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Percent dissociation of weak acidsPercent dissociation of weak acids
Percent dissociation = Percent dissociation =
[HA][HA]dissociateddissociated x 100% x 100%
[HA][HA]initialinitial
Increases as KIncreases as Kaa increases increases
For given acid, increases with dilutionFor given acid, increases with dilution
Dissociation increases with dilutionDissociation increases with dilution
Percent dissociation of acetic acid
0
1
2
3
4
5
0.00 0.20 0.40 0.60 0.80 1.00 1.20
Concentration/ M
% d
isso
ciat
ion
Polyprotic acidsPolyprotic acids
Dissociations are stepwiseDissociations are stepwise
HH22COCO33 + H + H22O = HO = H33OO++(aq) + HCO(aq) + HCO33--(aq)(aq)
HCOHCO33--(aq) + H(aq) + H22O = HO = H33OO++(aq) + CO(aq) + CO33
2-2-(aq)(aq)
7
32
331 103.4
][
]][[
xCOH
HCOOHKa
11
3
233
2 106.5][
]][[
xHCO
COOHKa
KKaa decreases with each step decreases with each step
It is harder to remove a proton from a It is harder to remove a proton from a negative ion than from a neutral moleculenegative ion than from a neutral molecule
Solution contains mixture of all speciesSolution contains mixture of all species
Strongest acid is the unionized molecule Strongest acid is the unionized molecule HHnnXX
Use the same strategy described Use the same strategy described earlierearlier
What are concentrations of species present in What are concentrations of species present in 0.020 M solution of carbonic acid?0.020 M solution of carbonic acid?
Step 1: initial species are HStep 1: initial species are H22COCO33 and H and H22OO
Step 2:Step 2: K Ka1a1 » K» Kww principal process is ionization of principal process is ionization of
HH22COCO33
ICE Age TwoICE Age Two
Principal Principal processprocess
Cod(aq) + HCod(aq) + H22O = CodHO = CodH++(aq) + OH(aq) + OH--(aq)(aq)
Initial concInitial conc 0.00120.0012 00 00
ChangeChange -x-x xx xx
Equilibrium Equilibrium concconc
0.0012 - x0.0012 - x xx xx
Step 5: Obtain x from KStep 5: Obtain x from Kaa
x
xxx
COH
HCOOHKa
020.0103.4
][
]][[ 7
32
331
5
72
7
103.9
020.0103.4
020.0103.4
xx
xx
x
xxx
X <<0.02
Step 6: Big concentrationsStep 6: Big concentrations
[[HH33OO++] = [HCO] = [HCO33--] = x = 9.3 x 10] = x = 9.3 x 10-5-5 M M
[[HH22COCO33] = 0.020 – x = 0.020 M] = 0.020 – x = 0.020 M
Step 7: small concentrationsStep 7: small concentrations
Obtained from subsidiary equilibria:Obtained from subsidiary equilibria:HCOHCO33
--(aq) + H(aq) + H22O = HO = H33OO++(aq) + (aq) + COCO332-2-(aq)(aq)
[CO[CO332-2-]] = K = Ka2a2 = 5.6 x 10 = 5.6 x 10-11-11 M M
In general, [AIn general, [A2-2-] = K] = Ka2a2
5
23
5
11
3
233
2
103.9
103.9
106.5][
]][[
x
COx
xHCO
COOHKa
Ignore H3O+ generated in
second ionization
Step 7 contd.Step 7 contd.
