Programming C for Engineers An exercise is posted on the web site! Due in one week Single submission

Programming C for Engineers

An exercise is posted on the web site! Due in one week Single submission

Selection Statements

Selects statements to execute based on the value of an expression The expression is sometimes called the

controlling expression Selection statements:

if statement switch statement

Selection statements: if

used to execute conditionally a statement or block of code.

if (expression)

statement

If expression is true, statement is executed (what is true?).

statement can be replaced by a block of statements, enclosed in curly braces.

An example

/* This program displays the absolute value of a number given by the user */

#include <stdio.h>

int main(){

double num;

printf("Please enter a real number: ");scanf("%lf", &num);if (num<0)

num = -num;

printf("The absolute value is %g\n", num);

return 0;}

if-else statement

if (expression) statement1

else statement2

if expression is true, statement1 is executed. if expression is false, statement2 is executed both statements can be (and very often are)

replaced by blocks of statements (“compound statements”)

An example (fragment)

int first, second, min;/* … */if (first < second) { min = first; printf ("The first number is smaller than the second.\n");} else { min = second; printf ("The second number is smaller than the first\n");}

printf("The smaller number is equal to %d\n", min);

True or false

In C, every expression has a numeric value An expression is ‘true’ when its value is

non-zero If it is zero, it is false Therefore, in the following –

if (expression) statement

statement is executed if expression is non zero.

More about operators

In C, every expression has a numeric value

When using arithmetical operators (+, -, *, /) this is straightforward The value of A+B is the sum of A and B And so on…

More about operators

Expressions with relational operators (<, <=, >, >=, etc.) have values as well (intuitively, we are used to thinking about them as ‘true’ or ‘false’)

A < B evaluates to zero if A is larger than or equal to B, and some non-zero value if A is smaller than B

The exact non-zero value varies (and is not important for that matter)

Relational operators

They are: A == B (Note the difference from A = B!!!!!) A != B A < B A > B A <= B A >= B

The value of the expression is non-zero if it’s true, zero if it’s false

An exampleint a, b;

printf("Enter two numbers\n");scanf("%d%d", &a, &b);

if (a == b){

printf("The numbers equal %d\n", a);printf("The expression a == b is %d\n", a ==

b);}else{

printf("The numbers are not equal\n");printf("The expression a == b is %d\n", a ==

b);}

The assignment operator =

The assignment operator is also an operator. Hence, expressions involving it have a numeric value.

This value equals to whatever appears on the right of the assignment operator

For example: (x = 4) evaluates to 4 (y = 0) evaluates to 0

A very common mistake

Very often a programmer might confuse between the equality operator and the assignment operator: if (x==4) … if (x=4) …

The second is usually a mistake, but legal in C so the compiler doesn’t warn us about it!

Example

/* This program exemplifies the difference between the equality relational

operator and the assignment operator. */

#include <stdio.h>

int main(){

int i = 2;

printf("i = %d\n", i);printf("(i==4) = %d\n", i==4);printf("i = %d\n", i);printf("(i=4) = %d\n", i=4);printf("i = %d\n", i);

}

Example



#include <stdio.h>

int main(){

int i = 2;


}

Example



#include <stdio.h>

int main(){

int i = 2;


}

i= 2

Example



#include <stdio.h>

int main(){

int i = 2;


}

Example



#include <stdio.h>

int main(){

int i = 2;


}

(i==4) = 0

Example



#include <stdio.h>

int main(){

int i = 2;


}

Example



#include <stdio.h>

int main(){

int i = 2;


}

i= 2

Example



#include <stdio.h>

int main(){

int i = 2;


}

Example



#include <stdio.h>

int main(){

int i = 2;


}

(i=4) = 4

Example



#include <stdio.h>

int main(){

int i = 2;


}

Example



#include <stdio.h>

int main(){

int i = 2;


}

i= 4

Logical operators

Allows to evaluate two or more expressions - !A – ‘not’ - True when A is not, and vice

versa. A && B – ‘and’ - True when both A and B

are true A || B – ‘or’ (inclusive or) - True when

either A or B (or both) are true

A silly example

#include <stdio.h>

int main(void) {

int grade;

printf("Please enter your grade: ");scanf("%d", &grade);

if (grade < 0 || grade > 100)printf("This is not a valid grade!\n");

elseprintf("This is indeed a grade.\n");

return 0;}

else if

if statements distinguish between exactly 2 cases and execute different code in each case

The else-if construction allows for a multi-way decision

else if

if (expression)

statement

else if (expression)

statement

else if (expression)

statement

else

statement

An example

if (grade >= 90) printf ("A\n");

else if (grade >= 80) printf ("B\n");

else if (grade >= 70) printf ("C\n");

else if (grade >= 60) printf ("D\n");

else printf ("F\n");

Validating input

When getting input from the user, it is highly recommended to check whether it is valid.

