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Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 1
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 2
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 3
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 4
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 5
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 6
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 7
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 8
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 9
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 10
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 11
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 12
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 13
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 14
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 15
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 16
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 17
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 18
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
eSolutions Manual - Powered by Cognero Page 19
Practice Test - Chapter 6
Graph each system and determine the number of solutions that it has. If it has one solution, name it.���y = 2x
y = 6 í x
62/87,21���To graph the system, write both equations in slope-intercept form. y = 2x y = íx + 6
The graph appears to intersect at the point (2, 4). You can check this by substituting 2 for x and 4 for y .
�
The solution is (2, 4).
���y = x í 3 y = í2x + 9
62/87,21���y = x í 3 y = í2x + 9
The graph appears to intersect at the point (4, 1). You can check this by substituting 4 for x and 1 for y .
�
The solution is (4, 1).
���x í y = 4 x + y = 10
62/87,21���To graph the system, write both equations in slope-intercept form. Equation 1:
Equation 2:
*UDSK�DQG�VROYH�� y = x í 4 y = íx + 10
The graph appears to intersect at the point (7, 3). You can check this by substituting 7 for x and 3 for y .
�
The solution is (7, 3).
���2x + 3y = 4 2x + 3y = í1
62/87,21���To graph the system, write both equations in slope-intercept form.Equation 1:
Equation 2:
Graph and solve.
The lines are parallel. So, there is no solution.
Use substitution to solve each system of equations.���y = x + 8
2x + y = í10
62/87,21���y = x + 8 2x + y = í10 Substitute x + 8 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (í6, 2).
���x = í4y í 3 3x í 2y = 5
62/87,21���x = í4y í 3 3x í 2y = 5 Substitute í4y í 3 for x in the second equation. �
� Use the solution for y and either equation to find the value for x.�
� The solution is (1, í1).
���*$5'(1,1*� Corey has 42 feet of fencing around his garden. The garden is rectangular in shape, and its length isequal to twice the width minus 3 feet. Define the variables, and write a system of equations to find the length and width of the garden. Solve the system by using substitution.
62/87,21���Sample answer: Let w be the width and let �EH�WKH�OHQJWK��7KHQ���w + 2 = 42 and � ��w í 3. Substitute 2w í 3 for �LQ�WKH�ILUVW�HTXDWLRQ� �
� Use the solution for w and either equation to find the value for . �
� The width of the garden is 8 feet and the length is 13 feet.
���08/7,3/(�&+2,&(� Use elimination to solve the system. 6x í 4y = 6 í6x + 3y = 0
$��(5, 6) %��(í3, í6) &��(1, 0) '��(4, í8)
62/87,21���Because 6x and í6x have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH��í6 for y in either equation to find the value of x. �
� The solution is (í3, í6). So, the correct choice is B.
���6+233,1*� Shelly has $175 to shop for jeans and sweaters. Each pair of jeans costs $25, each sweater costs $20, and she buys 8 items. Determine the number of pairs of jeans and sweaters Shelly bought.
62/87,21���Let j = the number of pairs of jeans and s = the number of sweaters. Then, j + s = 8 and 25j + 20s = 175.Solve the first equation for j . �
Substitute 8 ± s for j in the second equation. �
� Now, substitute 5 for s in either equation to find the value of j . �
� Shelly bought 3 pairs of jeans and 5 sweaters.
Use elimination to solve each system of equations.����x + y = 13
x í y = 5
62/87,21���Because y and íy have opposite coefficients, add the equations.�
� Now, substitute 9 for x in either equation to find the value of y . �
� The solution is (9, 4).
����3x + 7y = 2 3x í 4y = 13
62/87,21���Because 3x and 3x have the same coefficients, multiply equation 2 by í1, then add the equations.
� Add the equations. �
Now, substitute í1 for y in either equation to find the value of x. �
The solution is (3, í1).
����x + y = 8 x í 3y = í4
62/87,21���Because x and x have the same coefficients, multiply equation 2 by ±1 and then add the equations.
