OOPs Lab Madnual (1)

8/20/2019 OOPs Lab Madnual (1)

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PRACTICAL NO:- 01

AIM:-Write a program to find out the factorial of a given number.

OBJECTIVE:- Factorial is represented using ‘!’. So seven factorial will be written as (7!).

Factorial of a given number ‘n’ can be find out by the formula

n(n"#)(n"$)%%%%%%%%%..$#

or n! & n(n"#)(n"$)%%%%%%%%%..$#

'ero factorial (!) is defined as one i.e. ! & #.

SOURCE CODE:-//rogram to find out the factorial of a given number%..

*include+iostream, --eader file

using namespace std/int main( )

0

int i1 n1 fact/

cout++2enter the number2/

cin,, n/

for (i/ i+&n/ i33)

0

fact & facti/

4cout++2the factorial is2++fact/

return /

cin.get()/

cin.ignore()/

4

OUTPUT:-


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PRACTICAL NO:-02

AIM:- Write a program to check whether a given number is an Armstrong number ornot.

OBJECTIVE:- 5 number is 5rmstrong if the sum of cubes of individual digits of a numberis e6ual

to the number itself.

For eample 87# is an 5rmstrong number as

(888) 3 (777) 3 (###) & 87#.

SOURCE CODE:-


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int main( )

0

int n 1arm&1digit1num/

cout++2enter a number2/

cin,,n/

num&n/

while (n,)

0

digit&n:#/

n&n-#/

arm&(digitdigitdigit)3arm/

4

if(num&&arm)

cout++num++2is armstrong2/

else

cout++num++2is not armstrong2/

return /

cin.get()/

cin.ignore()/

4

OUTPUT:-


4/18

Try it…..

C++ Pror!" to #$% &'r(')t $*"'r.

C++ Pror!" to #$% &ri"' $*"'r .

C++ Pror!" to !r'! !$% &'ri"'t'r o( tri!$,'.

PRACTICAL NO:- 0 ;ate

AIM:- Create the equivalent of a four function calculator. The program should request theuser to

enter a number an operator and another number. !t should then carr" out the specified

arithmetical

operation: adding subtracting multipl"ing or dividing the two numbers. #!t should use a

switch

statement to select the operation$. %inall" it should displa" the result.

When it finishes the calculation the program should ask if the user wants to do another

calculation. The response can be &'( or &)(.

OBJECTIVE" 5 Four Function calculator can be made by using


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switch (opr)

0

case C3C result&num#3num$/

brea9/

case C"C result&num#"num$/

brea9/

case CC result&num#num$/

brea9/

case C-C result&num#-num$/

brea9/

default cout++2Dn?rong operator2/

4

Eoll no

#

cout++2Dn5nswerDt2++result/

cout++2Dnress for anotherDt2/

cin,,ch/

4 while((ch&&CC)GG(ch&&CyC))/

return /

cin.get()/

cin.ignore()/

4


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Eoll no

##

OUTPUT:-

PRACTICAL NO:-0

AIM:- Write a function called reversit # $ that reverses a string #an arra" of char$. *se afor loop that swaps the first and last characters then the second and ne+t to last characters

and so on. The string should be passed to reversit # $ as an argument.

Write a program to e+ercise reversit # $. The program should get a string from the user callreversit# $ and print out the result.


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ere we will use a for loop that swaps the first and last characters1 then the second and net to

last characters and so on. A a function which will reverse the input string.

SOURCE CODE:---rogram to reverse the input string..


using namespace std/

int reversit(char I J)/ --Function ;eclaration

int main( )

0

char string#IKJ/

cout++2Bnter the stringDn2/

gets(string#)/

reversit(string#)/ --Halling of Function reversit with input string

as argument.

return /

cin.get( )/ cin.ignore( )/

4

int reversit(char string#IKJ) --Function ;efinition

0

char string$IKJ/

int i1L19/

for (i&/string#IiJ!&CDC/i33)/

for (9&i1 L&/9,/9""1L33)

0

string$ILJ&string#I9"#J/

4

string$ILJ&CDC/

cout++2Dn2/

puts(string$)/

cout++2Dn>he reverse of input string is2/

puts(string$)/

return /

cin.get()/

cin.ignore()/

4


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OUTPUT:-


9/18

PRACTICAL NO:- 0/

AIM:- ,aising a number n to a power p is the same as multipl"ing n b" itself p times.Write a function called power # $ that takes a double value for n and an int value for p and

returns the result as double value. *se a default argument of for p so that if this

argument is omitted the number will be squared.

Write a main# $ function that gets values from the user to test this function.

OBJECTIVE:- >he nth of power $ can be find out as

($$$%%%%%..n times)

A

@f the argument p&$ is omitted then S6uare of a given number n can be find out as

S6uare & number number.

SOURCE CODE:---rogram to calculate the power of a given number%..



int power (int1 double)/ --Function ;eclaration of power

int s6uare (int)/ -- Function ;eclaration of s6uare

int main( )

0

int a/

double result/

cout++2enter a number2/

cin,,a/

result& power(a1 $)/ --Function calling

cout++2power of the number isDt2++result++=Dn=/

s6uare(a)/ --Function calling

return /

4

int power (int n1 double p ) --Function ;efinition of power

0 int c i/

for (i/ i+&n/ i&i3#)0

c cp/


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int s6uare (int a) -- Function ;efinition of s6uare

0

int c/

c&aa/

cout++2s6uare of the numberDt2++c/

return /

4

OUTPUT:-

AIM:- Write a C rograms to *nderstand 0ifferent %unction Call mechanism


11/18

OBJECTIVE:-

Swapping of two number by both call by value and call by reference mechanism1 using two

functions swapMvalue() and swapMreference respectively 1 by getting the choice from the user and

eecuting the user’s choice by switch"case.

