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P6 | Chapter7 Circles | Practice 6 © JustEdu Holdings Pte Ltd -1- 1) Match the figures that have the same shaded area. Primary 6 Chapter 7 Circles Practice 6

Primary 6 Chapter 7 Circles Practice 6 - Just Edu · Primary 6 Chapter 7 Circles . Practice 6 . P 6 ... A piece of wire is bent to form 6 similar semicircles as shown i n the figure

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P6 | Chapter7 Circles | Practice 6

© JustEdu Holdings Pte Ltd -1-

1) Match the figures that have the same shaded area.

Primary 6 Chapter 7 Circles Practice 6

P6 | Chapter7 Circles | Practice 6

© JustEdu Holdings Pte Ltd -2-

Solve the following problem sums. All essential workings must be shown clearly.

Calculators are allowed. 2) Take π = 22

7 and solve the following questions.

(a) The figure shows a square with a quadrant cut out. Find the area of the shaded part.

Ans:__________

(b) Using the answer in (a), find the area of the shaded part.

Ans:__________

(c) Using the answer in (b), find the area of the shaded part.

Ans:__________

14 cm

14 cm

14 cm

14 cm

14 cm

14 cm

Students are drilled and exposed to different types of problem sums to prepare them for examination.

P6 | Chapter7 Circles | Practice 6

© JustEdu Holdings Pte Ltd -3-

As much as we would love to show you everything,

we cannot be showing you the best.

Do drop by any JustEdu centre to view the full set!

P6 | Chapter7 Circles | Practice 6

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Worked Example 1

The figure shows 3 identical circles overlapping one another where X, Y and Z are the centers of the 3 circles. Each shaded area is 60 cm2.

Find the area of the whole figure given that XY = YZ = 7 cm. (Take π = 227

)

Solution:

Area of one circle → 227

× 7 cm × 7 cm = 154 cm²

Area of 3 circles → 3 × 154 cm² = 462 cm² Area of figure → 462 cm² – (2 × 60) cm²

= 462 cm² – 120 cm² = 342 cm²

Or

Area of 1 circle – shaded area → 154 cm2 – 60 cm2 = 94 cm2 2 × 94 cm2 = 188 cm2 Area of figure →188 cm2 + 154 cm2 = 342 cm2

The area of the whole figure is 342 cm2.

7 cm X

Y Z

7 cm Worked examples are used to guide students on the answering of the question. It is also useful for students to refer to when revising.

P6 | Chapter7 Circles | Practice 6

© JustEdu Holdings Pte Ltd -5-

3) The fan below is made up of two quadrants overlapping each other. The area of the shaded part is 40 cm2. Find the total area of the unshaded part.

(Take π = 227

)

Ans:__________

4) The figure shows a rectangle ABCD overlapping a circle (centre A) with radius 7 m.

If AB is twice AD, find the perimeter of the figure. (Take π = 227

)

Ans:__________

14 cm

B

C

O A

D

P6 | Chapter7 Circles | Practice 6

© JustEdu Holdings Pte Ltd -6-

5) The figure below shows a pattern made up of 4 identical squares, 4 semicircles and 4 quadrants. (a) Find the total area of the shaded regions. (b) Find the total perimeter of the shaded regions.

(Take π = 227

)

Ans:(a)_________

(b)_________

14 cm

14 cm

14 cm 14 cm

P6 | Chapter7 Circles | Practice 6

© JustEdu Holdings Pte Ltd -7-

Do drop by our centre to view the full set of materials.

P6 | Chapter7 Circles | Practice 6

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Do drop by our centre to view the full set of materials.

P6 | Chapter7 Circles | Practice 6

© JustEdu Holdings Pte Ltd -9-

6) The figure below is made up of 2 identical small semicircles enclosed in a large semicircle. The area of region QOR is 76 cm2 and its perimeter is 35.8 cm. Given that PQ = QR = RS = 10 cm, find (a) the area of the shaded region and (b) the perimeter of the shaded region. (Take π = 3.14)

Ans:(a)_________

(b)_________

P Q R S

O

P6 | Chapter7 Circles | Practice 6

© JustEdu Holdings Pte Ltd -10-

7) The figure below is made up of a big quadrant ONP, a small quadrant OMR and a square OMQR. The area of the big quadrant is thrice the area of the small quadrant. Given that the length of NO is 72 cm, what is the area of the shaded part? Leave your answer in terms of π.

