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Remembering: Molarity and Stoichiometry Because we know you brain is getting full!!!

Remembering: Molarity and Stoichiometry

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Remembering: Molarity and Stoichiometry. Because we know you brain is getting full!!!. Molarity = moles (Molar) or (M) litres. Calculate the molarity of 18 moles of LiBr dissolved in 6.0 L. = 18 moles 6.0 L = 3.0 M. - PowerPoint PPT Presentation

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Page 1: Remembering: Molarity  and  Stoichiometry

Remembering:Molarity

and Stoichiometry

Because we know you brain is getting full!!!

Page 2: Remembering: Molarity  and  Stoichiometry

Molarity = moles (Molar) or (M) litres

Page 3: Remembering: Molarity  and  Stoichiometry

Calculate the molarity of 18 moles of LiBr

dissolved in 6.0 L.

= 18 moles

6.0 L

= 3.0 M

Page 4: Remembering: Molarity  and  Stoichiometry

How many moles of AlF3 are there in 20.5 L of a

0.172 M solution?

Page 5: Remembering: Molarity  and  Stoichiometry

How many moles of AlF3 are there in 20.5 L of a

0.172 M solution?

20.5 L x

Page 6: Remembering: Molarity  and  Stoichiometry

How many moles of AlF3 are there in 20.5 L of a

0.172 M solution?

20.5 L x

1 L

Page 7: Remembering: Molarity  and  Stoichiometry

How many moles of AlF3 are there in 20.5 L of a

0.172 M solution?

20.5 L x 0.172 mole

1 L

Page 8: Remembering: Molarity  and  Stoichiometry

How many moles of AlF3 are there in 20.5 L of a

0.172 M solution?

20.5 L x 0.172 mole = 3.53 moles

1 L

Page 9: Remembering: Molarity  and  Stoichiometry

STOICHIOMETRY

Page 10: Remembering: Molarity  and  Stoichiometry

Stoichiometry is where you use the balancing coefficients to

create a ratio between two different compounds in a

chemical reaction.

Page 11: Remembering: Molarity  and  Stoichiometry

1. How many grams Fe2O3 of are required to produce

105 g of Fe?

2Fe2O3 + 3C → 4Fe + 3CO2

Page 12: Remembering: Molarity  and  Stoichiometry

1. How many grams Fe2O3 of are required to produce

105 g of Fe?

2Fe2O3 + 3C → 4Fe + 3CO2

?g 105 g

Page 13: Remembering: Molarity  and  Stoichiometry

1. How many grams Fe2O3 of are required to produce

105 g of Fe?

2Fe2O3 + 3C → 4Fe + 3CO2

?g 105 g 2

4

Page 14: Remembering: Molarity  and  Stoichiometry

1. How many grams Fe2O3 of are required to produce

105 g of Fe?

2Fe2O3 + 3C → 4Fe + 3CO2

?g 105 g

105 g Fe

Page 15: Remembering: Molarity  and  Stoichiometry

1. How many grams Fe2O3 of are required to produce

105 g of Fe?

2Fe2O3 + 3C → 4Fe + 3CO2

?g 105 g

105 g Fe x 1 mole55.8 g

Page 16: Remembering: Molarity  and  Stoichiometry

1. How many grams Fe2O3 of are required to produce

105 g of Fe?

2Fe2O3 + 3C → 4Fe + 3CO2

?g 105 g

105 g Fe x 1 mole x 2 mole Fe2O

55.8 g 4 mole Fe

Page 17: Remembering: Molarity  and  Stoichiometry

1. How many grams Fe2O3 of are required to produce

105 g of Fe?

2Fe2O3 + 3C → 4Fe + 3CO2

?g 105 g

105 g Fe x 1 mole x 2 mole Fe2O x 159.6 g

55.8 g 4 mole Fe 1 mole

Page 18: Remembering: Molarity  and  Stoichiometry

1. How many grams Fe2O3 of are required to produce

105 g of Fe?

2Fe2O3 + 3C → 4Fe + 3CO2

?g 105 g

105 g Fe x 1 mole x 2 mole Fe2O x 159.6 g = 150.

g55.8 g 4 mole Fe 1 mole

Page 19: Remembering: Molarity  and  Stoichiometry

How many grams of sodium chloride are produced when

you react 65.2 g of sodium carbonate?

1 Na2CO3 + 2 HCl → 2 NaCl + 1 H2O + 1 CO2

Page 20: Remembering: Molarity  and  Stoichiometry

How many grams of sodium chloride are produced when

you react 65.2 g of sodium carbonate?

1 Na2CO3 + 2 HCl → 2 NaCl + 1 H2O + 1 CO2

65.2 g ? g

Page 21: Remembering: Molarity  and  Stoichiometry

How many grams of sodium chloride are produced when

you react 65.2 g of sodium carbonate?

1 Na2CO3 + 2 HCl → 2 NaCl + 1 H2O + 1 CO2

65.2 g ? g

65.2 g x Na2CO3

2

1

Page 22: Remembering: Molarity  and  Stoichiometry

How many grams of sodium chloride are produced when

you react 65.2 g of sodium carbonate?

1 Na2CO3 + 2 HCl → 2 NaCl + 1 H2O + 1 CO2

65.2 g ? g

65.2 g x Na2CO3 x 1 mol Na2CO3

106.0 g Na2CO3

2

1

Page 23: Remembering: Molarity  and  Stoichiometry

How many grams of sodium chloride are produced when

you react 65.2 g of sodium carbonate?

