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8/3/2019 Probability Understanding Random Situations
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Chapter 6
Probability: Understanding
Random Situations
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Introduction
The study ofUncertainty
Changes Im not sure
to Im positive well succeed with probability 0.8
Cant predict for sure what will happen next
But can quantify the likelihood of what mighthappen
And can predict percentages well over the long run
e.g., a 60% chance of rain
e.g., success/failure of a new business venture
New terminology (words and concepts) Keeps as much as possible Certain (not random)
Put the randomness in only at the last minute
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Terminology
Random Experiment
A procedure that produces an outcome
Not perfectly predictable in advance
There are many random experiments (situations)
We will study them one at a time
Example: Record the income of a random family
Random telephone dialing in a target marketing area, repeat
until success (income obtained), round to nearest $thousand
Sample Space A list of all possible outcomes
Each random experiment has one (i.e., one list)
Example: {0, 1,000, 2,000, 3,000, 4,000, }
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Terminology (continued)
Event
Happens or not, each time random experiment is run
Formally: a collection of outcomes from sample space
A yes or no situation: if the outcome is in the list, the event
happens Each random experiment has many different events of interest
Example: the event Low Income ($15,000 or less)
The list of outcomes is {0, 1, 2, , 14,999, 15,000}
Example: the event Six Figures The list of outcomes is {100,000, 100,001, 100,002, , 999,999}
Example: the event Ten to Forty Thousand
The list of outcomes is {10,000, 10,001, , 39,900, 40,000}
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Terminology (continued)
Probability of an Event
A number between 0 and 1
The likelihood of occurrence of an event
Each random experiment has manyprobability numbers
One probability number for each event
Example: Probability of event Low Income is 0.17
Occurs about 17% over long run, but unpredictable each time
Example: Probability of event Six Figures is 0.08
Not very likely, but reasonably possible
Example: Probability of 10 to 40 thousand is 0.55
A little more likely to occur than not
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Sources of Probabilities
Relative Frequency
From data
What percent of the time the event happened in the past
Theoretical Probability From mathematical theory
Make assumptions, draw conclusions
Subjective Probability Anyones opinion, perhaps even without data or theory
Bayesian analysis uses subjective probability with data
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Relative Frequency
From data. Run random experiment n times
See how often an event happened
(Relative Frequency ofA) = (# of timesA happened)/n
e.g., of12 fligh
ts, 9 were on time. Relative frequency of the event on time is 9/12 = 0.75
Law of Large Numbers
Ifn is large, then the relative frequency will be close to
th
eprobability of an event
Probability is FIXED. Relative frequency is RANDOM
e.g., toss coin 20 times.Probability of heads is 0.5
Relative frequency is 12/20 = 0.6 , or9/20 = 0.45 , depending
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Relative Frequency (continued)
Suppose event has probability 0.25
In n = 5 runs of random experiment
Event happens: no, yes, no, no, yes
Relative frequency is 2/5 = 0.4 Graph of relative frequencies forn = 1 to 5
0.5
1 2 3 4 5
0.0
Relativefre
quency
Numbern of times random experiment was run
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Relative Frequency (continued)
As n gets larger
Relative frequency gets closer to probability
Graph of relative frequencies forn = 1 to 200
Relative frequency approach
es th
e probability
0
0.5
0 50 100 150 200
Numbern of times random experiment was run
Relativefrequency
Probability = 0.25
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Relative Frequency (continued)
About how far from the probability will the
relative frequency be?
The random relative frequency will be about one of its
standard deviations away from the (fixed) probability
Depends upon the probability and n
Farther apart when more uncertainty (probability near0.5)
Table 6.3.1
Probability Probability Probability
0.50 0.25 or 0.75 0.10 or 0.90
n = 10 0.16 0.14 0.09
25 0.10 0.09 0.06
50 0.07 0.06 0.04
100 0.05 0.04 0.03
1,000 0.02 0.01 0.01
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Theoretical Probability
From mathematical theory
One example: The Equally Likely Rule
If allNpossible outcomes in thesample space are
equally likely, then the probability of any eventA is
Prob(A) = (# of outcomes inA) / N
Note: this probability is nota random number. The
probability is based on the entire sample space
e.g., Suppose there are 35 defects in a production lot of400.