[OH[OH--] from dissociation of water:] from dissociation of water:
Mxx
x
OH
KOH w 10
5
14
3
101.1103.9
100.1
Step 8: Calculate pHStep 8: Calculate pH
pH = -logpH = -log1010[H[H33OO++]]
= -log(9.3x10= -log(9.3x10-5-5))
= 4.03= 4.03
Weak base equilibriaWeak base equilibria
Treated in an analogous way to weak acidsTreated in an analogous way to weak acids
Worked exampleWorked example
Calculate pH and concentrations of Calculate pH and concentrations of species in 0.0012 M solution of codeinespecies in 0.0012 M solution of codeine
Cod + HCod + H22O = CodHO = CodH++(aq) + OH(aq) + OH--(aq)(aq)
KKbb = 1.6x10 = 1.6x10-6-6
HH22O + HO + H22O = HO = H33OO++(aq) + OH(aq) + OH--(aq)(aq)
KKww = 1.0 x 10 = 1.0 x 10-14-14
Principal reaction is protonation of Principal reaction is protonation of codeinecodeine
Principal Principal processprocess
Cod(aq) + HCod(aq) + H22O = CodHO = CodH++(aq) + OH(aq) + OH--(aq)(aq)
Initial concInitial conc 0.00120.0012 00 00
ChangeChange -x-x xx xx
Equilibrium Equilibrium concconc
0.0012 - x0.0012 - x xx xx
Step 5: dissociationStep 5: dissociation
5
62
6
104.4
0012.0106.1
106.10012.0][
]][[
xx
xx
xx
xx
COD
OHCODHKb
X <<0.0012
Step 6: Big concentrationsStep 6: Big concentrations
[CodH[CodH++] = [OH] = [OH--] = x = 4.4x10] = x = 4.4x10-5-5 M M
[Cod] = 0.0012 – x = 0.0012 M (x[Cod] = 0.0012 – x = 0.0012 M (x«0.0012)«0.0012)
Step 7: small concentrationsStep 7: small concentrations
[H[H33OO++] from dissociation of water] from dissociation of water
Mx
x
x
OH
KOH w 10
5
14
3 103.2104.4
100.1
Step 8: Calculate pHStep 8: Calculate pH
pH = -logpH = -log1010[H[H33OO++]]
= -log(2.3x10= -log(2.3x10-10-10))
= 9.64= 9.64
Relationship between KRelationship between Kaa and K and Kbb for for
conjugate acid-base pairconjugate acid-base pairAcidAcid
HA + HHA + H22O = HO = H33OO++(aq) + A(aq) + A--(aq)(aq)
BaseBase
AA-- + H + H22O = HA(aq) + OHO = HA(aq) + OH--(aq)(aq)
][
]][[ 3
HA
AOHKa
][
]][[
A
OHHAKb
w
ba
KOHOH
A
OHHAx
HA
AOHxKK
]][[
][
]][[
][
]][[
3
3
K for the overall reaction is product K for the overall reaction is product of K’s for individual reactionsof K’s for individual reactions
In generalIn general
KKnetnet = K = K1 1 x Kx K22 x K x K33 x… x…
For conjugate acid-base pairsFor conjugate acid-base pairs
KKaa x K x Kbb = K = Kww
SaltsSalts
Products of acid-base neutralizationProducts of acid-base neutralization
HHClCl + + NaNaOH = OH = NaClNaCl + H + H22OO
HHClCl + + KKOH = OH = KClKCl + H + H22OO
HHNONO33 + + KKOH = OH = KNOKNO33 + H + H22OO
2H2HClCl + + CaCa(OH)(OH)22 = = CaClCaCl22 + 2H + 2H22OO
HHCNCN + + NaNaOH = OH = NaCNNaCN + H + H22OO
Unequally yokedUnequally yoked
Consequences for “neutralized” solutions of the Consequences for “neutralized” solutions of the following combinationsfollowing combinations
Strong acidStrong acid + + strong basestrong baseNEUTRALNEUTRAL
Strong acidStrong acid + + weak baseweak baseACIDICACIDIC
Weak acidWeak acid + + strong basestrong baseBASICBASIC
