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8/3/2019 Obj. 11 Exponential Functions (Presentation)
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Obj. 11 Exponential Functions
Unit 4 Exponential and Logarithmic Functions
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Concepts & Objectives Exponential Functions (Obj. #11)
Use exponent properties to solve equations Substitute values into exponential functions
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Properties of Exponents Recall that for a variablexand integers a and b:
+
=ia b a b x x x
=
aa b
b
x
x
( ) =b
a abx x
=ba b ax x
= =a b x x a b
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Simplifying Exponents Example: Simplify
1.
2.
3.
3 2 2
2 5
25
5
x y z
y z
( )
42 3
2r s t
i2 3 1 2
5 6y y
=3 1 2 2 2 5
5 x y z
( ) ( )
=
4 2 4 34 4
2 r s t
( ) ( )
=
2 1
3 25 6 y
=2 4 3
5 y z
=8 12 4
16r s t
=
1
630y
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Exponential Functions Ifa > 0 and a 1, then
defines the exponential function with base a.
Example: Graph
Domain: ( )
Range: ( ) y-intercept: ( 1)
( ) =x
f x a
( ) = 2x
f x
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Exponential Functions
Characteristics of the graph of :
1. The points are on the graph.
2. Ifa > 1 thenf is an increasing function; if < a < 1 thenf is a decreasing function.
3. Thex-axis is a horizontal asymptote.
4. The domain is ( ) and the range is ( ).
( ) = x f x a
( ) ( )
11 1 1a
a
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Exponential Equations
Exponential equations are equations with variables as
exponents. If you can re-write each side of the equation using a
common base then you can set the exponents equal to
each other and solve for the variable.
Example: Solve =1
5125
x
=
3
5 5x
= 3x
=3
125 5
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Exponential Equations
Example: Solve+
=1 3
3 9x x
=2
9 3
( )
+
=
31 2
3 3
xx
+
=1 2 6
3 3x x
+ = 1 2 6x=7 x
( )+=
2 313 3
xx
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Exponential Equations
To solve an equation with exponents remember you can
undo the exponent by using the reciprocal. Solve
or
=5 2
243b
( ) =5
243b
= =5 243 3b= 9b
( ) ( )=2
25 552 243b
= 9b
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Compound Interest
The formula for compound interest(interest paid on
both principal and interest) is an important applicationof exponential functions.
Recall that the formula for simple interest, I= Prt, wherePis principal (amount deposited), ris annual rate of
interest, and tis time in years.
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Compound Interest Now, suppose we deposit $1000 at 10% annual interest.
At the end of the first year, we have
so our account now has 1000 + .1(1000) = $1100.
At the end of the second year, we have
so our account now has 1100 + .1(1100) = $1210.
( )( )( )= =1000 0.1 1 100I
( )( )( )= =1100 .1 1 110I
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Compound Interest If we continue, we end up with
This leads us to the general formula.
Year Account
1 $1100 1000(1 + .1)
2 $1210 1000(1 + .1)2
3 $1331 1000(1 + .1)3
4 $1464.10 1000(1 + .1)4
t 1000(1 + .1)t
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Compound Interest Formulas For interest compounded annually:
For interest compounded n times per year:
For interest compounded continuously:
where e is the irrational constant 2.718281
( )= +1t
A P r
= +
1
tn
rA Pn
=rt A Pe
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Examples1. If $2500 is deposited in an account paying 6% per year
compounded twice per year, how much is the accountworth after 10 years with no withdrawals?
2. What amount deposited today at 4.8% compoundedquarterly will give $15,000 in 8 years?
( )
= +
2 10.06
2500 12
A
( )
= +
4 8.048
15000 14
P
( )15000 1.4648P
= $10,240.35P
= $4515.28
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Examples3. If $8000 is deposited in an account paying 5% interest
compounded continuously, how much is the accountworth at the end of 6 years?
4. Which is a better deal, depositing $7000 at 6.25%compounded every month for 5 years or 5.75%compounded continuously for 6 years?
( )( )=
.05 68000A e
= $10,798.87A
( )
= +
=
12 5
.06257000 112
$9560.11
A
( )( )=
=
.0575 6
7000$9883.93
A e
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Homework College Algebra
Page 429: 51-66, (3s), 67, 68, 69-78 (3s), 83 Homework: 54, 60, 68, 72, 78
Classwork: Algebra & Trigonometry Page 247: 21-45 (3s)