SOURCE CODE:-*include+iostream.h,

*include+conio.h,

void main(void)

0 clrscr()/ int 1y1n/

void swap#(int1int)/

void swap$(int1inty)/

cout++2enter two values to be swappedDn2/

cin,,,,y/

cout++2Dnfor H5NN O P5NQB press#2/ cout++2Dnfor H5NN O EBFBEBRHB press$2/

cin,,n/

switch(n)

0

case #

cout++2DnH5NN O P5NQB2/ cout++2Dnvalues before swap()2++++2Dt2++y/ swap#(1y)/

cout++2Dnafter swap outside of swap#()2/

cout++2Dn&2++++2Dny&2++y/

brea9/

case $

cout++2DnH5NN O EBFBEBRHB2/ cout++2Dnvalue before swap2++++y/ swap$(A1Ay)/

cout++2Dnafter swap(outside of swap$)2++++y/

brea9/

4

getch()/

4

void swap#(int 1int y)

0

int temp/ temp&/ &y/ y&temp/cout++2Dnswapped values(inside swap#())2++++2Dt2++y/

4

void swap$(int 1int y)

0

int temp/

temp&/

&y/

y&temp/

cout++2Dnswapped value(inside swap$())2++++2Dt2++y/

4


12/18

Try it……

PRACTICAL NO:- 0/

AIM: C++ program to demonstrate the concept of classes with primitive data


13/18

Create a 10!2TA)C31 class with :

- feet and inches as data members

- member function to input distance

- member function to output distance

- member function to add two distance ob4ects

Write a main function to create ob4ects of 0!2TA)C3 class. !nput two distances and

output the sum.

SOURCE CODE:-

*include+iostream.h,

*include+conio.h,

class

distance0 int feet1inch/

public

void getdistance()/void putdistance()/

void adddistance(distance d#1distance d$)/

4/

void distancegetdistance()

0cout++2DnBnter the feet 2/

cin,,feet/cout++2DnBnter the inches 2/

cin,,inch/

4

void distanceputdistance()

0

cout++2DnDnfeet & 2++feet/cout++2Dtinch & 2++ inch/

4void distanceadddistance(distance d#1distance d$)

0

4

int

main()

0

inch&d#.i

nch3d$.in

ch/feet&inch-

#$/

inch&inch

:#$/

feet&feet3

d#.feet3d

$.feet/


14/18

distance d#1d$1d8/

clrscr()/cout++ 2Dn;istance # Dn2/

d#.getdistance()/

cout++ 2Dn;istance $ Dn2/d$.getdistance()/d8.adddistance(d#1d$)/

cout++2Dn>he Sum f two distance is 2/

d8.putdistance()/

getch()/return()/

4

OUTPUT:

;istance #

Bnter the feet #8

Bnter the inches ##

;istance $

Bnter the feet ##

Bnter the inches ##

>he Sum f two distance is

feet & $T inch & #


15/18

PRACTICAL NO:-1D!t'

AIM:- A hospital wants to create a database regarding its indoor patients. Theinformation to store include

a$ )ame of the patient

b$ 0ate of admission

c$ 0isease

d$ 0ate of discharge

Create a structure to store the date #"ear month and date as its members$. Create a base

class to store the above information. The member function should include functions to

enter information and

displa" a list of all the patients in the database. Create a derived class to store the age of the

patients. 5ist the information about all the to store the age of the patients. 5ist the

information about all the pediatric patients #less than twelve "ears in age$.

OBJECTIVE :- ere we use the concept of both structure and the class. ?e declare structureglobally which store the value of date i.e. year1 month1 and date and a class which store the above

given information of patients. ere an obLect of structure is declared in the class and is

accessible using dot (.) operator.

SOURCE CODE:---rogram to print the patients details%%%%..



struct date --;eclaration of a Structure

0

int d1y/

char mI$J/

4/

class patients

0

char nameI8J/

date dMofMadd/

char diseaseI8J/date dMofMdis/

public

void getdata( )

0

cout++2DnBnter the name of the patient2/

cin,,name/


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cout++2Bnter the date of admission2/

cin,,dMofMadd.d,,dMofMadd.m,,dMofMadd.y/

cout++2Bnter the name of disease2/

cin,,disease/

cout++2Bnter the date of ;ischarge2/

cin,,dMofMdis.d,,dMofMdis.m,,dMofMdis.y/

4

void display( )

0

cout++2Dn>he name of patient is2++name/

cout++2Dn>he date of admission is2++dMofMadd.d++2"2++dMofMadd.m++2"2++dMofMadd.y/

cout++2Dn>he name of disease is2++disease/

cout++2Dn>he date of ;ischarge is2++dMofMdis.d++2"2++dMofMdis.m++2"2++dMofMdis.y/

4

4/

class patientsMage public patients

0

public

int age/

publicvoid getdata( )

0

patientsgetdata( )/

cout++2Bnter the age of the patient2/

cin,,age/

4

void display( )

0

patientsdisplay( )/

cout++2Dn>he age of the patient is2++age/

4

4/

int main( )


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0 patientsMage pI8J/

for (int i&/i+8/i33)

0

cout++2Dnatient no2++i3#/

pIiJ.getdata()/

4

cout++2Dn>he list of all the patients2/

for (int i&/ i+8/ i33)

0

cout++2Dnatient no2++i3#/

pIiJ.display( )/

cout++2Dn2/

4

cout++2Dn>he list of all the pediatric patients (less than twelve years in age)2/

for (int i&/ i+8/ i33)

0

if(pIiJ.age+#$)

pIiJ.display()/

cout++2Dn2/

4

return /

cin.get( )/

cin.ignore( )/

4


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OUTPUT:-

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OOPs Lab Madnual (1)