Choose item at random. Prob(defective) = 35/400 = 0.0875
e.g., Toss coin. Prob(heads) = 1/2
But: Tomorrow it may snow or not. Prob(snow) { 1/2
because snow and not snow are notequally likely
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Subjective Probability
Anyones opinion
What doyou think the chances are that the U.S.
economy will have steady expansion in the near future?
An economists answer
Bayesian analysis
Combines subjective probability with data to get results
Non-Bayesian Frequentist analysis computes using
only the data
But subjective opinions (prior beliefs) can still play a
background role, even when they are not introduced as
numbers into a calculation, when they influence the choice of
data and the methodology (model) used
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Bayesian and Nonbayesian Analysis
Bayesian Analysis
Frequentist (non-Bayesian) Analysis
Bayesian
Analysis
Data
Prior Probabilities
Model
Results
DataPrior
Beliefs
Model
Frequentist
AnalysisResults
Fig 6.3.3
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Combining Events
Complement of the eventA
Happens wheneverA does not happen
Union of eventsA andB
Happens wh
enever eith
erA orB or both
eventsh
appen Intersection ofA andB
Happens whenever bothA andB happen
Conditional Probability ofA GivenB
The updated probability ofA, possibly changed toreflect the fact thatB happens
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Complement of an Event
The event not A happens wheneverA does not
Venn diagram:A (in circle), not A (shaded)
Prob(not A) = 1 Prob(A)
If Prob(Succeed) = 0.7, then Prob(Fail) = 10.7 = 0.3
Anot
A
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Union ofTwo Events
Union happens whenever either (or both) happen
Venn diagram: Union A orB shaded)
e.g.,A = get Intel job offer,B = get GM job offer
Did the union happen? Congratulations! You have a job
e.g., Did I have eggs or cereal for breakfast? Yes
A B
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Intersection ofTwo Events
Intersection happens whenever both events happen
Venn diagram: Intersection A andB shaded)
e.g.,A = sign contract,B = get financing
Did the intersection happen? Great! Project has been launched!
e.g., Did I have eggs and cereal for breakfast? No
A B
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Relationship Betweenandand or
Prob(A orB) = Prob(A)+Prob(B)Prob(A andB)
= +
Prob(A andB) = Prob(A)+Prob(B)Prob(A orB)
Example: Customer purchases at appliance store Prob(Washer) = 0.20
Prob(Dryer) = 0.25
Prob(WasherandDryer) = 0.15
Then we must have
Prob(WasherorDryer) = 0.20+0.250.15 = 0.30
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Conditional Probability
Examples
Prob (Wingiven Ahead at halftime)
Higher than Prob (Win) evaluated before the game began
Prob (Succeedgiven Good results in test market) Higher than Prob (Succeed) evaluated before marketing study
Prob (Get jobgiven Poor interview)
Lower than Prob (Get job given Good interview)
Prob (Have AIDSgiven Test positive) Higher than Prob (Have AIDS) for the population-at-large
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Conditional Probability (continued)
Given the extra information thatB happens forsure, how must you change the probability forA to
correctly reflect this new knowledge?
