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•Electromagnetic Waves
•Interference of Sound Waves
•Young’s double slit experiment
•Intensity distribution for Young’s experiment
Electromagnetic Waves
•Existence predicted by James Clerk Maxwell (1865)
•Consist of “crossed” time-varying electric and magnetic fields
•Transverse wave, both electric and magnetic fields oscillate in a direction perpendicular to propagation direction
•No medium is necessary: Electromagnetic waves can propagate through a vacuum
•Constant speed of propagation through a vacuum: c ≈ 3 x 108 ms-1
Electromagnetic Waves
•It can be shown from MAXWELL’S EQUATIONS of Electromagnetism (See second year course) that the electric and magnetic fields obey the wave equations:
2
2
002
2
t
E
x
E yy
2
2
002
2
t
B
x
B zz
2
2
22
2 ),(1),(
t
txy
vx
txy
“standard” linear wave equation
00
1
c
Electromagnetic Waves
)sin(0 tkxEEy
)sin(0 tkxBBz
Where E0 and B0 are related by: E0 = cB0
INTENSITY of an EM wave E02
NB. we will see later that EM radiation sometimes behaves like a stream of particles (Photons) rather than a wave………………
Speed of light in a material
•Constant speed of propagation through a vacuum: c ≈ 3 x 108 ms-1
•But, when travelling through a material, light “slows down”
n
cv
n is the “refractive index” of the material.
Frequency of the radiation is constant, so from v = fλ, wavelength must decrease by a factor of 1/n.
(NB refractive index depends on the wavelength of the light)
Interference
First, consider case for sound waves, emitted by 2 loudspeakers:
Path difference =nλConstructive Interference
Path difference =(n+1/2)λDestructive Interference
(n = any integer, m = odd integer)
Interference
For interference effects to be observed,
•sources must emit at a single frequency
•Sources must have the same phase OR have a FIXED phase difference between them. This is known as COHERENCE
Conditions apply to interference effects for both light and sound
Young’s Double Slit Experiment
•Demonstrates wave nature of light
•Each slit S1 and S2 acts as a separate source of coherent light (like the loudspeakers for sound waves)
Young’s Double Slit Experiment
Consider intensity distribution on screen as a function of (angle measured from central axis of apparatus)……………………….
If light behaves as a conventional wave, then we expect high intensity (bright line) at a position on the screen for which r2-r1 = nλ
Expect zero intensity (dark line) at a position on the screen for which r2-r1=(n+1/2)λ
Young’s Double Slit Experiment
Assuming (justifiably) that R>>d, then lines r2 and r1 are approximately parallel, and path difference for the light from the 2 slits given by:
sin12 drr
Young’s Double Slit Experiment
Constructive interference:
Destructive interference:
nd sin
2
1sin nd
Young’s Double Slit Experiment
Y-position of bright fringe on screen: ym = Rtanm
Small , ie r1, r2 ≈ R, so tan ≈ sin
So, get bright fringe when:
d
nRym
(small only)
Young’s Double Slit Experiment:Intensity Distribution
For some general point P, the 2 arriving waves will have a path difference which is some fraction of a wavelength.
This corresponds to a difference in the phases of the electric field oscillations arriving at P:
tEE sin01
tEE sin02
Young’s Double Slit Experiment:Intensity Distribution
Total Electric field at point P:
tEtEEEETOT sinsin 0021
Trig. Identity:
2
1sin
2
1cos2sinsin
With = (t + ), = t, get:
tEETOT sin
2cos2 0
tEETOT sin
2cos2 0
So, ETOT has an “oscillating” amplitude:
2cos2 0
E
Since intensity is proportional to amplitude squared:
2cos4 22
0
EITOT
Or, since I0E02, and proportionality constant the same in both cases:
2cos4 2
0
IITOT
differencepath
2
difference phase
sin
2
d
2cos4 2
0
IITOT
sin
cos4 20
dIITOT
For the case where y<<R, sin ≈ y/R:
R
dyIITOT
20 cos4