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N N
Dimensioned diagram (m.)
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203x203x60UC
S355 20
3x203x60UC
S355
356x1
71x45U
BS355
6000
6000
6708
1608
1800
1500
1500
300
9000
973 816
603
588
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J1
J2
J3
J4
Joint numbers
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M1
M2
M3
N B1 N B2Member numbers
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Columnline1
203x203x60UC
S355
Rafter
356x17
1x45UB
S355
Co
lumnline2
203x2
03x60UC
S355
N NSections diagram
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3.00
Loading diagram for load case: Removable dead
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10.73
Loading diagram for load case: Imposed
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5.72
Loading diagram for load case: Snow1 - Uniform load
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10.54
12.99
14.26
8.41
Loading diagram for load case: Wind1 - Direction 0 deg
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10.50
13.48
22.07
20.26
Loading diagram for load case: Wind2 - Direction 180 deg
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13.02
12.99
18.45
Loading diagram for load case: Wind3 - Direction 90 deg
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0.43
0.43
Loading diagram for load case: Notional
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0.30
0.30
Loading diagram for load case: Notional snow
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Steel
Group Serial Grade kg/m Bars m Tonne
1 - Column line 1 203x203x60UC S355 59.95 1 6.000 0.360
2 - Rafter 356x171x45UB S355 45.00 1 6.708 0.3023 - Column line 2 203x203x60UC S355 59.95 1 9.000 0.540
1.201 per frame
Joints
Name X Ym m
J1 0.000 0.000J2 0.000 6.000
J3 6.000 9.000J4 6.000 0.000
Members
Name Length Section group Ends Jointsm Left/low' Other
M1 6.000 Column line 1 Fix Fix J1 to 2M2 6.708 Rafter Fix Fix J2 to 3
M3 9.000 Column line 2 Fix Fix J4 to 3
Nominal bases
Name Joint % of column stiffness Actual base stiffness
ULS SLS Lcr ULS SLS LcrkN.m/Rad kN.m/Rad kN.m/Rad
B1-Nominal pin J1 Pin 20% 10% Pinned 1674.04 837.018B2-Nominal pin J4 Pin 20% 10% Pinned 1116.02 558.012
Load cases
Name Type
Permanent dead Permanent dead
Removable dead Removable deadImposed Imposed
Snow1 - Uniform load Snow
Wind1 - Direction 0 deg Wind
Wind2 - Direction 180 deg WindWind3 - Direction 90 deg WindNotional Notional imposed
Notional snow Notional snow
Load combination set: 'Eurocode 3'
Name Limit Factor Load case
Dead+Imposed ULS 1.35 Permanent dead
1.35 Removable dead1.50 Imposed0.00 Snow1 - Uniform load
0.00 Wind1 - Direction 0 deg0.00 Wind2 - Direction 180 deg0.00 Wind3 - Direction 90 deg0.00 Notional
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Load combination set: 'Eurocode 3'
Name Limit Factor Load case
0.00 Notional snow
Uniformly distributed loads
Load case : Permanent deadName Member Value Direction
kN/m
L1 M2 0.44 Vertical Self weightL2 M1 0.59 Vertical Self weight
L3 M3 0.59 Vertical Self weightL4 M2 3.00 VerticalL5 M2 1.00 Vertical
Uniformly distributed loads
Load case : Removable deadName Member Value Direction
kN/m
L6 M2 3.00 Vertical
Uniformly distributed loads
Load case : ImposedName Member Value Direction
kN/m
L7 M2 10.73 Vertical
Uniformly distributed loads
Load case : Snow1 - Uniform loadName Member Value Direction
kN/m
L8 M2 5.72 Vertical
Uniformly distributed loads
Load case : Wind1 - Direction 0 degName Member Value Direction
kN/m
L9 M1 10.54 NormalL10 M3 12.99 Normal
Uniformly distributed loads over part of member
Load case : Wind1 - Direction 0 degName Member Value Start Finish Measured Direction
Distance Distance fromkN/m m m
L11 M2 14.26 0.000 2.012 Left end NormalL12 M2 8.41 2.012 6.708 Left end Normal
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Uniformly distributed loads
Load case : Wind2 - Direction 180 degName Member Value Direction
kN/m
L13 M3 10.50 Normal
L14 M1 13.48 Normal
