PECivilExampecivilexamcom.dot5hosting.com/New-Pe-exam_org/PE... · Copyright © 2008-2014 pecivilexam.com all rights reserved-PE Civil Breadth Exam Set #1, #2 & #3 P-14 40. PROBLEM

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Copyright © 2008-2014 pecivilexam.com all rights reserved- PE Civil Breadth Exam Set #1, #2 & #3 P-1

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PE Exam for Civil Engineer

PE Civil Exam 40-Mix Questions & Answers (pdf Format) For Breath Exam (Morning Session) Set #-1

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Breadth Exam (morning session): This practice exam contains 40 mix questions and answers of all five areas of civil engineering:

Table Contents: Pages 1. Construction-8 Q&A 3 2. Geotechnical-8 Q&A 11 3. Structural-8 Q&A 19

4. Transportation-8 Q&A 27

5. Water Resources and Environmental-8 Q&A 35

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I. Construction

1. PROBLEM (Earth Work) An embankment cross section is shown in the Figure, the soil in the embankment has to be compacted and its dry unit weight is 106 lb/ft3, the moisture content is 12.5%. The borrow soil will be brought in 10 cubic yard truck at haul void ratio 0.7 and moisture content of 10%. The borrowed site soil has a void ratio 1.0 and specific gravity, Gs=2.67. What will be the most moist unit weight of the borrow soil in the haul truck? a. 80.00 lb/ft3 b. 85.0 lb/ft3 c. 108.00 lb/ft3 d. 112.00 lb/ft3

1. Solution: Moist unit weight, γ=(1+w)Gs γw /(1+e)=2.67x62.4(1+0.1)/(1+.70)=107.80 lb/ft3

Correct Solution is (c)

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2. 18. PROBLEM (Loading)

A concrete slab is 5” thick as shown in the Figure. The slab’s live load is 60 psf and the beam weight is 50 lb/ft. Determine the reaction of column RA where, the Concrete unit weight is 150 lb/ft3.

a 5.90 Kip b 7.00 Kip c 5.20 Kip d 8.50 Kip

18. Solution:

Beam weight=50lb/ft Slab dead load =150 x 5/12 =62.5 lb/ft2 Live Load = 60.0 lb/ft2 Total Load W==122.5 lb/ft2

For 10 ft wide slab W1=122.5 x10 +50=1275.00 lb/ft

For 5 ft wide slab W2=122.5 x5 +50= 662.50 lb/ft

∑M=0

Reaction at RA, RA x 18 = 662.5 x 10 x (5 +8)+1275 x 8 x 4 = 126925.00 lbs RA= 126925.00/18 = 7051.39= 7.05 Kip

Correct Solution is (b)

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PECivilExam.com


Breadth Exam (morning session): This practice exam contains 40 mixed questions and answers, each set being from all five areas of civil engineering:

Table Contents: Page

1. Construction-8 Q&A 3 2. Geotechnical-8 Q&A 11 3. Structural-8 Q&A 19

4. Transportation-8 Q&A 27

5. Water Resources and Environmental-8 Q&A 34

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II. Geotechnical 9. PROBLEM (Soil Classification)

A soil sample has been given in the following value. What is the AASHTO soil classification?

Sieve Passing No-10 100% No- 4 80% No-200 37% L.L 44 PI 12

a. A-7-6 b. A-7-5 c. A-7 d. A-4

9. Solution:

Soil passing #200 sieves is 37% which is greater than 35%; therefore it is a silty clay soil. So it falls under A-7 on AASHTO classification chart. Also, PI=12<(LL-30=14), Therefore, it is A-7-5.

Correct Solution is (b)

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19. PROBLEM (Member Design)

A simply supported beam is shown in the Figure. Determine the ultimate bending moment.

a. 67.00 Kip-ft b. 145.00 Kip-ft c. 221.00 Kip-ft d. 171.00 Kip-ft

19. Solution:

L=30 ft WLL=200 #/ft WDL=300 #/ft (Considering Dead Load factor=1.4 & Live Load factor=1.7) WuDL= 1.4 x 300=420.00 #/ft WuLL= 1.7 x 200 =340.00 #/ft Moment for uniformly Dead Load, MD= WuDLL2/8 Moment for triangular live Load, ML=0.0642 WuLL L2 Mu= WuDLL2/8 + 0.0642 WuLL L2= 47250.00+19645.20= 66895.20#-ft = 66.90Kip-ft Correct Solution is (a)

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PECivilExam.com


Breadth Exam (morning session): This practice exam contains 40 mixed questions and answers, each set being from all five areas of civil engineering:

Table Contents: Page 1. Construction-8 Q & A 3 2. Geotechnical-8 Q & A 11 3. Structural-8 Q & A 21

4. Transportation-8 Q & A 25

5. Water Resources and Environmental-8 Q & A 39

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I. Construction 1. PROBLEM (Earth Work)

A borrow pit contour elevation has been shown in the figure; it has to be cut. What is the average volume (yds3) cut from the borrow pit?

.

a. V=11333 yds3 b. V=5666 yds3 c. V=7536 yds3 d. V=2833 yds3

1. Solution:

Area of each grid, A=60x60=3600 ft2 V=(1x5+2x7+1x9+2x6+1x5+1x7+3x8+1x9) x [(3600/(4x27)]=2833 yds3

Total Volume of Borrow pit, V=2833 yds3

Correct Answer is (d)

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19. PROBLEM (Analysis)

Determine the reaction of YA in the frame as shown in Figure.

a. -6.25 K b. 6.25 K c. 31.25 K d. -12.5 K

19. Solution:

Positive moment is in the clockwise direction

ΣMA=0,

5 x 15 x (15/2) + 25 x15-YD x30=0

YD= 31.25 K

ΣH=0, YD+ YA-25=0,

YA=-31.25+25= -6.25 K

Correct Answer is (a)

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40. PROBLEM (Water Collection)

A community has a population of 40,000. What would be the storage tank capacity for fire flow?

a. 1.2 MG b. 3.6 MG c. 4.5 MG d. 2.2 MG

40. Solution:

P=40,000

The fire flow is calculated as follows:

Fire flow (gpm) =

Where "P" is the population in 1,000's of people. So, for our community with a population of 40,000, the fire flow would be:

The required storage capacity for fire flow is calculated as follows:

Capacity, Q = Fire flow × Duration Capacity, Q = 6,043 gpm × 360 minutes Capacity, Q = 2,175,480 gals

The storage tank must thus have a fire flow capacity of 2.2 million gallons.

Correct Answer is (d)

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PECivilExampecivilexamcom.dot5hosting.com/New-Pe-exam_org/PE... · Copyright © 2008-2014 pecivilexam.com all rights reserved-PE Civil Breadth Exam Set #1, #2 & #3 P-14 40. PROBLEM