1 Na2CO3 + 2 HCl → 2 NaCl + 1 H2O + 1 CO2

65.2 g ? g

65.2 g x Na2CO3 x 1 mol Na2CO3 x 2 mol NaCl

106.0 g Na2CO3 1 mol Na2CO3

2

1

Page 24: Remembering: Molarity  and  Stoichiometry

How many grams of sodium chloride are produced when

you react 65.2 g of sodium carbonate?

1 Na2CO3 + 2 HCl → 2 NaCl + 1 H2O + 1 CO2

65.2 g ? g

65.2 g x Na2CO3 x 1 mol Na2CO3 x 2 mol NaCl x 58.5 g NaCl

106.0 g Na2CO3 1 mol Na2CO3 1 mol NaCl

2

1

Page 25: Remembering: Molarity  and  Stoichiometry

How many grams of sodium chloride are produced when

you react 65.2 g of sodium carbonate?

1 Na2CO3 + 2 HCl → 2 NaCl + 1 H2O + 1 CO2

65.2 g ? g

65.2 g x Na2CO3 x 1 mol Na2CO3 x 2 mol NaCl x 58.5 g NaCl = 72.0 g

106.0 g Na2CO3 1 mol Na2CO3 1 mol NaCl

2

1

Page 26: Remembering: Molarity  and  Stoichiometry

30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid

solution. What volume of 0.200 M Ba(OH)2 will neutralize this solution?

2 HCl + 1 Ba(OH)2 → 2 H2O + 1 BaCl2

Page 27: Remembering: Molarity  and  Stoichiometry

30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid

solution. What volume of 0.200 M Ba(OH)2 will neutralize this solution?

2 HCl + 1 Ba(OH)2 → 2 H2O + 1 BaCl2

30.2 L ? L

30.2 L HCl

1

2

Page 28: Remembering: Molarity  and  Stoichiometry

30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid

solution. What volume of 0.200 M Ba(OH)2 will neutralize this solution?

2 HCl + 1 Ba(OH)2 → 2 H2O + 1 BaCl2

30.2 L ? L

30.2 L HCl x 1 mol HCl 22.4 L

1

2

Page 29: Remembering: Molarity  and  Stoichiometry

30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid

solution. What volume of 0.200 M Ba(OH)2 will neutralize this solution?

2 HCl + 1 Ba(OH)2 → 2 H2O + 1 BaCl2

30.2 L ? L

30.2 L HCl x 1 mol HCl x 1 mol Ba(OH)2 22.4 L 2 mol HCl

1

2

Page 30: Remembering: Molarity  and  Stoichiometry

30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid

solution. What volume of 0.200 M Ba(OH)2 will neutralize this solution?

2 HCl + 1 Ba(OH)2 → 2 H2O + 1 BaCl2

30.2 L ? L

30.2 L HCl x 1 mol HCl x 1 mol Ba(OH)2 x 1 L Ba(OH)2 = 22.4 L 2 mol HCl 0.200 mol Ba(OH)2

1

2

Page 31: Remembering: Molarity  and  Stoichiometry

30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid

solution. What volume of 0.200 M Ba(OH)2 will neutralize this solution?

2 HCl + 1 Ba(OH)2 → 2 H2O + 1 BaCl2

30.2 L ? L

30.2 L HCl x 1 mol HCl x 1 mol Ba(OH)2 x 1 L Ba(OH)2 = 3.37 L 22.4 L 2 mol HCl 0.200 mol Ba(OH)2

1

2

Page 32: Remembering: Molarity  and  Stoichiometry

250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of

0.300 M KOH will neutralize it?

1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4

Page 33: Remembering: Molarity  and  Stoichiometry

250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of

0.300 M KOH will neutralize it?

1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4

0.100 L ? L

Page 34: Remembering: Molarity  and  Stoichiometry

250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of

0.300 M KOH will neutralize it?

1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4

0.100 L ? L

0.1000 L H2SO4

Page 35: Remembering: Molarity  and  Stoichiometry

250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of

0.300 M KOH will neutralize it?

1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4

0.100 L ? L

0.1000 L H2SO4 x 0.200 mol H2SO4

1L

Page 36: Remembering: Molarity  and  Stoichiometry

250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of

0.300 M KOH will neutralize it?

1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4

0.100 L ? L

0.1000 L H2SO4 x 0.200 mol H2SO4 x 2 mol KOH

1L 1 mol H2SO4

Page 37: Remembering: Molarity  and  Stoichiometry

250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of

0.300 M KOH will neutralize it?

1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4

0.100 L ? L

0.1000 L H2SO4 x 0.200 mol H2SO4 x 2 mol KOH x 1 L KOH

1L 1 mol H2SO4 0.300 mol KOH

Page 38: Remembering: Molarity  and  Stoichiometry

250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of

0.300 M KOH will neutralize it?

1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4

0.100 L ? L

0.1000 L H2SO4 x 0.200 mol H2SO4 x 2 mol KOH x 1 L KOH

1L 1 mol H2SO4 0.300 mol KOH

= 0.133 L of KOH

Page 39: Remembering: Molarity  and  Stoichiometry

Homework: Worksheet #4 (in Molarity Unit)