Practica Ultimo Metodo Newmark 1

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  • 7/26/2019 Practica Ultimo Metodo Newmark 1

    1/3

    f'c = 210 kg/cm2

    b h elemento 3 m

    0.35 0.35 C1 - C3 E = 2173706.512 T/m

    0.4 0.4 C20.45 0.45 C3

    1 C 1 = I = 0.00125052 m4 K = 1208.118 T/m

    2 C 1 = I = 0.00125052 m4 K = 1208.118 T/m

    3 C 2 = I = 0.00213333 m4 K = 2060.996 T/m

    4 C 2 = I = 0.00213333 m4 K = 2060.996 T/m

    5 C 2 = I = 0.00213333 m4 K = 2060.996 T/m6 C 2 = I = 0.00213333 m4 K = 2060.996 T/m

    7 C 2 = I = 0.00213333 m4 K = 2060.996 T/m

    8 C 2 = I = 0.00213333 m4 K = 2060.996 T/m

    9 C 3 = I = 0.00125052 m4 K = 1208.118 T/m

    10 C 3 = I = 0.00125052 m4 K = 1208.118 T/m

    11 C 4 = I = 0.00341719 m4 K = 3301.317 T/m

    b = 0.15 m

    h = 3 m

    L = 1.5 m

    P1= 10189.24927 T/m

    P2= 101.8924927 T/m

    K1= 30790.90 T/m

    K1= 307.91 T/cm

    Modulo de Elasticidad

    Placa

    Columna Altura del entrepiso

    RIGIDEZ PRIMER NIVEL

    DIRECCION X-X

    =

    =

    =

    UAP ALAS PERUANAS-CURSOS SISMORESISTENTE ALUMNO: ALEX BONY FLORES FLORES

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  • 7/26/2019 Practica Ultimo Metodo Newmark 1

    2/3

    f'c = 210 kg/cm2

    b h elemento 2.8 m

    0.35 0.35 C1 - C3 E = 2173706.512 T/m

    0.4 0.4 C20.45 0.45 C3

    1 C 1 = I = 0.00125052 m4 K = 1485.932 T/m

    2 C 1 = I = 0.00125052 m4 K = 1485.932 T/m

    3 C 2 = I = 0.00213333 m4 K = 2534.935 T/m

    4 C 2 = I = 0.00213333 m4 K = 2534.935 T/m

    5 C 2 = I = 0.00213333 m4 K = 2534.935 T/m6 C 2 = I = 0.00213333 m4 K = 2534.935 T/m

    7 C 2 = I = 0.00213333 m4 K = 2534.935 T/m

    8 C 2 = I = 0.00213333 m4 K = 2534.935 T/m

    9 C 3 = I = 0.00125052 m4 K = 1485.932 T/m

    10 C 3 = I = 0.00125052 m4 K = 1485.932 T/m

    11 C 4 = I = 0.00341719 m4 K = 4060.475 T/m

    b = 0.15 m

    h = 2.8 m

    L = 1.5 m

    P1= 12532.33101 T/m

    P2= 125.3233101 T/m

    K2 = 37871.47 T/m

    K2= 378.71 T/cm

    Modulo de Elasticidad

    Placa

    Columna Altura del entrepiso

    RIGIDEZ SEGUNDO NIVEL

    DIRECCION X-X

    =

    =

    =

    UAP ALAS PERUANAS-CURSOS SISMORESISTENTE ALUMNO: ALEX BONY FLORES FLORES

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  • 7/26/2019 Practica Ultimo Metodo Newmark 1

    3/3

    f'c = 210 kg/cm2

    b h elemento 2.5 m

    0.35 0.35 C1 - C3 E = 2173706.512 T/m

    0.4 0.4 C20.45 0.45 C3

    1 C 1 = I = 0.00125052 m4 K = 2087.628 T/m

    2 C 1 = I = 0.00125052 m4 K = 2087.628 T/m

    3 C 2 = I = 0.00213333 m4 K = 3561.401 T/m

    4 C 2 = I = 0.00213333 m4 K = 3561.401 T/m

    5 C 2 = I = 0.00213333 m4 K = 3561.401 T/m6 C 2 = I = 0.00213333 m4 K = 3561.401 T/m

    7 C 2 = I = 0.00213333 m4 K = 3561.401 T/m

    8 C 2 = I = 0.00213333 m4 K = 3561.401 T/m

    9 C 3 = I = 0.00125052 m4 K = 2087.628 T/m

    10 C 3 = I = 0.00125052 m4 K = 2087.628 T/m

    11 C 4 = I = 0.00341719 m4 K = 5704.675 T/m

    b = 0.15 m

    h = 2.5 m

    L = 1.5 m

    P1= 17607.02275 T/m

    P2= 176.0702275 T/m

    K3 = 53206.68 T/m

    K3= 532.07 T/cm

    Modulo de Elasticidad

    Placa

    Columna Altura del entrepiso

    RIGIDEZ TERCER NIVEL

    DIRECCION X-X

    =

    =

    =

    UAP ALAS PERUANAS-CURSOS SISMORESISTENTE ALUMNO: ALEX BONY FLORES FLORES

    You created this PDF from an application that is not licensed to print to novaPDF printer (http://www.novapdf.com)

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