Salts that yield neutral solutionsSalts that yield neutral solutions
Group 1A cationsGroup 1A cations
Group 2A cations (except BeGroup 2A cations (except Be2+2+))
Anions from strong monoprotic acidsAnions from strong monoprotic acids
(Cl(Cl--, Br, Br--, I, I--, NO, NO33--, ClO, ClO44
--))
Salts that yield acid solutionsSalts that yield acid solutions
Salts of weak basesSalts of weak bases
NHNH44++(aq) + H(aq) + H22O = NHO = NH33 + H + H33OO++(aq) (aq)
Hydrated small polarizing metal cationsHydrated small polarizing metal cations
What is pH of a 0.10 M solution of AlClWhat is pH of a 0.10 M solution of AlCl33
KKaa = 1.4 x 10 = 1.4 x 10-5-5
Using prior strategy:Using prior strategy:– Al(HAl(H22O)O)66
3+3+, Cl, Cl-- and H and H22O are initial speciesO are initial species
– Al(HAl(H22O)O)663+3+ is stronger acid than H is stronger acid than H22O O
Principal Principal processprocess
Al(HAl(H22O)O)66++(aq) + H(aq) + H22O(l) = HO(l) = H33OO++(aq) + (aq) +
Al(HAl(H22O)O)55OHOH2+2+(aq)(aq)
Initial concInitial conc 0.100.10 00 00
ChangeChange -x-x xx xx
Equilibrium Equilibrium concconc
0.10 – x0.10 – x xx xx
pH = -log(1.2 x 10pH = -log(1.2 x 10-3-3) = 2.92) = 2.92
Mxx
xx
x
xxx
OHAl
OHOHAlOHKa
3
52
5362
2523
102.1
104.110.0
10.0104.1
])([
])()(][[
X << 1
Salts that yield basic solutionsSalts that yield basic solutions
Salts of weak acid and strong baseSalts of weak acid and strong base
CNCN--(aq) + H(aq) + H22O = HCN(aq) + OHO = HCN(aq) + OH--(aq)(aq)
Calculation of pH follows same strategy as Calculation of pH follows same strategy as for the salt of strong acid and weak base for the salt of strong acid and weak base except use expression for Kexcept use expression for Kbb
Weak acid and base: what then?Weak acid and base: what then?
Competition between relative acid strength Competition between relative acid strength of cation and base strength of anionof cation and base strength of anion
Consider (NHConsider (NH44))22COCO33
NHNH44++(aq) + H(aq) + H22O = HO = H33OO++(aq) + NH(aq) + NH33(aq) K(aq) Kaa
COCO332-2-(aq)(aq) + + HH22O = HCOO = HCO33
--(aq) + OH(aq) + OH--(aq) K(aq) Kbb
If KIf Kaa > K > Kbb then pH < 7 then pH < 7
If KIf Kaa < K < Kbb then pH > 7 then pH > 7
If KIf Kaa ≈≈ K Kbb then pH then pH ≈ 7≈ 7
Summing upSumming upTypes of saltTypes of salt ExamplesExamples Ions that react
with waterpH of solution
Cation from strong base, anion from strong acid
NaCl, Ba(NO3)2, None 77
Cation from weak base, anion from strong acid
NH4Cl, (CH3)4CCl Cation <7
Small highly charged cation, anion from strong acid
AlCl3, Cr(NO3)3
Hydrated cation < 7< 7
Cation from strong base, anion from weak acid
NaCN, KF, Na2CO3
Anion 7
Cation from weak base, anion from weak acid
NH4CN, NH4F
Both
<7 if Ka > Kb
>7 if Ka < Kb
≈7 if Ka ≈ Kb
Factors affecting acid strengthFactors affecting acid strength
How easily is the H – X bond broken?How easily is the H – X bond broken?– the less easily dissociated, the weaker the the less easily dissociated, the weaker the
acid.acid.