Uniformly distributed loads over part of member
Load case : Wind2 - Direction 180 degName Member Value Start Finish Measured Direction
Distance Distance fromkN/m m m
L15 M2 22.07 4.696 6.708 Left end Normal
L16 M2 20.26 0.000 4.696 Left end Normal
Uniformly distributed loads
Load case : Wind3 - Direction 90 deg
Name Member Value DirectionkN/m
L17 M1 13.02 NormalL18 M3 12.99 Normal
L19 M2 18.45 Normal
Point loads
Load case : Notional
Name Member Value Distance Measured DirectionkN m from
L20 M1 0.43 6.000 Bottom HorizontalL21 M3 0.43 9.000 Bottom Horizontal
Point loads
Load case : Notional snowName Member Value Distance Measured Direction
kN m from
L22 M1 0.30 6.000 Bottom Horizontal
L23 M3 0.30 9.000 Bottom Horizontal
Purlins and rails
Name Member Distance Measured Flange Hasm from stay
P1 M2 6.408 Left end Top NoP2 M2 4.908 Left end Top No
P3 M2 3.408 Left end Top NoP4 M2 1.608 Left end Top No
Haunches
Name Rafter Column Length Depthm m
H1 M2 M1 1.000 0.603H2 M2 M3 1.000 0.588
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Forces - Linear elastic analysis
Loading combination: 'Dead+Imposed' of combination set: 'Eurocode 3'
Member Distance Measured Axial Sense Shear Moment
m from kN kN kN.m
M1 0.000 Bottom -87.59 Compression -5.45 -0.005.397 Bottom -83.31 Compression -5.45 -29.395.397 Bottom -83.31 Compression -5.45 -29.39
6.000 Bottom -82.83 Compression -5.45 -32.68
M2 0.000 Left end -41.91 Compression 71.65 -32.68
0.333 Left end -41.91 Compression 71.65 -8.800.333 Left end -41.91 Compression 71.65 -8.79
0.456 Left end -41.91 Compression 71.65 0.01
1.000 Left end -41.91 Compression 71.65 38.971.000 Left end -41.91 Compression 71.65 38.97
1.608 Left end -41.91 Compression 71.65 82.551.608 Left end -12.59 Compression 12.99 82.553.408 Left end -12.59 Compression 12.99 105.94
3.408 Left end 6.71 Tension -25.59 105.944.908 Left end 6.71 Tension -25.59 67.554.908 Left end 24.25 Tension -60.67 67.55
5.708 Left end 24.25 Tension -60.67 19.025.708 Left end 24.25 Tension -60.67 19.026.022 Left end 24.25 Tension -60.67 0.016.375 Left end 24.25 Tension -60.67 -21.43
6.375 Left end 24.25 Tension -60.67 -21.436.408 Left end 24.25 Tension -60.67 -23.45
6.408 Left end 36.52 Tension -85.22 -23.456.708 Left end 36.52 Tension -85.22 -49.02
M3 0.000 Bottom -99.71 Compression 5.45 0.00
8.412 Bottom -93.03 Compression 5.45 45.828.412 Bottom -93.03 Compression 5.45 45.82
9.000 Bottom -92.56 Compression 5.45 49.02
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The out of plane stability checks applied by Quikport are summarised:-
Elastic PlasticUniform Tapering Uniform Tapering
Between 6.3.3 6.3.3 BB.3.1.1 BB.3.2.1restraints to Mcrref 1 Mcrref 1 and 2 (Lm) (Lm)compression or BB.3.1.1 or BB.3.2.1flange
Between 6.3.3 6.3.3 BB.3.1.1 BB.3.2.1restraints to Mcrref 1 Mcrref 1 and 2tension flange or BB.3.1.1 or BB.3.2.1
Lengths between 6.3.3 6.3.3 BB.3.1.2 BB.3.2.2lateral torsional Ncrref 2 Ncrref 2restraints with Mcrref 2 Mcrref 2intermediaterestraints to thetension flange
ref 1 - Access Steel SN003a-EN-EUref 2 - Charles King, SCI P164: Design of Steel Portal Frames for Europe, The Steel
Construction Institute, 2001
Checks applied between restraints to the tension flange are a requirement of BB.3.1.2 and ref 1
Quikport assumes all haunches to be three flanged. Where a hinge forms at the end of a haunch in arafter, the program first checks that the haunch remains elastic and if beneficial selects an elasticcheck.
Annex BB.3 of EN 1993-1-1:2005 is similar to BS5950-1 Annex G. However it covers only lengths thatcontain plastic hinges. For elastic lengths with intermediate restraints to the tension flange Quikportuses the methods described in ref 1 above.
In the checks to lengths that contain intermediate restraints to the tension flange, a virtual torsionalrestraint is assumed at points of contraflexure. This approach is described in section 5.5.5 ofBS5950-1:2000. Quikport's behaviour may be changed by adding a rafter stay in the lengthimmediately prior to the contraflexure.