� Add the equations. �
� Now, substitute 3 for y in either equation to find the value of x. �
� The solution is (5, 3).
����2x + 6y = 18 3x + 2y = 13
62/87,21���Multiply the second equation by í3.
Now, because 6y and í6y have opposite coefficients, add the equations.�
� Now, substitute 3 for x in either equation to find the value of y . �
� The solution is (3, 2).
����0$*$=,1(6� Julie subscribes to a sports magazine and a fashion magazine. She received 24 issues this year. Thenumber of fashion issues is 6 less than twice the number of sports issues. Define the variables, and write a system ofequations to find the number of issues of each magazine.
62/87,21���Let f = the number of fashion issues and s = the number of sports issues. So, f + s = 24 and f = 2s ± 6.Substitute 2s ± 6 for f in the first equation. �
� Now, substitute 10 for s in either equation to find the value of f . �
� So, Julie received 14 fashion issues and 10 sports issues.
Determine the best method to solve each system of equations. Then solve the system.����y = 3x
x + 2y = 21
62/87,21���y = 3x x + 2y = 21 � Substitute 3x for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (3, 9).
����x + y = 12 y = x í 4
62/87,21���y = x ± 4 x + y = 12 � Substitute x ± 4 for y in the second equation. �
� Use the solution for x and either equation to find the value for y .�
� The solution is (8, 4).
����x + y = 15 x í y = 9
62/87,21���Because the y-terms have opposite coefficients, add the equations.�
� 1RZ��VXEVWLWXWH���� for x in either equation to find the value of y . �
� The solution is (12, 3).
����3x + 5y = 7 2x í 3y = 11
62/87,21���Because none of the terms are opposites, use elimination by multiplication to solve. Multiply the first equation by 2and the second equation by -3. Then add the equations to eliminate the x-term. 3x + 5y = 7 2x í 3y = 11 �
�
� �
� Substitute -1 for y in the second equation to find x. �
� The solution is (4, ±1).
����OFFICE SUPPLIES At a sale, Ricardo bought 24 reams of paper and 4 inkjet cartridges for $320. Britney bought 2 reams of paper and 1 inkjet cartridge for $50. The reams of paper were all the same price and the inkjet cartridges were all the same price. Write a system of equations to represent this situation. Determine the best method to solve the system of equations. Then solve the system.
62/87,21���24p + 4c = 320 2p + c = 50 � Solve equation 2 for c. c = 50 ± 2p � Substitute 50 ± 2p for c in the other equation.�
� Substitute 7.5 for p in equation 2. c = 50 ± 2(7.5) c = 50 ± 15 c = 35 � paper: $7.50; cartridge: $35
Solve each system of inequalities by graphing.����x > 2
y < 4
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x > 2 is dashed and is not included in the graph of the solution.
�7KH�JUDSK�RI�y �����LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of x > 2 and y < 4. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����x + y ���� y ��x + 2
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of x + y �����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y ���x + 2 is also solid and is included in the graph of the solution.
The solution of the system is the set of ordered pairs in the intersection of the graphs of x + y �����DQG�y ���x + 2. Overlay the graphs and locate the green region. This is the intersection.
The solution region is shaded in gray.
����3x í y > 9 y > í2x
62/87,21���*UDSK�HDFK�LQHTXDOLW\�� The graph of 3x í y �!���LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of y > í2x�LV�DOVR�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of 3x í y > 9 and y > í2x. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
����y ���x + 3 í4x í 3y > 12
62/87,21���Graph each inequality. �7KH�JUDSK�RI�y ����x�����LV�VROLG�DQG�LV�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The graph of í4x í 3y �!����LV�GDVKHG�DQG�LV�QRW�LQFOXGHG�LQ�WKH�JUDSK�RI�WKH�VROXWLRQ��
The solution of the system is the set of ordered pairs in the intersection of the graphs of y ����x + 3 and í4x í 3y > 12. Overlay the graphs and locate the green region. This is the intersection.
� The solution region is shaded in gray.
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Practice Test - Chapter 6