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2017 MSA Inv 3.notebook 1 September 19, 2017 Sep 78:54 AM Problem 3.1 2nd Period

Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

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Page 1: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

1

September 19, 2017

Sep 7­8:54 AM

Problem 3.1   2nd Period

Page 2: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

2

September 19, 2017

Sep 7­8:54 AM

Problem 3.1   3rd Period

Page 3: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

3

September 19, 2017

Jan 3­8:34 AM

Problem 3.2 2nd Period

10 = 3x + 4

2(x+2) = 12

2x + 4 = 12

3x = 2x + 12

Page 4: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

4

September 19, 2017

Jan 3­8:35 AM

Problem 3.2 2nd Period

3x + 3 = 30

3x + 3 = 2x + 12

2x + 21 = 5x + 3

Page 5: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

5

September 19, 2017

Jan 3­8:34 AM

Problem 3.2 3rd Period

Page 6: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

6

September 19, 2017

Jan 3­8:35 AM

Problem 3.2 3rd Period

Page 7: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

7

September 19, 2017

Jan 4­8:54 AM

Problem 3.3 2nd Period

Page 8: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

8

September 19, 2017

Jan 4­10:43 AM

B1.   30 = 6 + 4x

B2.   7x = 5 + 5x

B3.   7x + 2 = 12 + 5x

B4.   2(x + 4) = 16

Problem 3.3 2nd PeriodSOLVE CHECK

.

Page 9: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

9

September 19, 2017

Jan 4­8:54 AM

Problem 3.3 3rd Period

Page 10: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

10

September 19, 2017

Jan 4­10:43 AM

B1.   30 = 6 + 4x

B2.   7x = 5 + 5x

B3.   7x + 2 = 12 + 5x

B4.   2(x + 4) = 16

Problem 3.3 3rd PeriodSOLVE CHECK

.

Page 11: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

11

September 19, 2017

Jan 4­10:47 AM

Problem 3.4  2nd Period

1a.  5x + 10 = 20

1b.  5x ­ 10 = 20

SOLVE CHECK

1c.  5x + 10 = ­20

1d.  5x ­ 10 = ­20

1e.  10 ­ 5x = 20

1f.  10 ­ 5x = ­20

.

Page 12: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

12

September 19, 2017

Jan 4­10:47 AM

Problem 3.4  3rd Period

1a.  5x + 10 = 20

1b.  5x ­ 10 = 20

SOLVE CHECK

1c.  5x + 10 = ­20

1d.  5x ­ 10 = ­20

1e.  10 ­ 5x = 20

1f.  10 ­ 5x = ­20

.

Page 13: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

13

September 19, 2017

Jan 4­10:54 AM

Problem 3.4  2nd PeriodSOLVE CHECK

2a.  1x + 6 = 12       4

2b. 1 1x + 2x = 6 1         2                 2

2c.  3 = ­x + 1       5

2d.   3.5x = 130 + 10x

2e.   15 ­ 4x = 10x + 45

.

Page 14: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

14

September 19, 2017

Jan 4­10:54 AM

Problem 3.4  3rd PeriodSOLVE CHECK

2a.  1x + 6 = 12       4

2b. 1 1x + 2x = 6 1         2                 2

2c.  3 = ­x + 1       5

2d.   3.5x = 130 + 10x

2e.   15 ­ 4x = 10x + 45

.

Page 15: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

15

September 19, 2017

Sep 15­9:24 AM

Page 16: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

16

September 19, 2017

Sep 15­9:34 AM

Page 17: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

17

September 19, 2017

Sep 19­8:54 AM

Page 18: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

18

September 19, 2017

Sep 18­9:48 AM

Page 19: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

19

September 19, 2017

Sep 19­9:03 AM

Page 20: Problem 3.1 2nd Period · 2017. 9. 19. · 2017 MSA Inv 3.notebook 3 September 19, 2017 Jan 38:34 AM Problem 3.2 2nd Period 10 = 3x + 4 2(x+2) = 12 2x + 4 = 12 3x = 2x + 12

2017 MSA Inv 3.notebook

20

September 19, 2017

Sep 19­10:06 AM