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Quadratic Graphs – Day 2
• Warm-Up:• Find the turning point and roots of each
parabola without a calculator1.y = x2 – 8x + 12.y = -x2 – 6x - 2
Quadratic Graphs – Writing the Equation
• Standard Form:• y – y1 = a(x – x1)2
• (x1, y1) will be the turning point of the graph• Must find a value to complete equation.• Similar to finding “b” value in y = mx + b• Example: A parabola has a turning point of (1,2)
and also passes through the point (3, -6)• Find its equation
Quadratic Graphs – Writing the Equation Practice
1. Turning Point (4,-1) Passes through the point (2,3)
2. Vertex (2,3) Passes through the point (0,2)3. Turning Point (-2,-2) Passes through the point
(-1,0)4. Vertex (5/2, -3/4), passes through the point (-
2,4)5. Vertex (2,3) Passes through the point (0,2)
Quadratic Graphs – Writing the Equation Practice
1. Turning Point (5,-6) Passes through the point (1,3)
2. Vertex (2,3) Passes through the point (0,4)3. Turning Point (-2, 2) Passes through the point
(-3,0)4. Vertex (7/2, -1/4), passes through the point
(-5,3)
Quadratic Graphs – Applications
• Flight of an Object• The height of a football punted on 4th down is
given by the equation:• y = -16/2025 x2 + 9/5 x + 1.5
• where x is the distance in feet covered horizontally along the field.
• a) How high is the ball when punted?• b) What is the maximum height of the punt? • c) How far does the punt travel?
Quadratic Graphs – Applications
• Maximum Profit• The profit that a certain company makes is
dependent on the amount of advertising they do for their product.
• Profit follows the equation:• P = 230+ 20x - .5x2
– Where p is profit and x is $ spent on advertising.
• What amount of advertising will yield a maximum profit?
Quadratic Graphs – Applications
• Maximum Revenue– Total Revenue earned (in thousands of dollars)
from manufacturing hand-held smartphones is given by:• R(x) = -25x2 + 1200x• Where x is the price per unit
– Find revenue when price is• $20, $25, $30
– What price will result in the maximum revenue?– What is the maximum revenue?