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Recombinant Inbred Strains: Step 1: Initial Mendelian Cross. P 1. P 2. P 1 P 2 : Parental strains. Homozygous at all loci, but differing in phenotype. P 1 P 2 : Parental strains. Homozygous at all loci, but differing in phenotype. F 1 : First filial. - PowerPoint PPT Presentation
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P1 P2 : Parental strains.
Homozygous at all loci,but differing in phenotype.
F1: First filial.
Heterozygous at all loci.Breed with one another to get F2.
F2: Second filial.
Recombination in F1 gametes gives a mixtureof P1 and P2 chromosome sections.
P1 P2 : Parental strains.
Homozygous at all loci,but differing in phenotype.
F1: First filial.
Heterozygous at all loci.Breed with one another to get F2.
Recombinant Inbred Strains:Step 1: Initial Mendelian Cross
P1 P2
Recombinant Inbred Strains:Step 2: Sib-matings
× × × ×F2
× × × ×F3
× × × ×FA Lot
Recombinant Inbred Strains:Phenomenon 1: Recombination will break
up the red versus blue segments. Note how thereis more red/blue combinations in F3 than in F2.
× × × ×F2
× × × ×F3
Recombinant Inbred Strains:Phenomenon 2: Sib matings increase
homozygosity. After a large number of generations (20 is close to “large”), one creates
inbred strains that are identical at all loci.
× × × ×F3
× × × ×FA Lot
Common Sense Explanation:
Recombination breaks up the red versus blue areas.
But within a line of sib matings, the SAME red/blue combinations are transmitted and,
after a long time, become homozygous..
At each locus, ½ of the strains should be rr and the other 1/2will be bb. Do a t-test using phenotypic scores as thedependent variable and genotype ( rr versus bb) as the group variable.
If the test is significant, then that gene (or more likely, a geneclose to the genotyped locus) influences the phenotype.
A more complicated approach would use haplotypes.
Recombinant Inbred Strains:Linkage Analysis