Presentation 7.4 Inscribed Angles

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    Vocabulary

    inscribed angle

    intercepted arc

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    An inscribed angle is an angle whose vertex

    is on a circle and whose sides contain chords

    of the circle.

    intercepted

    arc

    The arc that lies in the interior of an inscribed

    angle and has endpoints on the angle is called

    the intercepted arc of the angle.

    inscribed

    angle

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    Ifanangleisinscribedinacircle,thenits

    measureis

    C68 Inscribed AngleConjecture

    m ADB = m AB1

    2

    C

    A

    BD

    halfthe measureofits

    interceptedarc.

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    Find the measure of the QTS.

    Finding Measuresof Arcsand Inscribed Angles

    110

    R

    T Q

    mQRS = mQTS

    =1

    2

    = mQTS

    220 = mQTS

    S

    C

    110

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    Find the measure ofQRS.

    Finding Measuresof Arcsand Inscribed Angles

    165mQRS = mQTS

    =1

    2

    mQRS =( )

    R

    T Q

    S

    C

    165mQRS = 82.5

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    100

    m NMP = 50

    N

    P

    M 100C

    Find the measure ofNMP.

    Finding Measuresof Arcsand Inscribed Angles

    m NMP = mNP

    =1

    2100

    m NMP = ( )

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    N

    P

    M

    235

    C

    If mNMP = 235, then find the measure

    ofNMP

    Finding Measuresof Arcsand Inscribed Angles

    125

    m NMP = 62.5

    m NMP = ( )

    =1

    2

    mNP = 360 mNMP

    mNP = 360 - 235

    mNP = 125

    m NMP = mNP

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    W

    X

    Z

    Find the measure ofZWX

    Finding Measuresof Arcsand Inscribed Angles

    m ZCX = m ZX

    m ZWX =360 - 115

    = m ZX115

    m ZWX = 245

    C

    115

    =

    MAJOR ARC= 360 minorarc

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    C69

    A

    D

    CB

    C

    $ D

    Iftwoinscribedanglesofa

    circleinterceptthesamearc,

    thentheanglesare

    congruent.

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    You decide that the

    middle of the sixth row

    has the best viewing

    angle, point F.

    THEATER DESIGN When you go to the movies, you want to be close to the

    movie screen, but you dont want to have to move your eyes too much

    to see the edges of the picture.

    Usingthe Measureofan Inscribed Angle

    moviescreenE G

    F

    IfEand Gare the ends of the screen and you are at F, mEFGis

    called yourviewing angle.

    If someone is sitting

    there, where else can

    you sit to have the

    same viewing angle?

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    SOLUTION

    Draw the circle that is determined by the

    endpoints of the screen and the sixth rowcenter seat.

    Any other location on the circle will have the

    same viewing angle.

    Why?

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    Ifalloftheverticesofapolygonlieonacircle,thepolygon

    isinscribed inthecircleandthecircleiscircumscribed

    aboutthepolygon.Thepolygonisaninscribedpolygonandthecircleisacircumscribedcircle. Thepolygonissaid

    to be cyclic.

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    A righttriangleisinscribedinacircleiffthehypotenuseisadiameterofthecircle.

    C

    A

    B

    C70

    Forexample,

    If ACisadiameterofthecircle,thenB isarightangleand

    See GSP 10.5A

    ifB isarightangle,then

    ACisadiameterofthecircle.

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    Ex: A, B, C, andDlieonacircle,

    A

    D

    B

    C

    180mD +mB =

    360mABC +mADC =

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    A quadrilateralcanbeinscribedinacircleifand

    onlyifitsoppositeanglesaresupplementary.

    C

    E

    D

    F

    G

    C71

    Ex: D, E, F, and G lieonC,

    iff m D + m F = 180 and

    m E+ m G = 180.

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    Is AC a diameter?ABCD is an inscribed quadrilateral inP.

    C

    B

    D

    53

    P

    mABC =

    mCPD=

    mBCD =

    mADB =

    mBCA =

    mDBC =

    180

    26.5

    307

    63.5

    106

    127

    ?

    If mBC = 53, then find ... A 53

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    In the diagram, ABCD is inscribed in P.

    Find the measure of each angle.

    P

    B

    C

    D

    A

    2y

    3y

    5x

    3x

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    ABCD is inscribed in a circle,

    so opposite angles are

    supplementary.

    PB

    C

    D

    A2y

    3y

    5x

    3x

    3x+

    3y=

    180 5x+

    2y

    =180

    15x+ 6y= 540

    -6x- 6y=

    -360

    *3

    *-2

    9x = 180

    x =20

    3(20) + 3y= 180

    60 + 3y = 180

    3y=

    120y = 40

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    x= 20 andy= 40

    mA = 2y= 2(40)

    = 80

    mB = 3x

    = 3(20)= 60

    m

    C = 5x= 5(20)

    =100

    m

    D = 3y= 3(40)

    = 120

    PB

    C

    D

    A2y

    3y

    5x

    3x

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    C72:Parallel lines interceptcongruent arcs on a circle.

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    1. Givenacirclewith

    centerpoint P.B

    D

    F

    E

    CA

    H

    P

    G

    2. Thecircleisdivided

    into8congruent

    arcs.

    3. Thepointsoftheoctagonare A, B,

    H,labeled

    counter-clockwise.

    4. Connectevery 3rd

    pointwitha

    diagonal, AD, DG,

    GB, BEuntilyou

    returntopoint A.

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    mDAF = ( )90mDAF = 45

    Find mDAF

    360/8 = 45

    45*2 = 90

    F

    mDAF = mDF

    D

    E

    CB

    A

    H

    P

    G