Finally the program checks that a lateral torsional restraint is provided within h/2 of each hinge.See 6.3.5.2(4)B.
Note:in the application of all stability checks Quikport always assumes lateral torsional restraint at allmember ends including the column at the underside of the haunch. The designer should carefullyconsider whether this assumption is true for each member. In particular this may be a problem at theapex, when considering wind uplift and in elastic designs at the eaves in the column at the undersideof the haunch.
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National Annex: UK National Annex
EN 1993-1-1: 2005 General rules and rules for buildings
3.2.1(1) fyand futaken from product standard
6.1(1) Partial factors
0 = 1.000 resistance of cross section1 = 1.000 resistance of members to instability2 = 1.100 resistance of cross-sections in tension fracture
6.3.2.3(1) For rolled sections, hot-finished and cold-formed hollow sections:_
LT,0 = 0.400 = 0.750
For welded sections_
LT,0 = 0.200 = 1.000
Table 6.5 taken from UK National Annex
6.3.3(5) Determination of interaction factors kyy, kyz, kzy, kzzFor doubly symmetrical sections use: Method 1 given in Annex AFor mono-symmetrical sections use: Method 2 given in Annex B
EN 1993-1-8: 2005 Design of joints
2.2(2) Partial factors
2 = 1.250 resistance of bolts2 = 1.250 resistance of welds2 = 1.250 resistance of plates in bearing3 = 1.250 slip resistance at ultimate limit state (Category C)3,ser = 1.100 slip resistance at serviceability limit state (Category B)u = 1.100 partial factor for tying resistance
EN 1992-1-1: 2004 Design of concrete structures - General rules and rules for buildings
C = 1.500 partial factor for concreteS = 1.150 partial factor for reinforcing steelcc = 1.000 is the coefficient taking account of long term effects on the compressive strength
and of unfavourable effects resulting from the way the load is applied
ct = 1.000 is the coefficient taking account of long term effects on the tensile strength andof unfavourable effects, resulting from the way the load is applied
CRd,c = 0.180/C as defined in 6.2.2(1)
EN 1994-1-1: 2004 Design of composite steel and concrete structures - General rulesand rules for buildings
V = 1.250 partial factor for design shear resistance of a headed stud
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Detailed steel calculationsM1 - From (0.000,0.000) to (0.000,6.000) length = 6.000
Section group : Column line 1Section size : 203x203x60UC S355 t = 14.2 mm. fy= 355 N/mm
2.
Analysis - Linear elastic analysisCombination - 'Dead+Imposed' of Combination set: 'Eurocode 3'
Section classificationNc,Ed = 87.59 kN. Compression
= 0.814
Classification - Y axis bendingFlange = Class 1 Part subject to compression c/t=6.20 limit=7.32Flange = Class 1 Part subject to tension
Web = Class 1 = 0.58 Bending and compression c/t=17.11 limit=49.11Section = Class 1
PropertiesWpl,y = 656.1 cm
3. (6.13)
Plastic shear capacity - Y axisVy,Ed = 5.45 kN.Avy = 22.16 cm
2Clause 6.2.6(3)
Vc,y,Rd= Avy(fy/3)/0 = 454.14 kN. (6.18)
Vy,Ed = 0.01 Pass (6.17) < 0.5 Low shearVc,y,Rd
Moment and axial - Y axis 6.2.9.1(4)NEd< 0.25 Npl,Rd (6.33)
NEd< 0.5 hw tw fy/ 0 (6.34)
Axial force may be ignored in the calculation of the plastic resistance moment.
MN,y,Rd= My,Ed = 232.91 kN.m.
Combined capacity @ 5.397 'before' 6.2.9.1(6) (6.41)
My,Ed 29.39 = = 0.13 PassMN,y,Rd 232.91
Checking portion 0.000 to 5.397 m. Elastic
Lateral torsional bucklingWy = Wpl,y Class 1 cross section
Determine C1 from published tablesC1 = 1.69
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Mcr = 467.44 kN.m. Access Steel SN003a-EN-EU
_LT = (Wy.fy/Mcr) = ( 656.1 x 355 x 0.001 / 467.44) = 0.706
_
Using Equation (6.57) : LT= 0.706 and buckling curve 'c' Rolled sections or equivalent weldedLT = 0.867
Flexural buckling 6.3.1.3
Ncrz =2E.I/Lcrz2 = 2 210 x 2065 x 104/ 53972 = 1469.20 kN._
= (A.fy/Ncrz) = ( 76.4 x 355 x 0.1 / 1469.20) = 1.36_
From Figure 6.4 using: = 1.36 and buckling curve 'c' (see Table 6.2)
z = 0.365Combined bending and axial compression Clause 6.3.3 and (6.62)
NEd My,Ed + kzy < 1.00 kzy = 0.989 from Annex Bz.NRk/ 1 LT.My.Rk/ 1
87.59 29.39
+ 0.989 = 0.23 Pass0.37 x 2711.25 / 1.00 0.87 x 232.91 / 1.00
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M2 - From (0.000,6.000) to (6.000,9.000) length = 6.708Section group : RafterSection size : 356x171x45UB S355 t = 9.7 mm. fy= 355 N/mm
2.
