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o Now : copy & complete The alveoli are bunches of tiny air sacks inside the lungs. Each individual sack is called an alveolus. They are located at the end of the bronchioles. When you breathe in, they fill with air. The alveoli are covered in tiny blood vessels called capillaries. The capillaries are very thin (one cell thick) so O 2 and CO 2 can pass through each alveolus into the blood stream. Word list: capillaries blood bronchioles alveolus alveoli

Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

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Page 1: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Quantitative Genetics

• Theoretical justification

• Estimation of heritability– Family studies– Response to selection– Inbred strain comparisons

• Quantitative trait loci (QTL)

• Genetic correlations

Page 2: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Most traits follow a normal distribution

Page 3: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

When multiple genes affect a trait, expect a continuous distribution

Page 4: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

But, the environment also contributes variation

Isogenic line of Drosophila

Page 5: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Quantitative genetics• Partitions genetic and environmental effects• Assumptions

– Each locus contributes additively to the trait– Environmental effects are independent

• Definitions: – p = phenotypic value– g = genotypic value– a = additive genetic value (breeding value)– e = environmental effect– d = dominance deviation

• p = g + e and g = a + d, so p = a + d + e

mean p

a Trait valuee

Page 6: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Dominance

• Exists whenever the phenotype of a heterozygote is not the average of the parental values

• Attribute of a genotype, not an allele• May be scale dependent• Only relationships which can share

genotypes can share dominance, e.g. full-sibs, twins

aa Aa AA

Phe

noty

pe

aa Aa AA

Phe

noty

pe

No dominance = additive

Complete dominance

aa Aa AA

Phe

noty

pe

Overdominance

Page 7: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Heritability

• Vp = Vg + Ve

= Va + Vd + Ve

• heritability = h2 = Va/Vp, i.e the fraction of phenotypic variation due to additive genetic effects, i.e. those which can be passed from parent to offspring

• applies only to population measured

• determines the rate of evolution

Page 8: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Galton’s parent-offspring regression

Note: median offspring values regress toward the parental median

h2 = heritability = slope of the regression of midoffspring on midparent

Page 9: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

The regression estimate of heritability

Page 10: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

h2 from family resemblance• Offspring and mid-parent: b = Va/Vp = h2

– b is a regression slope

• Offspring and one parent: b = Va/2Vp = h2/2

• Full-sibs (r = 1/2): t ≥ Vg/2Vp = h2/2

• Identical (MZ) twins: t ≥ Vg/Vp = h2

• Half-sibs (r = 1/4): t = Va/4Vp = h2/4– t is a correlation coefficient

• Therefore: resemblance (b or t) = rh2 where r = degree of relatedness

Page 11: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Example: h2 estimates for IQ

Can the environment alter expression of a trait when h2 = 0.5?

Page 12: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

French IQ experiment

Page 13: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

h2 from Artificial Selection

h2 = 1h2 = 0 h2 = 1/4

Page 14: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Response to selection

R = h2S is the breeder’s equation where

R = the change in means across a generation

h2 = heritability

S = the change in means within a generation due to selection

Page 15: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Response to selection = trait evolution

S

R

Page 16: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Selection for nest building behavior

Page 17: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

h2 from inbred strains

• Inbreeding leads to genetic uniformity

• Ve = variation within an inbred strain or among the F1 progeny

• Vp = variation among F2 progeny

• h2 “broad sense” = (VF2 - VF1)/VF2

Page 18: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Avoidance learning by inbred strains

Page 19: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Note: life history traits tend to have low heritabilities, presumably because selection reduces genetic variation, but almost all traits have some heritable variation

Heritabilities in Drosophila

Page 20: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

QTL analysis

•Much current work aims to locate and estimate the effect of quantitative trait loci (QTLs)•Use F2 or backcross individuals•Genotype each individual at multiple genetic markers•Construct linkage map•Measure association between markers and trait

Page 21: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Correlated response to selection

Troy Bartlett

Page 22: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Genetic correlations• Multiple potential causes

– Physical linkage (proximity of two loci)– Pleiotropy– Selection for allelic combinations– Nonrandom mating

• Persistance– Pleiotropy decays only by mutation– Linkage decays with random mating due to

recombination

• Can alter response to selection– Negative genetic correlation will cause one trait to

become reduced when another is increased– Expect such neg. correlations for life history traits

Page 23: Quantitative Genetics Theoretical justification Estimation of heritability –Family studies –Response to selection –Inbred strain comparisons Quantitative

Sample problem

• A population of sunfish has an average swimming speed of 80 cm/s, individuals having a mean of 110 cm/s survived a flood to be parents of the next generation; their offspring had a mean speed of 90 cm/s. Calculate the realized heritability for swimming speed.

• Selection differential (S) = mean after selection - mean before selection

• selection response (R) = mean of offspring generation - mean of previous generation

• heritability = response / selection, i.e. h2 = R/S

• So: S = 110 - 80 = 30

• R = 90-80 = 10

• and h2 = 10 / 30 = 0.33