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Part 1\: Sl?ecifc Topics Sample. Multiple-Choice Questions: Derivatives A. 4 B. 3 C. 1 D. 0 E. undefined x-a A. m B. m- 2jk C. -2jk D. -2k E. j C. fhas a vertical tangent at x = a. D. fhas a "hole" for x = a. E. None of these is necessarily true. 7. The slope of the curve Y == 6x 1/2 + x at the origin is .., j A. f(x) is discontinuous at x = a. B. limf(x) does not exist. 6. Given that j, k, and m are constants, ani that f(x) == m - 2kx, find t(j). r::;-- . dy 5. ForY==J3-2x, fmd dx' 1 A. ~ 2J3-2x 1 B.. -1-.-- J3-2x 2 C. ~ J3-2x -1 D. /3-2x -2 E. /3-2x 4. Ifj'(a) does NOT exist, which of the following MUST be true? 2. If y == 2 ~ - 1~, then the derivative 2Jx of y with respect to x is given by A. x+ l~ XJX '1 1 B. ~+ xi; 4x-l c. 4x~ D _l_+~ .~ 4x~ E. ~\x~ 3. The function f(x) == \x 2 - 4\ is NOT differentiable at A. x = '2only B. x = -2 only C. x = 2 or x = -2 D. x = 0 only E. x = 2 or x = -2 or x = 0 140 x- 3 dy 1. If y == 2_ 5x' then dx ==, 17-lOx A. (2_ 5x)2 13 B. (2_ 5x)2 x-3 C. (2_ 5x)2 17 D. (2_ 5x)2 -13 E. (2_ 5x)2

Sample.Multiple-Choice Questions: Derivatives · Sample.Multiple-Choice Questions: Derivatives A. 4 B. 3 C. 1 D. 0 E. undefined x-a A. m B. m- 2jk C.-2jk D.-2k E. j C. fhas avertical

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Part 1\: Sl?ecifc Topics

Sample. Multiple-Choice Questions: Derivatives

A. 4

B. 3

C. 1

D. 0

E. undefined

x-a

A. m

B. m- 2jk

C. -2jk

D. -2k

E. j

C. fhas a vertical tangent at x = a.

D. fhas a "hole" for x = a.E. None of these is necessarily true.

7. The slope of the curve Y == 6x 1/2 + x atthe origin is

..,

j

A. f(x) is discontinuous at x = a.

B. limf(x) does not exist.

6. Given that j, k, and m are constants, anithat f(x) == m - 2kx, find t(j).

r::;-- . dy5. ForY==J3-2x, fmd dx'

1A. ~2J3-2x

1B.. -1-.--J3-2x

2C. ~

J3-2x-1

D. /3-2x-2

E. /3-2x

4. Ifj'(a) does NOT exist, which of thefollowing MUST be true?

2. If y == 2 ~ - 1~, then the derivative2Jx

of y with respect to x is given by

A. x+ l~XJX

'1 1B. ~+ xi;

4x-lc. 4x~

D _l_+~. ~ 4x~

E. ~\x~3. The function f(x) == \x

2- 4\ is NOT

differentiable at

A. x = '2 onlyB. x = -2 only

C. x = 2 or x = -2

D. x = 0 onlyE. x = 2 or x = -2 or x = 0

140

x- 3 dy1. If y == 2 _ 5x' then dx ==,

17 -lOxA. (2 _ 5x)2

13B. (2 _ 5x)2

x-3C. (2 _ 5x)2

17D. (2 _ 5x)2

-13E. (2_ 5x)2