Analysis - Linear elastic analysisCombination - 'Dead+Imposed' of Combination set: 'Eurocode 3'
Section classificationNc,Ed = 41.91 kN. Compression
= 0.814
Classification - Y axis bendingFlange = Class 2 Part subject to compression c/t=7.41 limit=8.14
Flange = Class 1 Part subject to tensionWeb = Class 1 = 0.53 Bending and compression c/t=44.51 limit=55.06Section = Class 2
PropertiesWpl,y = 774.6 cm
3. (6.13)
Plastic shear capacity - Y axisVy,Ed = 71.65 kN.Avy = 26.79 cm
2Clause 6.2.6(3)
Vc,y,Rd= Avy(fy/3)/0 = 549.11 kN. (6.18)
Vy,Ed
= 0.13 Pass (6.17) < 0.5 Low shearVc,y,Rd
Moment and axial - Y axis 6.2.9.1(4)NEd< 0.25 Npl,Rd (6.33)
NEd< 0.5 hw tw fy/ 0 (6.34)
Axial force may be ignored in the calculation of the plastic resistance moment.
MN,y,Rd= My,Ed = 274.99 kN.m.
Combined capacity @ 3.408 'before' 6.2.9.1(6) (6.41)
My,Ed 105.94
= = 0.39 PassMN,y,Rd 274.99
Checking portion 3.408 to 4.908 m. Elastic
Use BB.3.1.1
Calculate Lmusing: NEd= 0.00 kN. M1= 105.94 M2= 67.55 = 0.246 C1 = 1.57iz= 3.76 cm A = 57.3 cm
2 Wpl,y = 774.6 cm3It= 15.85 cm
4 fy= 355 N/mm2
38 izLm = = 1.587 m. (BB.5)
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(..)> 1.500 m. Pass
Checking portion 6.022 to 6.708 m. Elastic intermediate tension flange restraints
Use SCI guide P164Calculate elastic critical torsional buckling force (tension flange restraints)is
2 = iy2+ iz
2+ a2 =199.552+ 34.52+ 300.72 = 131431 mm2
1 2E Iza2 2E IwNcrT = ( + + G It) = 41342.08 kN.
is2 Lt
2 Lt2
_
= (A.fy/NcrT) = ( 68.1 x 355 x 0.1 / 41342.08) = 0.24_From Figure 6.4 using: = 0.24 and buckling curve 'b' (see Table 6.2)z = 0.985
Calculate Cn
My,Ed Wel,y fyWpl,y R kN.m. cm3. kN.m. My,Ed/(fyWpl,y)
1 0.0 1211.3 430.0 0.0002 10.4 1365.2 484.7 0.0213 20.8 1560.5 554.0 0.0384 34.4 1787.4 634.5 0.054
5 49.0 2040.8 724.5 0.068S 49.0 2040.8 724.5 0.068E 49.0 2040.8 724.5 0.068
12
Cn = = 26.97 (BB.14) R1 +3R2 +4R3 +3R4 +R5 +2(RS - RE)
Calculate taper factorusing: h/tf= 52.1 hh= 0.339 hs= 0.393 Figure BB.6(b)Lh= 0.643 Ly= 0.330
3
c = 1 + (hh/hs - 1)2/3(Lh/Ly) = 1.088 (BB.17) (h/tf - 9)
Calculate the elastic critical moment (tension flange restraints)Mcr0 = is
2/ (2 a) NcrT = 9034.97 kN.m.Mcr = (Cn/ c
2) Mcr0 =205822.47 kN.m._
LT = (Wy.fy/Mcr) = ( 1259 x 355 x 0.001 /205822.47) = 0.047_
Using Equation (6.57) : LT= 0.047 and buckling curve 'b' Rolled sections or equivalent weldedLT = 1.000
Combined bending and axial compression NEd My,Ed
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+ < 1.00
z.NRk/ 1 LT.My.Rk/ 1
Distance NEd NRk=A.fy My,Ed My,Rk =Wpl,y.fy Unity m. kN. kN. kN.m. kN.m.