If it’s not, you should display an appropriate message and return a non-zero value.

For example –if (grade < 0 || grade > 100){

printf(“Invalid input!\n”);return 1;

}

The return keyword

For now, used to terminate the program and return a value to the operating system

If the program is successful the return value should be zero; non-zero otherwise

The exact nature of this keyword will become clear in the future

Exercise

Input – An English letter

Output – If input is a lowercase letter – the corresponding

uppercase letter If input is an uppercase letter - corresponding

lowercase letter Notes –

1. You do not need the specific ASCII values!!2. Remember to check for input validity!

Solution

#include <stdio.h>

int main( ){

char c;

printf("Please enter an english letter: ");scanf("%c", &c);

if (c <= 'z' && c >= 'a')printf("%c in uppercase is %c\n", c, c-'a'+'A');

else if (c <= 'Z' && c >= 'A')printf("%c in lowercase is %c\n", c, c-'A'+'a');

else{

printf("%c is not an english letter!\n", c);return 1;

}

return 0;}

The ?: operator

expr1 ? expr2 : expr3 Nicer way to write:

(expr1)? expr2 : expr3 If expr1 is true (non-zero), expr2 is

evaluated. Otherwise, expr3 is evaluated

The ?: operator

#include <stdio.h>

int main(){

int i, j, min;

printf("Please enter two numbers: ");scanf("%d%d", &i, &j);

min = (i < j)? i : j;printf("The minimum between %d and %d is %d\n", i, j, min);

return 0;}

The switch statement a multiway conditional statement

similar to if-else if-else allows the selection of an arbitrary number of choices

based on an integer value

switch (expression) { case const-expr:

statements case const-expr:

statements … default:

statements}

The switch statement

expression must have an integer value when the switch statement is executed:

the expression is evaluated if a case matches the value of the expression,

the program jumps to the first statement after that case label

otherwise, the default case is selected the default is optional

That grade example again

switch (grade/10) { case 10: case 9:

printf ("A\n"); break;

case 8: printf ("B\n"); break;

case 7: printf ("C\n"); break;

case 6: printf ("D\n"); break;

default: printf ("F\n");

}

Give me a break

when the switch transfers to the chosen case, it starts executing statements at that point

it will “fall through” to the next case unless you “break out”

break causes the program to immediately jump to the next statement after the switch statement

A more interesting example

#include <stdio.h>

int main( ) {

double n1, n2, res;char op;

printf("Please enter two numbers: ");scanf("%lf%lf", &n1, &n2);

printf("Please enter an arithmetical operator (+, -, * or /): ");scanf(" %c", &op); /* The space before the %c will be explained... */

A more interesting example

switch(op) {case '+':

res = n1+n2;break;

case '-':res = n1-n2;break;

case '*':res = n1*n2;break;

case '/': /* We're not checking for division by zero for clarity... */res = n1/n2;break;

default:printf("%c is an invalid arithmetical operator!\n", op);return 1;

}

/* Display the expression and its result */printf("%g %c %g = %g\n", n1, op, n2, res);

return 0;}

Exercise

Write a program that accepts a number between 1 and 100 from the user. If there is a coin of that value in cents, it should display its name. Otherwise, it should report that there is no such coin

1 = cent, 5 = nickel, 10 = dime, 25 = quarter, 100 = dollar

Remember to check for the validity of the input!

Solution

/#include <stdio.h>

int main(){

int num;

printf("Please enter a number from 1 to 100: ");scanf("%d", &num);

/* Make sure the input is valid */if (num<1 || num>100) {

printf("Invalid input!\n");return 1;

}

/* Display the correct coin name, or a default message if there's no such coin */switch (num) {case 1:

printf("It's a cent!\n");break;

case 5:printf("It's a nickel!\n");break;

case 10:printf("It's a dime!\n");break;

case 25:printf("It's a quarter!\n");break;

case 100:printf("It's a whole dollar!\n");break;

default:printf("It's not a coin!\n");

}

return 0;}

Debugging

It is virtually impossible to program without errors

Syntax errors are detected by the compiler

However, often a program has no syntax errors and compiles, but still doesn’t perform as desired

Debugging

Debuggers are software tools designed to help find software bugs

Both Visual C and the lcc compiler include a debugger

Debugging

The debugger allows us to – Execute the program one line at a time At each step see the values of all

variables and expressions Run the program up to a pre-specified

point And more…

Documents

Programming C for Engineers An exercise is posted on the web site! Due in one week Single submission