=70

Page 39: Oakland Math Test

Composition of functions: Find .

๐‘“ (๐‘” (3 ) )= ๐‘“ (32+1)ยฟ ๐‘“ (10)ยฟ3 (10 )โˆ’2

๐‘“ (๐‘” (3 ))=28

๐‘“ (๐‘” (3 ) )=( ๐‘“ โˆ˜๐‘”)(3)