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Phys. 121: Thursday, 13 Nov.● HW 11: due by 5:00 pm.● HW 12: ch. 16: # 16, 22, 59, and ch. 17, # 17, 20, and 46. Due date TBA (before Thanks. break).● Mast. Phys.: Assign. 10 due Tues. More ex. cred. up.● Reading: Finish chs. 16 and 17 by Tuesday. Exam 2: Test corr. through the OSL are available on problems 3, 4, 10, and 14; return them to me with your original exam by Tuesday. (Go to an OSL tutor; Work. 110 help session folks don't have the key.)● Exam 3: will cover chapters 9, 12, 13, and sect. 10.7, and will either be a week from today (the 20th) or the following Tues. (25th; Thanksgiving week). Usual stuff is already online.
Clickers: The moon takes about 27 days toorbit the Earth once, at a distance of about385,000 km. We can use this information toalso find...
a) the mass of the moon b) the mass of the sun c) the mass of the Earth d) the radius of the Earth e) the distance from the Earth to the sun
Clickers: The moon takes about 27 days toorbit the Earth once, at a distance of about385,000 km. What is the value of Earth's gat the moon's altitude? (RE = 6.37 x 10³ km,so this is about 60 RE .)
a) 9.8 m/s² , as always b) 9.8 cm/s² c) 2.8 cm/s² d) 9.8 mm/s² e) 2.8 mm/s²
Clickers: Circular orbits above the Earthhave a 1-day orbit for which radius r asa multiple of Earth's radius R? (Orbits
at R would take about 84 min.)
• a) r = 0.5 R
• b) r = 1.01 R
• c) r = 3.7 R
• d) r = 6.6 R
• e) r = 541 R
Clickers: An LED blinks once every1/10th of a second. The frequency of this
blinking is...
• a) 1/10 Hz• b) 1 Hz• c) 10 Hz• d) 1/10th s• e) 10 s
Chap. 14: OscillationsAny motion which repeats itself (exactly, or
nearly so) with the same time interval (T) is
an example of Periodic Motion.
The shortest time it takes to repeat is called
the Period, denoted by T (for “Time”),
measured in seconds (or minutes, hours, etc.)
From T, we can calculate the frequency f=1/T,
and the angular frequency ω = 2 π f.
Hooke's Law (Spring Force Law):the simplest type of restoring force
Now, we need to solve F = m ato find out what type of motion thiscauses:
Solution: Simple Harmonic Motion(SHM)
A = Amplitude = maximum distance on each sideof equilibrium that the object moves
Φ = Phase shift = adjustment for when the clockstarts (t=0)
Clickers:
A. 1.0 s.
B. 1.4 s.
C. 2.0 s.
D. 2.8 s.
E. 4.0 s.
A ball on a massless, rigid rod oscillates as a simple pendulum with a period of 2.0 s. If the ball is replaced with another ball having twice the mass, the period will be
Clickers:
A. The solid disk.
B. The circular hoop.
C. Both have the same period.
D. There’s not enough information to tell.
A solid disk and a circular hoop have the same radius and the same mass. Each can swing back and forth as a pendulum from a pivot at one edge. Which has the larger period of oscillation?
Yet another variant: the torsional oscillator(which produces actual angular oscillations):the pendulum is approximately one, for small angles.
Torsional oscillatorshave a restoringtorque, just as springshave a restoring force:
τ = - κ θ
Clickers: The angular (torsional) springconstant κ has the same units as...
a) an ordinary (linear) spring constant (k) b) Angle c) Force d) Torque e) Momentum
Angular version of SHM:
All of the previous stuff also applies to rotational
motion! We need only sub in θ for x, τ for F,
I for m, and κ (torsional spring constant) for k.
Result: SHM for θ, with ω² = κ/I instead of
k/m.
Angular Oscillators: ω versus d θ/dt
Unfortunately, we are overusing Greek letters!
To tell these two concepts apart:
ω is a CONSTANT, and represents the angular
speed of a wheel which turns once per period of
the motion. (Recall that its job is to convert time
to an angle!)
dθ /dt is the actual angular speed of the oscillating
object, and it WIGGLES WITH TIME like a sine
or cosine wave; it is NOT a constant!
Clickers:
A mass oscillates on a horizontal spring with period T 2.0 s. If the amplitude of the oscillation is doubled, the new period will be
A. 1.0 s.
B. 1.4 s.
C. 2.0 s.
D. 2.8 s.
E. 4.0 s
Slide 14-51