6.022 0.00 2418.57 0.01 446.81 0.00 6.208 0.00 2418.57 11.32 555.59 0.02 6.458 0.00 2418.57 27.71 715.73 0.04 6.708 0.00 2418.57 49.02 892.37 0.05
Passed
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M3 - From (6.000,0.000) to (6.000,9.000) length = 9.000Section group : Column line 2Section size : 203x203x60UC S355 t = 14.2 mm. fy= 355 N/mm
2.
Analysis - Linear elastic analysisCombination - 'Dead+Imposed' of Combination set: 'Eurocode 3'
Section classificationNc,Ed = 99.71 kN. Compression
= 0.814
Classification - Y axis bendingFlange = Class 1 Part subject to compression c/t=6.20 limit=7.32
Flange = Class 1 Part subject to tensionWeb = Class 1 = 0.59 Bending and compression c/t=17.11 limit=48.03Section = Class 1
PropertiesWpl,y = 656.1 cm
3. (6.13)
Plastic shear capacity - Y axisVy,Ed = 5.45 kN.Avy = 22.16 cm
2Clause 6.2.6(3)
Vc,y,Rd= Avy(fy/3)/0 = 454.14 kN. (6.18)
Vy,Ed
= 0.01 Pass (6.17) < 0.5 Low shearVc,y,Rd
Moment and axial - Y axis 6.2.9.1(4)NEd< 0.25 Npl,Rd (6.33)
NEd< 0.5 hw tw fy/ 0 (6.34)
Axial force may be ignored in the calculation of the plastic resistance moment.
MN,y,Rd= My,Ed = 232.91 kN.m.
Combined capacity @ 8.412 'before' 6.2.9.1(6) (6.41)
My,Ed 45.82
= = 0.20 PassMN,y,Rd 232.91
Checking portion 0.000 to 8.412 m. Elastic
Lateral torsional bucklingWy = Wpl,y Class 1 cross section
Determine C1 from published tablesC1 = 1.69Mcr = 275.20 kN.m. Access Steel SN003a-EN-EU_
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LT = (Wy.fy/Mcr) = ( 656.1 x 355 x 0.001 / 275.20) = 0.920_
Using Equation (6.57) : LT= 0.920 and buckling curve 'c' Rolled sections or equivalent weldedLT = 0.748
Flexural buckling 6.3.1.3
Ncrz =2E.I/Lcrz2 = 2 210 x 2065 x 104/ 84122 = 604.69 kN._
= (A.fy/Ncrz) = ( 76.4 x 355 x 0.1 / 604.69) = 2.12_
From Figure 6.4 using: = 2.12 and buckling curve 'c' (see Table 6.2)z = 0.178
Combined bending and axial compression Clause 6.3.3 and (6.62)NEd My,Ed + kzy < 1.00 kzy = 0.941 from Annex Bz.NRk/ 1 LT.My.Rk/ 1
99.71 45.82
+ 0.941 = 0.45 Pass0.18 x 2711.25 / 1.00 0.75 x 232.91 / 1.00
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End of steel calculations
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N N
-87.59
-82.83
-41.91
+36.52
-41.91
-99.71
-92.56
Axial force diagram compression negative (kN.) - Linear elastic analysis
Loading combination: 'Dead+Imposed' of combination set: 'Eurocode 3'
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N N
5.45
5.45
71.6
5
85.22
85.22
5.45
5.45
Shear force diagram (kN.) - Linear elastic analysis
Loading combination: 'Dead+Imposed' of combination set: 'Eurocode 3'
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N N
32.68
32.68
49.02
105.94
49.02
Bending moment diagram (kN.m.) - Linear elastic analysis
Loading combination: 'Dead+Imposed' of combination set: 'Eurocode 3'
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N N
Unity=0.13
Class1
Unity=
0.39
Class2
U
nity=0.20
Class1
Member capacity diagram - Linear elastic analysis
Loading combination: 'Dead+Imposed' of combination set: 'Eurocode 3'
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N N
5.397
1.608
1.800
1.500
1.500
0.300
0.687
8.412
Member stability diagram - Linear elastic analysis
Loading combination: 'Dead+Imposed' of combination set: 'Eurocode 3'
Skanska Technology LimitedMaple Cross HouseDenham WayMaple CrossRickmansworthWD3 6SW
Printed : 20/02/2014 Sheet : 34
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Title : Sports Hall
Designed : NT Checked : FM