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Parallel Lines and Proportional Parts Section 7.4

Parallel Lines and Proportional Parts

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Parallel Lines and Proportional Parts. Section 7.4. Proportional parts of triangles. Non parallel transversals that intersect parallel lines can be extended to form similar triangles. So, the sides of the triangles are proportional. Side Splitter Theorem or Triangle Proportionality Theorem. - PowerPoint PPT Presentation

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Page 1: Parallel Lines and Proportional Parts

Parallel Lines and Proportional Parts

Section 7.4

Page 2: Parallel Lines and Proportional Parts

Proportional parts of triangles

• Non parallel transversals that intersect parallel lines can be extended to form similar triangles.

• So, the sides of the triangles are proportional.

Page 3: Parallel Lines and Proportional Parts

Side Splitter Theorem or Triangle Proportionality Theorem

• If a line is parallel to one side of a triangle and intersects the other two sides, it divides those two sides proportionally.

• If BE || CD, then

A

C D

B EAB AE

BC ED

Page 4: Parallel Lines and Proportional Parts

AB||ED, BD = 8, DC = 4, and AE = 12.

• Find EC

• by ?

• EC = 6

C

B A

D E

CD CE

DB EA

4

8 12

EC

Page 5: Parallel Lines and Proportional Parts

UY|| VX, UV = 3, UW = 18, XW = 16.

• Find YX.

• YX = 3.2

W

U

YX

VUV YX

WV XW

3

15 16

YX

Page 6: Parallel Lines and Proportional Parts

Converse of Side Splitter

• If a line intersects the other two sides and separates the sides into corresponding segments of proportional lengths, then the line is parallel to the third side.

• If

• then BE || CD

A

C D

B E

AB AE

BC ED

Page 7: Parallel Lines and Proportional Parts

Determine if GH || FE. Justify

• In triangle DEF, DH = 18, and HE = 36, and DG = ½ GF.

• To show GH || FE,

• Show

• Let GF = x, then DG = ½ x.

DG DH

GF HE

Page 8: Parallel Lines and Proportional Parts

• Substitute

• Simplify

• Simplify

118236

x

x

1182

1 36

1 1

2 2

Page 9: Parallel Lines and Proportional Parts

• Since the sides are proportional, then GH || FE.

Page 10: Parallel Lines and Proportional Parts

Triangle Midsegment Theorem

• A midsegment of a triangle is parallel to one side of the triangle, and its length is one-half the length of that side.

• If D and E are mid-

• Points of AB and AC,

• Then DE || BC and

• DE = ½ BC

Page 11: Parallel Lines and Proportional Parts

Example

• Triangle ABC has vertices A(-2,2), B(2, 4) and C(4,-4). DE is the midsegment of triangle ABC.

• Find the coordinates of D and E.

• D midpt of AB• D(0,3)•

2 2 2 4,

2 2

Page 12: Parallel Lines and Proportional Parts

• E midpt of AC

• E(1, -1)

• Part 2 - Verify BC || DE

• Do this by finding slopes

• Slope of BC = -4 and slope of DE = -4

• BC || DE

Page 13: Parallel Lines and Proportional Parts

• Part 3 – Verify DE = ½ BC

• To do this use the distance formula

• BC = which simplifies to

• DE =

• DE = ½ BC

68 2 17

17

Page 14: Parallel Lines and Proportional Parts

Corollaries of side splitter thm.

• 1. If three or more parallel lines intersect two transversals, then they cut off the transversals proportionally.

Page 15: Parallel Lines and Proportional Parts

• If three or more parallel lines cut off congruent segments on one transversal, then they cut off congruent segments on every transversal.

Page 16: Parallel Lines and Proportional Parts

Examples

• 1. In the figure, Larch, Maple, and Nutthatch Streets are all parallel. The figure shows the distance between city blocks. Find x.

Page 17: Parallel Lines and Proportional Parts

• Find x and y.

• Given: AB = BC

• 3x + 4 = 6 – 2x

• X = 2

• Use the 2nd corollary to say DE = EF

• 3y = 5/3 y + 1

• Y = ¾

Page 18: Parallel Lines and Proportional Parts