23
Register-Transfer (RT) Synthesis Greg Stitt ECE Department University of Florida

Register-Transfer (RT) Synthesis

  • Upload
    kaili

  • View
    29

  • Download
    0

Embed Size (px)

DESCRIPTION

Register-Transfer (RT) Synthesis. Greg Stitt ECE Department University of Florida. Introduction. Register-transfer (RT) synthesis Definition: Synthesis from register transfer level (RTL) descriptions VHDL, Verilog typically describe circuits as connections of RTL components - PowerPoint PPT Presentation

Citation preview

Page 1: Register-Transfer (RT) Synthesis

Register-Transfer (RT) Synthesis

Greg StittECE Department

University of Florida

Page 2: Register-Transfer (RT) Synthesis

Introduction Register-transfer (RT) synthesis

Definition: Synthesis from register transfer level (RTL) descriptions

VHDL, Verilog typically describe circuits as connections of RTL components

What are register-transfer level components? Muxes, ALUs, registers, multipliers, etc. One abstraction level above gates

Basically, components you use in most structural descriptions What are other levels?

Transistor level Gate level Register transfer level High level System level Etc.

Page 3: Register-Transfer (RT) Synthesis

RT Synthesis Main Steps

Lex/Parsing Analyzes HDL, converts into intermediate representation

Resource Allocation Maps intermediate representation into RT components

Optimizations Logic minimization State minimization State encoding Etc.

Technology Mapping Placement + Routing

Page 4: Register-Transfer (RT) Synthesis

Technology Mapping Converts circuit from one technology

(e.g. gates) onto technology used by physical device (e.g. LUTs, CLBs, etc)

CLB CLB CLB CLB

CLBCLB

Page 5: Register-Transfer (RT) Synthesis

Placement Input: Technology-mapped circuit

For simplicity, just consider CLBs Technology-mapped circuit consists of “virtual” CLBs and

“virtual” connections FPGA fabric consists of physical CLBs

Simplified Placement Definition: Map “virtual” CLBs onto physical CLBs

I.e. Decide on a location in the FPGA for each virtual CLB

1 2 3 4

65

CLB CLB CLB CLB CLB

CLB CLB CLB CLB CLB

CLB CLB CLB CLB CLB

1 2 3 4 CLB

5 CLB 6 CLB CLB

CLB CLB CLB CLB CLB

Technology Mapped Circuit

FPGA Fabric Possible Placement

Page 6: Register-Transfer (RT) Synthesis

Routing Input: A set of placed components, and a list of

“virtual” connections Simplified Routing Definition:

Determine how to configure routing resources to implement “virtual” connections

1 2 3 4 CLB

5 CLB 6 CLB CLB

CLB CLB CLB CLB CLB

1 2 3 4

65

Physical CLBs not connected – must configure routing resources to implement these connections:

Page 7: Register-Transfer (RT) Synthesis

Placement+Routing (PAR) Placement and routing highly dependent

Placement affects how well circuit can be routed Example:

1 2 3 4

65

1 2 3 4 CLB

5 CLB 6 CLB CLB

CLB CLB CLB CLB CLB

6 3 CLB 1 CLB

CLB CLB 4 CLB CLB

2 CLB CLB CLB 5

Placement 1 Placement 2

Clearly, placement 1 is easier to route

Page 8: Register-Transfer (RT) Synthesis

Placement+Routing (PAR) Goals:

1) Make sure circuit can be implemented on fabric Trivial for placement, difficult for routing Bad placement may make circuit unroutable

2) Minimize delay of critical path Critical path is the longest register to register delay Important - Determines clock speed of circuit

Why is placement and routing important? Bad PAR = slow circuit

Even worse, BAD PAR = no circuit

1 2 3 4 CLB

5 CLB 6 CLB CLB

CLB CLB CLB CLB CLB

6 3 CLB 1 CLB

CLB CLB 4 CLB CLB

2 CLB CLB CLB 5

Even if routing is possible, placement 2 likely to have longer wires – slower clock

Placement 2Placement 1

Page 9: Register-Transfer (RT) Synthesis

Placement Problem: Find a placement for each CLB, such that

routing can maximize clock speed Challenges:

1) Huge solution space! Tiny Example: Fabric = 100 physical CLBs, Circuit = 10 “virtual” CLBs

Possibilities = 100! / 90! = 6.2 * 1019 And, that is for a tiny fabric and tiny circuit!!!!!!!!!!! Guess what … placement is NP-Complete

2) How to know how good the routing will be? One (im)possibility - perform routing for each possible placement