Bond strengthBond strength– Bond strength increases, acid strength Bond strength increases, acid strength
decreasesdecreases
PolarityPolarity– For a given bond strength, the more polar the For a given bond strength, the more polar the
more easily dissociated – closer to Hmore easily dissociated – closer to H++
In a group, bond strength is the In a group, bond strength is the more important factormore important factor
Polarity is not a good predictor: H-X polarity Polarity is not a good predictor: H-X polarity decreases down the group as acid strength decreases down the group as acid strength increasesincreasesBond strength decreases more strongly down Bond strength decreases more strongly down the groupthe group– Bond length increases sharplyBond length increases sharply
FF ClCl BrBr IIBond strength/kJmolBond strength/kJmol-1-1 567567 431431 366366 299299H – X bond length/H – X bond length/ÅÅ 0.9170.917 1.2741.274 1.4081.408 1.6081.608
ElectronegativityElectronegativity 4.04.0 3.03.0 2.82.8 2.52.5
Electronegativity more reliable Electronegativity more reliable indicator in a periodindicator in a period
H-X polarity increases across periodH-X polarity increases across period
Acid strength increases across periodAcid strength increases across period
Bond strength shows weaker trendBond strength shows weaker trend– Bond lengths vary littleBond lengths vary little
CC NN OO FFBond strength/kJmolBond strength/kJmol-1-1 410410 390390 460460 570570H – X bond length/H – X bond length/ÅÅ 1.0911.091 1.0081.008 0.9580.958 0.9170.917
ElectronegativityElectronegativity 2.52.5 3.03.0 3.53.5 4.04.0
Summing upSumming upElectronegativity increasesAcid strength increases
Bond strength decreases
Acid strength increases
NH3 H2O HF
PH3 H2S HCl
AsH3 H2Se HBr
Oxoacids and strength – where are Oxoacids and strength – where are the electrons goingthe electrons going
How to weaken the OH bond and increase How to weaken the OH bond and increase its polarity?its polarity?– Increase electronegativity of YIncrease electronegativity of Y– Increase oxidation number of Y (number of O Increase oxidation number of Y (number of O
atoms around Yatoms around Y
Both serve to withdraw electrons from the Both serve to withdraw electrons from the H making it more positive – closer to HH making it more positive – closer to H++
Increasing electronegativity of YIncreasing electronegativity of Y
In a homologous series, increasing electronegativity of Y In a homologous series, increasing electronegativity of Y increases strengthincreases strength– Y draws charge away from the H atom, more easily ionizedY draws charge away from the H atom, more easily ionized
NOTE: Opposite dependence to series HA, where A = F, NOTE: Opposite dependence to series HA, where A = F, Cl, Br, ICl, Br, I
Acid strengthAcid strength
AcidAcid HOIHOI HOBr HOCl
KKaa2.3 x 10-11 2.0 x 10-9 3.5 x 10-8
ElectronegativityElectronegativity 2.52.5 2.82.8 3.0
Increasing oxidation number (O atoms)Increasing oxidation number (O atoms)
More O atoms around Y, more acidicMore O atoms around Y, more acidic– The O atoms draw charge away from the H atom, The O atoms draw charge away from the H atom,
more easily ionizedmore easily ionized
Also think in terms of relative stabilities of the Also think in terms of relative stabilities of the oxoanions formed in the processoxoanions formed in the process
Acid strengthAcid strength
AcidAcidHOClHOCl HOClO HOClO2 HOClO3
Hypochlorous Chlorous Chloric Perchloric
KKaa3.5 x 10-8 1.2 x 10-2 -1 Large
Oxidation Oxidation number of Clnumber of Cl 1 3 5 7
Lewis acids – no protons requiredLewis acids – no protons required
Lewis acid: an electron pair acceptor (BFLewis acid: an electron pair acceptor (BF33))
Lewis base: an electron pair donor (NHLewis base: an electron pair donor (NH33))
ACCEPTORDONOR
BF3 NH3
Lewis definition casts the net Lewis definition casts the net furtherfurther
All Arrhenius acids are BrAll Arrhenius acids are Brønsted acidsønsted acids
All All BrBrønsted acids are Lewis acidsønsted acids are Lewis acids
The converses are not trueThe converses are not true
ExamplesExamples– AlAl3+3+(acid) H(acid) H22O (base)O (base)
– CuCu2+2+(acid) NH(acid) NH33 (base) (base)
– SOSO33 (acid) H (acid) H22O (base)O (base)