This is a (conditional) probability aboutA
The eventB gives information
Unconditional
The probability ofA
Conditional
A new universe, sinceB must happen
Prob (AgivenB) =
Prob (A andB)
Prob (B)
A B
A andB B
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Conditional Probability (continued)
Key words that may suggest conditionalprobability
By restricting attention to a particular situation where
some condition holds (thegiven information) Given
Of those
If
When
Within (this group)
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Conditional Probability (continued)
Example: appliance store purchases Prob(Washer) = 0.20
Prob(Dryer) = 0.25
Prob(WasherandDryer) = 0.15
Conditional probability of buying a Dryergiven thatthey bought a Washer
Prob(Dryergiven Washer)
= Prob(WasherandDryer)/Prob(Washer) = 0.15/0.20 = 0.75
75% of those buying a washer also bought a dryer
Conditional probability ofWashergiven Dryer
= Prob(WasherandDryer)/Prob(Dryer) = 0.15/0.25 = 0.60
60% of those buying a dryer also bought a washer
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Independent Events
Two events are Independent if information aboutone does not change the likelihood of the other
Three equivalent ways to check independence
Prob (AgivenB) = Prob (A)
Prob (BgivenA) = Prob (B)
Prob (A andB) = Prob (A) v Prob (B)
Two events are Dependent if not independent
e.g., Prob(WasherandDryer) = 0.15 Prob (Washer) v Prob (Dryer) = 0.20 v 0.25 = 0.05
Washerand Dryerare not independent
They are dependent
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Mutually Exclusive Events
Two events are Mutually Exclusive if they cannotbothhappen, that is, if
Prob(A andB) = 0
No overlapin Venn diagram
Examples
Profit and Loss (for a selected business division)
Green and Purple (for a manufactured product)
Country Squire and Urban Poor(marketing segments)
Mutually exclusive events are dependentevents
A B
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Probability Trees
A method for solving probability problems
Given probabilities for some events (perhaps union,
intersection, or conditional)
Find probabilities for other events
Record t he basic information on the tree Usually three probability numbers are given
Per haps two probability numbers if events are independent
The tree helps guide your calculations
Each column of circled probabilities adds up to 1
Circled prob times conditional prob gives next probability
For each group of branches
Conditional probabilities add up to 1
Circled probabilities at end add up to probability at start
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Probability Tree (continued)
Shows probabilities and conditional probabilities
P(A andB)
P(A andnotB)
P(notA andB)
P(notA andnotB)
P(A)
P(notA)
EventB
EventA
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Example: Appliance Purchases
First, record the basic information Prob(Washer) = 0.20, Prob(Dryer) = 0.25
Prob(WasherandDryer) = 0.15
0.15
0.20
Dryer?Washer?
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Example (continued)
Next, subtract: 10.20 = 0.80, 0.250.15 = 0.10
0.15
0.10
0.20
0.80
Dryer?Washer?
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Example (continued)
Now subtract: 0.200.15 = 0.05, 0.800.10 = 0.70
0.15
0.05
0.10
0.70
0.20
0.80
Dryer?Washer?
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Example (completed tree)
Now divide to find conditional probabilities0.15/0.20 = 0.75, 0.05/0.20 = 0.25
0.10/0.80 = 0.125, 0.70/0.80 = 0.875
0.15
0.05
0.10
0.70
0.20
0.80
Dryer?Washer?
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Example (finding probabilities)
Finding probabilities from the completed treeP(Washer) = 0.20
P(Dryer) = 0.15+0.10 = 0.25
P(WasherandDryer) = 0.15
P(WasherorDryer) =
0.15+0.05+0.10 = 0.30
P(Washerand notDryer) = 0.05
P(Dryergiven Washer) = 0.75
P(Dryergiven notWasher) = 0.125
P(Washergiven Dryer) = 0.15/0.25 = 0.60
(using the conditional probability formula)
0.15
0.05
0.10
0.70
0.20
0.80
Dryer?Washer?
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Example: Venn Diagram
Venn diagram probabilities correspond to right-hand endpoints of probability tree
Washer Dryer
0.05
0.15
0.10
0.70
P(WasherandDryer)
P(WasherandnotDryer )
P(notWasher andDryer)
P(notWasher andnotDryer )
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Example: Joint Probability Table
Shows probabilities for each event, theircomplements, and combinations using and
Note: rows add up, and columns add up
Washer
Yes No
D
ryer Yes
No
0.15 0.10
0.700.05
0.20 0.80 1
0.75
0.25
P(WasherandDryer)
P(WasherandnotDryer )
P(notWasher andDryer)
P(notWasher andnotDryer )
P(Dryer)
P(notDryer)
P(Washer)