Tiny example, cont. - assume same number of routing possibilities as placement possibilities

6.2 * 1019 * 6.2 * 1019 = A BIG NUMBER! Routing is also NP-complete

Cleary, placement needs to estimate quality of routing Estimate known as a cost function

Page 10: Register-Transfer (RT) Synthesis

Cost Function Examples Example: average wire length

Motivation: short wires faster than long wires

Not perfect - many short wires not on critical path may lead to inaccuracy

i.e. critical path may still be long despite short average wire length

How to determine wire length? Without routing, don’t know length Possibilities:

1) Euclidian distance - measure straight line distance between CLBs

Ignores how wire would be routed (can’t route diagonals)

2) Manhattan distance - shortest “zig-zag” distance

Includes bends between CLBs

CLB CLB CLB

CLB CLB CLB

CLB CLB CLB

CLB CLB CLB

CLB CLB CLB

CLB CLB CLB

Euclidian Distance

Manhattan Distance

Page 11: Register-Transfer (RT) Synthesis

Placement Techniques Placement is an NP-complete optimization problem

Many possible placements, we want the best one What does this suggest for a solution? Remember last lecture!

1) Branch and bound Likely not feasible

2) Map to other NP-complete problem - use heuristic for that problem 3) Use general optimization heuristics

Simulated annealing Hill climbing Very common (notice the temperature numbers in Xilinx ISE)

How to use general optimization heuristics? Cost function represents quality of placement Neighboring solution – try new location for a “virtual” CLB, swap 2 CLBs,

etc.

Page 12: Register-Transfer (RT) Synthesis

Placement Techniques Also common to map placement to other NP-

complete problems Example: Min-cut problem

Background: Given a graph, a cut is a set of edges that divides the graph into two (or more) groups

Min-cut problem definition: Find the minimum cut size for a given graph

Similar to graph bipartitioning problemCutsize = 5 Cutsize = 3

Page 13: Register-Transfer (RT) Synthesis

Placement Techniques How can graph bipartitioning/min-cut be used for

placement? Graph: Nodes are CLBs, Edges are wires Partition divides FPGA into sections

Goal: minimize communication between sections Bipartitioning attempts to reduce routing

“congestion” i.e. Cost function is cut size

We can use common heuristic for graph bipartitioning Kernighan-Lin (KL) Heuristic

Page 14: Register-Transfer (RT) Synthesis

Placement Techniques KLFM Heuristic (Kernighan-Lin Fiduccia-Mattheyses) Basic Idea:

Start with initial partition Iteratively improves cutsize

Cutsize is number of edges between partitions Moves one node at a time

Node that gives greatest reduction or least degradation Lock node after moving Continue moving nodes until all locked or size constraints

are violated Find best partitioning, unlock all nodes Repeat until no improvement found

Page 15: Register-Transfer (RT) Synthesis

KLFM Algorithm

Initial Partition

Cutsize = 5

Size = 3 Size = 3Maximum Size = 4

Page 16: Register-Transfer (RT) Synthesis

KLFM Algorithm

Cutsize = 3

Size = 4 Size = 2Maximum Size = 4

Page 17: Register-Transfer (RT) Synthesis

KLFM Algorithm

Cutsize = 2

Size = 3 Size = 3Maximum Size = 4

Page 18: Register-Transfer (RT) Synthesis

KLFM Algorithm

Cutsize = 2

Size = 2 Size = 4Maximum Size = 4

Page 19: Register-Transfer (RT) Synthesis

KLFM Algorithm

Cutsize = 4

Size = 3 Size = 3Maximum Size = 4

Page 20: Register-Transfer (RT) Synthesis

KLFM Algorithm

Cutsize = 4

Size = 2 Size = 4Maximum Size = 4

Page 21: Register-Transfer (RT) Synthesis

KLFM Algorithm

Cutsize = 5

Size = 3 Size = 3Maximum Size = 4

Page 22: Register-Transfer (RT) Synthesis

KLFM Algorithm

Cutsize = 2

Size = 3 Size = 3

Backtrack to minimum cut size, unlock nodes, and repeat

Page 23: Register-Transfer (RT) Synthesis

Circuit Partitioning How does a partition help us place CLBs?

Apply bipartitioning hierarchically – circuit partitioning

Basic idea 1) Initially divide FPGA into 2 sections

Execute bipartitioning to determine which section “virtual” CLBs get mapped into

2) Divide each section into 2 subsections Execute bipartitioning to determine which subsection

“virtual” CLBs get mapped into 3) Divided each subsection into 2 subsubsections And so on