Ans:__________

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P6 | Challenging Word Problems: Area & Perimeter | Practice 1

© JustEdu Holdings Pte Ltd -1-

Calculators are allowed.

1) A piece of wire is bent to form 6 similar semicircles as shown in the figure. The area of the enclosed rectangle is 32 cm2. Find the length of the piece of wire. (Take π = 3.14)

Ans:__________

Primary 6 Challenging Word Problems: Area & Perimeter Practice 1

Please refer to Maths Power Guide: Power Summary Pg 26

Challenging word problems worksheets are given to further expose students to more challenging questions which help them in scoring their ‘A*’ in PSLE.

Worksheets are designed to complement our own in-house assessment book which comprises of Notes and some Practice questions to further enhance students’ understanding of the new topic.

P6 | Challenging Word Problems: Area & Perimeter | Practice 1

© JustEdu Holdings Pte Ltd -2-

2) The figure shown is made up of 4 identical circles, which are drawn in such a way that each circle intersects two other circles. The 4 circles meet at a common point E. Point E is also the centre of the square ABCD. The length of the square ABCD is 14 cm.

(a) Find the area of the shaded part. (b) Find the perimeter of the shaded part.

(Take π = 227

)

Ans:(a)_________

(b)_________

A B

D C

E

P6 | Challenging Word Problems: Area & Perimeter | Practice 1

© JustEdu Holdings Pte Ltd -3-

3) The figure below is made up of two semi-circles that overlapped each other. Express the area of the shaded regions in terms of π.

Ans:__________

*

16 cm

20 cm

P6 | Challenging Word Problems: Area & Perimeter | Practice 1

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4)

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P6 | Challenging Word Problems: Area & Perimeter | Practice 1

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Ans:__________

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P6 | Challenging Word Problems: Area & Perimeter | Practice 1

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Do drop by our centre to view the full set of materials.

P6 | Challenging Word Problems: Area & Perimeter | Practice 1

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5) Oscar cut two triangles from a piece of rectangular paper as shown. The area of Triangle P is 25.5 cm2 more than the area of Triangle Q. The length and breadth of the paper is 17 cm and 9 cm respectively. Find the base of Triangle Q.

Ans:__________

17 cm

P

Q

9 cm

?

*

P6 | Challenging Word Problems: Area & Perimeter | Practice 1

© JustEdu Holdings Pte Ltd -8-

6) In the diagram below, ABCD is a rectangle. The area of Triangle ABE is 50 m2 and the area of Triangle BCE is 34 m2. Given that BE = EC and DF = FC, find the area of AEFD.

Ans:__________

A B

C D

E

F

P6 | Challenging Word Problems: Area & Perimeter | Practice 1

© JustEdu Holdings Pte Ltd -1-

Calculators are allowed.

7) The figure below is made up of Rectangle BCDE, Triangle ABD and

Square ABEF. The length of Square ABEF is 48 cm. Find the difference between the shaded areas.

Ans:__________

A B C

D E F

48 cm

Primary 6 Challenging Word Problems: Area & Perimeter Practice 1

Worksheets are given at the end for students to revise challenging questions and answers are provided to promote independent learning.

P6 | Challenging Word Problems: Area & Perimeter | Practice 1

© JustEdu Holdings Pte Ltd -2-

8) In the figure below, two triangles are enclosed in Rectangle WXYZ. The length of VZ : WZ is 1 : 2 and the length of ZU : ZY is 1 : 4. The length of WX is 48 cm. Given that the area of Triangle UVW is 27 cm2, find the perimeter of Rectangle WXYZ.

Ans:__________

W X

Y Z U

V

P6 | Challenging Word Problems: Area & Perimeter | Practice 1

© JustEdu Holdings Pte Ltd -3-

Ans:__________

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